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I am trying to design a macro to search for multiple strings in an excel.
I have the following code which searches for the word "techno" in an excel but, I need to include a variable into the code so that I can search for multiple words such "Techno", "electromagnetic", "waves", etc. at once. I am unable to create a loop for this condition.
Can anyone suggest a solution to this problem? The below code works fine but, only a tweak is required to include multiple strings in the search.
Sub SearchFolders()
Dim xFso As Object
Dim xFld As Object
Dim xStrSearch As String
Dim xStrPath As String
Dim xStrFile As String
Dim xOut As Worksheet
Dim xWb As Workbook
Dim xWk As Worksheet
Dim xRow As Long
Dim xFound As Range
Dim xStrAddress As String
Dim xFileDialog As FileDialog
Dim xUpdate As Boolean
Dim xCount As Long
myArray = Array("techno", "magnetic", "laser", "trent")
On Error GoTo ErrHandler
Set xFileDialog = Application.FileDialog(msoFileDialogFolderPicker)
xFileDialog.AllowMultiSelect = False
xFileDialog.Title = "Select a forlder"
If xFileDialog.Show = -1 Then
xStrPath = xFileDialog.SelectedItems(1)
End If
If xStrPath = "" Then Exit Sub
xUpdate = Application.ScreenUpdating
Application.ScreenUpdating = False
Set xOut = Worksheets.Add
For myCounter = 0 To UBound(myArray)
MsgBox myCounter & " is the Count No."
xStrSearch = myArray(myCounter)
MsgBox xStrSearch & " is the Value fr String search"
xRow = 1
With xOut
.Cells(xRow, 1) = "Workbook"
.Cells(xRow, 2) = "Worksheet"
.Cells(xRow, 3) = "Cell"
.Cells(xRow, 4) = "Text in Cell"
Set xFso = CreateObject("Scripting.FileSystemObject")
Set xFld = xFso.GetFolder(xStrPath)
xStrFile = Dir(xStrPath & "*.xls*")
Do While xStrFile <> ""
Set xWb = Workbooks.Open(Filename:=xStrPath & "\" & xStrFile, UpdateLinks:=0, ReadOnly:=True, AddToMRU:=False)
For Each xWk In xWb.Worksheets
Set xFound = xWk.UsedRange.Find(xStrSearch)
MsgBox xFound & " is the strings found"
If Not xFound Is Nothing Then
xStrAddress = xFound.Address
End If
Do
If xFound Is Nothing Then
Exit Do
Else
xCount = xCount + 1
MsgBox xCount & " is the count of strings"
xRow = xRow + 1
.Cells(xRow, 1) = xWb.Name
.Cells(xRow, 2) = xWk.Name
.Cells(xRow, 3) = xFound.Address
.Cells(xRow, 4) = xFound.Value
End If
Set xFound = xWk.Cells.FindNext(After:=xFound)
MsgBox xFound & " next string"
MsgBox xStrAddress & " is the address "
MsgBox xFound.Address & " is the address found"
Loop While xStrAddress <> xFound.Address 'To check how xStrAddress is populated or do we need to declare it as a help from excel pointed out
myCounter = myCounter + 1
Next
xWb.Close (False)
xStrFile = Dir
Loop
.Columns("A:D").EntireColumn.AutoFit
End With
Next myCounter
MsgBox xCount & "cells have been found", ,
ExitHandler:
Set xOut = Nothing
Set xWk = Nothing
Set xWb = Nothing
Set xFld = Nothing
Set xFso = Nothing
Application.ScreenUpdating = xUpdate
Exit Sub
ErrHandler:
MsgBox Err.Description, vbExclamation
Resume ExitHandler
End Sub
If the strings you are searching will always be the same, hard code them into an array and Loop through the array elements to search each string, like so:
Dim myArray as Variant
Dim myCounter as Long
myArray = Array("techno", "electromagnetic", ...etc.)
For myCounter = 0 To UBound(myArray)
... 'your code here
xStrSearch = myArray(myCounter)
... 'the rest if your code here
Next myCounter
I have a 20x3 table on an excel sheet. Each of the three columns is labeled Date, Price, and Volume. I want to convert this data into a .txt file that contains an array of array, i.e an array containing twenty arrays, where each of the twenty arrays has the format [Date, price, volume]. The final array should have the format:
[[Date_0, Price_0, Volume_0], . . .,[Date_19, Price_19, Volume_19]].
I believe this can be done by writing a loop for each row and printing as an array.
This is a modification from the above that will take input as a range. It is capable of handling ranges with several areas (multiselection).
Public Sub writeRangeToFile(ByRef rng As Range, ByVal path As String)
Dim fso As Object, _
fOut As Object, _
rArea As Range, _
row As Integer, _
col As Integer
Set fso = CreateObject("Scripting.FileSystemObject")
Set fOut = fso.CreateTextFile(path, overwrite:=True, Unicode:=False)
With fOut
For Each rArea In rng.Areas '' iterate over areas of range, insures all are rects
fOut.Write "["
For row = 1 To rArea.Rows.Count Step 1
.Write IIf(row > 1, ",", "") & "["
For col = 1 To rArea.Columns.Count Step 1
.Write IIf(col > 1, ",", "") & rArea.Cells(row, col).Value
Next col
.Write "]"
Next row
.Write "]" & vbCrLf
Next rArea
.Close
End With
End Sub
Tester
This serves as a general test case, but I think you would want to use a named range in place of Selection in your case
Sub tester()
writeRangeToFile Selection, "C:\[your directory]\Test.txt"
End Sub
Output
Given the selection of
the tester function outputs
[[B2,C2,D2,E2,F2,G2],[B3,C3,D3,E3,F3,G3],[B4,C4,D4,E4,F4,G4],[B5,C5,D5,E5,F5,G5]]
[[M3,N3,O3,P3,Q3],[M4,N4,O4,P4,Q4],[M5,N5,O5,P5,Q5],[M6,N6,O6,P6,Q6],[M7,N7,O7,P7,Q7],[M8,N8,O8,P8,Q8]]
[[D10,E10,F10,G10,H10,I10,J10],[D11,E11,F11,G11,H11,I11,J11],[D12,E12,F12,G12,H12,I12,J12],[D13,E13,F13,G13,H13,I13,J13],[D14,E14,F14,G14,H14,I14,J14],[D15,E15,F15,G15,H15,I15,J15],[D16,E16,F16,G16,H16,I16,J16]]
[[Q15,R15,S15,T15],[Q16,R16,S16,T16],[Q17,R17,S17,T17],[Q18,R18,S18,T18],[Q19,R19,S19,T19],[Q20,R20,S20,T20]]
You can do this using the Open path For Output call, and then by iterating across the array in both directions.
Sub writeArrToFile(ByRef arr() As String, ByVal path As String)
Dim lOuter As Integer, _
uOuter As Integer, _
lInner As Integer, _
uInner As Integer
Open path For Output As #1
Let lOuter = LBound(arr(), 1)
Let uOuter = UBound(arr(), 1)
Let lInner = LBound(arr(), 2)
Let uInner = UBound(arr(), 2)
Print #1, "[";
For i = lOuter To uOuter
Print #1, IIf(i > lOuter, ",", ""); "[";
For j = lInner To uInner
Print #1, IIf(j > lInner, ",", ""); arr(i, j);
Next j
Print #1, "]";
Next i
Print #1, "]";
Close #1
End Sub
or you may achieve this by using a more modern, object oriented approach with
Sub writeArrToFile(ByRef arr() As String, ByVal path As String)
Dim fso As Object, _
fOut As Object, _
lInner As Integer, _
lOuter As Integer
Set fso = CreateObject("Scripting.FileSystemObject")
Set fOut = fso.CreateTextFile(path, overwrite:=True, Unicode:=False)
Let lInner = LBound(arr(), 2)
Let uInner = UBound(arr(), 2)
With fOut
.Write "["
For i = LBound(arr(), 1) To UBound(arr(), 1) Step 1
.Write IIf(i > lOuter, ",", "") & "["
For j = lInner To uInner
.Write IIf(j > lInner, ",", "") & arr(i, j)
Next j
.Write "]"
Next i
.Write "]"
.Close
End With
End Sub
Tester Function
You can test the above with this function. Modify the file path to designate where the subroutine should output.
Sub tester()
Dim arr(0 To 2, 0 To 2) As String
arr(0, 0) = "a"
arr(0, 1) = "b"
arr(0, 2) = "c"
arr(1, 0) = "d"
arr(1, 1) = "e"
arr(1, 2) = "f"
arr(2, 0) = "g"
arr(2, 1) = "h"
arr(2, 2) = "i"
writeArrToFile arr, "C:\[your directory]\Test.txt"
End Sub
Output
The above tester function outputs to "C:\[your directory]\Test.txt"
[[a,b,c],[d,e,f],[g,h,i]]
I am trying to visualize a 2D Matrix (Array) using a MsgBox, but the code I have doesn't give me the correct representation.
Sub test()
Dim M(22, 7) As Double
TwoD_Array_Matrix_In_MSGBOX (M)
End Sub
'_________________________________________________________________________
Public Function TwoD_Array_Matrix_In_MSGBOX(arr As Variant)
h = UBound(arr, 1)
w = UBound(arr, 2)
'MsgBox ("h = " & CStr(h + 1) & vbCrLf & "w = " & CStr(w + 1)) ' to check if the width and hight of the Matrix are correct
Dim msg As String
For i = 0 To w
For ii = 0 To h
msg = msg & arr(ii, i) & vbTab
Next ii
msg = msg & vbCrLf
Next i
MsgBox msg
End Function
This is the result I get:
You have w and h interchanged.
Dim msg As String
For i = 0 To h
For ii = 0 To w
msg = msg & arr(i, ii) & vbTab
Next ii
msg = msg & vbCrLf
Next i
MsgBox msg
this works perfectly for me
Private Sub this()
Dim this(22, 7) As Integer
Dim msg$
For i = LBound(this, 1) To UBound(this, 1)
For j = LBound(this, 2) To UBound(this, 2)
msg = msg & this(i, j) & vbTab
Next j
Next i
MsgBox msg
End Sub
It might be more flexible to write a function which returns a string, a sort of 2-dimensional join, which allows you to choose both the item delimiter (defaulting to vbTab) and the row delimiter (defaulting to vbCrLf).
You can MsgBox this string -- or write it to the immediate window -- or (with a comma chosen as one of the delimiters) -- write it to a CSV file, etc.:
Function MatrixJoin(M As Variant, Optional delim1 As String = vbTab, Optional delim2 As String = vbCrLf) As String
Dim i As Long, j As Long
Dim row As Variant, rows As Variant
ReDim rows(LBound(M, 1) To UBound(M, 1))
ReDim row(LBound(M, 2) To UBound(M, 2))
For i = LBound(M, 1) To UBound(M, 1)
For j = LBound(M, 2) To UBound(M, 2)
row(j) = M(i, j)
Next j
rows(i) = Join(row, delim1)
Next i
MatrixJoin = Join(rows, delim2)
End Function
Tested by:
Sub test()
Dim A As Variant
A = Range("A1:B3").Value
MsgBox MatrixJoin(A)
Debug.Print MatrixJoin(A, ",", ";")
End Sub
Screenshots of output:
Ubound can return the max index value of an array, but in a multidimensional array, how would I specify WHICH dimension I want the max index of?
For example
Dim arr(1 to 4, 1 to 3) As Variant
In this 4x3 array, how would I have Ubound return 4, and how would I have Ubound return 3?
ubound(arr, 1)
and
ubound(arr, 2)
You need to deal with the optional Rank parameter of UBound.
Dim arr(1 To 4, 1 To 3) As Variant
Debug.Print UBound(arr, 1) '◄ returns 4
Debug.Print UBound(arr, 2) '◄ returns 3
More at: UBound Function (Visual Basic)
[This is a late answer addressing the title of the question (since that is what people would encounter when searching) rather than the specifics of OP's question which has already been answered adequately]
Ubound is a bit fragile in that it provides no way to know how many dimensions an array has. You can use error trapping to determine the full layout of an array. The following returns a collection of arrays, one for each dimension. The count property can be used to determine the number of dimensions and their lower and upper bounds can be extracted as needed:
Function Bounds(A As Variant) As Collection
Dim C As New Collection
Dim v As Variant, i As Long
On Error GoTo exit_function
i = 1
Do While True
v = Array(LBound(A, i), UBound(A, i))
C.Add v
i = i + 1
Loop
exit_function:
Set Bounds = C
End Function
Used like this:
Sub test()
Dim i As Long
Dim A(1 To 10, 1 To 5, 4 To 10) As Integer
Dim B(1 To 5) As Variant
Dim C As Variant
Dim sizes As Collection
Set sizes = Bounds(A)
Debug.Print "A has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(B)
Debug.Print vbCrLf & "B has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(C)
Debug.Print vbCrLf & "C has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
End Sub
Output:
A has 3 dimensions:
1 to 10
1 to 5
4 to 10
B has 1 dimensions:
1 to 5
C has 0 dimensions:
UBound(myArray, 1) returns the number of rows in 2d array
UBound(myArray, 2) returns the number of columns in 2d array
However, let's go 1 step further and assume that you need the last row and last column of range, that has been written as a 2d array. That row (or column) should be converted to a 1d array. E.g. if our 2d array looks like this:
Then running the code below, will give you 2 1D arrays, that are the last column and last row:
Sub PrintMultidimensionalArrayExample()
Dim myRange As Range: Set myRange = Range("a1").CurrentRegion
Dim myArray As Variant: myArray = myRange
Dim lastRowArray As Variant: lastRowArray = GetRowFromMdArray(myArray, UBound(myArray, 1))
Dim lastColumnArray As Variant
lastColumnArray = GetColumnFromMdArray(myArray, UBound(myArray, 2))
End Sub
Function GetColumnFromMdArray(myArray As Variant, myCol As Long) As Variant
'returning a column from multidimensional array
'the returned array is 0-based, but the 0th element is Empty.
Dim i As Long
Dim result As Variant
Dim size As Long: size = UBound(myArray, 1)
ReDim result(size)
For i = LBound(myArray, 1) To UBound(myArray, 1)
result(i) = myArray(i, myCol)
Next
GetColumnFromMdArray = result
End Function
Function GetRowFromMdArray(myArray As Variant, myRow As Long) As Variant
'returning a row from multidimensional array
'the returned array is 0-based, but the 0th element is Empty.
Dim i As Long
Dim result As Variant
Dim size As Long: size = UBound(myArray, 2)
ReDim result(size)
For i = LBound(myArray, 2) To UBound(myArray, 2)
result(i) = myArray(myRow, i)
Next
GetRowFromMdArray = result
End Function
In addition to the already excellent answers, also consider this function to retrieve both the number of dimensions and their bounds, which is similar to John's answer, but works and looks a little differently:
Function sizeOfArray(arr As Variant) As String
Dim str As String
Dim numDim As Integer
numDim = NumberOfArrayDimensions(arr)
str = "Array"
For i = 1 To numDim
str = str & "(" & LBound(arr, i) & " To " & UBound(arr, i)
If Not i = numDim Then
str = str & ", "
Else
str = str & ")"
End If
Next i
sizeOfArray = str
End Function
Private Function NumberOfArrayDimensions(arr As Variant) As Integer
' By Chip Pearson
' http://www.cpearson.com/excel/vbaarrays.htm
Dim Ndx As Integer
Dim Res As Integer
On Error Resume Next
' Loop, increasing the dimension index Ndx, until an error occurs.
' An error will occur when Ndx exceeds the number of dimension
' in the array. Return Ndx - 1.
Do
Ndx = Ndx + 1
Res = UBound(arr, Ndx)
Loop Until Err.Number <> 0
NumberOfArrayDimensions = Ndx - 1
End Function
Example usage:
Sub arrSizeTester()
Dim arr(1 To 2, 3 To 22, 2 To 9, 12 To 18) As Variant
Debug.Print sizeOfArray(arr())
End Sub
And its output:
Array(1 To 2, 3 To 22, 2 To 9, 12 To 18)
Looping D3 ways;
Sub SearchArray()
Dim arr(3, 2) As Variant
arr(0, 0) = "A"
arr(0, 1) = "1"
arr(0, 2) = "w"
arr(1, 0) = "B"
arr(1, 1) = "2"
arr(1, 2) = "x"
arr(2, 0) = "C"
arr(2, 1) = "3"
arr(2, 2) = "y"
arr(3, 0) = "D"
arr(3, 1) = "4"
arr(3, 2) = "z"
Debug.Print "Loop Dimension 1"
For i = 0 To UBound(arr, 1)
Debug.Print "arr(" & i & ", 0) is " & arr(i, 0)
Next i
Debug.Print ""
Debug.Print "Loop Dimension 2"
For j = 0 To UBound(arr, 2)
Debug.Print "arr(0, " & j & ") is " & arr(0, j)
Next j
Debug.Print ""
Debug.Print "Loop Dimension 1 and 2"
For i = 0 To UBound(arr, 1)
For j = 0 To UBound(arr, 2)
Debug.Print "arr(" & i & ", " & j & ") is " & arr(i, j)
Next j
Next i
Debug.Print ""
End Sub
If I declare a dynamic sized array like this
Dim myArray()
Then how I can get in the code if this array is empty or it contains elements?
I tried with IsArray(myArray) function that give me always True,
otherwise if I try with UBound(myArray) function, I get an error.
Any ideas? thanks in advance,
Max
After declaring the array, you have to initialize it:
Dim myArray()
ReDim myArray(-1)
Then such code will always work:
If UBound(myArray)<0 Then
'array is empty....
Else
'array not empty....
End If
Edit: as you can't initialize the array, here is longer way to check if it's empty or not:
Dim x, myCount
myCount = 0
If IsArray(myArray) Then
For Each x In myArray
myCount = myCount + 1
Next
End If
If myCount=0 Then
'array is empty....
Else
'array not empty....
End If
First some notes.
Using Dim A() is not so practical in VBScript, better use ReDim
A(n).
For example ReDim A(-1) is also empty array (no elements) but initialized.
And as the best way coders to talk is by examples...
Dim a(), b(0), c
c = Array(a, b)
ReDim d(-1)
WScript.Echo "Testing HasBound:"
WScript.Echo "a = " & HasBound(a) & ",", _
"b = " & HasBound(b) & ",", _
"c = " & HasBound(c) & ",", _
"d = " & HasBound(d)
WScript.Echo "Testing HasItems:"
WScript.Echo "a = " & HasItems(a) & ",", _
"b = " & HasItems(b) & ",", _
"c = " & HasItems(c) & ",", _
"d = " & HasItems(d)
'> Testing HasBound:
'> a = False, b = True, c = True, d = True
'> Testing HasItems:
'> a = False, b = True, c = True, d = False
Function HasBound(anyArray)
On Error Resume Next
HasBound = UBound(anyArray)
HasBound = (0 = Err)
On Error Goto 0
End Function
Function HasItems(anyArray)
For Each HasItems In anyArray
HasItems = 1
Exit For
Next
HasItems = (HasItems > 0)
End Function
As you see, 2 functions with different purpose. The difference is visible on array d which "has-boundary" but "has-not-items".
I found a solution, I wrote a specific function to check if an array is null or not; the function doesn't check if it has elements inside but only if the array is declared as dynamic without dimensions and no elements.
Dim dynamic_array() 'array without a dimension
Dim empty_array(0) 'array with a dimension but without an element inside
Dim full_array(0) : full_array(0) = "max" 'array with a dimension and with an element inside
Function IsNullArray(input_array)
On Error Resume Next
Dim is_null : is_null = UBound(input_array)
If Err.Number = 0 Then
is_null = False
Else
is_null = True
End If
IsNullArray = is_null
End Function
If IsNullArray(dynamic_array) Then
Response.Write("<p>dynamic array not 'ReDimed'</p>")
End If
If Not IsNullArray(empty_array) Then
Response.Write("<p>" & UBound(empty_array) & "</p>") 'return the last index of the array
End If
If Not IsNullArray(full_array) Then
Response.Write("<p>" & full_array(UBound(full_array)) & "</p>") 'return the value of the last element of the array
End If
The one thing I can think of right now is:
On Error resume next
if UBound(myArray) < 0 then response.write "Empty array" end if
EDIT: Max's comment
I've always checked for UBound = 0 and the first element is empty too:
If UBound(myArray) = 0 Then
if myArray(0) = "" then ''Depending on the type of the array
''array is empty....
End If
End If