How to sum the values of a Row in sql server - sql-server

I have a dataset, like this. and i want to sum the values of each row.
ID F01 F02 F03
1 1 0 0
2 0 1 1
3 1 0 1
I need the sum for each row. for example:
ID RowSum
1 1 (1+0+0)
2 2 (0+1+1)
3 2 (1+0+1)


use
SELECT ID, ISNULL(F01,0) + ISNULL(F02,0) + IsNULL(F3,0) as RowSum
FROM yourtable

Related

Count number of rows for each id to create a new column

ID
value
1
4
1
5
3
4
2
10
I want to add another column called count, that has for each id the number of observations.
Transformed table
id
value
count
1
4
2
1
5
2
3
4
1
2
10
1

You can use the OVER() clause to aggregate.
SELECT
ID,
value,
[count] = COUNT(*) OVER (PARTITION BY ID)
FROM dbo.TableName;

Get count of lDs where all status is greater than equal to 1

I want to select count of ids where all status is greater than equal to 1
I want something like this
SELECT count(ID)FROM table where all status >= 1
ID
status
1
1
1
2
1
1
1
1
1
1
1
1
2
0
2
1
2
0
2
1
1
1
3
1
3
1
3
1
3
2
3
2
3
2
As you can see in the table where ID = 1,3 has all status greater than equal to 1.
I want to select the count of those IDs.
For example, I want count 2 from the above table.
How can I get those ids count where all status is >=1
Edited:Edited table

To get the ID where all status are >=1 you can use
SELECT ID
FROM Table1
GROUP BY ID
HAVING MIN([status]) >= 1
to count them you can use
SELECT COUNT(*)
FROM (SELECT ID
FROM Table1
GROUP BY ID
HAVING MIN([status]) >= 1) T

TSQL Aggregating values based on other column

I have a table that looks as follows
Amount Factor Month Customer
1 1 2 A
3 1 2 A
4 -1 2 A
2 1 2 B
2 1 2 B
3 -1 2 B
4 1 3 A
5 1 3 A
6 -1 3 A
I want to aggregate (sum) the column Amount per Month and Customer. The Amounts should be multiplied with the value in the column Factor.
Hence, the result should look as follows (could be an UPDATE to the same table or a new table):
Amount Factor Month Customer
0 1 2 A
1 1 2 B
3 1 3 A

Try below
SELECT SUM(Amount * Factor) as Amount,Month,Customer
FROM tableName
GROUP BY Month,Customer

I think this is what you want:
select month, customer, sum(amount * factor) as sum_amount
from t
group by month, customer;
I'm not sure why you would want factor in the result set.

Get Min and Max Dates from SQL Server SQL

Data in my table looks like this
PAY_END_DT Sal
10/27/2013 0
11/10/2013 0
11/24/2013 2473.14
12/08/2013 0
01/19/2014 0
02/02/2014 0
02/16/2014 0
My desired result should be like as below
10/27/2013 11/10/2013
12/08/2013 02/16/2014
I need a SQL to generate this result set.. please help

SELECT
employee_id,
MIN(pay_end_dt) AS island_min_pay_end_dt,
MAX(pay_end_dt) AS island_max_pay_end_dt
FROM
(
SELECT
pay_end_dt,
ROW_NUMBER() OVER (PARTITION BY employee_id,
ORDER BY pay_end_dt ) AS full_set_ordinal,
ROW_NUMBER() OVER (PARTITION BY employee_id, sal
ORDER BY pay_end_dt ) AS zero_set_ordinal
FROM
yourTable
)
AS sorted_set
WHERE
sal = 0
GROUP BY
employee_id,
full_set_ordinal - zero_set_ordinal
;
Using your data as an example:
PAY_END_DT Sal FULL_SET_ORIDINAL ZERO_SET_ORDINAL "FULL - ZERO"
10/27/2013 0 1 1 0
11/10/2013 0 2 2 0
11/24/2013 2473.14 3 1 2
12/08/2013 0 4 3 1
01/19/2014 0 5 4 1
02/02/2014 0 6 5 1
02/16/2014 0 7 6 1
Which then allows us to include only the rows WHERE sal = 0 and then GROUP BY "FULL - ZERO" to get our two sets, and then finally apply the MIN() and MAX() functions.
As stated in a comment, this is known as "Gaps and Islands".
1 1 1 1
0 0 0 0 0
1 2 3 4 5 6 7 8 9 - ordinal from the whole set
1 2 3 4 - ordinal from just the "islands"
1 2 3 4 5 - ordinal from just the "gaps"
2 2 2 3 - ordinal of the "islands" (whole_set_id - islands_id)
0 0 3 4 4 - ordinal of the "gaps" (whole_set_id - gaps_id)

;)
SELECT "10/27/2013 11/10/2013"
UNION
SELECT "12/08/2013 02/16/2014"

Partition data into subgroups based on bit fields

I have the first 4 columns of data, and I wan't to use the Ranking functions in the SQL 2008 R2 to derive the fifth column. What's the best way to partition the data into subgroups based on the nextiteminsubgroup and previousiteminsubgroup fields?
Group OrderInGroup NextItemInSubGroup PreviousItemInSubGroup SubGroup
1 1 1 0 1
1 2 1 1 1
1 3 1 1 1
1 4 0 1 1
1 5 0 0 2
1 6 0 0 3
1 7 1 0 4
1 8 1 1 4
1 9 0 1 4
2 1 0 0 1
2 2 0 0 2
2 3 0 0 3
2 4 1 0 4
2 5 0 1 4
3 1 0 0 1
4 1 0 0 1
4 2 0 0 2
4 3 0 0 3

A recursive CTE solution:
DECLARE #t TABLE
([Group] INT
,OrderInGroup INT
,NextItemInSubGroup INT
,PreviousItemInSubGroup INT
,SubGroup INT
)
INSERT #t
VALUES
(1,1,1,0,1),(1,2,1,1,1),(1,3,1,1,1),(1,4,0,1,1),(1,5,0,0,2),(1,6,0,0,3),
(1,7,1,0,4),(1,8,1,1,4),(1,9,0,1,4),(2,1,0,0,1),(2,2,0,0,2),(2,3,0,0,3),
(2,4,1,0,4),(2,5,0,1,4),(3,1,0,0,1),(4,1,0,0,1),(4,2,0,0,2),(4,3,0,0,3)
;WITH recCTE
AS
(
SELECT [Group], OrderInGroup,NextItemInSubGroup , PreviousItemInSubGroup, 1 AS subgroup
FROM #t
WHERE OrderInGroup = 1
UNION ALL
SELECT r.[Group], t.OrderInGroup,t.NextItemInSubGroup , t.PreviousItemInSubGroup,
CASE WHEN r.NextItemInSubGroup = 1 THEN r.subgroup ELSE r.subgroup + 1 END
FROM recCTE AS r
JOIN #t AS t
ON t.[Group] = r.[Group]
AND t.OrderInGroup = r.OrderInGroup + 1
)
SELECT * FROM recCTE
ORDER BY [Group],OrderInGroup ;
P.S. it's best practice to avoid using SQL keywords (e.g. GROUP) as table/column names

Seems like 0 and 0 restart the ranking.
Select
Rank() Over (
Partition By
[Group]
, Case When [NextItemInSubGroup] + [PreviousItemInSubGroup] = 0
Then 0
Else 1
End
Order By [OrderInGroup]
) as [SubGroup]
From Your_Table;

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