Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 8 years ago.
Improve this question
I understand the basic difference between function call & interrupt (ISR) jump from below SE question.
difference between function call & ISR
But I am still not clear about, what are the registers will be pushed /pop to/from stack in both the cases? How context switching will happen in both the case? As we don't know when interrupt will occur, what we need to save (variables, PC, flags (PSW), registers, context) before entering into ISR?
How can we resume back original context without any data lose with multiple thread environment.
I tried to google it & I found the needed information from this:
Interrupts
Context Switch
Thanks #Drew McGowen
So to sum up, the general sequence for an interrupt is as follows:
Foreground code is running, interrupts are enabled
Interrupt event sends an interrupt request to the CPU
After completing the current instruction(s), the CPU begins the interrupt response
automatically saves current program counter
automatically saves some status (depending on CPU)
jump to correct interrupt service routine for this request
ISR code saves any registers and flags it will modify
ISR services the interrupt and re-arms it if necessary
ISR code restores any saved registers and flags
ISR executes a return-from-interrupt instruction or sequence
return-from-interrupt instruction restores automatically-saved status
return-from-interrupt instruction recovers saved program counter
Foreground code continues to run from the point it responded to the interrupt
As usual, the details of this process will depend on the CPU design. Many devices use the hardware stack for all saved data, but RISC designs typically save the PC in a register (the link register). Many designs also have separate duplicate registers that can be used for interrupt processing, thus reducing the amount of state data that must be saved and restored.
Note that saving and restoring the foreground code state is generally a two-step process for reasons of efficiency. The hardware response to the interrupt automatically saves the most essential state, but the first lines of ISR code are usually dedicated to saving additional state (usually in the form of saving condition flags if not saved by the hardware, along with saving additional registers). This two-step process is used because every ISR will have different requirements for the number of registers it needs, and thus every ISR may need to save save different registers, and different numbers of registers, assuring all appropriate state data is saved without wasting time saving registers unnecessarily (that is, saving registers that are not modified in the ISR and thus didn’t need to be saved). A very simple ISR may not need to use any registers, another ISR may need to use only one or two registers, while a more complicated ISR may need to use a large number of registers. In every case, the ISR should only save and restore those registers it actually uses.
I'm sure there are different implementations based on the CPU you're using. On a general level, the function calls store the input parameters within the given registers (%o0-%o9) on SPARC and are available in the (%i0-%i9) registers in the calle's function. The callee function will then place the return value in the %i0 register to be available in the %o0 register for the caller function. According to the Sparc Manual, each interrupt is:
Accompanied by data, referred to as an “interrupt packet”.
An interrupt packet is 64 bytes long, consisting of eight 64-bit doublewords.
According to this source, the data in your current executing thread is:
Saved either on a stack (PDP-11, VAX, MIPS, x86_64)
or in a single set of dedicated registers (ARM, PowerPC)
The above source mentions how interrupts are handeled on a couple of different architectures as well.
Please let me know if you have any questions!
Related
I'm working on one of Freesacle micro controller. This microcontroller has several reset sources (e.g. clock monitor reset, watchdog reset and ...).
Suppose that because of watchdog, my micro controller is reset. How can I save some data just before reset happens. I mean for example how can I understand that where had been the program counter just before watchdog reset. With this method I want to know where I have error (in another words long process) that causes watchdog reset.
Most Freescale MCUs work like this:
RAM is preserved after watchdog reset. But probably not after LVD reset and certainly not after power-on reset. This is in most cases completely undocumented.
The MCU will either have a status register where you can check the reset cause (for example HCS08, MPC5x, Kinetis), or it will have special reset vectors for different reset causes (for example HC11, HCS12, Coldfire).
There is no way to save anything upon reset. Reset happens and only afterwards can you find out what caused the reset.
It is however possible to reserve a chunk of RAM as a special segment. Upon power-on reset, you can initialize this segment by setting everything to zero. If you get a watchdog reset, you can assume that this RAM segment is still valid and intact. So you don't initialize it, but leave it as it is. This method enables you to save variable values across reset. Probably - this is not well documented for most MCU families. I have used this trick at least on HCS08, HCS12 and MPC56.
As for the program counter, you are out of luck. It is reset with no means to recover it. Meaning that the only way to find out where a watchdog reset occurred is the tedious old school way of moving a breakpoint bit by bit down your code, run the program and check if it reached the breakpoint.
Though in case of modern MCUs like MPC56 or Cortex M, you simply check the trace buffer and see what code that caused the reset. Not only do you get the PC, you get to see the C source code. But you might need a professional, Eclipse-free tool chain to do this.
Depending on your microcontroller you may get Reset Reason, but getting previous program counter (PC/IP) after reset is not possible.
Most of modern microcontrollers have provision for Watchdog Interrupt Instead of reset.
You can configure watchdog peripheral to enable interrupt , In that ISR you can check stored context on stack. ( You can take help from JTAG debugger to check call stack).
There are multiple debugging methods available if your micro-controller dosent support above method.
e.g
In simple while(1) based architecture you can use a HW timer and restart it after some section of code. In Timer ISR you will know which code section is consuming long enough than the timer.
Two things:
Write a log! And rotate that log to keep the last 30 min. or whatever reasonable amount of time you think you need to reproduce the error. Where the log stops, you can see what happened just before that. Even in production-level devices there is some level of logging.
(Less, practical) You can attach a debugger to nearly every micrcontroller and step through the code. Probably put a break-point that is hit just before you enter the critical section of code. Some IDEs/uCs allow having "data-breakpoints" that get triggered when certain variables contain certain values.
Disclaimer: I am not familiar with the exact microcontroller that you are using.
It is written in your manual.
I don't know that specific processor but in most microprocessors a watchdog reset is a soft reset, meaning that certain registers will keep information about the reset source and sometimes reason.
You need to post more specific information on your Freescale μC for this be answered properly.
Even if you could get the Program Counter before reset, it wouldn't be advisable to blindly set the program counter to another after reset --- as there would likely have been stack and heap information as well as the data itself may also have changed.
It depends on what you want to preserve after reset, certain behaviour or data? Volatile memory may or may not have been cleared after watchdog (see your uC datasheet) and you will be able to detect a reset after checking reset registers (again see your uC datasheet). By detecting a reset and checking volatile memory you may be able to prepare your uC to restart in a way that you'd prefer after the unlikely event of a reset occurring. You could create a global value and set it to a particular value in global scope, then if it resets, check the value against it when a reset event occurs -- if it is the same, you could assume other memory may also be the same. If volatile memory is not an option you'll need to have a look at the datasheet for non-volatile options, however it is also advisable not to continually write to non-volatile memory due to writing limitations.
The only reliable solution is to use a debugger with trace capability if your chip supports embedded instruction trace.
Some devices have an option to redirect the watchdog timeout to an interrupt rather then a reset. This would allow you to write the watchdog timeout handler much like an exception handler and dump or store the stack information including the return address which will indicate the location the interrupt occurred.
However in some cases, neither solution is a reliable method of achieving your aim. In a multi-tasking environment or system with interrupt handlers, the code running when the watchdog timeout occurs may not be the process that is causing the problem.
I am learning embedded systems on the ARM9 processor (SAM9G20). I am more familiar with procedural programming for general purpose. Thus what I am doing is going through the data sheet and learning what registers there are and how to manipulate them.
My question is, how do I know when the computer reset? I know that there is a Reset Controller that manages resets. A register called the Status Register (RSTC_SR) stores the source of the reset. Do I need to keep periodically reading this register?
My solution is to store the number of resets in the FRAM (or start by setting it to 0), once a reset happens, I compare this variable with the register value in my main function. If the register value is higher then obviously it reset. However I am sure there is a more optimized way (perhaps using interrupts). Or is this how its usually done?
You do not need to periodically check, since every time the machine is reset your program will re-start from the beginning.
Simply add checks to the startup code, i.e. early in main(), as needed. If you want to figure out things like how often you reset, then that is more difficult since typically (no experience with SAMs, I'm an STM32 type of guy) on-board timers etc will also reset. Best would be some kind of real-world independent clock, like an RTC that you can poll and save the value of. Please consider if you really need this, though.
A simple solution is to exploit the structure of your code.
Many code bases for embedded take this form:
int main(void)
{
// setup stuff here
while (1)
{
// handle stuff here
}
return 0;
}
You can exploit that the code above while(1) is only run once at startup. You could increment a counter there, and save it in non-volatile storage. That would tell you how many times the microcontroller has reset.
Another example is on Arduino, where the code is structured such that a function called setup() is called once, and a function called loop() is called continuously. With this structure, you could increment the variable in the setup()-function to achieve the same effect.
Whenever your processor starts up, it has by definition come out of reset. What the reset status register does is indicate the source or reason for the reset, such as power-on, watchdog-timer, brown-out, software-instruction, reset-pin etc.
It is not a matter of knowing when your processor has reset - that is implicit by the fact that your code has restarted. It is rather a matter of knowing the cause of the reset.
You need not monitor or read the reset status at all if your application has no need of it, but in some applications perhaps it is a useful diagnostic for example to maintain a count of various reset causes as it may be indicative of the stability of your system software, its power-supply or the behaviour of the operators. Ideally you'd want to log the cause with a timestamp assuming you have an suitable RTC source early enough in your start-up. The timing of resets is often a useful diagnostic where simply counting them may not be.
Any counting of the reset cause should occur early in your code start-up before any interrupts are enabled (because an interrupt may itself cause a reset). This may require you to implement the counters in the start-up code before main() is invoked in cases where the start-up code might enable interrupts - for stdio or filesystem support fro example.
A way to do this is to run the code in debug mode (if you got a debugger for the SAM). After a reset the program counter(PC) points to the address where your code starts.
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 5 years ago.
Improve this question
I'm trying to understand how Interrupts are handled by the system and how does it work if there is a DMA integrated in the system.
I will express what I understood until now, and I would like to have some feedback if I'm right or not.
In order for the system to catch I/O actions performed by some device, the system uses what's called Interrupts.
The system sets up interrupts for given actions (we're interested in, for example typing on a keyboard), and once the action is performed the system catches it.
Now I have some doubts, once we catch an Interrupt what happens in the background? What are the overheads? What has does the CPU needs to set up? Is there a context switch? How does the interrupt handler works?
The CPU has to do some work in order to handle the interrupt, does it read the registers and writes the "message" in the memory, in order for the user to see it?
If we have a DMA, instead, once the CPU catches the Interrupt it doesn't need to handle the memory access for the device, thus it can perform other thing until the DMA interrupts the CPU telling him that the transfer it completed and that the CPU can safely close the handling?
As you can see there is some stuff I need to clarify. I would really appreciate your help. I know that an answer to all those questions could be written in one book, but all I need is to know how the things are connected, to get an intuition on what's going on behind the scenes in order to reason more easily about it.
Interrupts are handled by something called Interrupt Service Routines (ISRs). These are functions implemented by the kernel and registered with the hardware. Each type of an interrupt is registered with a separate handler.
When a hardware receives an interrupt, it halts the execution of any running process (on that processor), pushes the state of the process (registers, flags, segments) on the stack and executes the ISR.
Apart from saving the context, the hardware also does one more important thing. It changes the processor context to Privileged mode (lower ring). This is of course if the processor is already not in Ring 0 and if Privileged operations are required by the ISR. There is a flag in the Interrupt Descriptor Table (IDT) which tells the processor whether it is a user mode exception or a privileged mode exception.
Since these ISRs are written by the kernel they are trusted. These ISRs perform whatever is required for example in case of a keyboard interrupt, it moves the byte reads into the input stream of the foreground process.
After the ISR is done, (signaled by an iret instruction on X86), the state of the program is popped off and the execution of the process continues.
Yes, this can be thought of a context switch, but it really isn't since other process is not loaded. It can be just thought of as a halt till a more important job is done.
While this has some overhead, it is not much in case of frequent interrupts like keyboards interrupts (the ISRs are very small) and also these interrupts are very infrequent.
But say there is a hardware that does jobs are very regular interval. Like disk read/write or network card. In this case, interrupting again and again would be very costly.
So what we use is DMA (direct memory access). The processor allocates some physical memory to these hardware. They can access this part of the RAM without halting the process, since the processor's intervention is not required.
They keep doing all the IO they need to, but in the end when the job is done (or if it fails), they signal the processor with a single interrupt.
As we know we write Embedded C programming, for task management, memory management, ISR, File system and all.
I would like to know if some task or process is running and at the same time an interrupt occurred, then how SW or process or system comes to know that, the interrupt has occurred? and pauses the current task execution and starts serving ISR.
Suppose if I will write the below code like;
// Dummy Code
void main()
{
for(;;)
printf("\n forever");
}
// Dummy code for ISR for understanding
void ISR()
{
printf("\n Interrupt occurred");
}
In this above code if an external interrupt(ISR) occurs, then how main() comes to know that the interrupt occurred? So that it would start serving ISR first?
main doesn't know. You have to execute some-system dependent function in your setup code (maybe in main) that registers the interrupt handler with the hardware interrupt routine/vector, etc.
Whether that interrupt code can execute a C function directly varies quite a lot; runtime conventions for interrupt procedures don't always follow runtime conventions for application code. Usually there's some indirection involved in getting a signal from the interrupt routine to your C code.
your query: I understood your answer. But I wanted to know when Interrupt occurs how the current task execution gets stopped/paused and the ISR starts executing?
well Rashmi to answer your query read below,
when microcontroller detects interrupt, it stops exucution of the program after executing current instruction. Then it pushes PC(program counter) on to stack and loads PC with the vector location of that inerrupt hence, program flow is directed to interrrupt service routine. On completion of ISR the microcontroller again pops the stored program counter from stack and loads it on to PC hence, program execution again resumes from next location it was stopped.
does that replied to your query?
It depends on your target.
For example the ATMEL mega family uses a pre-processor directive to register the ISR with an interrupt vector. When an interrupt occurs the corrosponding interrupt flag is raised in the relevant status register. If the global interrupt flag is raised the program counter is stored on the stack before the ISR is called. This all happens in hardware and the main function knows nothing about it.
In order to allow main to know if an interrupt has occurred you need to implement a shared data resource between the interrupt routine and your main function and all the rules from RTOS programming apply here. This means that as the ISR may be executed at any time it as not safe to read from a shared resource from main without disabling interrupts first.
On an ATMEL target this could look like:
volatile int shared;
int main() {
char status_register;
int buffer;
while(1) {
status_register = SREG;
CLI();
buffer = shared;
SREG = status_register;
// perform some action on the shared resource here.
}
return 0;
}
void ISR(void) {
// update shared resource here.
}
Please note that the ISR is not added to the vector table here. Check your compiler documentation for instructions on how to do that.
Also, an important thing to remember is that ISRs should be very short and very fast to execute.
On most embedded systems the hardware has some specific memory address that the instruction pointer will move to when a hardware condition indicates an interrupt is required.
When the instruction pointer is at this specific location it will then begin to execute the code there.
On a lot of systems the programmer will place only an address of the ISR at this location so that when the interrupt occurs and the instruction pointer moves to the specific location it will then jump to the ISR
try doing a Google search on "interrupt vectoring"
An interrupt handling is transparent for the running program. The processor branchs automatically to a previously configured address, depending on the event, and this address being the corresponding ISR function. When returning from the interrupt, a special instruction restores the interrupted program.
Actually, most of the time you won't ever want that a program interrupted know it has been interrupted. If you need to know such info, the program should call a driver function instead.
interrupts are a hardware thing not a software thing. When the interrupt signal hits the processor the processor (generally) completes the current instruction. In some way shape or form preserves the state (so it can get back to where it was) and in some way shape or form starts executing the interrupt service routine. The isr is generally not C code at least the entry point is usually special as the processor does not conform to the calling convention for the compiler. The ISR might call C code, but you end up with the mistakes that you made, making calls like printf that should not be in an ISR. hard once in C to keep from trying to write general C code in an isr, rather than the typical get in and get out type of thing.
Ideally your application layer code should never know the interrupt happened, there should be no (hardware based) residuals affecting your program. You may choose to leave something for the application to see like a counter or other shared data which you need to mark as volatile so the application and isr can share it. this is not uncommon to have the isr simply flag that an interrupt happened and the application polls that flag/counter/variable and the handling happens primarily in the application not isr. This way the application can make whatever system calls it wants. So long as the overall bandwidth or performance is met this can and does work as a solution.
Software doesnt recognize the interrupt to be specific, it is microprocessor (INTC) or microcontrollers JOB.
Interrupt routine call is just like normal function call for Main(), the only difference is that main dont know when that routine will be called.
And every interrupt has specific priority and vector address. Once the interrput is received (either software or hardware), depending on interrupt priority, mask values and program flow is diverted to specific vector location associated with that interrupt.
hope it helps.
Can someone please explain to me what happens inside an interrupt service routine (although it depends upon specific routine, a general explanation is enough)? This always used be a black box for me.
There is a good wikipedia page on interrupt handlers.
"An interrupt handler, also known as an interrupt service routine (ISR), is a callback subroutine in an operating system or device driver whose execution is triggered by the reception of an interrupt. Interrupt handlers have a multitude of functions, which vary based on the reason the interrupt was generated and the speed at which the Interrupt Handler completes its task."
Basically when a piece of hardware (a hardware interrupt) or some OS task (software interrupt) needs to run it triggers an interrupt. If these interrupts aren't masked (ignored) the OS will stop what it's doing and call some special code to handle this new event.
One good example is reading from a hard drive. The drive is slow and you don't want your OS to wait for the data to come back; you want the OS to go and do other things. So you set up the system so that when the disk has the data requested, it raises an interrupt. In the interrupt service routine for the disk the CPU will take the data that is now ready and will return it to the requester.
ISRs often need to happen quickly as the hardware can have a limited buffer, which will be overwritten by new data if the older data is not pulled off quickly enough.
It's also important to have your ISR complete quickly as while the CPU is servicing one ISR other interrupts will be masked, which means if the CPU can't get to them quickly enough data can be lost.
Minimal 16-bit example
The best way to understand is to make some minimal examples yourself.
First learn how to create a minimal bootloader OS and run it on QEMU and real hardware as I've explained here: https://stackoverflow.com/a/32483545/895245
Now you can run in 16-bit real mode:
movw $handler0, 0x00
mov %cs, 0x02
movw $handler1, 0x04
mov %cs, 0x06
int $0
int $1
hlt
handler0:
/* Do 0. */
iret
handler1:
/* Do 1. */
iret
This would do in order:
Do 0.
Do 1.
hlt: stop executing
Note how the processor looks for the first handler at address 0, and the second one at 4: that is a table of handlers called the IVT, and each entry has 4 bytes.
Minimal example that does some IO to make handlers visible.
Protected mode
Modern operating systems run in the so called protected mode.
The handling has more options in this mode, so it is more complex, but the spirit is the same.
Minimal example
See also
Related question: What does "int 0x80" mean in assembly code?
While the 8086 is executing a program an interrupt breaks the normal sequence of execution of instruction, divert its execution to some other program called interrupt service Routine (ISR). after executing, control return the back again to the main program.
An interrupt is used to cause a temporary halt in the execution of program. Microprocessor responds to the interrupt service routine, which is short program or subroutine that instruct the microprocessor on how to handle the interrupt.