Convert Ascii to Binary - c

Question

I am writing a program where I need to convert Ascii characters to binary and then do a count. I have gotten my code working but it is printing additional information and not necessarily the correct binary. Below is my code as well as the output for a given set of characters. Any assistance would be greatly appreciated!
#include <stdio.h>
#include <stdlib.h>
void binaryPrinter(int digEnd, int value, int * noOfOnes);
void print(char c);
int charToInt(char c)
{
return (int) c;
}
int main()
{
char value;
int result = 1;
while(result != EOF)
{
result = scanf("%c", &value);
if(result != EOF)
{
print(value);
}
}
}
void binaryPrinter(int digEnd, int value, int * noOfOnes)
{
if(value & 1)
{
(*noOfOnes) = (*noOfOnes) + 1;
value = value >> 1;
digEnd--;
printf("1");
}
else
{
value = value >> 1;
digEnd--;
printf("0");
}
if(digEnd == 0)
return;
else
binaryPrinter(digEnd, value, noOfOnes);
}
void print(char c)
{
int count = 0;
printf("The character %c =", c);
binaryPrinter(8, charToInt(c), &count);
printf(" 1's = %d\n", count);
}

Answer 1

Here's a pair of functions:
void printCharAsBinary(char c) {
int i;
for(i = 0; i < 8; i++){
printf("%d", (c >> i) & 0x1);
}
}
void printStringAsBinary(char* s){
for(; *s; s++){
printCharAsBinary(*s);
printf(" ");
}
printf("\n");
}
You can see them in action here: http://ideone.com/3mEVbE. They work by masking out a single bit of each character and printing one at a time.