I’m new to Swift and have been having some troubles figuring out some aspects of Arrays and Dictionaries.
I have an array of dictionaries, for which I have used Type Aliases - e.g.
typealias myDicts = Dictionary<String, Double>
var myArray : [myDicts] = [
["id":0,
"lat”:55.555555,
"lng”:-55.555555,
"distance":0],
["id":1,
"lat": 44.444444,
"lng”:-44.444444,
"distance":0]
]
I then want to iterate through the dictionaries in the array and change the “distance” key value. I did it like this:
for dict:myDicts in myArray {
dict["distance"] = 5
}
Or even specifically making sure 5 is a double with many different approaches including e.g.
for dict:myDicts in myArray {
let numberFive : Double = 5
dict["distance"] = numberFive
}
All my attempts cause an error:
#lvalue $T5' is not identical to '(String, Double)
It seems to be acting as if the Dictionaries inside were immutable “let” rather than “var”. So I randomly tried this:
for (var dict:myDicts) in myArray {
dict["distance"] = 5
}
This removes the error and the key is indeed assigned 5 within the for loop, but this doesn't seem to actually modify the array itself in the long run. What am I doing wrong?
The implicitly declared variable in a for-in loop in Swift is constant by default (let), that's why you can't modify it directly in the loop.
The for-in documentation has this:
for index in 1...5 {
println("\(index) times 5 is \(index * 5)")
}
In the example above, index is a constant whose value is automatically
set at the start of each iteration of the loop. As such, it does not
have to be declared before it is used. It is implicitly declared
simply by its inclusion in the loop declaration, without the need for
a let declaration keyword.
As you've discovered, you can make it a variable by explicitly declaring it with var. However, in this case, you're trying to modify a dictionary which is a struct and, therefore, a value type and it is copied on assignment. When you do dict["distance"] = 5 you're actually modifying a copy of the dictionary and not the original stored in the array.
You can still modify the dictionary in the array, you just have to do it directly by looping over the array by index:
for index in 0..<myArray.count {
myArray[index]["distance"] = 5
}
This way, you're sure to by modifying the original dictionary instead of a copy of it.
That being said, #matt's suggestion to use a custom class is usually the best route to take.
You're not doing anything wrong. That's how Swift works. You have two options:
Use NSMutableDictionary rather than a Swift dictionary.
Use a custom class instead of a dictionary. In a way this is a better solution anyway because it's what you should have been doing all along in a situation where all the dictionaries have the same structure.
The "custom class" I'm talking about would be a mere "value class", a bundle of properties. This was kind of a pain to make in Objective-C, but in Swift it's trivial, so I now do this a lot. The thing is that you can stick the class definition for your custom class anywhere; it doesn't need a file of its own, and of course in Swift you don't have the interface/implementation foo to grapple with, let alone memory management and other stuff. So this is just a few lines of code that you can stick right in with the code you've already got.
Here's an example from my own code:
class Model {
var task : NSURLSessionTask!
var im : UIImage!
var text : String!
var picurl : String!
}
We then have an array of Model and away we go.
So, in your example:
class MyDict : NSObject {
var id = 0.0
var lat = 0.0
var lng = 0.0
var distance = 0.0
}
var myArray = [MyDict]()
let d1 = MyDict()
d1.id = 0
d1.lat = 55.55
d1.lng = -55.55
d1.distance = 0
let d2 = MyDict()
d2.id = 0
d2.lat = 44.44
d2.lng = -44.44
d2.distance = 0
myArray = [d1,d2]
// now we come to the actual heart of the matter
for d in myArray {
d.distance = 5
}
println(myArray[0].distance) // it worked
println(myArray[1].distance) // it worked
Yes, the dictionary retrieved in the loop is immutable, hence you cannot change.
I'm afraid your last attempt just creates a mutable copy of it.
One possible workaround is to use NSMutableDictionary:
typealias myDicts = NSMutableDictionary
Have a class wrapper for the Swift dictionary or array.
class MyDictionary: NSObject {
var data : Dictionary<String,Any>!
init(_ data: Dictionary<String,Any>) {
self.data = data
}}
MyDictionary.data
Related
Sorry, I don't even have an idea of the keywords to search for answer.
I want to store all items within a global structure to a local variable.
struct HighScores: Codable {
var highscoreRecord: [HighscoreRecord]
}
struct HighscoreRecord: Codable {
var Rank:Int
var Date:Date
var avDuration:Float
var Score:Int
}
A global variable is based on this structure and populated within a UIViewController
var jsonResult: HighScores?
Now, in another UIViewController, I want to extract the values of Score for all Highscores and store it to a local variable. I thought it should look somewhat like this, however, I do not get it to work
#IBDesignable class ScoreTimeGraphView: UIView {
var graphScore = jsonResult!.highscoreRecord.Score
The declaration above throws "Value of type '[HighscoreRecord]' has no member 'Score'"
Any ideas how to do this?
Cheers!
highscoreRecord is an Array. You can't use .Score directly on it because the Array type doesn't have a property named Score.
However, because it's element type is HighScore (which does have the property you want), you can iterate over it and collect the Score property from each one.
I think this is what you are after:
var allGraphScores = jsonResult!.highscoreRecord.map { $0.Score }
.map(_:) takes a closure with one parameter, and passes in each element of a sequence in turn.
So, highscoreRecord.map { $0.Score } returns a new array, by finding the Score property of each HighScoreRecord in the array highscoreRecord.
PS it's probably a good idea to name your variables using lowercase camelCase, for readability and instant recognition by any Swift dev that Score is a variable and not an object.
You're trying to access the property from an array. You need to provide an index to remove the error. Update this line:
var graphScore = jsonResult!.highscoreRecord.Score
To this:
var graphScore = jsonResult!.highscoreRecord[0].Score
I ran into an issue with arrays in Swift. The problem is that it's a value type in Swift. I'm trying to find a workaround.
Here is the code that I have:
class Object: Codable{
var name : String?
}
var objects: Array<Object>?
objects = Array<Object>()
if var obj = objects { // <----- Creates a copy of array here
let o = Object()
o.name = "1"
objects?.append(o)
print(obj) //<----- this one is missing "o" object
print(objects)
}
I cannot use NSMutableArray because I have an array inside another codable class.
What's everybody's experience on this one? If somebody can share a solutions for that.
Getting used to arrays as value types isn't too tough really. If i were you my version of the code would just look like this
var objects: Array<Object>?
objects = Array<Object>()
if var unwrappedObjs = objects {
let o = Object()
o.name = "1"
unwrappedObjs.append(o)
objects = unwrappedObjs
}
or alternatively maybe this:
var objects: Array<Object>?
objects = Array<Object>()
if objects != nil {
let o = Object()
o.name = "1"
objects?.append(o)
}
Lastly you could always try making your own "ReferenceArray" class that wraps the array APIs and gives you reference semantics but that seems like overkill. Sooner rather than later, arrays as value types will seem natural to reason about.
bitwit already mentioned this to a point, but I think that your biggest mistake is simply not accepting the new object as the source. Unless it's important to retain the Array<Object>? you should replace it with the Array<Object> one.
var objects: Array<Object>?
objects = Array<Object>()
if var objects = objects { // <----- Creates a copy of array here
let o = Object()
o.name = "1"
objects.append(o) // objects is now the non-optional one
print(objects)
}
If it needs to be in the same scope, use guard:
var objects: Array<Object>?
objects = Array<Object>()
guard var objects = objects else { // <----- Creates a copy of array here
fatalError()
}
let o = Object()
o.name = "1"
objects.append(o) // objects is now the non-optional one
print(objects)
If you absolutely need an array to be referenced, you can make a container class:
public class ReferenceContainer<Element> {
public var element: Element
init(_ element: Element) {
self.element = element
}
}
I'm trying to change the value of a global variable transferredData in the function didTransferData(_ data: Data?). My code looks like this:
var transferredData: [Double] = [0.0]
func didTransferData(_ data: Data?) {
var dataArray = [CUnsignedChar](repeating:0, count: (data?.count)!)
data?.copyBytes(to: &dataArray, count: dataArray.count)
let dataInt = dataArray.filter({ Int(String($0)) != nil }).map({ Int(String($0))! })
let dataDouble = dataInt.map { Double($0) }
print("Data double: \(dataDouble)")
transferredData = dataDouble
}
Printing transferredData inside of didTransferData returns the correct array, containing all values of dataDouble. But when I try to access it in this function later on
func returnData() -> [Double]{
print("return Data: \(transferredData)")
return transferredData
}
it returns [0.0]. I'm not sure if I'm missing something crucial here, but I thought that even if I change the value of a global variable in a function, the new value should be accessible for every other functions, too.
Thanks for any advice!!
You said that this code is inside a class. The variable transferredData is not a global, it is a member variable.
There is one of these per object of the class. I suspect that you are not using the same object to make these two calls.
You could make the member shared between all objects by declaring it static, but I think it would be better to leave as is and arrange to use the same object.
EDIT: based on comment
If you write the code
let centralInstance = CentralViewController()
You will get a new object with its own transferredData member initially set to [0.0]. You need to either
Get a reference to the same VC object that has the data
Store the data some where else in an object that you can get back (since the VC might be gone)
To hack something that works (not recommended, but to help understand)
You could move transferredData out of the class and make it an actual global variable. I would do this only to help you get past this issue and understand what's going on.
You could also make it static, which makes all of the VC's share the same instance of the transferredData
When you understand what is going on, you can try to do something a little better (at least move it to its own model object, and not in the VC at all). The next simplest thing is some kind of singleton to manage it -- this is just a glorified global variable but puts you more on the road to a more typical solution.
Where is the problem:
$ swift
Welcome to Apple Swift version 3.0.2 (swiftlang-800.0.63 clang-800.0.42.1). Type :help for assistance.
1> var data:[Double] = [0.0]
2.
3. class MuckWithData {
4.
5. func showData () -> [Double] {
6. print ("Data: \(data)")
7. return data
8. }
9.
10. func modifyData () {
11. data = [1.0]
12. }
13. }
data: [Double] = 1 value {
[0] = 0
}
14>
15> var mucked = MuckWithData()
mucked: MuckWithData = {}
16> mucked.showData()
Data: [0.0]
$R0: [Double] = 1 value {
[0] = 0
}
17> mucked.modifyData()
18> mucked.showData()
Data: [1.0]
$R1: [Double] = 1 value {
[0] = 1
}
Probably your computation for dataDouble is actually [0.0] and thus it appears that transferredData didn't change, but it did.
I know this is going to be super elementary, but I have this piece of code:
var labels: [String]?
func initVC(image: Images){
self.image = image
let tempLabels = image.label?.allObjects as! [Labels]
for i in 0..<tempLabels.count{
labels?.append(tempLabels[i].label!)
}
}
labels is in the public scope, so the function should have access to it, but when the loop runs through, labels is still nil with no elements.
When I po during debugging, tempLabels is as I expect it to be with 2 string elements.
I'm pretty sure this is a very simple problem, but I guess I'm just out of it right now.
Labels has never been initialised. Change
var labels:[String]?
to
var labels:[String] = []
You are declaring the labels variable but never allowing it to store information. This means that it does not necessarily exist, since it is not initialized, and therefore cannot be used.
For it to be useable, you must initialize it
var labels:[String] = []
Yep, it was super simple.
Changed
var labels: [String]?
To
var labels = [String]()
I have searched for a while but couldn't find reasonable answer for this. I want to add/remove objects in one array to make effect in 2nd array which points to first array.
class Person
{
var name:String = ""
}
var arr1:[Person] = [Person]()
let p1 = Person()
p1.name = "Umair"
let p2 = Person()
p2.name = "Ali"
arr1.append(p1)
arr1.append(p2)
var arr2 = arr1
print("\(arr1.count)") //"2\n"
print("\(arr2.count)") //"2\n"
arr1.removeFirst()
print("\(arr1.count)") //"1\n"
print("\(arr2.count)") //"2\n"
Why changing arr1 does not affect arr2. Please help me out to accomplish this.
Arrays are value types. When we copy them, each copy is independent of the other. This is a virtue in Swift. What you are trying to do requires references so that effects on one can be seen by others. Try this code. Create a class (reference type) containing your data. Now changes to the container can be seen in the other.
class Person
{
var name: String
init(_ name: String) {
self.name = name
}
}
let p1 = Person("Umair")
let p2 = Person("Ali")
class Container {
var people = [Person]()
init(people: [Person]) {
self.people = people
}
}
let arr1 = Container(people: [p1, p2])
let arr2 = arr1
print(arr1.people)
print(arr2.people)
arr1.people.removeFirst()
print(arr1.people)
print(arr2.people)
Even if you're using Swift, you can still use NSArray.
Per Apple's documentation,
NSArray is an object representing a static ordered collection, for use instead of an Array constant in cases that require reference semantics.
The only downside is you'll have to import Foundation. This isn't a problem if you're creating an iOS or Mac app, as you're depending on it already.