i want to create a simple cross, that consists of two lines. The lines should have different colors. I've created a class that inherits form Shape. This class contains the two lines and computes the coordinates of the lines. I've read that i have to implement the DefiningGeometry property if i inherit from Shape. But how can i return both lines in the get section of that property?
Thanks in advance.
It sounds like you could use the CombinedGeometry Class to combine your lines together... the only thing is that you'll need to use LineGeometry classes instead of Lines. You could do something like this (from the linked CombinedGeometry page on MSDN):
<Path Stroke="Black" StrokeThickness="1" Fill="#CCCCFF">
<Path.Data>
<!-- Combines two geometries using the XOR combine mode. -->
<CombinedGeometry GeometryCombineMode="Xor">
<CombinedGeometry.Geometry1>
<EllipseGeometry RadiusX="50" RadiusY="50" Center="75,75" />
</CombinedGeometry.Geometry1>
<CombinedGeometry.Geometry2>
<EllipseGeometry RadiusX="50" RadiusY="50" Center="125,75" />
</CombinedGeometry.Geometry2>
</CombinedGeometry>
</Path.Data>
</Path>
Of course, you'd want to replace these EllipseGeometry objects with LineGeometry objects, but that shouldn't be difficult as they have similar properties.
UPDATE >>>
Unfortunately, I don't think that you can use a CombinedGeometry object that contains geometries of different colours... the whole shape would have to be painted with one Brush. However, you could fake two colours with cleverly positioned GradientStops. Also, as #Clemens mentioned, perhaps a GeometryGroup would be easier for you to use... try something like this:
<Path StrokeThickness="5" Fill="Blue" HorizontalAlignment="Center" VerticalAlignment="Center">
<Path.Data>
<GeometryGroup>
<LineGeometry StartPoint="50,0" EndPoint="50,100" />
<LineGeometry StartPoint="0,50" EndPoint="100,50" />
</GeometryGroup>
</Path.Data>
<Path.Stroke>
<LinearGradientBrush StartPoint="0,0" EndPoint="1,0">
<GradientStop Color="LightGreen" Offset="0" />
<GradientStop Color="LightGreen" Offset="0.475" />
<GradientStop Color="Red" Offset="0.475" />
<GradientStop Color="Red" Offset="0.525" />
<GradientStop Color="LightGreen" Offset="0.525" />
<GradientStop Color="LightGreen" Offset="0" />
</LinearGradientBrush>
</Path.Stroke>
</Path>
This Brush will appear as if it were actually different colours on the two lines:
Then all you'll need to do is to convert this into C# to return it from the DefiningGeometry property. Please use the examples from the linked pages and the GeometryGroup class page on MSDN to help you with this.
You may draw two differently colored lines by means of two GeometryDrawings in a DrawingBrush that fills a Rectangle:
<Rectangle Width="20" Height="20">
<Rectangle.Fill>
<DrawingBrush>
<DrawingBrush.Drawing>
<DrawingGroup>
<GeometryDrawing Geometry="M0,-10 L0,10">
<GeometryDrawing.Pen>
<Pen Brush="Blue" Thickness="3"/>
</GeometryDrawing.Pen>
</GeometryDrawing>
<GeometryDrawing Geometry="M-10,0 L10,0">
<GeometryDrawing.Pen>
<Pen Brush="Red" Thickness="3"/>
</GeometryDrawing.Pen>
</GeometryDrawing>
</DrawingGroup>
</DrawingBrush.Drawing>
</DrawingBrush>
</Rectangle.Fill>
</Rectangle>
Related
Now many graphics designers provide the images as xaml file not ico, png, ..., How can I use a xaml file as image source?
Thanks
From the MSDN
<Image>
<Image.Source>
<DrawingImage PresentationOptions:Freeze="True">
<DrawingImage.Drawing>
<GeometryDrawing>
<GeometryDrawing.Geometry>
<GeometryGroup>
<EllipseGeometry Center="50,50" RadiusX="45" RadiusY="20" />
<EllipseGeometry Center="50,50" RadiusX="20" RadiusY="45" />
</GeometryGroup>
</GeometryDrawing.Geometry>
<GeometryDrawing.Brush>
<LinearGradientBrush>
<GradientStop Offset="0.0" Color="Blue" />
<GradientStop Offset="1.0" Color="#CCCCFF" />
</LinearGradientBrush>
</GeometryDrawing.Brush>
<GeometryDrawing.Pen>
<Pen Thickness="10" Brush="Black" />
</GeometryDrawing.Pen>
</GeometryDrawing>
</DrawingImage.Drawing>
</DrawingImage>
</Image.Source>
</Image>
Instead of in-lining the GeometryDrawing you could refer to it as a static resource that you keep in a Resourcedictionary.
<Image>
<Image.Source>
<DrawingImage PresentationOptions:Freeze="True"
Drawing="{StaticResource myDrawing}">
</Image.Source>
</Image>
You will also find that you can show the drawing only once this way. So if you want this image to be present in the UI in multiple places, put the Image in a control template and style the controls with the template.
Thanks too all, this approach I know, my question was what happens when I have 100 xaml graphics files provided by a designer, now I have to extract the content from each file to move in a resource dictionary and set a key for each. I ask only if a more easy way as time.
Thank again too all.
I got a graphic like this
<Viewbox xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" Width="128" Height="128">
<Canvas Width="10240" Height="10240">
<Path Data="M5986 6814l828 -828c124,-124 328,-124 452,0l2428 2428c124,124 124,328 0,452l-828 828c-124,124 -328,124 -452,0l-2428 -2428c-124,-124 -124,-328 0,-452z" Fill="#EDC87E"/>
<Path Data="M6082 5442l412 412 -640 640 -412 -412c-534,401 -1197,638 -1916,638 -1764,0 -3194,-1430 -3194,-3194 0,-1764 1430,-3194 3194,-3194 1764,0 3194,1430 3194,3194 0,719 -237,1382 -638,1916zm-2556 -4471c-1411,0 -2555,1144 -2555,2555 0,1411 1144,2555 2555,2555 1411,0 2555,-1144 2555,-2555 0,-1411 -1144,-2555 -2555,-2555z" Fill="#808080"/>
</Canvas>
</Viewbox>
This can be user very easy as a content to a Content control, but to youse this for a control which requires Image source I cannot I have to transform to:
<DrawingImage>
<DrawingImage.Drawing>
<DrawingGroup>
<DrawingGroup.Children>
<GeometryDrawing Geometry="M5986 6814l828 -828c124,-124 328,-124 452,0l2428 2428c124,124 124,328 0,452l-828 828c-124,124 -328,124 -452,0l-2428 -2428c-124,-124 -124,-328 0,-452z" Brush="#EDC87E">
<GeometryDrawing.Pen>
<Pen Thickness="1000" Brush="Blue"></Pen>
</GeometryDrawing.Pen>
</GeometryDrawing>
<GeometryDrawing Geometry="M6082 5442l412 412 -640 640 -412 -412c-534,401 -1197,638 -1916,638 -1764,0 -3194,-1430 -3194,-3194 0,-1764 1430,-3194 3194,-3194 1764,0 3194,1430 3194,3194 0,719 -237,1382 -638,1916zm-2556 -4471c-1411,0 -2555,1144 -2555,2555 0,1411 1144,2555 2555,2555 1411,0 2555,-1144 2555,-2555 0,-1411 -1144,-2555 -2555,-2555z" Brush="#808080"/>
</DrawingGroup.Children>
</DrawingGroup>
</DrawingImage.Drawing>
</DrawingImage>
The work in to trivial :(
I am trying to create the following shape as a background to a border. You will notice that the bottom section on the shape has a linear gradient to it.
I have played around with lines and shapes and gradients, but i have not been able to apply the below to a border. nor can i get a shape that looks like that.
Is this even possible? if so, can anyone help
The below XAML produces a brush that looks similar to your picture. You should play around the colors, offsets, and the rest for the best appearance.
<DrawingBrush x:Key="br1" Viewbox="0,0,100,100" ViewboxUnits="Absolute" >
<DrawingBrush.Drawing>
<DrawingGroup>
<GeometryDrawing Brush="Lavender">
<GeometryDrawing.Geometry>
<RectangleGeometry Rect="0,0,100,100" />
</GeometryDrawing.Geometry>
</GeometryDrawing>
<GeometryDrawing>
<GeometryDrawing.Brush>
<RadialGradientBrush GradientOrigin="0.5,0.01" Center="0.5,-0.2" RadiusX="100">
<GradientStop Color="MidnightBlue" Offset="1.0" />
<GradientStop Color="LightSteelBlue" Offset="0.0" />
</RadialGradientBrush>
</GeometryDrawing.Brush>
<GeometryDrawing.Geometry>
<EllipseGeometry Center="60,310" RadiusX="160" RadiusY="300" />
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingGroup>
</DrawingBrush.Drawing>
</DrawingBrush>
Have fun!
I am trying to draw a transparent line in a solid block using a gradient:
<Grid>
<Border Margin="-102,-27,102,27">
<Border.Background>
<LinearGradientBrush EndPoint="517,160" StartPoint="0,160" MappingMode="Absolute">
<GradientStop Color="#FF2DBCF2" Offset="0"/>
<GradientStop Color="#FF2DBCF2" Offset="1"/>
<GradientStop Color="#002DBCF2" Offset="0.0091" />
<GradientStop Color="#FF2DBCF2" Offset="0.009"/>
<GradientStop Color="#002DBCF2" Offset="0.015"/>
<GradientStop Color="#FF2DBCF2" Offset="0.0151"/>
</LinearGradientBrush>
</Border.Background>
</Border>
</Grid>
The problem is that on the edges of the gap in the solid colour block there is a faint fading effect which makes the edge slightly less than crisp. Is there a way to get rid of this faint fading? I just can't seem to find a way around it.
You may use something like the following DrawingBrush for the background:
<Border Margin="-102,-27,102,27">
<Border.Background>
<DrawingBrush>
<DrawingBrush.Drawing>
<GeometryDrawing Brush="#FF2DBCF2">
<GeometryDrawing.Geometry>
<GeometryGroup>
<RectangleGeometry Rect="0,0,0.01,1"/>
<RectangleGeometry Rect="0.015,0,0.985,1"/>
</GeometryGroup>
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingBrush.Drawing>
</DrawingBrush>
</Border.Background>
</Border>
The only way to get a sharp line in the background is to use an ImageBrush or DrawingBrush as background instead of a LinearGradientBrush
I can't work out a complete example right now, but this should get you started on how to implement a DrawingBrush as background.
<Border.Background>
<DrawingBrush TileMode="Tile" Stretch="None" Viewport="0,0,20,20" ViewportUnits="Absolute">
<DrawingBrush.Drawing>
<GeometryDrawing>
<GeometryDrawing.Pen>
<Pen Brush="White"/>
</GeometryDrawing.Pen>
<GeometryDrawing.Geometry>
<LineGeometry StartPoint="0.3,0"
EndPoint="0.3,20"/>
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingBrush.Drawing>
</DrawingBrush>
<Border.Background>
I encountered following problem during creation of radioactive geometry:
Orange dot represents RadialGradientBrush center point (0,0). It should be in the center of black circle, not on the bottom. This cause another problem: spinning animation.
Is there a way to fix this at the geometry level ? I could fix it by setting brush's center point explicitly, but that is inconvenient and brittle.
<GeometryDrawing>
<GeometryDrawing.Geometry>
<GeometryGroup>
<PathGeometry Figures="
M-10,0 Q0,5 10,0
Q20,25 25,50
Q0,60 -25,50
Q-20,25 -10,0 Z">
<PathGeometry.Transform>
<TranslateTransform Y="15" />
</PathGeometry.Transform>
</PathGeometry>
<PathGeometry Figures="
M-10,0 Q0,5 10,0
Q20,25 25,50
Q0,60 -25,50
Q-20,25 -10,0 Z" >
<PathGeometry.Transform>
<TransformGroup>
<TranslateTransform Y="15" />
<RotateTransform Angle="120" />
</TransformGroup>
</PathGeometry.Transform>
</PathGeometry>
<PathGeometry Figures="
M-10,0 Q0,5 10,0
Q20,25 25,50
Q0,60 -25,50
Q-20,25 -10,0 Z" >
<PathGeometry.Transform>
<TransformGroup>
<TranslateTransform Y="15" />
<RotateTransform Angle="240" />
</TransformGroup>
</PathGeometry.Transform>
</PathGeometry>
<EllipseGeometry RadiusX="10" RadiusY="10" />
</GeometryGroup>
</GeometryDrawing.Geometry>
<GeometryDrawing.Brush>
<RadialGradientBrush ColorInterpolationMode="ScRgbLinearInterpolation">
<GradientStop Offset="0" Color="Orange" />
<GradientStop Offset="0.03" Color="Black" />
</RadialGradientBrush>
</GeometryDrawing.Brush>
<GeometryDrawing.Pen>
<Pen Thickness="0">
<Pen.Brush>
<SolidColorBrush Color="Black" />
</Pen.Brush>
</Pen>
</GeometryDrawing.Pen>
</GeometryDrawing>
This is caused by the fact that the top of the box cuts off the top of the big circle. It is cut off because the top two petals are rotated.
You could fix this by adding the outer circle (transparent) to the geometry or perhaps by adding a margin to the top.
this will move down the black parts of the drawing, centering the orange dot and fixing the rotation.
Does this make sense? It is hard to explain, when needed I could create a sketch.
I want to draw a triangle as a border background. One way of doing this is by using a DrawingBrush, but at smaller sizes anti-aliasing is distorting the triangle and making it blurry. How can I disable anti-aliasing?
<Border>
<Border.Background>
<DrawingBrush>
<DrawingBrush.Drawing>
<GeometryDrawing Brush="Red">
<GeometryDrawing.Geometry>
<PathGeometry>
<PathGeometry.Figures>
<PathFigureCollection>
<PathFigure IsClosed="True" StartPoint="0,3" IsFilled="True">
<PathFigure.Segments>
<LineSegment Point="3,0" />
<LineSegment Point="6,3" />
</PathFigure.Segments>
</PathFigure>
</PathFigureCollection>
</PathGeometry.Figures>
</PathGeometry>
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingBrush.Drawing>
</DrawingBrush>
</Border.Background>
</Border>
I've tried setting RenderOptions.EdgeMode="Aliased" and SnapsToDevicePixels="true" on all possible elements, but that hasn't worked...
Edit:
This is what the drawn triangle looks like at Width=17; Height=12 (zoomed to 800%):
As you can see the edges are anti-aliased. All the usual options for disabling anti-aliasing don't seem to be working...
I also became very frustrated with this. After some research, I found the answer: Using a Visual Brush with the Image element in the visual set to SnapToDevicePixels = true and Aliased Edge Mode. See the example below:
<Canvas VerticalAlignment="Top" Height="12" Margin="0,24,0,0">
<Canvas.Background>
<VisualBrush TileMode="Tile" Stretch="None" Viewport="-5,0,10,10" ViewportUnits="Absolute">
<VisualBrush.Visual>
<Image Stretch="None" RenderOptions.EdgeMode="Aliased" SnapsToDevicePixels="True">
<Image.Source>
<DrawingImage>
<DrawingImage.Drawing>
<GeometryDrawing>
<GeometryDrawing.Pen>
<Pen Brush="#8F8E8F" Thickness="1" />
</GeometryDrawing.Pen>
<GeometryDrawing.Geometry>
<LineGeometry StartPoint="0,0" EndPoint="0,10"/>
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingImage.Drawing>
</DrawingImage>
</Image.Source>
</Image>
</VisualBrush.Visual>
</VisualBrush>
</Canvas.Background>
</Canvas>
Considering there haven't been any more replies, then it seems that the answer is - it's impossible.
I think you should be able to do it with SnapToDevicePixels (although sometimes it takes a little trial and error). You should set it on the owning object (so whatever the border is being put in). Have you read this article?
http://msdn.microsoft.com/en-us/library/aa970908.aspx