Array of Structures in C. not linked list - c

Question

I am having trouble making an array of structures. I want to store data regarding multiple students and take input using the execution of the program. Then output the memory address of persons name with highest marks.
I tried getting to know the answers on similar issues on site, to no help.
The code I have written is
the struct
struct student{
char name;
int marks;
};
and the function is
int num,max = 0,i;
printf("Number of students?\n");
scanf("%d", &num);
struct student* students = (struct student*)malloc (num* (sizeof(struct student)));
for (int x = 0; x < num; x++)
{
printf("Enter Name\n");
scanf("%c" , &students[x].name);
printf("Enter Marks\n");
scanf ("%d" , &students[x].marks);
}
for (i = 1; i < num; i++)
{
if (students[max].marks<students[i].marks)
{
max = i;
}
}
printf("The Memory Add for %c is %p\n", students[max].name , &students[max].name );
It is a part of menu driven program. It goes into a weird loop after line 5 in function code. And i can't create a doubly linked list for the same.
Edit 1
These are the changes i made to struct and func
struct student{
char name[20];
int marks;
};
void memadd(){
int num,max = 0,i, mark;
printf("Number of students?\n");
scanf("%d", &num);
struct student* students = (struct student*)malloc (num* (sizeof(struct student)));
for (int x = 0; x < num; x++)
{
printf("Enter Name\n");
scanf("%s" , &students[x].name);
printf("Enter Marks\n");
scanf ("%d" , &mark);
students[x].marks = mark;
}
for (i = 1; i < num; i++)
{
if (students[max].marks<students[i].marks)
{
max = i;
}
}
printf("The Memory Add for %s is %p\n", students[max].name , &students[max].name );
It is giving an array at input of the name. "format specifies type 'char ' but the argument has
type 'char ()[20]'"
How do I make the format to be char * [20]?
Edit 2
The final working code after correcting the char name to being a character array
And issue with scanning of names.
struct student{
char name[20];
int marks;
};
int num,max = 0,i, mark;
printf("Number of students?\n");
scanf("%d", &num);
struct student* students = (struct student*)malloc (num* (sizeof(struct student)));
for (int x = 0; x < num; x++)
{
printf("Enter Name\n");
scanf("%19s" , students[x].name);
printf("Enter Marks\n");
scanf ("%d" , &mark);
students[x].marks = mark;
}
for (i = 1; i < num; i++)
{
if (students[max].marks<students[i].marks)
{
max = i;
}
}
printf("The Memory Add for %s is %p\n", students[max].name , &students[max].name );
However, what if I wish to print the address in Hex numbers? or the one that am getting is hex already.?
Because I got an output of The Memory Add for XYZ is 0x7fb340c03928

Answer 1

The problem is with the student name being a char and
scanf("%c" , &students[x].name);
What happens is, you read in the number of students with
scanf("%d", &num);
Now you have read num, but there is still a newline in the input buffer.
Then you try to read a character with %c, but this reads the remaining newline.
When you change the student's name to a character array, e.g.
struct student{
char name[20];
int marks;
};
and read the name with
scanf("%19s" , students[x].name);
it will skip the remaining whitespace/newline and read the name as it should.