sorting array with date in string without comparator - ios6

Question

everyone
I am in another mess. I need to sort an array with date in strings and names corresponding to their birthday (date).And then view it in table view. Is there any way?

Answer 1

Use this function to sort by birthday. And make Conditions as per your requirements.
-(void)sortAllDate:(NSMutableArray *)arrayToSort
{
NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:#"self"
ascending:YES];
NSArray *descriptors = [NSArray arrayWithObject:descriptor];
NSArray *reverseOrder = [arrayToSort sortedArrayUsingDescriptors:descriptors];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM-dd-yyyy"];
NSMutableArray *temp = [[NSMutableArray alloc] init];
for (int k=0; k<[reverseOrder count]; k++) {
for(int m=0;m<[frdArray count];m++)
{
NSString *dateStr = [NSString stringWithFormat:#"%#",[[frdArray objectAtIndex:m] birthday]];
if([dateStr isEqualToString:[formatter stringFromDate:[reverseOrder objectAtIndex:k]]])
{
[temp addObject:[frdArray objectAtIndex:m]];
}
}
}
frdArray = temp;
}

Answer 2

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM/dd"];
sortedDataSource = [BdayArr sortedArrayUsingComparator:^NSComparisonResult(NSDictionary *obj1, NSDictionary *obj2) {
NSDate *d1 = [formatter dateFromString:obj1[kKeyDOB]];
NSDate *d2 = [formatter dateFromString:obj2[kKeyDOB]];
return [d1 compare:d2]; // ascending order
//return [d2 compare:d1]; // descending order
}];
NSLog(#"%#",sortedDataSource);
}