How to extract data from xml in specific way sql server - sql-server

Question

here is my sample xml
<NewDataSet>
<Employee>
<EmpID>1005</EmpID>
<Name> keith </Name>
<DOB>12/02/1981</DOB>
<Salary>10,500</Salary>
</Employee>
</NewDataSet>
from where i want to extract data and store in string variable like this way
SET #Data='EmpID=1005,Name='Keith',DOB='12/02/1981',Salary=10,500'
so show me the way to extract data from xml and re-arrange or store data in string variable the way i want but please give me suggested sql in such way which should work for different or any xml template. looking for idea. thanks

Answer 1

DECLARE #xmlVar AS XML
DECLARE #vcRow AS VARCHAR(500)
SET #xmlVar ='<NewDataSet>
<Employee>
<EmpID>1005</EmpID>
<Name> keith </Name>
<DOB>12/02/1981</DOB>
<Salary>10,500</Salary>
</Employee>
</NewDataSet>'
;with yourDataSet
AS (
SELECT
t.u.value('EmpID[1]','INT') AS EmpID
,t.u.value('Name[1]','VARCHAR(50)') AS Name
,t.u.value('DOB[1]','DATE') AS DOB
,t.u.value('Salary[1]','MONEY') AS Salary
FROM
#xmlVar.nodes('/NewDataSet/Employee') AS t(u) )
SELECT
/*#vcRow = */'EmpID='+ CAST(EmpID AS VARCHAR(50)) +',' +
'Name='''+Name +''',DOB=''' + CONVERT(VARCHAR(10),DOB,110) + ''',Salary='+CAST(Salary AS VARCHAR(50))
FROM
yourDataSet

Answer 2

Something like this would work. The query extracts all Employee sub-nodes and concatenates to a string. The script will only work if there's only one row in #tbl though but it just illustrates a way to get the string you want. It's not generic either, that would be a lot harder I imagine.
DECLARE #tbl TABLE(data XML NOT NULL);
INSERT INTO #tbl(data)VALUES('<NewDataSet>
<Employee>
<EmpID>1005</EmpID>
<Name> keith </Name>
<DOB>12/02/1981</DOB>
<Salary>10,500</Salary>
</Employee>
</NewDataSet>');
DECLARE #data VARCHAR(4000);
SELECT
#data =
'EmpID=' + N.T.value('EmpID[1]','VARCHAR(512)') + ',' +
'Name=''' + N.T.value('Name[1]','VARCHAR(512)') + ''',' +
'DOB=''' + N.T.value('DOB[1]','VARCHAR(512)') + ''',' +
'Salary=' + N.T.value('Salary[1]','VARCHAR(512)')
FROM
#tbl AS t
CROSS APPLY t.data.nodes('//Employee') AS N(T)
PRINT #data;