Calculate number of primary and secondary key columns - sql-server

Question

Is there a tool or query that will give me output as the total number of primary and secondary keys in a database table?
UPDATE ANSWER
Please note that secondary key is different from foreign key.
So count of no. of primary keys is possible in 2 ways:-
SELECT *
FROM sys.indexes i
INNER JOIN sys.tables t ON i.object_id = t.object_id AND
t.type = 'U'
LEFT JOIN sys.extended_properties AS EP ON EP.major_id = T.[object_id]
where is_primary_key=1
OR
SELECT COUNT(*) AS 'PRIMARY_KEY_CONSTRAINT'
FROM sys.objects
WHERE type_desc IN ('PRIMARY_KEY_CONSTRAINT')
To count no. of secondary keys use:
SELECT *
FROM sys.indexes i
INNER JOIN sys.tables t ON i.object_id = t.object_id AND
t.type = 'U'
LEFT JOIN sys.extended_properties AS EP ON EP.major_id = T.[object_id]
where is_unique=1 and is_primary_key=0

Answer 1

USE database
SELECT OBJECT_NAME(OBJECT_ID) AS NameofConstraint,
SCHEMA_NAME(schema_id) AS SchemaName,
OBJECT_NAME(parent_object_id) AS TableName
FROM sys.objects
WHERE type_desc IN ('PRIMARY_KEY_CONSTRAINT')
SELECT OBJECT_NAME(OBJECT_ID) AS NameofConstraint,
SCHEMA_NAME(schema_id) AS SchemaName,
OBJECT_NAME(parent_object_id) AS TableName
FROM sys.objects
WHERE type_desc IN ('FOREIGN_KEY_CONSTRAINT')
Simple count
SELECT COUNT(*) AS 'PRIMARY_KEY_CONSTRAINT'
FROM sys.objects
WHERE type_desc IN ('PRIMARY_KEY_CONSTRAINT')
SELECT COUNT(*) AS 'FOREIGN_KEY_CONSTRAINT'
FROM sys.objects
WHERE type_desc IN ('FOREIGN_KEY_CONSTRAINT')

Answer 2

The tool is SQL and this is another method to get what you want. A bit more complex then #kevchadders, but this way you can also make a listing of column names, types, etc
Count Foreign keys
SELECT count(*) from
INFORMATION_SCHEMA.TABLE_CONSTRAINTS Tab,
INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE Col
WHERE
Col.Constraint_Name = Tab.Constraint_Name
AND Col.Table_Name = Tab.Table_Name
AND Constraint_Type in ( 'FOREIGN KEY')
AND Col.Table_Name in (select name from sysobjects where xtype = 'U')
Count Pirmairy keys
SELECT count(*) from
INFORMATION_SCHEMA.TABLE_CONSTRAINTS Tab,
INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE Col
WHERE
Col.Constraint_Name = Tab.Constraint_Name
AND Col.Table_Name = Tab.Table_Name
AND Constraint_Type in ('PRIMARY KEY')
AND Col.Table_Name in (select name from sysobjects where xtype = 'U')
For all tables, show the PK and FK
FK
SELECT *, Col.Column_Name from
INFORMATION_SCHEMA.TABLE_CONSTRAINTS Tab,
INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE Col
WHERE
Col.Constraint_Name = Tab.Constraint_Name
AND Col.Table_Name = Tab.Table_Name
AND Constraint_Type in ('PRIMARY KEY', 'FOREIGN KEY')
AND Col.Table_Name in (select name from sysobjects where xtype = 'U')

Answer 3

You can try this
SELECT 'PRIMARY KEYS' AS KeyType, COUNT(*) AS Total
FROM sys.tables AS TB INNER JOIN
sys.key_constraints AS KC ON KC.parent_object_id = TB.object_id
GROUP BY KC.type
UNION
SELECT 'FOREIGN KEYS' AS KeyType, COUNT(*) AS Total
FROM sys.tables AS TB INNER JOIN
sys.foreign_keys AS FK ON FK.referenced_object_id = TB.object_id
GROUP BY FK.type