C programming Hex to Char - c

Question

What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h>
int main(void) {
char myChar;
int counter = 0;
while (EOF != (myChar = getchar())) {
/* don't convert newline into hex */
if (myChar == '\n')
continue;
printf("%02x ", myChar);
if (counter > 18) {
printf("\n");
counter = -1;
}
counter++;
}
system("pause");
return 0;
}
this is what i want to the program to do except it would do this continuously
#include <stdio.h>
int main() {
char myChar;
printf("Enter any hex number: ");
scanf("%x", &myChar);
printf("Equivalent Char is: %c\n", myChar);
system("pause");
return 0;
}
any help would be appreciated
thank you

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main(void) {
int myChar;
int counter = 0;
char buff[3] = {0};
while (EOF != (myChar = getchar())) {
if(isxdigit(myChar)){
buff[counter++] = myChar;
if(counter == 2){
counter = 0;
myChar = strtol(buff, NULL, 16);
putchar(myChar);
}
}
}
printf("\n");
system("pause");
return 0;
}

Answer 2

Because chars and ints can be used interchangably in C, you can use the following code:
int main(void) {
int myChar;
printf("Enter any hex number: ");
scanf("%x", &myChar);
printf("Equivalent Char is: %c\n", myChar);
system("pause");
return 0;
}
If you want it to loop then just enclose it in the while loop as in your example code.
Edit: You can try out the working code here http://ideone.com/yyvz85