Does a string contains a word from a list - c

Question

I have a string and an array of keywords. If the string contains one of the keywords on the list, I want to check if the keyword is the only element of this string. If it's not, I want to return an error. Last thing, the string will always end with \n.
My keyword array is the following:
const char * keywordsTable[] =
{
"INIT",
"BEGIN",
"END",
"ROUTINES",
"ENDROUTINES",
"ENDWHEN",
"WHEN",
"WHILE"
};
For instance if my string is "BEGIN\n", everything is fine. If my string is "BEGIN FOO\n" or "FOO BEGIN\n", I have to return an error. Finally if my string is "BEGINFOO\n", everything is fine. (error code is 1, else it's 0)
I've tried something (I don't know how to proceed):
int CheckKeyword(char * str)
{
int nKeywords = sizeof(keywordsTable) / sizeof(keywordsTable[0]);
char * strTok = NULL;
char * keywrdWithLF = malloc(20);
// I don't want to check for the last two keywords nor the first
for (int i = 1; i < nKeywords - 2; i++)
{
strcpy_s(keywrdWithLF, 20, keywordsTable[i]);
strcat_s(keywrdWithLF, 20, "\n");
strTok = strstr(str, keywrdWithLF);
// If my string contains a keyword
if (strTok != NULL)
{
// If the string contains other characters... and I'm stuck
if (strcmp(str, keywrdWithLF))
{
}
else
{
free(keywrdWithLF);
return 1;
}
}
}
free(keywrdWithLF);
return 0;
}
Thank you in advance (please don't complain bout my indent style, I have to use Whitesmith indent) !

Answer 1

int CheckKeyword(char * str)
{
int nKeywords = sizeof(keywordsTable) / sizeof(keywordsTable[0]);
char * strTok = NULL;
for (int i = 1; i < nKeywords - 2; i++)
{
if(NULL!=(strTok = strstr(str, keywordsTable[i])))
{
int len = strlen(keywordsTable[i]);
if(strTok == str)
{
if(str[len]==' ' || str[len]=='\t')
return 1;
}
else
{
if((strTok[-1]==' ' || strTok[-1]=='\t') && isspace(strTok[len]))//isspace in <ctype.h>
return 1;
}
}
}
return 0;
}

Answer 2

Perhaps another method?
int CheckKeyword(char * str)
{
int rCode=0;
int nKeywords = sizeof(keywordsTable) / sizeof(keywordsTable[0]);
char *keyword;
char *cp = keywordsTable;
I assume that since str is defined as "char * str" and not "const char * str", it is OK to modify the input string. Hence, why not just eliminate the '\n' problem from the equation?
/* Elininate the newline character from the end of the string. */
if((cp = strchr(str, '\n'))
*cp = \0;
// I don't want to check for the last two keywords nor the first.
nKeywords -= 3;
++keyword;
/* Loop through the keywords. */
while(nKeywords)
{
// "I want to check if the keyword is the only element of this string."
// "If it's not, I want to return an error."
if((cp=strstr(str, keyword))
{
/* Check for stuff prior to the keyword. */
if(cp != str)
rCode=1;
/* Check for stuff after the keyword. */
// Finally if my string is "BEGINFOO\n", everything is fine.
if(' ' == str[strlen[keyword])
rCode=1;
if(strcmp(cp, keyword))
rCode=1
break;
}
++keyword;
--nKeywords;
}
return(rCode);
}