I have this CSV file that it need to be uploaded in a WebSite , but this website have an input type file.
I know its pretty impossible because i spent like three weeks loking for an answer,i found another way to upload the file WITHOUT USING THE INPUT TYPE FILE* so i was wondering if anyone found a solution to my probleme
This is what i have :
This is my firt attempt like any average personne using VBA :
Set UploadCSV = IEDoc.getElementById("namecsv")
UploadCSV.Value = "something\toto.csv"
This is my input type file:
<input name="filename" class="text align_center" id="nomfichiercsv" type="file" size="24" accept="text/html,text/plain" value=""/>
Thank's
I tried the SendKeys function no luck
Like mentioned you can do this in an Eclipse project using the Java Selenium driver. Afterwards part of the code could look like this;
driver.findElement(By.id("nomfichiercsv")).sendKeys(UploadCSV);
driver.findElement(By.id("submit")).click();
In VBA, you can use the below code after you have identified the element:
driver.FindElementById("Id of the element").SendKeys ("path to the input file")
If the frame changes when you are trying to upload the file, you will need to switch to the new frame.
If Id is not present for the element, use other Web Element selector methods.
Related
I want to make a Spinner to select the age ofthe users of my app. I wanted to know how I could create an array of all integers between 0 and 10 in the string resource file .xml in android Studio.
This is what I thought I was going to do
<integer-array name="AgeArray">
<item>1</item>
<item>2</item>
<item>3</item>
<item>4</item>
<item>5</item>
<item>6</item>
<item>7</item>
<item>8</item>
<item>9</item>
<item>10</item>
<item>12</item>
<item>13</item>
<item>14</item>
<item>15</item>
<item>16</item>
<item>17</item>
<item>18</item>
<item>19</item>
<item>20</item>
</integer-array>
But I thought that there must be a more elegant, more efficient way of creating such an array, or am I wrong?
Thanks in advance
You cannot write to a resource file (at runtime), resource files are read-only.
While developing you can create a scratch file in Android Studio, execute the following code and then copy-paste the result from the output panel to the resource file:
val list = (1..100).joinToString("\n") { " <item>$it</item>" }
val xml = "<integer-array name=\"AgeArray\">\n$list\n</integer-array>\n"
println(xml)
I am new to Oracle Apex 5.1, and I have been asked to implement a button that when clicked, the user gets (downloads) a .doc file of an Interactive report.
I have noticed that the Interactive Report gives you the option to download it as .pdf, .xls, and so, but I need it to be a Word (.doc) file.
In addition, the file must be in a specific format (with heading, indentation, font, etc.) that I was given (as a template) in a Word file.
Any help would be appreciated.
Additional Information: I was able to open the template (.doc) file in NotePad++ and get the <html> version of it, so I could edit it in both NotePad++ and Word.
One of the best actually to do that is APEX OFFICE PRINT(AOP) but isn't free licence.
otherwise you can check this solution
How do we export a ms-word (or rtf) document (from a web browser) to generated by pl/sql?
I end up finding information in this page: http://davidsgale.com/apex-how-to-download-a-file/ and I wrote this code:
declare
l_clob clob;
begin
l_clob := null;
sys.htp.init;
sys.owa_util.mime_header('application/vnd.ms-word', FALSE,'utf-8');
sys.htp.p('Content-length: ' || sys.dbms_lob.getlength( l_clob ));
sys.htp.p('Content-Disposition: inline; filename="test_file.doc"' );
sys.owa_util.http_header_close;
sys.htp.p(SET_DOC_HEADER);
sys.htp.p(SET_TABLE_HEADER);
sys.htp.p(ADD_TABLE_ENTRY("arguments"));
sys.htp.p(SET_TABLE_FOOTER);
sys.wpg_docload.download_file(l_clob);
apex_application.stop_apex_engine;
exception when others then
--sys.htp.prn('error: '||sqlerrm);
apex_application.stop_apex_engine;
end;
It works, but I had to create functions in the SQL Workshop because writting a table in html is really long.
The LabelMe database can be downloaded from http://www.cs.toronto.edu/~norouzi/research/mlh/data/LabelMe_gist.mat
However, there is another link http://labelme.csail.mit.edu/Release3.0/
The webpage has a toolbox but I could not find any database to download. So, I was wondering if I could use the LabelMe_gist.mat which has the following fields. The field names contins the labels for the images, and img perhaps contains the images. How do I display the training and test images? I tried
im = imread(img)
Error using imread>parse_inputs (line 486)
The filename or url argument must be a string.
Error in imread (line 336)
[filename, fmt_s, extraArgs, msg] = parse_inputs(varargin{:});
but surely this is not the way. Please help
load LabelMe_gist.mat;
load('LabelMe_gist.mat', 'img')
Since we had no idea from your post what kind of data this is I went ahead and downloaded it. Turns out, img is a collection of 22019 images that are of size 32x32 (RGB). This is why img is a 32 x 32 x 3 x 22019 variable. Therefore, the i-th image is accessible via imshow(img(:,:,:,i));
Here is an animation of all of them (press Ctrl+C to interrupt):
for iImage = 1:size(img,4)
figure(1);clf;
imshow(img(:,:,:,iImage));
drawnow;
end
I'm currently trying to attach image files to a model directly from a zip file (i.e. without first saving them on a disk). It seems like there should be a clearer way of converting a ZipEntry to a Tempfile or File that can be stored in memory to be passed to another method or object that knows what to do with it.
Here's my code:
def extract (file = nil)
Zip::ZipFile.open(file) { |zip_file|
zip_file.each { |image|
photo = self.photos.build
# photo.image = image # this doesn't work
# photo.image = File.open image # also doesn't work
# photo.image = File.new image.filename
photo.save
}
}
end
But the problem is that photo.image is an attachment (via paperclip) to the model, and assigning something as an attachment requires that something to be a File object. However, I cannot for the life of me figure out how to convert a ZipEntry to a File. The only way I've seen of opening or creating a File is to use a string to its path - meaning I have to extract the file to a location. Really, that just seems silly. Why can't I just extract the ZipEntry file to the output stream and convert it to a File there?
So the ultimate question: Can I extract a ZipEntry from a Zip file and turn it directly into a File object (or attach it directly as a Paperclip object)? Or am I stuck actually storing it on the hard drive before I can attach it, even though that version will be deleted in the end?
UPDATE
Thanks to blueberry fields, I think I'm a little closer to my solution. Here's the line of code that I added, and it gives me the Tempfile/File that I need:
photo.image = zip_file.get_output_stream image
However, my Photo object won't accept the file that's getting passed, since it's not an image/jpeg. In fact, checking the content_type of the file shows application/x-empty. I think this may be because getting the output stream seems to append a timestamp to the end of the file, so that it ends up looking like imagename.jpg20110203-20203-hukq0n. Edit: Also, the tempfile that it creates doesn't contain any data and is of size 0. So it's looking like this might not be the answer.
So, next question: does anyone know how to get this to give me an image/jpeg file?
UPDATE:
I've been playing around with this some more. It seems output stream is not the way to go, but rather an input stream (which is which has always kind of confused me). Using get_input_stream on the ZipEntry, I get the binary data in the file. I think now I just need to figure out how to get this into a Paperclip attachment (as a File object). I've tried pushing the ZipInputStream directly to the attachment, but of course, that doesn't work. I really find it hard to believe that no one has tried to cast an extracted ZipEntry as a File. Is there some reason that this would be considered bad programming practice? It seems to me like skipping the disk write for a temp file would be perfectly acceptable and supported in something like Zip archive management.
Anyway, the question still stands:
Is there a way of converting an Input Stream to a File object (or Tempfile)? Preferably without having to write to a disk.
Try this
Zip::ZipFile.open(params[:avatar].path) do |zipfile|
zipfile.each do |entry|
filename = entry.name
basename = File.basename(filename)
tempfile = Tempfile.new(basename)
tempfile.binmode
tempfile.write entry.get_input_stream.read
user = User.new
user.avatar = {
:tempfile => tempfile,
:filename => filename
}
user.save
end
end
Check out the get_input_stream and get_output_stream messages on ZipFile.
I'm working on a data migration task, where I have to export a somewhat large Lotus Notes application into a blogging platform. My first task was to export the articles from Lotus Notes into CSV files.
I created a Agent in LotusScript to export the data into CSV files. I use a modified version of this IBM DeveloperWorks forum post. And it basically does the job. But the contents of the Rich Text field is stripped of any formatting. And this is not what I want, I want the Rich Text field rendered as HTML.
The documentation for the GetItemValue method explicitly states that the text is rendered into plain text. So I began to research for something that would retrieve the HTML. I found the NotesMIMEEntity class and some sample code in the IBM article How To Access HTML in a Rich Text Field Using LotusScript.
But for the technique described in the above article to work, the Rich Text field need to have the property "Store Contents as HTML and MIME". And this is not the case with my Lotus Notes database. I tried to set the property on the fields in question, but it didn't do the trick.
Is it possible to use the NotesMIMEEntity and set the "Store Contents as HTML and MIME" property after the content has been added, to export the field rendered as HTML?
Or what are my options for exporting the Notes database Rich Text fields as HTML?
Bonus information: I'm using IBM Lotus Domino Designer version 8.5
There is this fairly unknown command that does exactly what you want: retrieve the URL using the command OpenField.
Example that converts only the Body-field:
http://SERVER/your%5Fdatabase%5Fpath.nsf/NEW%5FVIEW/docid/Body?OpenField
Here is how I did it, using the OpenField command, see D.Bugger's post above
Function GetHtmlFromField(doc As NotesDocument, fieldname As String) As String
Dim obj
Set obj = CreateObject("Microsoft.XMLHTTP")
obj.open "GET", "http://www.mydomain.dk/database.nsf/0/" + doc.Universalid + "/" + fieldname + "?openfield&charset=utf-8", False, "", ""
obj.send("")
Dim html As String
html = Trim$(obj.responseText)
GetHtmlFromField = html
End Function
I'd suggest looking at Midas' Rich Text LSX (http://www.geniisoft.com/showcase.nsf/MidasLSX)
I haven't used the personally, but I remember them from years ago being the best option for working with Rich Text. I'd bet it saves you a lot of headaches.
As for the NotesMIMEEntity class, I don't believe there is a way to convert RichText to MIME, only MIME to RichText (or retain the MIME within the document for emailing purposes).
If you upgrade to Notes Domino 8.5.1 then you can use the new ConvertToMIME method of the NotesDocument class. See the docs. This should do what you want.
Alternativly the easiest way to get the Domino server to render the RichText will be to actually retrieve it via a url call. Set up a simple form that just has the RichText field and then use your favourite HTTP api to pull in the page. It should then be pretty straight forward to pull out the body.
Keep it simple.
Change the BODY field to Store contents as HTML and MIME
Open the doc in editmode.
Save.
Close.
You can now use the NotesMIMEEntity to get what you need from script.
You can use the NotesDXLExporter class to export the Rich Text and use an XSLT to transform the output to what you need.
I know you mentioned using LotusScript, but if you don't mind writing a small Java agent (in the Notes client), this can be done fairly easily - and there is no need to modify the existing form design.
The basic idea is to have your Java code open a particular document through a localhost http request (which is simple in Java) and to have your code capture that html output and save it back to that document. You basically allow the Domino rendering engine to do the heavy lifting.
You would want do this:
Create a form which contains only the rich-text field you want to convert, and with Content Type of HTML
Create a view with a selection formula for all of the documents you want to convert, and with a form formula which computes to the new form
Create the Java agent which just walks your view, and for each document gets its docid, opens a URL in the form http://SERVER/your_database_path.nsf/NEW_VIEW/docid?openDocument, grabs the http response and saves it.
I put up some sample code in a similar SO post here:
How to convert text and rich text fields in a document to html using lotusscript?
Works in Domino 10 (have not tested with 9)
HTMLStrings$ = NotesRichTextItem .Converttohtml([options] ) As String
See documentation :
https://help.hcltechsw.com/dom_designer/10.0.1/basic/H_CONVERTOHTML_METHOD_NOTESRICHTEXTITEM.html
UPDATE (2022)
HCL no longer support this method since version 11. The documentation does not include any info about the method.
I have made some tests and it still works in v12 but HCL recommended to not use it.
Casper's recommendation above works well, but make sure the ACL is such to allow Anonymous Access otherwise your HTML will be the HTML from your login form
If you do not need to get the Richtext from the items specifically, you can use ?OpenDocument, which is documented (at least) here: https://www.ibm.com/developerworks/lotus/library/ls-Domino_URL_cheat_sheet/
https://www.ibm.com/support/knowledgecenter/SSVRGU_9.0.1/com.ibm.designer.domino.main.doc/H_ABOUT_URL_COMMANDS_FOR_OPENING_DOCUMENTS_BY_KEY.html
OpenDocument also allows you to expand sections (I am unsure if OpenField does)
Syntax is:
http://Host/Database/View/DocumentUniversalID?OpenDocument
But be sure to include the charset parameter as well - Japanese documents were unreadable without specifying utf-8 as the charset.
Here is the method I use that takes a NotesDocument and returns the HTML for the doc as a string.
private string ConvertDocumentToHml(Domino.NotesDocument doc, string sectionList = null)
{
var server = doc.ParentDatabase.Server.Split('/')[0];
var dbPath = doc.ParentDatabase.FilePath;
string viewName = "0";
string documentId = doc.UniversalID.ToUpper();
var ub = new UriBuilder();
ub.Host = server;
ub.Path = dbPath.Replace("\\", "/") + "/" + viewName + "/" + documentId;
if (string.IsNullOrEmpty(sectionList))
{
ub.Query = "OpenDocument&charset=utf-8";
}
else
{
ub.Query = "OpenDocument&charset=utf-8&ExpandSection=" + sectionList;
}
var url = ub.ToString();
var req = HttpWebRequest.CreateHttp(url);
try
{
var resp = req.GetResponse();
string respText = null;
using (var sr = new StreamReader(resp.GetResponseStream()))
{
respText = sr.ReadToEnd();
}
return respText;
}
catch (WebException ex)
{
return "";
}
}