parsing a string into tokens without strtok/lexer - c

Question

I want to parse a string into an array of tokens . '\n' and ';' are delimiters , for e.g. :
hello;hello
world
should be converted to an array containing: {"hello","hello","world"}.
I tried many different methods for doing this and always I fail (since it needs a dynamic array of char * I have trouble with implementing it).
Please note that I cannot use strtok or lexical analyzer.
How may I do this ? Any points ?
EDIT : here is one of methods I tried to use but I get segmentation fault (maybe a memory access issue somewhere in my code) :
#include <stdio.h>
#include <malloc.h>
#include <fcntl.h>
#include <string.h>
typedef struct {
int fd;
char *path;
int size;
char *mem;
struct stat st;
} file;
file *readfile(char *path) {
file *a=malloc(sizeof(file));
a->path=path;
a->fd=open(a->path,O_RDONLY);
if(a->fd<0) return 0;
fstat(a->fd,&a->st);
a->size=a->st.st_size;
a->mem=malloc(a->size);
read(a->fd,a->mem,a->size);
return a;
}
void releasefile(file *a) {
free(a->mem);
close(a->fd);
free(a);
}
char **parse(int *w,file *a) {
int i,j=0;
w=0;
for(i=0;i<=a->size;i++) {
if(a->mem[i]=='\n' || a->mem[i]==';') { a->mem[i]='\0'; j++; }
}
char **out=malloc(sizeof(char *)*j);
for(i=0;i<=a->size;i++) {
if(a->mem[i-1]!='\0') continue;
out[*w]=malloc(strlen(a->mem+i)+1);
memcpy(out[*w],a->mem+i,strlen(a->mem+i)+1);
w++;
return out;
}
int main(int argc,char **argv) {
file *a=readfile(argv[1]);
int *w=malloc(sizeof(int));
char **tokens=parse(w,a);
int i;
for(i=0;i<=*w;i++) {
puts(tokens[i]);
}
releasefile(a);
// ATM no need to check for mem leaks :)
}
Algorithm description : read file, put \0 where you see a delimiter, start and push tokens seprated by \0 into an array.

Answer 1

What has happened to computer science?
Anyway write a FSA - http://en.wikipedia.org/wiki/Finite-state_machine
Can do this using a table