What does the -lcs50 command line argument do in clang? - c

Is it a combination of the -l -c and -s arguments? That is my best guess, but why would that be the case if -s only runs the preprocess and compiler when -c does all that and assembles? And what is the 50 on the end for?

-l_libname_ is a switch to tell the compiler (the linker) to include the library named _libname_ in the link phase.
-lcs50 tells the linker to include the cs50 library.

Related

How to let gcc compiler know where a certain file is

I'm trying to compile my C code but I need to tell the GCC compiler where two file are.
The two files are located here
/usr/local/ssl/include/
/usr/local/ssl/lib/
I want to add this to my gcc -o file file.c so that my program can work.
In gcc, the -I option is used for adding a directory to the set of directories to search for header files, and the -L option is used for adding a directory to the set of directories to search for libraries. Since you're not explicitly linking in any libraries, you shouldn't need the -L option in this case.
gcc -I/usr/local/ssl/include -o file file.c
If you were linking in libraries, something like the following format should work, assuming that file.c calls a function in libmyLib.a:
gcc -I/usr/local/ssl/include -o file file.c -L/path/to/my/library -lmyLib
See this question for more details regarding library linking order.

How to compile an executable using clang and safe-stack flag

I am trying to compile a simple hello-world executable using clang-3.7 (also tried 3.8 (dev)) with -fsanitize=safe-stack flag. As explained here (http://clang.llvm.org/docs/SafeStack.html), I need to pass this flag to compiler and linker.
"To enable SafeStack, just pass -fsanitize=safe-stack flag to both compile and link command lines."
I tried the following command to compile an executable:
clang-3.7 -fsanitize=safe-stack -o a.out -Wl,-fsanitize=safe-stack test.c
But the linker tells me, that i need to compile it as a shared library (-shared), if I pass the -f flag to the linker.
/usr/bin/ld: -f may not be used without -shared
How can I compile an executable using the -fsanitize=safe-stack flag?
By "pass it to both the compile and link command lines" the documentation means to pass it both when you're compiling, and when you're linking. It does not mean to use -Wl, which passes it straight through to the linker - -f means something entirely unrelated to the linker.
In this case,
clang-3.7 -fsanitize=safe-stack -o a.out test.c
is sufficient. If you were using separate command executions to compile and link, you would need to pass it on both:
clang-3.7 -fsanitize=safe-stack -c -o test.o test.c
clang-3.7 -fsanitize=safe-stack -o a.out test.o

Trying to pass preprocessor directive via command line in bash script

I'm trying to write a bash script that will take in an optional argument,
and based on the value of that argument, compile code using that argument
as a preprocessor directive. This is my file so far:
#!/bin/bash
OPTIMIZE="$1"
if[ $OPTIMIZE = "OPTIMIZE" ] then
echo "Compiling optimized algorithm..."
gcc -c -std=c99 -O2 code.c -D $OPTIMIZE
else
echo "Compiling naive algorithm..."
gcc -c -std=c99 -O2 code.c
fi
However, it doesn't seem to like the "-D" option, complaining that there is a macro name missing after -D. I was under the impression -D defines a new macro (as 1) with name of whatever is specified. I wanted "OPTIMIZE" to be the name of that macro. Any hints?
The -D should be glued to the name (ie -DFOO not -D FOO)
gcc -c -std=c99 -Wall "-D$OPTIMIZE" -O2 code.c
and you forgot to pass -Wall to gcc. It is almost always useful.
BTW, you might consider (even for a single file) using make with two phony targets: the default one (e.g. plain), and an optimized one.

Linking a C program directly with ld fails with undefined reference to `__libc_csu_fini`

I'm trying to compile a C program under Linux. However, out of curiosity, I'm trying to execute some steps by hand: I use:
the gcc frontend to produce assembler code
then run the GNU assembler to get an object file
and then link it with the C runtime to get a working executable.
Now I'm stuck with the linking part.
The program is a very basic "Hello world":
#include <stdio.h>
int main() {
printf("Hello\n");
return 0;
}
I use the following command to produce the assembly code:
gcc hello.c -S -masm=intel
I'm telling gcc to quit after compiling and dump the assembly code with Intel syntax.
Then I use th GNU assembler to produce the object file:
as -o hello.o hello.s
Then I try using ld to produce the final executable:
ld hello.o /usr/lib/libc.so /usr/lib/crt1.o -o hello
But I keep getting the following error message:
/usr/lib/crt1.o: In function `_start':
(.text+0xc): undefined reference to `__libc_csu_fini'
/usr/lib/crt1.o: In function `_start':
(.text+0x11): undefined reference to `__libc_csu_init'
The symbols __libc_csu_fini/init seem to be a part of glibc, but I can't find them anywhere! I tried linking against libc statically (against /usr/lib/libc.a) with the same result.
What could the problem be?
/usr/lib/libc.so is a linker script which tells the linker to pull in the shared library /lib/libc.so.6, and a non-shared portion, /usr/lib/libc_nonshared.a.
__libc_csu_init and __libc_csu_fini come from /usr/lib/libc_nonshared.a. They're not being found because references to symbols in non-shared libraries need to appear before the archive that defines them on the linker line. In your case, /usr/lib/crt1.o (which references them) appears after /usr/lib/libc.so (which pulls them in), so it doesn't work.
Fixing the order on the link line will get you a bit further, but then you'll probably get a new problem, where __libc_csu_init and __libc_csu_fini (which are now found) can't find _init and _fini. In order to call C library functions, you should also link /usr/lib/crti.o (after crt1.o but before the C library) and /usr/lib/crtn.o (after the C library), which contain initialisation and finalisation code.
Adding those should give you a successfully linked executable. It still won't work, because it uses the dynamically linked C library without specifying what the dynamic linker is. You'll need to tell the linker that as well, with something like -dynamic-linker /lib/ld-linux.so.2 (for 32-bit x86 at least; the name of the standard dynamic linker varies across platforms).
If you do all that (essentially as per Rob's answer), you'll get something that works in simple cases. But you may come across further problems with more complex code, as GCC provides some of its own library routines which may be needed if your code uses certain features. These will be buried somewhere deep inside the GCC installation directories...
You can see what gcc is doing by running it with either the -v option (which will show you the commands it invokes as it runs), or the -### option (which just prints the commands it would run, with all of the arguments quotes, but doesn't actually run anything). The output will be confusing unless you know that it usually invokes ld indirectly via one of its own components, collect2 (which is used to glue in C++ constructor calls at the right point).
I found another post which contained a clue: -dynamic-linker /lib/ld-linux.so.2.
Try this:
$ gcc hello.c -S -masm=intel
$ as -o hello.o hello.s
$ ld -o hello -dynamic-linker /lib/ld-linux.so.2 /usr/lib/crt1.o /usr/lib/crti.o hello.o -lc /usr/lib/crtn.o
$ ./hello
hello, world
$
Assuming that a normal invocation of gcc -o hello hello.c produces a working build, run this command:
gcc --verbose -o hello hello.c
and gcc will tell you how it's linking things. That should give you a good idea of everything that you might need to account for in your link step.
In Ubuntu 14.04 (GCC 4.8), the minimal linking command is:
ld -dynamic-linker /lib64/ld-linux-x86-64.so.2 \
/usr/lib/x86_64-linux-gnu/crt1.o \
/usr/lib/x86_64-linux-gnu/crti.o \
-L/usr/lib/gcc/x86_64-linux-gnu/4.8/ \
-lc -lgcc -lgcc_s \
hello.o \
/usr/lib/x86_64-linux-gnu/crtn.o
Although they may not be necessary, you should also link to -lgcc and -lgcc_s, since GCC may emit calls to functions present in those libraries for operations which your hardware does not implement natively, e.g. long long int operations on 32-bit. See also: Do I really need libgcc?
I had to add:
-L/usr/lib/gcc/x86_64-linux-gnu/4.8/ \
because the default linker script does not include that directory, and that is where libgcc.a was located.
As mentioned by Michael Burr, you can find the paths with gcc -v. More precisely, you need:
gcc -v hello_world.c |& grep 'collect2' | tr ' ' '\n'
This is how I fixed it on ubuntu 11.10:
apt-get remove libc-dev
Say yes to remove all the packages but copy the list to reinstall after.
apt-get install libc-dev
If you're running a 64-bit OS, your glibc(-devel) may be broken. By looking at this and this you can find these 3 possible solutions:
add lib64 to LD_LIBRARY_PATH
use lc_noshared
reinstall glibc-devel
Since you are doing the link process by hand, you are forgetting to link the C run time initializer, or whatever it is called.
To not get into the specifics of where and what you should link for you platform, after getting your intel asm file, use gcc to generate (compile and link) your executable.
simply doing gcc hello.c -o hello should work.
Take it:
$ echo 'main(){puts("ok");}' > hello.c
$ gcc -c hello.c -o hello.o
$ ld hello.o -o hello.exe /usr/lib/crt1.o /usr/lib/crti.o /usr/lib/crtn.o \
-dynamic-linker /lib/ld-linux.so.2 -lc
$ ./hello.exe
ok
Path to /usr/lib/crt*.o will when glibc configured with --prefix=/usr

how to add a library to 'make' command in c

This is the header file and its C file:
cs50.h and
cs50.c
Now I use them in the following example http://www.paste.ubuntu.com/576370/ — which is no longer available.
I already put the header file in /usr/bin/include or something like that and when I try to compile my code using gcc -o xxx xxx.c, it doesn't work, so tried to fix this and the following way worked: http://www.paste.ubuntu.com/576371/ — which is no longer available.
Now I want to do something to make the 'make' command work as the gcc does.
What do I need to do?
The following was the old topic:
I was using gcc command to
compile C programs but after a period
of time I got a problem. I need
to compile a new header file and use
it as a library.
The header file called cs50.h.
so after doing it and it's ok I can
compile using the following
gcc -o xxx xxx.c -lcs50
It works but now I want to use 'make'
command and I can't get it to work.
It just don't compile the header file
and library as gcc was before I edit
it to accept the cs50 library.
So now I want to add to the 'make'
command the following: -lcs50
Can anyone help me in this please?
Near the top of your Makefile, add the line:
LDLIBS = -lcs50
If you are using Make's default (implicit) rules for the building, then that is all you need to do. If you are using explicit rules, you will need to add $(LDLIBS) to your explicit rules.
If there is no Makefile, then make is using default rules, and you can either just create a makefile with
echo LDLIBS = -lcs50 > Makefile
or tell make to link with certain libraries by specifying the required libraries in LDLIBS in the environment. For example, if you are using a sh-derived shell (anything other than csh or tcsh) you can do:
LDLIBS=-lcs50 make target
If you are using a csh variant, you can do:
env LDLIBS=-lcs50 make target
or just do (again, for non-csh shells)
export LDLIBS=-lcs50
before running make. (For csh variants, do setenv LDLIBS -lcs50)
You can use below “make” command to link library and include header directories,
make <.c or .cpp source filename_without_extension> LDLIBS="-l<lib1> -l<lib2>"
suppose you have server.cpp file to compile using make command,
make server LDLIBS="-lcpprest -lpthread -lssl -lcrypto" LDFLAGS="-L/usr/lib/" CXXFLAGS="-I/usr/include/"
Output will expand the compilation command as,
g++ -I/usr/include/ -L/usr/lib/ server.cpp -lcpprest -lpthread -lssl -lcrypto -o server
Did you forget that you have to tell gcc in what directory the CS50 library is located?
gcc … -L/directory/for/cs50_library -lcs50

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