linkisted have a pointer for required data - c

Question

I have a linked list , which has full information
typdef struct details
{
struct details *head, *next, *curr;
char* values;
}
Details *fyllinfo ; //(this strcuct has full information)
/* fyllinfo this has been filled with many vallues*/
Now I need to copy the pointers to new list which can point only my required or matched data
Details *required;
char* myValue;
details *pstPtr =fyllinfo->head;
details *required = (details*) malloc(
sizeof(details));
required->head = required->next = NULL;
while(pstPtr != NULL)
{
if(NULL == pstPtr->values) goto NEXT;
printf("UUID FOUND IS [%s] and comapre with [%s] ",pstPtr->values,myvalue);
if(strCmp(pstPtr->values,myvalue)==0)
{
if(required->head == NULL)
{
required->head = required->curr = pstPtr;
}
else
{
required->next = pstPtr;
required->curr->next = pstPtr;
}
}
NEXT: pstPtr = pstPtr->next;
}
My Required ptr should have the pointer to only matched values
My code only points the first matched data and it has unmatched data in reuired->next pointer

Answer 1

This code works now... you just need to put some effort to understand it. you should be able to print the values. see how values are stored now.
details *pstPtr = fyllinfo;
details *required = NULL; //(details*)malloc(
details *head=NULL;
while (pstPtr != NULL)
{
if (1 == pstPtr->values)
printf("UUID FOUND IS [%d] and comapre with [%d] \n", pstPtr->values, 1);
if (pstPtr->values==1)
{
if (required == NULL)
{
required = (details*)malloc( sizeof(details));
head = required;
required->head = required->curr = pstPtr;
required->next = NULL;
}
else
{
required->next = (details*)malloc(sizeof(details));
required = required->next;
required->next = NULL;
required->curr = pstPtr;
}
}
pstPtr = pstPtr->next;
}
void display(struct details *r)
{
// r = fyllinfo;
if (r == NULL)
{
return;
}
while (r != NULL)
{
printf("%d ", r->curr->values);
r = r->next;
}
printf("\n");
}