Printing the code of the file - c

Question

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main()
{
FILE *f;
f = fopen("my file.txt", "w");
int n = 5;
fprintf(f, "n equals to %d", n);
fclose(f);
f = fopen("my file2.txt", "w");
char *txt = "New file";
fwrite(txt, 1, strlen(txt), f);
fclose(f);
f = fopen("my file3.txt", "w");
char *txt2 = "Hello";
for(int i = 0; i < strlen(txt2); i++)
{
printf("Mouse cursor at %d.\n", ftell(f));
fputc(txt2[i], f);
}
fclose(f);
f = fopen(__FILE__, "r");
char str[1024];
while (!feof(f))
{
fscanf(f, "%s", str);
puts(str);
}
putchar('\n');
fclose(f);
f = fopen(__FILE__, "r");
long size = fseek(f, 0, SEEK_END);
char *buffer = malloc(sizeof(char) * size + 1);
fread(buffer, 1, size, f);
puts(buffer);
free(buffer);
fclose(f);
return 0;
}
Take a look in this part of the code :
f = fopen(__FILE__, "r");
long size = fseek(f, 0, SEEK_END);
char *buffer = malloc(sizeof(char) * size + 1);
fread(buffer, 1, size, f);
puts(buffer);
free(buffer);
fclose(f);
I've tried to print the code in my file and this is what I wrote to do it ^
When I try to print it with puts function it prints 3 characters :
http://i61.tinypic.com/ortdvl.png
The third character is changing in each execution.
Anyway to the question, I don't know why this happens can someone explain me what I did wrong ?

Answer 1

fseek(f, 0, SEEK_END);
long size = ftell(f);
char *buffer = calloc(size + 1, sizeof(char));
rewind(f);
fread(buffer, 1, size, f);