Printing a two dimensional array in C - c

Question

I want to print a two dimensional array which I get from another method, see code:
int** getPrint(){
const int EIGHT[7][5] = {
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 }
};
return EIGHT;
}
int main(){
int **ptr;
ptr = getPrint();
return 0;
}
What would be the best method to print this?

Answer 1

Something as the following
#include <stdio.h>
#define N 7
#define M 5
const int ( * getPrint( void ) )[M]
{
static const int EIGHT[N][M] =
{
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 }
};
return EIGHT;
}
int main( void )
{
const int ( *ptr )[M];
int i, j;
ptr = getPrint();
for ( i = 0; i < N; i++ )
{
for ( j = 0; j < M; j++ ) printf( "%d ", ptr[i][j] );
printf( "\n" );
}
return 0;
}
Or you could use a typedef. For example
#include <stdio.h>
#define N 7
#define M 5
typedef const int ( *ArrayPtr )[M];
ArrayPtr getPrint( void )
{
static const int EIGHT[N][M] =
{
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 },
{ 1, 0, 0, 0, 1 },
{ 1, 0, 0, 0, 1 },
{ 0, 1, 1, 1, 0 }
};
return EIGHT;
}
int main( void )
{
ArrayPtr ptr;
int i, j;
ptr = getPrint();
for ( i = 0; i < N; i++ )
{
for ( j = 0; j < M; j++ ) printf( "%d ", ptr[i][j] );
printf( "\n" );
}
return 0;
}