ReDim Preserve with multidimensional array in Excel VBA - arrays

I can get this to work but am not sure if this is the correct or the most efficient way of doing this.
Details: Looping through 151 rows then assigning column A and B only of those rows to a two dimensional array based on criteria in column C. With the criteria only 114 of the 151 rows are needed in the array.
I know that with ReDim Preserve you can only resize the last array dimension and you can't change the number of dimensions at all. So I have sized the rows in the array to be the total 151 rows using the LRow variable but the actual rows I only need in the array is in variable ValidRow so it seems that (151-114) = 37 superfluous rows are in the array as a result of the ReDim Preserve line. I would like to make the array only as big as it needs to be which is 114 rows not 151 but not sure if this is possible see code below and any help much appreciated as I am new to arrays and have spent the best part of two days looking at this. Note: Columns are a constant no issue with them but rows vary.
Sub FillArray2()
Dim Data() As Variant
Dim ValidRow, r, LRow As Integer
Sheets("Contract_BR_CONMaster").Select
LRow = Range("A1").End(xlDown).Row '151 total rows
Erase Data()
For r = 2 To LRow
If Cells(r, 3).Value <> "Bridge From" And Cells(r, 3).Value <> "Bridge To" Then
ValidRow = ValidRow + 1
ReDim Preserve Data(1 To LRow, 1 To 2)
Data(ValidRow, 1) = Range("A" & r).Value 'fills the array with col A
Data(ValidRow, 2) = Range("B" & r).Value 'fills the array with col B
End If
Next r
ActiveWorkbook.Worksheets("Test").Range("A2:B" & ValidRow + 1) = Data() 'assign after loop has run through all data and assessed it
End Sub

I seemed to have got this to work by using transposition where the rows and cols are swapped around and still using ReDim Preserve then transposing at the end when assigning to a range. This way the array is exactly the size it needs to be with no blank cells.
Sub FillArray3() 'Option 3 works using transposition where row and cols are swapped then swapped back at the end upon assignment to the range with no blank cells as array is sized incrementally via the For/Next loop
Dim Data() As Variant
Dim ValidRow, r, LRow As Integer
Sheets("Contract_BR_CONMaster").Select
LRow = Range("A1").End(xlDown).Row '151 total rows
Erase Data()
For r = 2 To LRow
If Cells(r, 3).Value <> "Bridge From" And Cells(r, 3).Value <> "Bridge To" Then
ValidRow = ValidRow + 1
ReDim Preserve Data(1 To 2, 1 To ValidRow) 'can change the size of only the last dimension if you use Preserve so swapped rows and cols around
Data(1, ValidRow) = Range("A" & r).Value 'fills the array with col A
Data(2, ValidRow) = Range("B" & r).Value 'fills the array with col B
End If
Next r
ActiveWorkbook.Worksheets("Test").Range("A2:B" & ValidRow + 1) = Application.Transpose(Data) 'swap rows and cols back
End Sub

Note also that the internal VBA implementation of REDIM is not guaranteeing to release the storage when it is sized down. It would be a common choice in such an implementation to not physically reduce the storage until the size dropped to less than half the input size.
Have you considered creating a type-safe collection class to store this information instead of an array? In it's most basic form (for a storage type of Integer) it would look be a Class Module like this:
Option Explicit
Private mData As Collection
Public Sub Add(Key As String, Data As Integer)
mData.Add Key, Data
End Sub
Public Property Get Count() As Integer
Count = mData.Count
End Property
Public Function Item(Index As Variant) As Integer
Item = mData.Item(Index)
End Function
Public Sub Remove(Item As Integer)
mData.Remove Item
End Sub
Private Sub Class_Initialize()
Set mData = New Collection
End Sub
A particular advantage of this implementation is that the sizing logic is completely removed from the client code, as it should be.
Note that the Data type stored by such a patter can be any type supported by VBA, including an Array or another Class.

Two more ways of doing this.
FillArray4 - Initial array is created too large but second part of code moves this to a new array using a double loop which creates the array to be the exact size it needs to be.
Sub FillArray4()
Dim Data() As Variant, Data2() As Variant
Dim ValidRow As Integer, r As Integer, lRow As Integer
Sheets("Contract_BR_CONMaster").Select
lRow = Range("A1").End(xlDown).Row '151 total rows
'Part I - array is bigger than it has to be
Erase Data()
For r = 2 To lRow
If Cells(r, 3).Value <> "Bridge From" And Cells(r, 3).Value <> "Bridge To" Then
ValidRow = ValidRow + 1 'this is the size the array needs to be 114 rows
ReDim Preserve Data(1 To lRow, 1 To 2) 'but makes array to be 151 rows as based on lrow not ValidRow as cannot dynamically resize 1st dim of array when using preserve
Data(ValidRow, 1) = Range("A" & r).Value 'fills the array with col A
Data(ValidRow, 2) = Range("B" & r).Value 'fills the array with col B
End If
Next r
'Part II
'move data from Data() array that is too big to new array Data2() that is perfectly sized as it uses ValidRow instead of lrow
Erase Data2()
For i = LBound(Data, 1) To UBound(Data, 1) 'Rows
For j = LBound(Data, 2) To UBound(Data, 2) 'Cols
If Not IsEmpty(Data(i, j)) Then
ReDim Preserve Data2(1 To ValidRow, 1 To 2)
Data2(i, j) = Data(i, j) 'fills the new array with data from original array but only non blank dims; Data2(i,j) is not one particular row or col its an intersection in the array
'as opposed to part one where you fill the initial array with data from cols A and B using seperate lines for each col
End If
Next
Next
ActiveWorkbook.Worksheets("Test").Range("A2:B" & ValidRow + 1) = Data2() 'assign data from new array to worksheet
End Sub
Sub FillArray5 - Much simpler and my preferred option as you only create one array. Initial loop determines the size the array needs to be and then second loop uses this to create array and store data. Note only two cols in both cases. Issue I had in this scenario was creating 2D array where rows varied. That's it for me time to go to the tropics for a well earned holiday!
Sub FillArray5()
Dim Data() As Variant
Dim ValidRow As Integer, r As Integer, lRow As Integer, DimCount As Integer, RemSpaceInArr As Integer
Sheets("Contract_BR_CONMaster").Select
lRow = Range("A1").End(xlDown).Row
Erase Data()
For r = 2 To lRow
If Cells(r, 3).Value <> "Bridge From" And Cells(r, 3).Value <> "Bridge To" Then
ValidRow = ValidRow + 1 'this is the size the array needs to be 114 rows
End If
Next r
DimCount = 0 'reset
For r = 2 To lRow
If Cells(r, 3).Value <> "Bridge From" And Cells(r, 3).Value <> "Bridge To" Then
ReDim Preserve Data(1 To ValidRow, 1 To 2) 'makes array exact size 114 rows using ValidRow from first loop above
DimCount = DimCount + 1 'need this otherwise ValidRow starts the dim at 114 but needs to start at 1 and increment to max of ValidRow
Data(DimCount, 1) = Range("A" & r).Value 'fills the array with col A
Data(DimCount, 2) = Range("B" & r).Value 'fills the array with col B
End If
Next r
RemSpaceInArr = ValidRow - DimCount 'just a check it should be 0
ActiveWorkbook.Worksheets("Test").Range("A2:B" & ValidRow + 1) = Data() 'assign data from array to worksheet
End Sub

Related

Performance of Excel Array and small VBA Loop vs. Big VBA Loop w/o Array

I've got two worksheets. The first (Calculation) contains 10.000 rows with a lot of RTD formulas and different calculations. The second (observer) observes the first one.
I've got a VBA script that runs every second and checks every row of worksheet 1 (Calculation). If the loop finds some marked data on worksheet 1 then it will copy some data from WS1 to WS2.
Solution 1: Loop checking 10.000 rows
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
For I = 1 To 10000
If CStr(.Cells(I, 1)) = "X" Then
'DO SOME SUFF (copy the line from WS 1 to WS2)
'Find first empty row
LR2 = WS2.Cells(15, 1).End(xlDown).Row + 1
'Copy data from WS1 to WS2
WS1.Range(.Cells(I, 1), .Cells(I, 14)).Copy
WS2.Cells(LR2, 1).PasteSpecial xlValues
End If
Next
Application.Calculation = xlCalculationAutomatic
Application.ScreenUpdating = True
Solution 2: Array function with a small loop
Can I use, instead of the 10.000 row loop, an Excel Array to observe the 10.000 rows and do some stuff with the smaller array.
On worksheet 2, I would have this code: (A1:O15)
{=index(Calculation!A$1:$O$10000; .....)....))}
Again I would have a smaller loop through the 15 lines of array function:
Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual
For K = 1 To 15
If CStr(.Cells(I, 1)) = "X" Then
'Find first empty row
LR2 = WS2.Cells(15, 1).End(xlDown).Row + 1
'Copy data from WS1 to WS2
WS1.Range(.Cells(I, 1), .Cells(I, 14)).Copy
WS2.Cells(LR2, 1).PasteSpecial xlValues
End If
Next
Application.Calculation = xlCalculationAutomatic
Application.ScreenUpdating = True
I would like to know what solution has the better performance.
I am not sure if an Excel array over 10.000 rows has a good performance. For sure the 15-rowLoop is faster than a 10000-row-Loop.
I don't know how to measure if a 15-row Loop in connection with an array (observing 10.000 rows) is faster.
Copy to Sheet With Criteria
Copies each row of a dataset in a worksheet containing a specified value (Criteria) in a specified column, to another worksheet.
Adjust the values in the constants section of createReport.
The data transfer will only (always) happen when the worksheet "Observer" is activated e.g. when another sheet is currently selected and the "Observer" tab is clicked on.
This code took about 5 seconds for a million (all) rows, and under a second for 100.000 rows on my machine.
The efficiency can further be improved by using the code with the Worksheet Change event in the "Calculation" worksheet and by turning off certain Application events (e.g. .ScreenUpdating, .Calculation, .EnableEvents).
Excel Test Setup (Worksheet "Calculation")
[A1:I1] ="Column "&COLUMN()
[A2] =IF(I2=1,"X","Y")
[B2:H2] =RANDBETWEEN(1,1000)
[I2] =RANDBETWEEN(1,100)
Sheet Module (Worksheet "Observer")
Option Explicit
Private Sub Worksheet_Activate()
createReport
End Sub
Standard Module e.g. Module1
Option Explicit
Sub createReport()
' Constants
' Source
Const srcName As String = "Calculation"
Const CriteriaColumn As Long = 1
Const Criteria As String = "X"
Const srcFirstCellAddress As String = "A1"
' Target
Const tgtName As String = "Observer"
Const tgtFirstCellAddress As String = "A1"
Const includeHeaders As Boolean = True
' Other
Dim wb As Workbook
Set wb = ThisWorkbook ' The workbook containing this code.
' Define Source Range ('rng').
' Define Source First Cell ('cel').
Dim cel As Range
Set cel = wb.Worksheets(srcName).Range(srcFirstCellAddress)
' Define the Current Region ('rng') 'around' First Cell.
Dim rng As Range
Set rng = cel.CurrentRegion
' Define Source Range ('rng') i.e. exclude cells to the left and above
' of Source First Cell from the Current Region.
Set rng = rng.Resize(rng.Rows.Count - cel.Row + rng.Row, _
rng.Columns.Count - cel.Column + rng.Column) _
.Offset(cel.Row - rng.Row, cel.Column - rng.Column)
' Write values from Source Range to Data Array ('Data').
Dim Data As Variant
Data = rng.Value
' Write resulting values from Data Array to Data Array
' i.e. 'shift' them to the beginning.
Dim NoC As Long ' Number of Columns
NoC = UBound(Data, 2)
Dim i As Long ' Source Data Rows Counter
Dim j As Long ' Source/Target Data Columns Counter
Dim CurrentRow As Long ' Target Data Rows Counter
Dim checkHeaders As Long
checkHeaders = -CLng(includeHeaders) ' True is '-1' in VBA.
CurrentRow = checkHeaders
For i = 1 To UBound(Data, 1)
If Data(i, CriteriaColumn) = Criteria Then
CurrentRow = CurrentRow + 1
For j = 1 To NoC
' 'Shift' from 'i' to 'CurrentRow'.
Data(CurrentRow, j) = Data(i, j)
Next j
End If
Next i
' Write values from Data Array to Target Range ('rng').
' Define Target First Cell ('cel').
Set cel = wb.Worksheets(tgtName).Range(tgtFirstCellAddress)
' Define Target First Row ('rng').
Set rng = cel.Resize(, NoC)
' Clear contents in columns.
rng.Resize(rng.Worksheet.Rows.Count - cel.Row + 1).ClearContents
Select Case CurrentRow
Case 0
GoTo CriteriaNotFound
Case checkHeaders
' Write headers from Data Array to Target Range.
rng.Resize(CurrentRow).Value = Data
GoTo CriteriaNotFound
Case Else
' Write values from Data Array to Target Range.
rng.Resize(CurrentRow).Value = Data
GoTo Success
End Select
' Exit.
ProcExit:
Exit Sub
' Inform user.
CriteriaNotFound:
MsgBox "Value '" & Criteria & "' not found.", vbExclamation, "Fail"
GoTo ProcExit
Success:
MsgBox CurrentRow - checkHeaders & " row(s) of data transferred.", _
vbInformation, "Success"
GoTo ProcExit
End Sub
Rather than going back to column A 10,000 times, bring all the values into a 1D VBA array and then loop over that array:
Sub whatever()
Dim rng As Range, arr
Set rng = Sheets("Calculation").Range("A1:A10000")
arr = WorksheetFunction.Transpose(rng)
For i = 1 To 10000
If arr(i) = "X" Then
'do some stuff
End If
Next i
End Sub
If there are very few X's then it may be nearly instantaneous.
EDIT#1:
Based on Chris Neilsen's comment, here is a version that does not use Transpose():
Sub whatever2()
Dim rng As Range, arr
Set rng = Sheets("Calculation").Range("A1:A10000")
arr = rng
For i = 1 To 10000
If arr(i, 1) = "X" Then
'do some stuff
End If
Next i
End Sub
Test the next code, please. It should be very fast, using arrays and everything happening in memory. The code assumes that you need to copy all occurrences starting with the last empty cell of WS2:
Sub CopyFromWS1ToWs2Array()
Dim WS1 As Worksheet, WS2 As Worksheet, lastRow As Long, searchStr As String
Dim LR2 As Long, arr1 As Variant, arr2 As Variant, i As Long, k As Long, j As Long
Set WS1 = ActiveSheet 'use here your necessary sheet
Set WS2 = WS1.Next 'use here your necessary sheet. I used this only for testing reason
lastRow = WS1.Range("A" & rows.count).End(xlUp).row 'last row of the first sheet
arr1 = WS1.Range("A1:N" & lastRow).Value 'put the range in an array
ReDim arr2(1 To UBound(arr1, 2), 1 To UBound(arr1)) 'redim the array to be returned
'columns and rows are reversed because
'only the second dimension can be Redim Preserve(d)
searchStr = "X" 'setting the search string
For i = 1 To UBound(arr1)
If arr1(i, 1) = searchStr Then
k = k + 1 'the array row is incremented (in fact, it is the column now...)
For j = 1 To UBound(arr1, 2)
arr2(j, k) = arr1(i, j) 'the row is loaded with all the necessary values
Next j
End If
Next i
'the final array is Redim, preserving only the existing values:
ReDim Preserve arr2(1 To UBound(arr1, 2), 1 To k)
LR2 = WS2.cells(rows.count, 1).End(xlUp).row + 1 'last empty row of the second worksheet
'Dropping the array content at once (the fastest way of copying):
WS2.Range("A" & LR2).Resize(UBound(arr2, 2), UBound(arr2)).Value = _
WorksheetFunction.Transpose(arr2)
WS2.Activate: WS2.Range("A" & LR2).Select
MsgBox "Ready...", vbInformation, "Job done"
End Sub
Edited:
Please, test the next code, which should also solve your last requests (as I understood them):
Sub CopyFromWS1ToWs2ArrayBis()
Dim WS1 As Worksheet, WS2 As Worksheet, lastRow As Long, searchStr As String
Dim LR2 As Long, arr1 As Variant, arr2 As Variant, arrWS2 As Variant
Dim i As Long, k As Long, j As Long, s As Long, boolFound As Boolean
Set WS1 = ActiveSheet 'use here your necessary sheet
Set WS2 = WS1.Next 'use here your necessary sheet. I used this only for testing reason
lastRow = WS1.Range("A" & rows.count).End(xlUp).row 'last row of the first sheet
LR2 = WS2.cells(rows.count, 1).End(xlUp).row 'last empty row of the second worksheet
arr1 = WS1.Range("A1:N" & lastRow).Value 'put the range of WS1 in an array
ReDim arr2(1 To UBound(arr1, 2), 1 To UBound(arr1)) 'redim the array to be returned
'columns and rows are reversed because
'only the second dimension can be Redim Preserve(d)
arrWS2 = WS2.Range("A1:N" & LR2).Value 'put the range of WS2 in an array
searchStr = "X" 'setting the search string
For i = 1 To UBound(arr1)
If arr1(i, 1) = searchStr Then
For s = 1 To UBound(arrWS2)
If arr1(i, 1) = arrWS2(s, 1) And arr1(i, 2) = arrWS2(s, 2) And _
arr1(i, 3) = arrWS2(s, 3) Then
boolFound = True: Exit For 'if first three array columns are the same
End If
Next s
If Not boolFound Then 'if first thrree array columns not the same:
k = k + 1 'the array row is incremented
For j = 1 To UBound(arr1, 2)
arr2(j, k) = arr1(i, j) 'the row is loaded with all the necessary values
Next j
'swap the columns 4 and 5 values:
If arr1(i, 4) = "ABC" And arr1(i, 5) = "XYZ" Then arr2(4, k) = "XYZ": arr2(5, k) = "ABC"
End If
boolFound = False 'reinitialize the boolean variable
End If
Next i
If k > 0 Then
'Preserving only the existing array elements:
ReDim Preserve arr2(1 To UBound(arr1, 2), 1 To k)
'Dropping the array content at once (the fastest way of copying):
WS2.Range("A" & LR2 + 1).Resize(UBound(arr2, 2), UBound(arr2)).Value = _
WorksheetFunction.Transpose(arr2)
WS2.Activate: WS2.Range("A" & LR2 + 1).Select
MsgBox "Ready...", vbInformation, "Job done"
Else
MsgBox "No any row to be copied!", vbInformation, "Nothing changed"
End If
End Sub

Storing data to array from worksheet

I'm trying to analyze some data from a worksheet, the first step was to find the last row, which I managed. Then I need to store the data in an array for each column to simplify further analysis.
My data looks like this:
I'm trying to store let's say the B column in an array but starting at B6:
Sub List_Rem_stock()
Dim array_Rem_Batch(1 To last_row_Rem_stock - 5) As Integer
For i = 1 To last_row_Rem_stock - 5
array_Rem_Batch(i) = Worksheets("Rem stock").Range(Bi)
Next i
Debug.Print array_Rem_Index
End Sub
last_row_Rem_stock represents the last row of the table.
Am I doing this properly?
Almost, try the code below (find explanation inside code's comments):
Option Explicit
Sub List_Rem_stock()
Dim last_row_Rem_stock As Long, i As Long
Dim array_Rem_Batch() As Long
With Worksheets("Rem stock")
last_row_Rem_stock = .Cells(.Rows.Count, "B").End(xlUp).Row ' get last row with value in colum B
ReDim array_Rem_Batch(1 To last_row_Rem_stock - 5) ' redim array size
For i = 1 To last_row_Rem_stock - 5
array_Rem_Batch(i) = .Range("B" & i).Value
Next i
End With
End Sub
You can allocate a range to an array (2D) as such:
Dim arrData as variant: arrData = Range("B1:B" & lastrow).
You can also put the array back on the spreadsheet the same way:
Range("B1:B" & lastrow) = arrData
Simple, easy and fast, without the need of iterating through data.
In your example, you would probably do it like this.
Sub List_Rem_stock()
Dim i As Long, last_row_Rem_stock As Long
Dim array_Rem_Batch As Variant
With Worksheets("Rem stock")
last_row_Rem_stock = .Cells(.Rows.Count, "B").End(xlUp).Row 'get last row in B
array_Rem_Batch = .Range("B1:B" & last_row_Rem_stock)
End With
For i = 6 To last_row_Rem_stock
Debug.Print array_Rem_Batch(i, 1)
Next i
End Sub
To note that arrays allocated this way will always start at 1, not 0.
EDIT:
I'm allocating the data starting at row 1, and not at row 6, purely for the nice 1:1 relation between array index and sheet rows. Is my prefered way, wherever the situation allows.
If array_Rem_Batch(i, 1) = Range("B" & i) Then ....
Can always allocate the data from any row you want:
array_Rem_Batch = Worksheets("Rem stock").Range("B6:B100") 'now the array has 95 rows.
In this case, array index 1, will corespond to row 6 in the sheet, and will have to manage this in the code if you need to something like this:
If array_Rem_Batch(i, 1) = Range("B" & i + 5) Then ....

Adjust Values As They Are Being Stored In VBA Array

I am trying to write Column A to an array and while passing into the array or when writing the array to the sheet, I would like to multiple each value stored by a set number (specifically .01). I will be writing the array back over the same column it was set from.
Ex.
Sheet before macro:
Col A Col B Col C
Header Header Header
100
50
50
40
100
Sheet after macro:
Col A Col B Col C
Header Header Header
1
.5
.5
.4
1
So far I have been working off a basic array portion of code from a tutorial I saw online shown below:
Sub ArrayTest
Dim Arr() As Variant
Arr = Range("A1:A6")
Dim R As Long
Dim C As Long
For R = 1 To UBound(Arr, 1) ' First array dimension is rows.
For C = 1 To UBound(Arr, 2) ' Second array dimension is columns.
Debug.Print Arr(R, C)
Next C
Next R
'resize range array will be written to
Dim Destination As Range
Set Destination = Range("K1")
Destination.Resize(UBound(Arr, 1), UBound(Arr, 2)).Value = Arr
'transpose / write array to range
Set Destination = Range("A1")
Destination.Resize(UBound(Arr, 2), UBound(Arr, 1)).Value = Application.Transpose(Arr)
End Sub
This code has no errors, but I'm unsure of where / how I can "manipulate" the values (either on the way into the array or on the way back to the sheet).
An array may not even be the best way to achieve this overall goal of overwriting a columns values with itself multiplied by a another number. I know I could write the column to a dummy sheet, do the calculation then move back over the original sheet and column, but I was trying to find something cleaner and potentially faster than that. This is also a simplified example, my actual data set is much larger and more variable, but for the ease of discussion I created this example.
Any advice is much appreciated!
Here's a "no loop" approach:
Sub Tester()
Dim arr, rngSrc As Range, sht As Worksheet
Set sht = ActiveSheet
Set rngSrc = sht.Range("A2:A6")
arr = rngSrc.Parent.Evaluate(rngSrc.Address() & " * 10") '<< returns an array
sht.Range("B2").Resize(UBound(arr, 1), UBound(arr, 2)).Value = arr
End Sub
For your specific case:
With Range("A2:A6")
.Value = .Parent.Evaluate(.Address & " * 0.01")
End With
You can do it like this, but easier to use pastespecial (multiply or divide).
Sub x()
Dim v As Variant, i As Long
v = Range("A2:A6").Value
For i = LBound(v) To UBound(v)
v(i, 1) = v(i, 1) * 0.01
Debug.Print v(i, 1)
Next i
Range("A2:A6").Value = v
End Sub
Was working on this as I saw Tim post... similar use of evaluate, but doesn't need an additional array or loop:
Dim rng As Range, lr As Long
lr = Cells(Rows.Count, 1).End(xlUp).Row
Set rng = Range(Cells(1, 1), Cells(lr, 1))
rng = Evaluate(rng.Address & "*0.01")
Perhaps you should collect the values first and process the adjustment(s) in memory.
dim i as long, arr as variant
with worksheets("sheet1")
arr = .range(.cells(2, "A"), .cells(.rows.count, "A").end(xlup)).value2
for i=lbound(arr, 1) to ubound(arr, 1)
arr(i, 1) = arr(i, 1)/100
next i
for i=lbound(arr, 1) to ubound(arr, 1)
debug.print arr(i, 1)
next i
.cells(1, "K").resize(ubound(arr, 1), ubound(arr, 2)) = arr
.cells(1, "L").resize(ubound(arr, 2), ubound(arr, 1)) = application.transpose(arr)
end with

Loop to replicate values into an array

I’m in a situation where I need to reproduce something in VBA and a bit stuck given my lack of understanding of object oriented language and VBA in general.
Problem:
I need to produce an array or vector based on a 2 column table.
The first range (column) contains unit counts.
The second range (column) contains numeric values.
I need to replicate the value based on the number of units.
For example,
if the first row contains 3 units with a value of $100
I need the array to contain $100, $100, $100.
This will need to be looped thru each row containing units.
So if row 2 contains 2 units with a value of $50
I need to complete array to be $100, $100, $100, $50, $50, and so on.
I understand this situation will require ReDim the array based on the total values. My struggle is I’ve been unable to figure out the nested for loops.
I get how to replicate the value based on the number of “units” like the below...
ReDim arr(0 To x - 1)
For i = 0 To x - 1
arr(i) = rng.Offset(0, 1).Value
Next
What is the best way to loop thru each row and replicate the values for each row in the range based on the unit count?
If anyone is familiar with R, I'm essentially looking for something that achieves the rep() function (e.g., rep(df$b, df$a)) and return the values in a single array.
Any help is greatly appreciated. Thanks
Or a one liner which uses the REPT function as you would have used in r :)
This assumes your data is in A1:B10 - the length can be made variable
s = Split(Join(Application.Transpose(Evaluate("=INDEx(REPT(B1:B10&"","",A1:A10),,1)"))), ",")
An an example, to dump the new to array to C1
s = Split(Join(Application.Transpose(Evaluate("=INDEx(REPT(B1:B10&"","",A1:A10),,1)"))), ",")
[c1].Resize(UBound(s), 1) = Application.Transpose(s)
When you say Row contains 3 units, do you mean the cell has value 3 or 3 Units? If it is 3 then you may not have to Redim the array in the loop. Simply find the sum of values in Col A which has units and Redim it in one go as shown below.
Sub Sample()
Dim ws As Worksheet
Dim Ar() As String
Dim n As Long, i As Long, lRow As Long
'~~> Change this to the relevant sheet
Set ws = Sheet6
With ws
n = Application.WorksheetFunction.Sum(.Columns(1))
ReDim Ar(t To n)
lRow = .Range("A" & .Rows.Count).End(xlUp).Row
n = 1
For i = 1 To lRow
If Len(Trim(.Range("A" & i).Value)) <> 0 Then
For j = 1 To .Range("A" & i).Value
Ar(n) = .Range("B" & i).Value
n = n + 1
Next j
End If
Next i
For i = LBound(Ar) To UBound(Ar)
Debug.Print Ar(i)
Next i
End With
End Sub
Screenshot
And if the cell has 3 Units then you will have to store the values of Col A in an array, do a replace on Unit/Units, find the sum and finally use the above code. Here is an example
Sub Sample()
Dim ws As Worksheet
Dim Ar() As String, tmpAr As Variant
Dim n As Long, i As Long, j As Long, k As Long, lRow As Long
'~~> Change this to the relevant sheet
Set ws = Sheet6
With ws
lRow = .Range("A" & .Rows.Count).End(xlUp).Row
tmpAr = .Range("A1:A" & lRow).Value
For i = LBound(tmpAr) To UBound(tmpAr)
tmpAr(i, 1) = Replace(tmpAr(i, 1), "Units", "")
tmpAr(i, 1) = Trim(Replace(tmpAr(i, 1), "Unit", ""))
n = n + Val(tmpAr(i, 1))
Next i
ReDim Ar(t To n)
n = 1
For i = 1 To lRow
If Len(Trim(.Range("A" & i).Value)) <> 0 Then
k = Val(Trim(Replace(Replace(.Range("A" & i).Value, "Units", ""), "Unit", "")))
For j = 1 To k
Ar(n) = .Range("B" & i).Value
n = n + 1
Next j
End If
Next i
For i = 1 To UBound(Ar)
Debug.Print Ar(i)
Next i
End With
End Sub
Screenshot
if your data is already in an array then ReDim'ing will delete it's contents. You can ReDim Preserve but it's an expensive operation, better to create a new array to put the results into.
I have assumed the data is contained within a Named Range called "Data" with Units being the first column and Values being the second column.
if your data changes regularly you can create a dynamic range using the OFFSET function i.e. =OFFSET(Sheet1!$A$1,0,0,COUNTA(Sheet1!$A:$A),2) assuming your data starts in cell A1 and there is no header row.
Sub ProcessData()
Dim DataArr() As Variant
Dim QtyColArr() As Variant
Dim ResultArr() As Variant
Dim TotalQty As Long
Dim i As Long, j As Long, k As Long
'store data into array
DataArr = Range("Data") 'assume data stored in named range called "Data"
'store Qty col into 1D array
QtyColArr = Range("Data").Resize(, 1)
'sum all qty vals
TotalQty = Application.Sum(QtyColArr)
're-size ResultsArray
ReDim ResultArr(1 To TotalQty)
'Initialize ResultsArr counter
k = LBound(ResultArr)
'loop DataArr
For i = LBound(DataArr) To UBound(DataArr)
'loop qty for current row
For j = 1 To DataArr(i, 1)
'copy value
ResultArr(k) = DataArr(i, 2)
'iterate ResultsArr counter
k = k + 1
Next j
Next i
'output to intermediate window
Debug.Print "{" & Join(ResultArr) & "}"
End Sub

Condensing Excel data with overlapping index/repetitive word occurrence

I have an excel sheet that is formatted like so:
I would like to format it to be something like this:
It is about 40,000 cells of information, so is there any way to do this that isn't manually?
You could probably use =SUMIF to achieve this, since you appear to have numbers as values.
Create a new sheet, copy column A from your data sheet to your new sheet and remove duplicates. Copy row 1 from your data sheet to your new sheet.
Use this formula in sheet 2 cell B2:
=SUMIF(Sheet1!$A:$A;Sheet2!$A2;Sheet1!B:B)
Drag the formula to the right, then down.
I am by no means an excel expert, and this is going to be my first answer ever. Take this into account please.
I've checked it and it works.
I've add a command button in Sheet1 (where the original data is), and when clicked this code writes formatted data into Sheet2.
No need to manually remove duplicates!
Dim dU1 As Object, cU1 As Variant, iU1 As Long, lrU As Long
Dim MyArray() As Variant
Dim i As Integer
Dim j As Integer
Dim k As Integer
Dim h As Integer
Private Sub CommandButton1_Click()
'Get unique indexes
Set dU1 = CreateObject("Scripting.Dictionary")
lrU = Cells(Rows.Count, 1).End(xlUp).Row 'number of rows
cU1 = Range("A2:A" & lrU) 'Assuming your data starts in A2
For iU1 = 1 To UBound(cU1, 1)
dU1(cU1(iU1, 1)) = 1
Next iU1
'Now dU1 contains indexes as unique values (about, absence, etc.)
For i = 0 To dU1.Count - 1 'for each index
ReDim MyArray(1 To 1) As Variant 'starts a "new" array
For j = 2 To 9 'each of the columns with values (D1-D8)
a = 0
For k = 2 To lrU 'all rows
If (Worksheets("Sheet1").Cells(k, 1).Value = dU1.keys()(i) And Worksheets("Sheet1").Cells(k, j).Value <> "") Then
MyArray(UBound(MyArray)) = Worksheets("Sheet1").Cells(k, j).Value 'add value to array
ReDim Preserve MyArray(1 To UBound(MyArray) + 1) As Variant 'resize array (now is 1 element longer)
a = a + 1
End If
Next
If a = 0 Then 'if no value found, add an element to array anyway
MyArray(UBound(MyArray)) = "" 'add value to array
ReDim Preserve MyArray(1 To UBound(MyArray) + 1) As Variant 'resize array (now is 1 element longer)
End If
Next
Worksheets("Sheet2").Cells(i + 2, 1) = dU1.keys()(i) 'write indexes in another sheet
For h = 2 To UBound(MyArray)
Worksheets("Sheet2").Cells(i + 2, h) = MyArray(h - 1)
Next
Next
End Sub

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