Sum of missing data - sql-server

Question

The below query displays sites against the total orders within last week.
But if there is no order for a given site in last week, i should still see the site with a sum of zero.
At the moment its only giving me four sites, thats because no order has been made in the last week for those sites.
select SITE
,SUM(Case When OrderDate >= dateadd(dd,(datediff(dd,-53690,getdate()-1)/7)*7,-53690)
Then 1
Else 0
End) as COMPLETED
from
(
SELECT DISTINCT ORDERS.SITE, ORDERS.ORDERDATE FROM ORDERS
INNER JOIN PHONEDATA AS P
ON ORDERS.RECID = P.OrderID
where SITE IN ('SITE1','SITE2','SITE3','SITE4','SITE5','SITE6','SITE7')
) X
GROUP BY SITE
order by SITE
RESULT:
Site---------------------Completed
SITE1-----------------------2
SITE2-----------------------2
SITE3-----------------------2
SITE4-----------------------2
EXPECTED RESULT:
Site---------------------Completed
SITE1-----------------------2
SITE2-----------------------2
SITE3-----------------------2
SITE4-----------------------2
SITE5-----------------------0
SITE6-----------------------0
SITE7-----------------------0
updated:
select SITE
,SUM(Case When OrderDate >= dateadd(dd,(datediff(dd,-53690,getdate()-1)/7)*7,-53690)
Then 1
Else 0
End) as COMPLETED
from
(
SELECT DISTINCT ORDERS.SITE, ORDERS.ORDERDATE FROM ORDERS
where SITE IN ('SITE1','SITE2','SITE3','SITE4','SITE5','SITE6','SITE7')
) X
GROUP BY SITE
order by SITE
I have now removed the inner join with phone data table, so i am now getting the missing sites. but the reason i avoided this approach is because if i only rely on the orders table the orderdate time field is inserted few times for a given order, and the final order makes it to the phonedata table, so now i get more values in completed count but it should only consider the latest value for each day for each site
result of update :
Site---------------------Completed
SITE1-----------------------5
SITE2-----------------------5
SITE3-----------------------5
SITE4-----------------------5
SITE5-----------------------0
SITE6-----------------------0
SITE7-----------------------0
expected
Site---------------------Completed
SITE1-----------------------2
SITE2-----------------------2
SITE3-----------------------2
SITE4-----------------------2
SITE5-----------------------0
SITE6-----------------------0
SITE7-----------------------0

Answer 1

If there are no rows in the table with the sites that have no orders, how can it return any rows to count? Perhaps you have a table with all the possible sites that can be joined to? Or create a temp table with the site values. You could then left join the orders table to this. i.e.
create table #sites (site varchar(25));
insert into #sites values ('SITE1','SITE2','SITE3','SITE4','SITE5','SITE6','SITE7');
...
from
(
SELECT DISTINCT ORDERS.SITE, ORDERS.ORDERDATE FROM
#sites s left join ORDERS on orders.site = s.site
INNER JOIN PHONEDATA AS P
ON ORDERS.RECID = P.OrderID
) X
...

Answer 2

Try using a left join instead of the inner join. It is probably not getting rows from the phone data table:
select SITE
,SUM(Case When OrderDate >= dateadd(dd,(datediff(dd,-53690,getdate()-1)/7)*7,-53690)
Then 1
Else 0
End) as COMPLETED
from
(
SELECT DISTINCT ORDERS.SITE, ORDERS.ORDERDATE FROM ORDERS
Left JOIN PHONEDATA AS P
ON ORDERS.RECID = P.OrderID
where SITE IN ('SITE1','SITE2','SITE3','SITE4','SITE5','SITE6','SITE7')
) X
GROUP BY SITE
order by SITE

Answer 3

It'd be best to start with a "Site" table and then left join to your results. This example mimics the behavior, and can be used as a hack-workaround.
DECLARE #table TABLE
(
site VARCHAR(10) ,
Completed TINYINT
)
INSERT INTO #table
( site, Completed )
VALUES ( 'SITE1', 0 ),
( 'SITE2', 0 ),
( 'SITE3', 0 ),
( 'SITE4', 0 ),
( 'SITE5', 0 ),
( 'SITE6', 0 ),
( 'SITE7', 0 )
WITH cte
AS ( SELECT SITE ,
SUM(CASE WHEN OrderDate >= DATEADD(dd,( DATEDIFF(dd, -53690, GETDATE() - 1) / 7 ) * 7, -53690)
THEN 1
ELSE 0
END) AS COMPLETED
FROM ( SELECT DISTINCT
ORDERS.SITE ,
ORDERS.ORDERDATE
FROM ORDERS
INNER JOIN PHONEDATA AS P ON ORDERS.RECID = P.OrderID
WHERE SITE IN ( 'SITE1', 'SITE2', 'SITE3',
'SITE4', 'SITE5', 'SITE6',
'SITE7' )
)
GROUP BY SITE
)
SELECT t.site ,
t.completed + cte.COMPLETED
FROM #table t
LEFT OUTER JOIN cte ON t.site = cte.Site
ORDER BY t.site