there is a column comment_id of a table called pic_alb_love which i'd like to add to the query below but i don't know how. Actually what i want to do is to count the total comment_id of the table pic_alb_love.
SELECT users_pics.wardrobe,
profile.fname,
users_pics.pic,
users_pics.u_pic_id,
users_pics.email,
users_pics.make,
users_pics.designer,
photo_comment.comment,
max_photo_comment.count_pic_id
FROM dbo.users_pics
INNER JOIN profile
ON users_pics.email = profile.email
LEFT Join (SELECT pic_id
,MAX(comment_id) max_comment_id
,COUNT(pic_id) count_pic_id
FROM photo_comment
GROUP BY pic_id
) max_photo_comment
On users_pics.u_pic_id = max_photo_comment.pic_id
LEFT Join photo_comment
On max_photo_comment.pic_id = photo_comment.pic_id
AND max_photo_comment.max_comment_id = photo_comment.comment_id
WHERE users_pics.wardrobe = MMColParam
AND users_pics.email = MMColParam2
ORDER BY u_pic_id asc
these are the various fields of the table pic_alb_love:
(comment_id,pic,love_com, wardrobe, email
,com_name,resp_email, play_count, com_stat)
LEFT JOIN (SELECT Pic
,Count(*) [CommentCount]
FROM pic_alb_love
GROUP BY Pic) c
ON c.Pic=u_pic_id
Assuming that pic_alb_love.pic is the FK on the table...
Use [CommentCount] in the select list.
Related
I have 3 tables in that 2 tables are master table and 3rd is transaction table. i need to get count from transaction table for each value in other two table without loosing rows in mater table
i need result like below
Table layout for understanding
This is the code i have tried,
select s.status_name, e.machine_group_name, qty = COALESCE(COUNT(e.id),0)
from tbl_status s
left outer JOIN tbl_transaction as e ON e.status_name = s.status_name
group by e.machine_group_name, s.status_name
This is solution i have figured:
select m.machine_group_name, s.status_name, qty = COUNT(e.id) from
tbl_machine_group as m
cross join tbl_status as s
left outer join tbl_transaction as e on e.status_name = s.status_name
and e.machine_group_name = m.machine_group_name
group by m.machine_group_name, s.status_name
order by machine_group_name
select
MC_Group_Name
,Status_Name
,count(1) as [Count of Transaction]
from
tbl_Transaction tbl_3
left join tbl_Machine_Group tbl_1
on tbl_3.MC_Group_Name = tbl_1.MC_Group_Name
left join tbl_Status tbl_2
on tbl_3.Status_Name = tbl_2.Status_Name
group by
MC_Group_Name
,Status_Name
I am trying to run a SELECT query using LEFT JOIN. I get a COUNT on my second table ( the table on the right side of LEFT JOIN ). This process becomes slightly heavy as the number of records on the second table goes up. My first and second table have a one-to-many relationship. The second table's CampaignId column is a foreign key to the first table's Id. This is a simplified version of my query:
SELECT a.[Id]
,a.CampaignId
,a.[Inserted] AS 'Date'
,COUNT(b.Id) AS 'Received'
FROM [CampaignRun] AS a
LEFT JOIN [CampaignRecipient] AS b
ON a.Id = b.CampaignRunId
GROUP BY
a.[Id], a.CampaignId,a.[Inserted]
HAVING
a.CampaignId = 637
ORDER BY
a.[Inserted] DESC
The number 637 is an example for one the records only.
Is there a way to make this query run faster?
Use a sub-select to calculate Received:
SELECT a.[Id]
,a.CampaignId
,a.[Inserted] AS 'Date'
, (SELECT COUNT(*) FROM [CampaignRecipient] AS b
WHERE a.Id = b.CampaignRunId ) AS 'Received'
FROM [CampaignRun] AS a
WHERE a.CampaignId = 637
ORDER BY a.[Inserted] DESC
You have unneed HAVING clause here, which you can move to WHERE clause
SELECT a.[Id]
,a.CampaignId
,a.[Inserted] AS 'Date'
,COUNT(b.Id) AS 'Received'
FROM [CampaignRun] AS a
LEFT JOIN [CampaignRecipient] AS b
ON a.Id = b.CampaignRunId
WHERE a.CampaignId = 637
GROUP BY a.[Id], a.CampaignId,a.[Inserted]
ORDER BY a.[Inserted] DESC
Also ensure that you have index on foreign key in [CampaignRecipient] table on CampaignRunId column. It's considered a good practice.
I have an existing proc which I have chopped up for brevity's sake
SELECT col1, col2
FROM (
col1, col2
SELECT col3--aggregate columns
FROM iep i
INNER JOIN student s ON s.studentID = i.studentID
INNER JOIN dbo.IDuration id ON i.IepID = id.iepID
INNER JOIN AppointmentStudent as ON s.studentID = as.studentID
INNER JOIN Appointment a ON as.appointmentID = a.appointmentID
INNER JOIN AppointmentTherapist at ON a.appointmentID = at.appointmentID
WHERE s.studentID = #studentID
GROUP BY col1, col2
) t
The aggregate columns summarizes appointments into the weeks of the year, but it only does sos for the weeks the student had appointments. I have an additional table called SchoolWeekYear that is populated with all of the weeks of the year that I am trying to integrate to this proc so I get 52 records back and not just the handful I am currently getting.
SELECT col1, col2
FROM (
col1, col2
SELECT col3--aggregate columns
FROM iep i
INNER JOIN student s ON s.studentID = i.studentID
INNER JOIN dbo.IDuration id ON i.IepID = id.iepID
INNER JOIN AppointmentStudent as ON s.studentID = as.studentID
INNER JOIN Appointment a ON as.appointmentID = a.appointmentID
LEFT OUTER JOIN SchoolWeekYear swy on a.calWeekNumber = swy.calWeekNumber
INNER JOIN AppointmentTherapist at ON a.appointmentID = at.appointmentID
WHERE s.studentID = #studentID
GROUP BY col1, col2
) t
Is this possible?
You need to integrate SchoolWeekYear into the existing table set at an earlier stage.
To show you the principle, let us simplify the problem even further. Let there be a table called WeeklyData with columns WeekNumber and SomeData. Some weeks might have multiple entries, some others none. So this query
SELECT
WeekNumber,
AGG(SomeData)
FROM
WeeklyData
GROUP BY
WeekNumber
;
would return only weeks present in WeeklyData. If you want to return data for all weeks, use a corresponding reference table (let it be called AllWeeks) like this:
SELECT
aw.WeekNumber,
AGG(wd.SomeData)
FROM
AllWeeks AS aw
LEFT JOIN
WeeklyData AS wd ON aw.WeekNumber = wd.WeekNumber
GROUP BY
aw.WeekNumber
;
So, you take the reference table (AllWeeks) and join the data table (WeeklyData) to it, not the other round.
Now, what if the original query was slightly more complex? Let us now suppose the data table is called StudentWeeklyData and has a column called StudentID which is a reference to a Students table. Let us also imagine the query is similar to yours in that it logically includes the Students table before the data table is joined and filters the results on the primary key of Students:
SELECT
s.StudentID,
s.StudentName,
swd.WeekNumber,
AGG(swd.SomeData)
FROM
Students AS s
INNER JOIN
StudentWeeklyData AS swd ON s.StudentID = swd.StudentID
WHERE
s.StudentID = #StudentID
GROUP BY
s.StudentID,
s.StudentName,
swd.WeekNumber
;
(Not every detail matters here, I just wanted to use a more similar example for you that would still be simple enough to understand.) Again, this would return only weeks where the specified student has data in StudentWeeklyTable. If you wanted to return all weeks for the student (some of them potentially empty, of course), this is how you could go about it:
SELECT
s.StudentID,
s.StudentName,
aw.WeekNumber,
AGG(swd.SomeData)
FROM
Students AS s
CROSS JOIN
AllWeeks AS aw
LEFT JOIN
StudentWeeklyData AS swd ON s.StudentID = swd.StudentID
AND aw.WeekNumber = swd.WeekNumber
WHERE
s.StudentID = #StudentID
GROUP BY
s.StudentID,
s.StudentName,
aw.WeekNumber
;
Here you can see again that the AllWeeks table is included before the data table. The difference to the previous case is we are not left-joining the result of the join between Students and StudentWeekly to AllWeeks, nor are we left-joining the data table itself specifically to AllWeeks. Instead, the data table is joined to the result of a cross join, Students × AllWeeks.
Returning to your specific situation, I realise that in your case even more tables are involved. Since you are not specifying how all those tables are related to one another, I can only guess that SchoolWeekYear should be cross-joined somewhere after FROM and before this line:
INNER JOIN Appointment a ON as.appointmentID = a.appointmentID
and that the said line should be modified like this:
LEFT JOIN Appointment a ON as.appointmentID = a.appointmentID
AND swy.calWeekNumber = a.calWeekNumber
the swy being an alias assigned to SchoolWeekYear.
It is also worth noting that there is a subsequent inner join with AppointmentTherapist. That join would eliminate the effect of the above left join if it remained unchanged, because its condition references the Appointment table. Perhaps, the syntactically easiest way to fix the issue would be to change that inner join to a left one too, although there is another way: instead of
LEFT JOIN Appointment a ON as.appointmentID = a.appointmentID
AND swy.calWeekNumber = a.calWeekNumber
LEFT JOIN AppointmentTherapist at ON a.appointmentID = at.appointmentID
you could use this syntax:
LEFT JOIN
Appointment a
INNER JOIN AppointmentTherapist at ON a.appointmentID = at.appointmentID
ON as.appointmentID = a.appointmentID
AND swy.calWeekNumber = a.calWeekNumber
That way the logical order of joining would be changed: Appointment and AppointmentTherapist would be first inner-joined with each other, then the result set would be outer-joined to the result of the previously specified joins.
It is possible. But if you have multiple row with some calWeekNumber on the SchoolWeekYear table, your aggregate function return wrong result.
If you want all lines in SchoolWeekYear shown, regardless of a match, you should use RIGHT OUTER JOIN instead of LEFT.
I have 3 Tables
News (News_ID,Title,Article,Attatchment,Publish_Status,Sort_Order,Date,Read_Status)
Category (Category_ID,Category_Name,Parent)
News_Category(ID,News_ID,Category_ID)
I want to select top 4 records from table News whose Category_ID in News_Category table is 12 and also whose Parent in category table is 12.
I have used following query:-
SELECT DISTINCT
News.News_ID, News.Title, News.Article, News.Attatchment, News.Publish_Status, News.Sort_Order, News.Read_Status, News.[Date]
,News_Category.ID
,Category.Category_Name
FROM News
INNER JOIN News_Category ON News_Category.News_ID = News.News_ID
INNER JOIN Category ON News_Category.Category = Category.Category_ID
WHERE News_Category.Category in
( select Category_ID
from Category
where Category_ID=12
union
select Category_ID
from Category
where Parent=12 )
ORDER BY News.News_ID DESC
But when i insert a single news in two Category having Parent=12 then it is showing duplicate data.Please help me.
Leaving out the News_Category.ID should fix it I believe.
SELECT DISTINCT
News.News_ID, News.Title, News.Article, News.Attatchment, News.Publish_Status, News.Sort_Order, News.Read_Status, News.[Date]
,Category.Category_Name
FROM News
INNER JOIN News_Category ON News_Category.News_ID = News.News_ID
INNER JOIN Category ON News_Category.Category = Category.Category_ID
WHERE News_Category.Category in
( select Category_ID
from Category
where Category_ID=12
or Parent=12 )
ORDER BY News.News_ID DESC
I need to select a random record from 3 tables and ensure I am ordering by photoOrder
Select TOP 1(a.id), a.mls_number, a.parcel_name, a.property_type, a.ownership_type, b.filename, b.photoOrder, c.county_Name
From property as a
Inner JOIN
listingPhotos as b on a.id = b.ListingID
LEFT JOIN
counties as C on a.county_name = c.id
WHERE a.isCommercial = 'True'
Order By NEWID()
So this query works, but I need to ensure that the b.filename record is ordered by b.photoOrder and thus the b.photoOrder should always be 1.
The b table (listing photos) has multiple photo files per property and I need to only select the photo that is 1st in the photo order.
Thanks
You could subquery your listingPhotos table and limit to WHERE PhotoOrder = 1:
Select TOP 1(a.id), a.mls_number, a.parcel_name, a.property_type, a.ownership_type, b.filename, b.photoOrder, c.county_Name
From property as a
Inner JOIN
(SELECT ListingID , filename, PhotoOrder FROM listingPhotos WHERE PhotoORder = 1
) as b on a.id = b.ListingID
LEFT JOIN
counties as C on a.county_name = c.id
WHERE a.isCommercial = 'True'
Order By NEWID()