I have this Camel Route:
<route id="externalRestPushRoute">
<from uri="jms:pushProcessedRecordsToExternal" />
<setHeader headerName="PAYLOAD">
<simple>body</simple>
</setHeader>
<marshal ref="jack"></marshal>
<to uri="http://localhost/front/rest/karec/dummy-push"/>
<transform>
<simple>in.header[PAYLOAD]</simple>
</transform>
<to uri="bean:noAuthRecordPersistenceService?method=deliverySuccess" />
</route>
The idea is this:
I want to deliver an object in JSON format to a REST endpoint(all the headers are properly set and the rest endpoint receives the json format)/
To convert the object to JSON format I use marshal and it works.
Now, the response back from the http endpoint is of type java.io.InputStream but I don't care.
What I care is converting the body back to the original object before it was marshaled.
I did save the object in a header before marshaling in a header named PAYLOAD.
Now I want to use transform to get it back into the body of the message.
Well, that does not seem to work. When it get to the last bean it complains that body is still of type java.io.InputStream.
Stores the body on the exchange property instead of a header, that is safer.
<setProperty propertyName="PAYLOAD">
<simple>body</simple>
</setProperty>
<transform>
<simple>${property.PAYLOAD}</simple>
</transform>
Related
Is there a Camel unmarshaler that I could use to unmarshal from multiple data formats (JSON, XML, etc) to, say XML?
This "universal" unmarshaller would then be used as, for example:
<route id="myRoute">
<from uri="file:test/input"/>
<!-- The input can be in JSON or in XML -->
<unmarshal ref="universalUnmarshallerToXML"/>
<!-- The input payload is always in XML -->
<choice >
<when>
<xpath>/order/customer/country = 'US'</xpath>
<to uri="file:test/output/us"/>
</when>
<when>
<xpath>/order/customer/country = 'UK'</xpath>
<to uri="file:test/output/uk"/>
</when>
<otherwise>
<to uri="file:test/output/others"/>
</otherwise>
</choice>
</route>
Does this universal unmarshaller exist (hopefully it does), or should I implement my own?
Thanks!
It's not exactly a universal unmarshaller, but similar to what you are asking for:
When you create a REST service, you can set a BindingMode so that Camel will unmarshal from JSON or XML automatically, depending on the incoming Content-Type:
restConfiguration()
.bindingMode(RestBindingMode.auto) // can also be .xml, .json,....
.component("servlet");
But, I haven't seen this being feature used or exposed outside of REST services, yet.
Implementation is in RestBindingAdvice if you're interested.
I have a task to handle all incoming messages within the route and save them to database.
My route starts with webservice (camel-cxf), and then process to ejb and return soap response.
I've decided to use camel-sql component. As far as I don't have any problems with logging incoming message:
<camelContext id="InstitutionContext" xmlns="http://camel.apache.org/schema/spring">
<onException>
<exception>org.example.MyException</exception>
<continued><constant>true</constant></continued>
<to uri="bean:myExceptionHandler?method=handle" />
</onException>
<route id="InstitutionRoute" >
<from uri="direct:start" />
<to uri="sql:insert into translog(id,type,data) values(2,'IN',#)" />
<split>
<tokenize token="\n" />
<unmarshal>
<csv delimiter=";" />
</unmarshal>
<process ref="InstitutionProcessorTest" />
</split>
<to uri="bean:myExceptionHandler?method=checkErrors" />
</route>
</camelContext>
but I don't have idea how to handle exceptions and save them in the form of SOAP message.
<onCompletion onFailureOnly="true">
<to uri="sql:insert into translog(id,type,data) values(2,'ERROR',#)" />
</onCompletion>
but it saves original message in data column. Is there any body who can help?
I might be misunderstanding the question but it looks you are trying to save the SOAP message in XML format if there is a exception.
By default the dataFormat for CXF is POJO meaning it sends a POJO around the camel route i.e. the SOAP XML is converted to a POJO.
Two options come to mind:
Set the dataformat to message or payload. This will send the XML message across the camel route instead of a POJO
Marshall the POJO into a XML message and save it.
How can i call a SOAP web service with an empty message body using Apache Camel?
For example, the final endpoint on a route would be the invocation of a method on my proxy that takes 0 arguments.
EDIT:
example xml configuration:
<route id="someRoute">
<from uri="ref:activemq-queue"/>
<setHeader headerName="operationName">
<constant>invoke</constant>
</setHeader>
<to uri="cxf:bean:someWS"/>
</route>
...
<cxf:cxfEndpoint id="someWS" address="${ws.address}"
serviceClass="com.example.ws.SomeWS"
The problem is that the method 'invoke' on the WS takes 0 arguments, and an exception is thrown stating that 1 argument is being received. Is there a way for me to specify to ignore this received input?
You can set the message body to be null, if the invocation just take 0 argument. null simple expression is added since camel 2.12.3.
<route id="someRoute">
<from uri="ref:activemq-queue"/>
<setBody>
<simple>null</simple>
</setBody>
<setHeader headerName="operationName">
<constant>invoke</constant>
</setHeader>
<to uri="cxf:bean:someWS"/>
</route>
I also needed to set an empty body to Apache Camel xml and the solution below worked for me.
<setBody id="set-empty-body">
<constant/>
</setBody>
Hope this helps to whoever need it.
The xml configuration will fail if the content of the body is not with the correct type of the class required by the method of your bean. By default, it could be an Object and not a String. When the method recieves the body in an incorrect format, it would process a null value, instead of the body of the route. To solve this problem, you will need to convert the body into the expected class of the method of your bean. For example, if the method's argument of the bean is a String, then you could do something like:
<route id="someRoute">
<from uri="ref:activemq-queue"/>
<setHeader headerName="operationName">
<constant>invoke</constant>
</setHeader>
<convertBodyTo type="String"/>
<to uri="cxf:bean:someWS"/>
</route>
For more information about body conversion, you can check the docs: https://camel.apache.org/components/3.14.x/eips/convertBodyTo-eip.html
I have created a simple cxf web service. following is the body of soap message
<soapenv:Body>
<bean:getRTOEmployeeSalary>
<!--Optional:-->
<bean:arg0>sdf</bean:arg0>
</bean:getRTOEmployeeSalary>
</soapenv:Body>
My requirement is to extract the value of arg0 in my camel context file. i.e. i want to log the value of arg0. Please help me on this
<route routePolicyRef="loggingInInterceptor">
<from uri="cxf:bean:rtoemplyeeService"/>
<setHeader headerName="exchange">
<spel>${exchange}</spel>
</setHeader>
<log message="value of arg0======== "/>
<convertBodyTo type="java.lang.String" id="stringInput"/>
<bean ref="rtoEmpBean" method="getRTOEmployeeSalary" beanType="rtoEmpBean" id="govtRTOEmp"/>
</route>
I need to use the value of arg0 here.
We can use camel provided spring expression language to extract the value from exchange object. Since exchange object also resides in spring container.
below will be code src to extract the value of arg0 in camel context-
<setHeader headerName="arg0">
<spel>#{exchange.in.body.get(0)}</spel>
</setHeader>
This will set the value of arg0 of soap message in a header named arg0.
http://camel.apache.org/spel.html
I want to set the endpoint specific header value in Multicast component.
XML DSL as below:
<route>
<from uri="direct:testRoute"/>
<multicast strategyRef="MyAggregator" parallelProcessing="true">
<to uri="direct:call1"/> <!-- set the header MY_HEADER = "call_1" -->
<to uri="direct:call2/> <!-- set the header MY_HEADER = "call_2" -->
</multicast>
</route>
Basically in the response aggregation I want to know, to which service request this response belongs to.
I tried by doing this, but its not the correct way (parse exception):
<to uri="direct:call1">
<setHeader headerName="MY_HEADER"><simple>call1</simple></setHeader>
</to>
What I see from reading the documentation is that, multicast will copy the source Exchange and multicast each copy. So its a shallow copy of the Exchange and kind of reference shared between all the multicast recipient.
But here I am looking for specific header value for individual recipient.
How to do this? Any pointers?
You can't do that in the multicast route. But it should be simple in the direct route afterwards.
<route>
<from uri="direct:call1"/>
<setHeader headerName="MY_HEADER"><simple>call1</simple></setHeader>
.. do whatever
</from>
</route>
otherwise, if call1 is used for other things and you cannot know when to put the header once in that route, make a simple prep-route:
<route>
<from uri="direct:prepCall1"/>
<setHeader headerName="MY_HEADER"><simple>call1</simple></setHeader>
<to uri="direct:call1"/>
</from>
</route>
As a third option, even though you cannot place DSL (xml or java) in the multicast list, you can supply an "onPrepareRef" processor bean that adds the headers to your exchange. But one processor will handle all multicast endpoints.
There is a header with the key Exchange.TO_ENDPOINT that you can see which of the 2 endpoints the response is from.