As I am including elements/header.ctp file in another main.ctp file..
<?php echo $this->element('header'); ?>
I have included header in main.ctp it is displaying quite good. but when I am writing the query in ElementsController in is throwing an error undefined varible..
Below code for Elements Controller header() is the included file function.
public function header()
{
$this->set('marquee',$this->Newsmaster->find('all',array('order'=>array('Newsmaster.priority DESC'),'limit' =>20)));
$userid = $this->Session->read('user');
}
can anyone help me in solving this please... thank You
Elements Controller is not needed to set "marquee" varaible , you need to code in your usual controller for eg. for pages/index you will need to set variable in PagesController's index function not in under ElementsController
Related
I am having an issue setting variables in the controller and showing it at the view.
my codes are as follow:
In my view (pages/anything.ctp):
<?php echo $anything; ?>
In my controller (pagesController.php):
public function anything() {
$a = "asdasdas";
$this->set('anything', $a);
}
I am new to Cake, and I've done quite a number of search in google and stack. Still no luck.
I'd be grateful if anybody could help, or if anyone already asked this question before please provide a link that would be best.
First read the following article Controller actions in CakePHP CookBook
When you use controller methods with requestAction(), you will often want to return data that isn’t a string. If you have controller methods that are used for normal web requests + requestAction, you should check the request type before returning:
class RecipesController extends AppController {
public function popular() {
$popular = $this->Recipe->popular();
if (!empty($this->request->params['requested'])) {
return $popular;
}
$this->set('popular', $popular);
}
}
The above controller action is an example of how a method can be used with requestAction() and normal requests. Returning array data to a non-requestAction request will cause errors and should be avoided. See the section on requestAction() for more tips on using requestAction()
Try this:
public function anything() {
$a = "asdasdas";
$this->set(compact('a'));
}
<?php echo $a; ?>
I have a function in controller which contains an array
function get_art(){
$data['rec']=$this->article_model->get_article();
$this->load->view('first',$data);}
I need the section_id from $data to pass it to another function in model.How can I get that?
Thanks from your help.
try this
function get_art(){
$data['rec']=$this->article_model->get_article();
foreach ($data['rec'] as $a) {
print_r($a->section_id); // $this->article_model->anotherfun($a->section_id);
}
$this->load->view('first',$data);
}
In View you can simply access it like below.
<?php echo $rec->section_id; ?>
But without viewing the model function I cannot determine whether you return an array or single object from the db read.
I need to make a DOM substitution, something like this:
$("#target").html('<?php echo $html?>');
where the $html variable could be a complex markup
$html = '<div>
<input type="text" name="test" />
</div>';
Of course I need some kind of escaping, or the javascript engine will break for a syntax problem at the first crlf or quote. In rails there's a simple function escape_javascript that makes it very easy. Is there anything similar in cakephp?
I think using
$("#target").html('<?php echo $this->element("element_path"); ?>');
makes more sense. But it depends on what is in your element_path.ctp file.
On the other hand, it's a bit weird to put replacement HTML in like this. Espacially if it's a lott, I would make an ajax call to load the HTML and have a Controller function return the contents of the element.
$("#target").html('Loading...').load('/myController/loadHtml/');
and the myController
function loadHtml(){
$this->layout = false;
}
and the view for the function app/View/my/load_html.ctp:
<?php echo $this->element("element_path"); ?>
you can do this by using requestAction
in your view file add the below code
$html = $this->requestAction('/tests/func_name');
echo $this->Html->scriptBlock('
$("#target").html('. $this->Js->value($html) .');
');
And in your TestsController.
public function func_name() {
$this->layout = 'layout_name'; // The layout you want here for design.
$this->render('/Elements/element_name'); // you can directly render the content of element by writing like this.
}
I am using CakePHP's UploadPlugin (https://github.com/szajbus/uploadpack). Storing images goes smooth as documented, the problem kicks in when trying to use the helper to view the images:
Fatal Error
Error: Call to a member function image() on a non-object
Code:
<?php echo $upload->image($entry['User']['id'], 'User.avatar') ?>
The helper is correctly loaded in the controllers. What could caseis issue? thanks
UPDATE:
My helper is included as follows:
public $helpers = array('Form', 'UploadPack.Upload');
I had the same issue. I was able to fix it by doing the following:
echo $this->upload->image($MODELNAME, 'MODEL.avatar');
I searched a lot but I couldn't find on How to use the find('all') in Views as used in Rails, but here I'm getting the error "Undefined property: View::$Menu [APP\Lib\Cake\View\View.php, line 804]"
'Menu' is the model which I'm using to fetch data from the menus table.
I'm using the below code in views:
$this->set('test',$this->Menu->find('all'));
print_r($test);
Inside your Menu model create a method, something like getMenu(). In this method do your find() and get the results you want. Modify the results as you need and like to within the getMenu() method and return the data.
If you need that menu on every page in AppController::beforeFilter() or beforeRender() simply do
$this->set('menu', ClassRegistry::init('Menu')->getMenu());
If you do not need it everywhere you might go better with using requestAction getting the data using this method from the Menus controller that will call getMenu() from the model and return the data. Setting it where you need it would be still better, if you use requestAction you also want to cache it very likely.
TRY TO NOT RETRIEVE DATA WITHIN VIEW FILE. VIOLATION OF MVC RULE
try this in view file:
$menu = ClassRegistry::init('Menu');
pr($menu->find('all'));
In AppHelper ,
Make a below function
function getMenu()
{
App::import('Model', 'Menu');
$this->Menu= &new Menu();
$test = array();
$test = $this->Menu->find('all');
return $test;
}
Use above function in view like :
<?php
$menu = $html->getMenu();
print_r($menu);
?>
Cakephp not allow this .
First create the reference(object) of your model using ClassRegistry::init('Model');
And then call find function from using object
$obj = ClassRegistry::init('Menu');
$test = $obj->find('all');
echo ""; print_r($test); `
This will work.