How can I get a random file in linux? including subdirectories - c

Lets say I am in /home/myuser
there are 90,000 files there inside 3000 directories.
How can I write a bash function or with linux commands to get one random file?
It could be C as well I suppose

You can list all your files and then pick a random line between them:
find /home/myuser | sort -R | head -n1
However this is not very efficient, and could take a while, but is easy to understand. You can work from here.

You can use shuf for this task, for example set globstar option and try
shuf -e path/**/*.txt | head -n1

Related

How to run a command on all .cs files in directory and store file path as a variable to be used as command on windows

I'm trying to run the following command on each file of a directory.
svn blame FILEPATH | gawk '{print $2}' | sort | uniq -c
It works well however it only works on individual files. For whatever reason, it won't run on the directory as a whole. I was hoping to create some form of batch script that would iterate through the directory and would grab the file path and store it as a variable to be used in the command. However, I've never written a batch script nor do I know the first thing about them. I tried this loop but couldn't get it to work
set codedirectory=%C:\Repo\Pineapple% for %codedirectory% %%i in (*.cs) do
but I'm not necessarily sure what to do next. Unfortunately, this all has to be run on windows. Any help would be greatly appreciated. Thanks!
use for and find, similar to example on
https://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-7.html
for i in $(find . -name "*.cs"); do
svn blame $i | gawk '{print $2}' | sort | uniq -c
done

Vlookup-like function using awk in ksh

Disclaimers:
1) English is my second language, so please forgive any gramatical horrors you may find. I am pretty confident you will be able to understand what I need despite these.
2) I have found several examples in this site that address questions/problems similar to mine, though I was unfortunately not able to figure out the modifications that would need to be introduced to fit my needs.
3) You will find some text in capital letters here and there. Is is of course not me "shouting" at you, but only a way to make portions of text stand out. Plase do not consider this an act of unpoliteness.
4) For those of you who get to the bottom of this novella alive, THANKS IN ADVANCE for your patience, even if you do not get to be able to/feel like help/ing me. My disclamer here would be the fact that, after surfing the site for a while, I noticed that the most common "complaint" from people willing to help seems to be lack of information (and/or the lack of quality) provided by the ones seeking for help. I then preferred to be accused of overwording if need be... It would be, at least, not a common offense...
The "Problem":
I have 2 files (a and b for simplification). File a has 7 columns separated by commas. File b has 2 columns separated by commas.
What I need: Whenever the data in the 7th column of file a matches -EXACT MATCHES ONLY- the data on the 1st column of file b, a new line, containing the whole line of file a plus column 2 of file b is to be appended into a new file "c".
--- MORE INFO IN THE NOTES AT THE BOTTOM ---
file a:
Server Name,File System,Path,File,Date,Type,ID
horror,/tmp,foldera/folder/b/folderc,binaryfile.bin,2014-01-21 22:21:59.000000,typet,aaaaaaaa
host1,/,somefolder,test1.txt,2016-08-18 00:00:20.000000,typez,11111111
host20,/,somefolder/somesubfolder,usr.cfg,2015-12-288 05:00:20.000000,typen,22222222
hoster,/lol,foolie,anotherfile.sad,2014-01-21 22:21:59.000000,typelol,66666666
hostie,/,someotherfolder,somefile.txt,2016-06-17 18:43:12.000000,typea,33333333
hostile,/sad,folder22,higefile.hug,2016-06-17 18:43:12.000000,typeasd,77777777
hostin,/var,folder30,someotherfile.cfg,2014-01-21 22:21:59.000000,typo,44444444
hostn,/usr,foldie,tinyfile.lol,2016-08-18 00:00:20.000000,typewhatever,55555555
server10,/usr,foldern,tempfile.tmp,2016-06-17 18:43:12.000000,tipesad,99999999
file b:
ID,Size
11111111,215915
22222222,1716
33333333,212856
44444444,1729
55555555,215927
66666666,1728
88888888,1729
99999999,213876
bbbbbbbb,26669080
Expected file c:
Server Name,File System,Path,File,Date,Type,ID,Size
host1,/,somefolder,test1.txt,2016-08-18 00:00:20.000000,typez,11111111,215915
host20,/,somefolder/somesubfolder,usr.cfg,2015-12-288 05:00:20.000000,typen,22222222,1716
hoster,/lol,foolie,anotherfile.sad,2014-01-21 22:21:59.000000,typelol,66666666,1728
hostie,/,someotherfolder,somefile.txt,2016-06-17 18:43:12.000000,typea,33333333,212856
hostin,/var,folder30,someotherfile.cfg,2014-01-21 22:21:59.000000,typo,44444444,1729
hostn,/usr,foldie,tinyfile.lol,2016-08-18 00:00:20.000000,typewhatever,55555555,215927
server10,/usr,foldern,tempfile.tmp,2016-06-17 18:43:12.000000,tipesad,99999999,213876
Additional notes:
0) Notice how line with ID "aaaaaaaa" in file a does not make it into file c since ID "aaaaaaaa" is not present in file b. Likewise, line with ID "bbbbbbbb" in file b does not make it into file c since ID "bbbbbbbb" is not present in file a and it is therefore never looked out for in the first place.
1) Data is clearly completely made out due to confidenciality issues, though the examples provided fairly resemble what the real files look like.
2) I added headers just to provide a better idea of the nature of the data. The real files don't have it, so no need to skip them on the source file nor create it in the destination file.
3) Both files come sorted by default, meaning that IDs will be properly sorted in file b, while they will be most likely scrambled in file a. File c should preferably follow the order of file a (though I can manipulate later to fit my needs anyway, so no worries there, as long as the code does what I need and doesn't mess up with the data by combining the wrong lines).
4) VERY VERY VERY IMPORTANT:
4.a) I already have a "working" ksh code (attached below) that uses "cat", "grep", "while" and "if" to do the job. It worked like a charm (well, acceptably) with 160K-lines sample files (it was able to output 60K lines -approx- an hour, which, in projection, would yield an acceptable "20 days" to produce 30 million lines [KEEP ON READING]), but somehow (I have plenty of processor and memory capacity) cat and/or grep seem to be struggling to process a real life 5Million-lines file (both file a and b can have up to 30 million lines each, so that's the maximum probable amount of lines in the resulting file, even assuming 100% lines in file a find it's match in file b) and the c file is now only being feed with a couple hundred lines every 24 hours.
4.b) I was told that awk, being stronger, should succeed where the more weaker commands I worked with seem to fail. I was also told that working with arrays might be the solution to my performance problem, since all data is uploded to memory at once and worked from there, instead of having to cat | grep file b as many times as there are lines in file a, as I am currently doing.
4.c) I am working on AIX, so I only have sh and ksh, no bash, therefore I cannot use the array tools provided by the latter, that's why I thought of AWK, that and the fact that I think AWK is probably "stronger", though I might be (probably?) wrong.
Now, I present to you the magnificent piece of ksh code (obvious sarcasm here, though I like the idea of you picturing for a brief moment in your mind the image of the monkey holding up and showing all other jungle-crawlers their future lion king) I have managed to develop (feel free to laugh as hard as you need while reading this code, I will not be able to hear you anyway, so no feelings harmed :P ):
cat "${file_a}" | while read -r line_file_a; do
server_name_file_a=`echo "${line_file_a}" | awk -F"," '{print $1}'`
filespace_name_file_a=`echo "${line_file_a}" | awk -F"," '{print $2}'`
folder_name_file_a=`echo "${line_file_a}" | awk -F"," '{print $3}'`
file_name_file_a=`echo "${line_file_a}" | awk -F"," '{print $4}'`
file_date_file_a=`echo "${line_file_a}" | awk -F"," '{print $5}'`
file_type_file_a=`echo "${line_file_a}" | awk -F"," '{print $6}'`
file_id_file_a=`echo "${line_file_a}" | awk -F"," '{print $7}'`
cat "${file_b}" | grep ${object_id_file_a} | while read -r line_file_b; do
file_id_file_b=`echo "${line_file_b}" | awk -F"," '{print $1}'`
file_size_file_b=`echo "${line_file_b}" | awk -F"," '{print $2}'`
if [ "${file_id_file_a}" = "${file_id_file_b}" ]; then
echo "${server_name_file_a},${filespace_name_file_a},${folder_name_file_a},${file_name_file_a},${file_date_file_a},${file_type_file_a},${file_id_file_a},${file_size_file_b}" >> ${file_c}.csv
fi
done
done
One last additional note, just in case you wonder:
The "if" section was not only built as a mean to articulate the output line, but it servers a double purpose, while safe-proofing any false positives that may derive from grep, IE 100 matching 1000 (Bear in mind that, as I mentioned earlier, I am working on AIX, so my grep does not have the -m switch the GNU one has, and I need matches to be exact/absolute).
You have reached the end. CONGRATULATIONS! You've been awarded the medal to patience.
$ cat stuff.awk
BEGIN { FS=OFS="," }
NR == FNR { a[$1] = $2; next }
$7 in a { print $0, a[$7] }
Note the order for providing the files to the awk command, b first, followed by a:
$ awk -f stuff.awk b.txt a.txt
host1,/,somefolder,test1.txt,2016-08-18 00:00:20.000000,typez,11111111,215915
host20,/,somefolder/somesubfolder,usr.cfg,2015-12-288 05:00:20.000000,typen,22222222,1716
hoster,/lol,foolie,anotherfile.sad,2014-01-21 22:21:59.000000,typelol,66666666,1728
hostie,/,someotherfolder,somefile.txt,2016-06-17 18:43:12.000000,typea,33333333,212856
hostin,/var,folder30,someotherfile.cfg,2014-01-21 22:21:59.000000,typo,44444444,1729
hostn,/usr,foldie,tinyfile.lol,2016-08-18 00:00:20.000000,typewhatever,55555555,215927
server10,/usr,foldern,tempfile.tmp,2016-06-17 18:43:12.000000,tipesad,99999999,213876
EDIT: Updated calculation
You can try to predict how often you are calling another program:
At least 7 awk's + 1 cat + 1 grep for each line in file a multiplied by 2 awk's for each line in file b.
(9 * 160.000).
For file b: 2 awk's, one file open and one file close for each hit. With 60K output, that would be 4 * 60.000.
A small change in the code can change this into "only" 160.000 times a grep:
cat "${file_a}" | while IFS=, read -r server_name_file_a \
filespace_name_file_a folder_name_file_a file_name_file_a \
file_date_file_a file_type_file_a file_id_file_a; do
grep "${object_id_file_a}" "${file_b}" | while IFS="," read -r line_file_b; do
if [ "${file_id_file_a}" = "${file_id_file_b}" ]; then
echo "${server_name_file_a},${filespace_name_file_a},${folder_name_file_a},${file_name_file_a},${file_date_file_a},${file_type_file_a},${file_id_file_a},${file_size_file_b}"
fi
done
done >> ${file_c}.csv
Well, try this with your 160K files and see how much faster it is.
Before I explain that this still is the wrong way I will make another small improvement: I will move the cat for the while loop to the end (after done).
while IFS=, read -r server_name_file_a \
filespace_name_file_a folder_name_file_a file_name_file_a \
file_date_file_a file_type_file_a file_id_file_a; do
grep "${object_id_file_a}" "${file_b}" | while IFS="," read -r line_file_b; do
if [ "${file_id_file_a}" = "${file_id_file_b}" ]; then
echo "${server_name_file_a},${filespace_name_file_a},${folder_name_file_a},${file_name_file_a},${file_date_file_a},${file_type_file_a},${file_id_file_a},${file_size_file_b}"
fi
done
done < "${file_a}" >> ${file_c}.csv
The main drawback of the solutions is that you are reading the complete file_b again and again with your grep for each line in file a.
This solution is a nice improvement in the performance, but still a lot overhead with grep. Another huge improvement can be found with awk.
The best solution is using awk as explained in What is "NR==FNR" in awk? and found in the answer of #jas.
It is only one system call and both files are only read once.

bash array count always returns 1

I searched all over for this, but the terms are apparently too general. I'm writing a script to search a group of folders for .mp3 files. Some folders don't have mp3's so they have to be excluded.
I created an array to hold the uniq'd folder names. This find command will get the folders I need.
Folders=$(sudo find /my/music/ -type f -name "*.mp3" | cut -d'/' -f7 | sort -u)
When I try to count the number of folders in the array, I always get 1
echo ${#Folders[#]}
echo ${Folders[#]} prints them out on separate lines so I thought they were separate array elements. Can anyone explain what is going on? You might have to jiggle the field number in the cut command to reproduce locally.
Folders is not an array but a variable.
You need:
Folders=( $(sudo find /my/music/ -type f -name "*.mp3" | cut -d'/' -f7 | sort -u) )
i.e. enclose the command substitution with (). Now ${#Folders[#]} would give you the number of elements of array Folders.
Or do :
sudo find /my/music/ -type f -name "*.mp3" | cut -d'/' -f7 | sort -u | wc -l
Note
wc -l prints the number of lines which in this case would be the number of unique files
to make things a bit more explicit, use -printf "%p\n" option with find where %p specifier prints the file with full path.
Assuming bash 4 or later, don't use find here; use the globstar operator.
shopt -s globstar
folders=( /my/music/**/*.mp3 )
Also assuming that cut -d/ -f7 is supposed to extract the filename alone, follow this up with
folders=${folders[#]##*/}
Other methods for populating the array must take more care to accomodate files containing whitespace or characters like ?, *, or [. File names containing newlines (rare, but not illegal) are much more difficult to handle correctly. Pathname expansion is done inside the shell, so you don't need to worry about any such special characters.

Find the most frequent entry in a file using unix

I have a file containing around 2,000,000 entries - just one column with that many entries, all numbers. I would like to quickly find out what the most frequent number in the file is.. Is there a way to do this using unix?
I know how to do it using gnuplot but it is a slightly tedious way and was wondering if there was a simpler way just by using some unix commands?
Like if my file is
1
1
1
2
3
4
Then I want it to read the file and give me the answer 1 because thats the most frequent.
You can do it like this:
$ cat file|sort -n|uniq -c|sort -n|tail -n 1|awk '{print $2}'
sort test.txt | uniq -c | sort -rn | head -n 1 should help. It prints the number of occurences and the number that is most used, so for your example file it would be: 3 1
My first answer to that would be building an histogram. It helps if the range of possible values is small enough.
Once the histogram is built, just look for the highest amount in it.

Moving things in terminal based on their name

Edit: I think this has been answered successfully, but I can't check 'til later. I've reformatted it as suggested though.
The question: I have a series of files, each with a name of the form XXXXNAME, where XXXX is some number. I want to move them all to separate folders called XXXX and have them called NAME. I can do this manually, but I was hoping that by naming them XXXXNAME there'd be some way I could tell Terminal (I think that's the right name, but not really sure) to move them there. Something like
mv *NAME */NAME
but where it takes whatever * was in the first case and regurgitates it to the path.
This is on some form of Linux, with a bash shell.
In the real life case, the files are 0000GNUmakefile, with sequential numbering. I'm having to make lots of similar-but-slightly-altered versions of a program to compile and run on a cluster as part of my research. It would probably have been quicker to write a program to edit all the files and put in the right place in the first place, but I didn't.
This is probably extremely simple, and I should be able to find an answer myself, if I knew the right words. Thing is, I have no formal training in programming, so I don't know what to call things to search for them. So hopefully this will result in me getting an answer, and maybe knowing how to find out the answer for similar things myself next time. With the basic programming I've picked up, I'm sure I could write a program to do this for me, but I'm hoping there's a simple way to do it just using functionality already in Terminal. I probably shouldn't be allowed to play with these things.
Thanks for any help! I can actually program in C and Python a fair amount, but that's through trial and error largely, and I still don't know what I can do and can't do in Terminal.
SO many ways to achieve this.
I find that the old standbys sed and awk are often the most powerful.
ls | sed -rne 's:^([0-9]{4})(NAME)$:mv -iv & \1/\2:p'
If you're satisfied that the commands look right, pipe the command line through a shell:
ls | sed -rne 's:^([0-9]{4})(NAME)$:mv -iv & \1/\2:p' | sh
I put NAME in brackets and used \2 so that if it varies more than your example indicates, you can come up with a regular expression to handle your filenames better.
To do the same thing in gawk (GNU awk, the variant found in most GNU/Linux distros):
ls | gawk '/^[0-9]{4}NAME$/ {printf("mv -iv %s %s/%s\n", $1, substr($0,0,4), substr($0,5))}'
As with the first sample, this produces commands which, if they make sense to you, can be piped through a shell by appending | sh to the end of the line.
Note that with all these mv commands, I've added the -i and -v options. This is for your protection. Read the man page for mv (by typing man mv in your Linux terminal) to see if you should be comfortable leaving them out.
Also, I'm assuming with these lines that all your directories already exist. You didn't mention if they do. If they don't, here's a one-liner to create the directories.
ls | sed -rne 's:^([0-9]{4})(NAME)$:mkdir -p \1:p' | sort -u
As with the others, append | sh to run the commands.
I should mention that it is generally recommended to use constructs like for (in Tim's answer) or find instead of parsing the output of ls. That said, when your filename format is as simple as /[0-9]{4}word/, I find the quick sed one-liner to be the way to go.
Lastly, if by NAME you actually mean "any string of characters" rather than the literal string "NAME", then in all my examples above, replace NAME with .*.
The following script will do this for you. Copy the script into a file on the remote machine (we'll call it sortfiles.sh).
#!/bin/bash
# Get all files in current directory having names XXXXsomename, where X is an integer
files=$(find . -name '[0-9][0-9][0-9][0-9]*')
# Build a list of the XXXX patterns found in the list of files
dirs=
for name in ${files}; do
dirs="${dirs} $(echo ${name} | cut -c 3-6)"
done
# Remove redundant entries from the list of XXXX patterns
dirs=$(echo ${dirs} | uniq)
# Create any XXXX directories that are not already present
for name in ${dirs}; do
if [[ ! -d ${name} ]]; then
mkdir ${name}
fi
done
# Move each of the XXXXsomename files to the appropriate directory
for name in ${files}; do
mv ${name} $(echo ${name} | cut -c 3-6)
done
# Return from script with normal status
exit 0
From the command line, do chmod +x sortfiles.sh
Execute the script with ./sortfiles.sh
Just open the Terminal application, cd into the directory that contains the files you want moved/renamed, and copy and paste these commands into the command line.
for file in [0-9][0-9][0-9][0-9]*; do
dirName="${file%%*([^0-9])}"
mkdir -p "$dirName"
mv "$file" "$dirName/${file##*([0-9])}"
done
This assumes all the files that you want to rename and move are in the same directory. The file globbing also assumes that there are at least four digits at the start of the filename. If there are more than four numbers, it will still be caught, but not if there are less than four. If there are less than four, take off the appropriate number of [0-9]s from the first line.
It does not handle the case where "NAME" (i.e. the name of the new file you want) starts with a number.
See this site for more information about string manipulation in bash.

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