I have table in SQL Server with values for example :
1
2
2
2
1
2
I want to count how many times there is 1 value, so result of query from my example should be 2
I try
count (case status_d when 1 then 1 end) as COUNT_STATUS_1
but the result is 4, not 2
You can achieve this by using a WHERE clause.
SELECT COUNT(*) As Total_Ones
FROM TABLE_NAME
WHERE ColumnName = 1
Or you can use the case statement as well
SELECT COUNT(CASE WHEN ColumnName = 1 THEN 1 ELSE NULL END) As Total_Ones
FROM TABLE_NAME
SELECT COUNT(*)
FROM YourTable
WHERE status_d = 1
Related
I have this table . .
ID item_ID status
----------------------------
1 1 'available'
2 1 'available'
3 1 'available'
4 1 'reserved'
5 2 'available'
6 2 'available'
7 3 'reserved'
8 3 'reserved'
9 3 'reserved'
I want my SQL query to return this result:
item_ID quantity
------------------
1 3
2 2
3 0
Please help with this. I'm not really good with T-SQL.
You could use aggregation, but first you need to filter only "available" products:
SELECT item_id, COUNT(*) as quantity
FROM table
WHERE status = 'available'
GROUP BY item_id
ORDER BY item_id;
EDIT:
To get 0 you could use:
SELECT s.item_id, COUNT(t.item_ID) AS quantity
FROM (SELECT DISTINCT item_ID FROM table) s
LEFT JOIN table t
ON s.item_ID = t.item_id
AND t.status = 'available'
GROUP BY s.item_id
ORDER BY s.item_id;
one more way is to use Sum with case
select item_id,
sum(Case when status='available'
then 1 else 0 end) as 'quantity
from
table
group by item_id
Given the following table:
Column1 Column2 idx
-------------------
1 1 0
2 1 0
3 2 0
4 3 0
5 3 0
1 3 0
How could I increase the idx column dependent on column2 in SQL Server and Oracle with an UPDATE statement?
I would like to have:
Column1 Column2 idx
--------------------
1 1 0
2 1 1
3 2 0
4 3 0
5 3 1
1 3 2
Thank you!
This (or similar) approach should work for both:
;with x as (
select idx, row_number() over(partition by Column2 order by Column1) as new_idx
from tbl
)
update x set idx = new_idx
(Here I assume that there is a typo in 6th row for Column1 - if not, there should be something else for ordering)
With Oracle you need a MERGE statement for this:
merge into x using (
select rowid as rid,
row_number() over(partition by Column2 order by Column1) as new_idx
from tbl
) t on (t.rid = x.rowid)
when matched then
set idx = t.new_idx;
Instead of using rowid you can replace the join with the primary key columns of the table.
For a SQL Server based report,
Table:
CID Date ID Service Days
1 3/7/2016 1 Individual 3
2 4/5/2016 2 Individual 4
3 5/24/2016 1 Individual 3
4 4/4/2016 4 Group 2
5 4/4/2016 4 Group 2
6 2/18/2016 4 Group 2
7 5/5/2016 5 Group 1
8 5/5/2016 5 Group 1
I used this code:
SELECT
ID,
Service,
COUNT(WHEN Days = 4 THEN 1 END) AS '4Days',
COUNT(WHEN Days = 3 THEN 1 END) AS '3Days',
COUNT(WHEN Days = 2 THEN 1 END) AS '2Days',
COUNT(WHEN Days = 1 THEN 1 END) AS '1Day'
FROM Table T1
GROUP BY
ID,
Service
which gives me this Output:
ID Service 4Days 3Days 2Days 1Day
1 Individual 0 2 0 0
2 Individual 1 0 0 0
4 Group 0 0 3 0
5 Group 0 0 0 2
What I want to do is not count the Group services as separate services for separate individuals, but just as one service per group. A Count Distinct used with the Date or ID could help me do that but I don't know how to make that play with the Individual services where I just wanna count them individually and not using DISTINCT. So the desired output is:
ID Service 4Days 3Days 2Days 1Day
1 Individual 0 2 0 0
2 Individual 1 0 0 0
4 Group 0 0 2 0
5 Group 0 0 0 1
I'll edit the post in case I oversimplified the problem since this is dummy data.
Looks like you could use distinct this way if you wanted:
count(distinct
case when Days = 1 then case when Service = 'Group' then 1 else "Date" end end
) as [1Day]
Depending on your indexing it's possible that introducing another column in the query would change the query plan. I suspect that probably isn't the case though.
If I am not wrong for '2Days' column service type 'Group' count should be '2' if our grouping based on 'Date' column, if so then try this:
SELECT
ID,
Service,
CASE WHEN MAX(t.days) = 4 THEN MAX(t.date) ELSE 0 END AS '4Days',
CASE WHEN MAX(t.days) = 3 THEN MAX(t.date) ELSE 0 END AS '3Days',
CASE WHEN MAX(t.days) = 2 THEN MAX(t.date) ELSE 0 END AS '2Days',
CASE WHEN MAX(t.days) = 1 THEN MAX(t.date) ELSE 0 END AS '1Day'
FROM table T1
OUTER APPLY (SELECT days,
COUNT(DISTINCT(date)) date
FROM Table WHERE days = t1.days GROUP BY days) t
GROUP BY id, service
ORDER BY ID
Based on your last edit, this is the most straight forward way I could think of to handle the query:
with cte as (
select id, service, days
from table t1
where service = 'Individual'
union all
select id, service, days
from table t1
where service = 'Group'
group by id, service, days, date
)
select id,
service,
count(case when days = 4 then 'X' end) as [4Days],
count(case when days = 3 then 'X' end) as [3Days],
count(case when days = 2 then 'X' end) as [2Days],
count(case when days = 1 then 'X' end) as [1Day]
from cte
group by id, service
Rownum Status
1 2
2 1
3 3
4 2
5 3
6 1
The condition is to query records appear before the first record of status=3 which in the above scenario the expected output will be rownum = 1 and 2.
In the case if there is no status=3 then show everything.
I'm not sure from where to start hence currently no findings
If you are using SQL Server 2012+, then you can use window version of SUM with an ORDER BY clause:
SELECT Rownum, Status
FROM (
SELECT Rownum, Status,
SUM(CASE WHEN Status = 3 THEN 1 ELSE 0 END)
OVER
(ORDER BY Rownum) AS s
FROM mytable) t
WHERE t.s = 0
Calculated field s is a running total of Status = 3 occurrences. The query returns all records before the first occurrence of a 3 value.
Demo here
Please see fiddle: http://sqlfiddle.com/#!6/e6768/2
I have data, like below:
DRIVER DROP
1 1
1 2
1 ReturnToBase
1 4
1 5
1 ReturnToBase
1 6
1 7
2 1
2 2
2 ReturnToBase
2 4
I am trying to group my data, so for each driver, each group of return to bases have a grouping number.
My output should look like this:
DRIVER DROP GROUP
1 1 1
1 2 1
1 ReturnToBase 1
1 4 2
1 5 2
1 ReturnToBase 2
1 6 3
1 7 3
1 ReturnToBase 3
2 1 1
2 2 1
2 ReturnToBase 1
2 4 2
I've tried getting this result with a combination of windowed functions but I've been miles off so far
Below is what I had so far, it isn't supposed to be functional I was trying to figure out how it could be done, if it's even possible.
SELECT
ROW_NUMBER() OVER (Partition BY Driver order by Driver Desc) rownum,
Count(1) OVER (Partition By Driver Order By Driver Desc) counter,
Count
DropNo,
Driver,
CASE DropNo
WHEN 'ReturnToBase' THEN 1 ELSE 0 END AS EnumerateRound
FROM
Rounds
You can use the following query:
SELECT id, DRIVER, DROPno,
1 + SUM(flag) OVER (PARTITION BY DRIVER ORDER BY id) -
CASE
WHEN DROPno = 'ReturnToBase' THEN 1
ELSE 0
END AS grp
FROM (
SELECT id, DRIVER, DROPno,
CASE
WHEN DROPno = 'ReturnToBase' THEN 1
ELSE 0
END AS flag
FROM rounds ) AS t
Demo here
This query uses windowed version of SUM with ORDER BY in the OVER clause to calculate a running total. This version of SUM is available from SQL Server 2012 onwards AFAIK.
Fiddling a bit with this running total value is all we need in order to get the correct GROUP value.
EDIT: (credit goes to #Conrad Frix)
Using CROSS APPLY instead of an in-line view can considerably simplify things:
SELECT id, DRIVER, DROPno,
1 + SUM(x.flag) OVER (PARTITION BY DRIVER ORDER BY id) - x.flag
FROM rounds
CROSS APPLY (SELECT CASE WHEN DROPno = 'ReturnToBase' THEN 1 ELSE 0 END) AS x(flag)
Demo here
Added a sequential ID column to your example for use in a recursive CTE:
with cte as (
select ID,DRIVER,DROPno,1 as GRP
FROM rounds
where ID = 1
union all
select a.ID
,a.DRIVER
,a.DROPno
,case when b.DROPno = 'ReturnToBase'
or b.DRIVER <> a.DRIVER then b.GRP + 1
else b.GRP end
from rounds a
inner join cte b
on a.ID = b.ID + 1
)
select * from cte
SQL Fiddle