Function Does nothing - c

Question

I can't make the function mostrarmatriz() work. The program does compile and run from beginning to end without errors, but the function mostrarmatriz() doesn't show up anything. When I copy that function into the main function it works perfectly. It seems I'm having a problem passing the values by reference. Please help, I'm stuck.
Main.c File:
#include "InvMatriz.h"
#include <stdio.h>
int main(int argc, char **argv)
{
float **A;
int n;
printf("Ingrese el tamaño de la matriz: ");
scanf("%d", &n);
A = ingresematriz(n);
void mostrarmatriz(A, n);
printf("adfasd");
return 0;
}
Header File InvMatriz.h
#ifndef INVMATRIZ_H_
#define INVMATRIZ_H_
float** ingresematriz(int );
void mostrarmatriz(float**X ,int x);
#endif // INVMATRIZ_H
Ingrese Matriz.c File
#include "InvMatriz.h"
#include <stdio.h>
float **ingresematriz(int n)
{
int i, j;
//Asigna espacio en la memoria
float **A;
A = malloc(n * sizeof (float *));
for (i = 0; i < n; i++)
{
*(A + i) = malloc(n * sizeof(float));
}
//Pide los elementos y los guarda
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
printf("Elemento [%d] [%d]: ", i + 1, j + 1);
scanf("%f", *(A + i) + j);
}
}
return A;
}
Mostrar Matriz.c File
#include "InvMatriz.h"
#include <stdio.h>
void mostrarmatriz(float **X , int x) //Porque no hace nada pero si compila?
{
int i, j;
for (i = 0; i < x; i++)
{
for (j = 0; j < x; j++)
{
printf("%f ", *(*(X + i) + j));
}
printf("\n");
}
}

Answer 1

The line
void mostrarmatriz(A,n);
does not call mostrarmatriz, but it declares a function void mostrarmatriz(int,int) (the int type for the arguments is the old "implicit int" rule). Remove the void in that line, and your function will be called.
If you compiled your code with warnings, your compiler would have told you.