I've a simple cakephp app with search and pagination. I'm using GET as type for forms.
When I click search with desired filters, paginated results are shown. I get desired results when I move across pages (with URL being modified with desired index of page number and filtered parameters).
Say I'm on page:4 of paginated search results. Now when I modify some search filter and hit search button again with page:4 shown, if results have less records (say that can be accommodated on one page), I get error - unable to find xxxxxx on server. (....../page:4/.... doesn't exist)..
Please help!
when you press search usually you want to reset all or same of the paginator parameters
I guess that in your view you just did
echo $this->Form->create('Model');
in this way cake assume that the action of the form is the url of the page you are in
but you can set the url of the form this way
echo $this->Form->create('Model', array('url' => array('page' => 1));
Resolved it as follows
$url = array('controller' => 'cc', 'action' => 'aa') + $this->request->params['pass'];
echo $this->Form->create(null, array('type' => 'get','url' => $url));
Thanks for your help.
Related
I have a one-to-many relationship where one House can have many Pictures. The models that I have are "House" and "Picture". I am using CakePHP 1.2 and I can upload one picture successfully by using this:
echo $form->input('Picture.filename', array('type' => 'file', 'label' => __l('Image')));
In my houses_controller.php file, I have this code to save the picture and corresponding association with its house:
$this->House->Picture->save($this->data['Picture']);
But I need to save several pictures now. I read the documentation at https://book.cakephp.org/1.2/en/The-Manual/Core-Helpers/Form.html and based on that information, I am trying to use this:
echo $form->input('Picture.0.filename', array('type' => 'file', 'label' => __l('Image 1'));
echo $form->input('Picture.1.filename', array('type' => 'file', 'label' => __l('Image 2'));
Then my houses_controller.php file has this:
$this->House->Picture->saveAll($this->data['Picture']);
I see that one new record is saved in my pictures table, but I was expecting to see two new entries in my table because I should have added two pictures, not only one. Any ideas about why this may not be saving two pictures for me? Thank you.
Solution:
$this->Deal->Picture->save($this->data['Picture'][0]);
$this->Deal->Picture->save($this->data['Picture'][1]);
Using $this->data['Picture'] was not sufficient because the array was returning multiple elements, so I had to reference each with the corresponding index such as $this->data['Picture'][0] for the first element, $this->data['Picture'][1] for the second one, etc.
NOTE: It was not saving two records for me, even thought I was using save() twice. But that was another issue. You can read the answers at Save multiple times in Cakephp for the corresponding solution. Basically you need to use create() before you use save().
I have designed page in cakephp contains form which input filed name 'id' and submit button. I want to display the data filtered by the 'id' in view page. Please give me an example with code for this.
So you wanna search into a database for this ID and return back all stored data to the view?
First of all,you have to retrieve your data. See here: http://book.cakephp.org/2.0/en/models/retrieving-your-data.html
Secondly, you have to use
$this->set('var_name', $var_name_containing_found_data);
and finally you can handle your data into the view by manipulating as you wish the $var_name variable.
Put this action in your controller:
public function your_action($id = null) {//your action
if ($this->request->is('post')) {
$search = $this->YourModel->find('all', array('conditions' => array('id' => $this->request->data['id'])));//assuming id is submitted like you said $_POST['id']
$this->set('search', $search);
}
}
You can access the search variable in your view (your_view.ctp) like this $this->search
assuming your cakephp version is 2.x
When I've Search my listing i'm getting some results with pagination, but when i go for second page my search is
breaking as it was a get request where i'm getting the search results via post method.
Note: For getting search results I don't want to submit the form via get request (i.e. Query string params) and also don't want to store the form data in session
Is there any way to get the results which satisfy the above conditions ?
You want to implement the PRG Pattern.
Post/Redirect/Get (PRG) is a web development design pattern that
prevents some duplicate form submissions, creating a more intuitive
interface for user agents (users). PRG implements bookmarks and the
refresh button in a predictable way that does not create duplicate
form submissions.
The CakeDC Search plugin makes that pretty easy to do in CakePHP.
It would be very hard to do it using only "POST" calls. You'll need to transfor your POST into a GET call.
Check this post i made or clone it from github
Hope this helps
EDIT:
Using my git repo. If you want url querystrings instead of named parameters:
in this line, instead of the foreach build the querystring and pass it to the redirect
in this line, get the parameters from the query string ($GET)
and in this line add page, sort and direction to this->paginate
I haven't tested it, but it should be something like that
We can do it with a patch.
In Views :
create search form :
$this->Form->create('Search', array('url' => array('controller' => 'controller', 'action' => 'index', substr(time(), 2,rand(1, 7) ))) );
Note : A random number appended at the end of the form action. This will let us know when to clear session.
in Controller :
public function index( $search = null)
{
$conditions = array(1 => 1);
if( !empty($this->data['Search']['keyword']) && $search)
{
$conditions = array('Model.field like' => $this->data['Search']['keyword'] . '%');
// store search array in session
$this->Session->write('conditions', $this->data['Search']);
}
if ($search)
{
$this->request->data['Search'] = $this->Session->read('conditions');
$conditions = array('Model.field like' => $this->data['Search']['keyword'] . '%');
}
else
{
$conditions = array(1 => 1);
$this->Session->delete('conditions');
}
$this->paginate= array('limit'=> 10, 'conditions' => $conditions);
$lists = $this->Paginate('Model');
}
Hope you understand the logic behind.
I would like to make a configuration page like this for my CMS
http://img4.hostingpics.net/pics/72087272ok.png
I want this page (admin/settings/index) gets me the various settings (ID 1 to 21) came to my table and in case of change, I can, in this form, do an update
After 3 days of not especially fruitful research I found something. I put in my SettingsController:
admin_index public function () {
if (!empty($this->data)) {
$this->Setting->saveAll($this->request->data['Setting']);
} else {
$this->request->data['Setting'] = Set::combine($this->Setting->find('all'),
'{n}. Setting.id', '{n}. Setting');
}
}
and my view:
<?php
echo $this->Form->create('Setting', array ('class' => 'form-horizontal'));
foreach($this->request->data['Setting'] as $key => $value) {
echo $this->Form->input('Setting.' . $key . '.pair');
echo $this->Form->input('Setting.' . $key . '.id');
}
echo $this->Form->end(array('class' => 'btn btn-primary', 'label' => 'Save',
'value' => 'Update!', 'div' => array ('class' => 'form-actions')));
?>
he is recovering well all my information, I can even update. The trouble is that I do not really know how I can do to get the same result as my first screenshot. He puts everything in the textarea while in some cases I want the checkbox and / or drop-down.
please help me or explain to me how to make a page that retrieves configuration information from my table and allows me to edit without use an address like admin/settings/edit/ID
My table settings is something like this here
http://img4.hostingpics.net/pics/724403settings.png
If you are asking about how to format the output to produce a "settings" page, you will need to do it manually or add some kind of metadata to your table schema, such as "field_type".
Now Cake will automatically generate a checkbox for a boolean or tiny int, for example, but as you have varchars, ints, texts and so on, this won't work for you (pair is presumably varchar or text to allow for the different possible values.
You cannot really automagically generate the outputs you want without telling Cake.
One option would be to add a field_type to the table, so:
key value field
site_name My Site input
site_online 1 checkbox
meta_desc [some text] textarea
and something like
foreach($settings as $setting) {
echo $this->Form->{$setting['field']}($setting['key'],
array('value' => $setting['value']));
}
might do what you are after.
Or if($key=='site_name') // output a textbox
but this is not exactly ideal.
I have created a plugin called movies, I have used custom routes.
I have used pagination limit as '5'.
The first page is fine, but when I click on next or numbers. Those things doesn't works.
URL: something.com/movieslist/2
my Plugin/Movies/Config/routes.php
Router::connect('/movieslist', array('plugin' => 'Movies', 'controller' => 'Movies', 'action' => 'index'));
Router::connect('/movieslist/:page', array('plugin' => 'Movies', 'controller' => 'Movies', 'action' => 'index'));
my action code: Plugin/Movies/Controller/MoviesController.php
public function index() {
$this->Movie->recursive = 0;
$this->paginate = array('limit'=>5);
$this->set('movies', $this->paginate());
}
my view file code: Plugin/Movies/View/Movies/index.ctp
Same one from cakebake console. No changes made here.
Even the sort doesn't works :(
I'm tiered of searching my problems in many places :(
I had previously getting error in links itself and I fixed this after seeing this page:
CakePHP custom route pagination
Links are fixed but the links doesn't works. Pls don't down vote, I'm struggling from long time.
I'm using cakephp 2.0 version.
As a first step I'd swap the order of the router rules, since cakephp stops after the first match found. While the "/movieslist/:page" one will match a url with a page, it only does so for the named parameter page. Without it a url of the form "/movielist/2", might be interpreted as a link to "/movielist" with a normal parameter "2", hence the first router rule triggers.
If that does not work you can always just manually set the named page parameter. paginate just looks to see if it is set, but does not care if cakephp automagically figured it out from the url or if you do it yourself.
public function index($myPage=1) {
$this->Movie->recursive = 0;
$this->paginate = array('limit'=>5);
$this->params["page"] = $myPage;
$this->set('movies', $this->paginate());
}