when this query is executed
DECLARE #Temp TABLE (ID INT IDENTITY,Name VARCHAR(50),ID2 INT NULL)
INSERT INTO #Temp ([Name]) VALUES ('Ali')
UPDATE #Temp SET ID2= (SELECT SCOPE_IDENTITY()) WHERE [ID]=(SELECT SCOPE_IDENTITY())
INSERT INTO #Temp ([Name]) VALUES ('Veli')
UPDATE #Temp SET ID2= (SELECT SCOPE_IDENTITY()) WHERE [ID]=(SELECT SCOPE_IDENTITY())
SELECT * FROM #Temp
We can get this table
ID-NAME-ID2
1 - Ali - 1
2 - Veli - 2
is there a way to do this in one insert query ( Assigning inserted id to another column without using idendity property in that column) ?
thanks a lot.
You want to make it a computed column like below
create TABLE Temp(ID INT IDENTITY,Name
VARCHAR(50),
ID2 AS ID PERSISTED);
Then insert rows ... your ID values will be persisted in ID2 column
INSERT INTO Temp ([Name])
VALUES ('Ali');
INSERT INTO Temp ([Name])
VALUES ('Veli');
INSERT INTO Temp ([Name])
VALUES ('Neli');
Which will results in
See a demo fiddle here http://sqlfiddle.com/#!3/59fca/1
EDIT:
If you can't change your table structure then the only way insert ID value to ID2 column is the way you are currently doing it cause in same insert statement the identity value is still not available and so it will be null.
Related
I want to display a few specific Rows always at top of the query results.
For example: Cities Table. Columns: City ID, City Name
I want to fetch Query result where Mumbai, Bangalore, Chennai, Hyderabad should display at the top always.
1st way:
I can insert these records first in the table so that they will get displayed always at the top.
But, this way will not work if any other city gets added after a few months that I also want to display at the top.
Use an iif in your order by clause:
SELECT CityId, CityName
FROM Cities
ORDER BY IIF(CityName IN ('Mumbai', 'Bangalore', 'Chennai', 'Hyderabad'), 0, 1), CityName
You can't rely on the order in which you've entered the records to the table, because database tables are unsorted by nature, and without an order by clause, the order of the result set will be arbitrary.
For more information, read The “Natural order” misconception on my blog.
Try this:
Declare #t table (cityID int,cityname nvarchar(50))
insert into #t values (2,'Gujrat')
insert into #t values (4,'Surat')
insert into #t values (6,'Mumbai')
insert into #t values (3,'Bangalore')
insert into #t values (5,'Chennai')
insert into #t values (1,'Hyderabad')
select * from #t
order by case when cityname in ('Mumbai','Bangalore','Chennai','Hyderabad') then 0 else 1 END
Clean way of doing this,
Declare #t table (cityID int,cityname nvarchar(50))
Declare #DesireOrder table (id int identity,CityID int) -- instead of cityname
insert into #DesireOrder values (6),(3),(5),(1)
insert into #t values (2,'Gujrat')
insert into #t values (4,'Surat')
insert into #t values (6,'Mumbai')
insert into #t values (3,'Bangalore')
insert into #t values (5,'Chennai')
insert into #t values (1,'Hyderabad')
insert into #t values (8,'Delhi')
insert into #t values (7,'New Delhi')
select t.* from #t t
left join DesireOrder O on t.cityid=O.cityid
order by o.id,t.cityID
Main idea is #DesireOrder, rest you can implement as per your requirement.
I have two tables in MS SQL:
CREATE TABLE Table1 (ID INT IDENTITY(1,1) NOT NULL, TEXTVal VARCHAR(100), Table2Id int)
insert into Table1 (TEXTVal) values('aaa');
insert into Table1 (TEXTVal) values('bbb'); insert into Table1 (TEXTVal) values('ccc');
CREATE TABLE Table2 (ID INT IDENTITY(1,1) NOT NULL, TEXTVal VARCHAR(100), Table2Id int)
Id are identity columns. I want to copy TEXTVal values from Table1 to Table2:
INSERT INTO Table2 (TEXTVal)
SELECT TEXTVal FROM Table1
where TEXTVal <> 'ccc'
and after that update column Table2Id in Table1 with appropriate values of Id from Table2. I can do this with cursor and SCOPE_IDENTITY().
I am just wondering, is there a way to do it without cursor in T-SQL?
As Jeroen stated in comments, you'll want to use OUTPUT. In the following example if you don't have an AdventureWorks database, just use a test database. You should be able to copy/paste this and just run it to see it in action!
USE AdventureWorks;
GO
----Creating the table which will store permanent table
CREATE TABLE TestTable (ID INT, TEXTVal VARCHAR(100))
----Creating temp table to store ovalues of OUTPUT clause
DECLARE #TmpTable TABLE (ID_New INT, TEXTVal_New VARCHAR(100),ID_Old INT, TEXTVal_Old VARCHAR(100))
----Insert values in real table
INSERT TestTable (ID, TEXTVal)
VALUES (1,'FirstVal')
INSERT TestTable (ID, TEXTVal)
VALUES (2,'SecondVal')
----Update the table and insert values in temp table using Output clause
UPDATE TestTable
SET TEXTVal = 'NewValue'
OUTPUT Inserted.ID, Inserted.TEXTVal, Deleted.ID, Deleted.TEXTVal INTO #TmpTable
WHERE ID IN (1,2)
----Check the values in the temp table and real table
----The values in both the tables will be same
SELECT * FROM #TmpTable
SELECT * FROM TestTable
----Clean up time
DROP TABLE TestTable
GO
ResultSet:
TmpTable:
ID_New TextVal_New ID_Old TextVal_Old
——————— ——————— ——————— ———————
1 NewValue 1 FirstVal
2 NewValue 2 SecondVal
Original Table:
ID TextVal
——————— ———————
1 NewValue
2 NewValue
As you can see it is possible to capture new values, and the values you are updating. In this example I'm just stuffing them into a table variable but you could do whatever you'd like with them. :)
I have a situation in which I need to insert some values from a query into a table that has an identity PK. For some of the records, I need also to insert values in another table which has a 1-to-1 (partial) relationship:
CREATE TABLE A (
Id int identity primary key clustered,
Somevalue varchar(100),
SomeOtherValue int)
CREATE TABLE B (Id int primary key clustered,
SomeFlag bit)
DECLARE #inserted TABLE(NewId int, OldId)
INSERT INTO A (Somevalue)
OUTPUT Inserted.Id into #inserted(NewId)
SELECT SomeValue
FROM A
WHERE <certain condition>
INSERT INTO B (Id, SomeFlag)
SELECT
i.NewId, B.SomeFlag
FROM #inserted i
JOIN A ON <some condition>
JOIN B ON A.Id = B.Id
The problem is that the query from A in the first INSERT/SELECT returns records that can only be differentiated by the Id, which I cannot insert. Unfortunately I cannot change the structure of the A table, to insert the "previous" Id which would solve my problem.
Any idea that could lead to a solution?
With INSERT ... OUTPUT ... SELECT ... you can't output columns that are not in the target table. You can try MERGE instead:
MERGE INTO A as tgt
USING (SELECT Id, SomeValue FROM A WHERE <your conditions>) AS src
ON 0 = 1
WHEN NOT MATCHED THEN
INSERT (SomeValue)
VALUES (src.SomeValue)
OUTPUT (inserted.Id, src.Id) -- this is your new Id / old Id mapping
INTO #inserted
;
SCOPE_IDENTITY() returns the last identity value generated by the current session and current scope. You could stick that into a #table and use that to insert into B
SELECT SCOPE_IDENTITY() as newid into #c
Though, your INSERT INTO B join conditions implies to me that the value in B is already known ?
I have stored procedures that inserts/updates records in some tables. Some columns of those tables have default values or auto-increment. Here's what I have:
ALTER PROCEDURE [dbo].[Usp___NewExpense]
#iCampaignID int,
#iCategory int,
#iUserID int,
#dDate Date,
#iAmountInINR int,
#strComments VarChar(200)
AS
BEGIN
SET NOCOUNT ON;
INSERT INTO dbo.Tbl_Expenses(iCampaignID, iCategory, dDate, iAmountInINR, strComments)
VALUES (#iCampaignID, #iCategory, #dDate, #iAmountInINR, #strComments);
-- How to get the record inserted using the above statement here without using triggers
-- or another select statement, so that I can assign values to the following variables?
Declare #justInsertedValue1 type1;
Declare #justInsertedValue2 type2;
Declare #justInsertedValue3 type3;
INSERT INTO dbo.Tbl_SomeOtherTable(col1, col2, col3)
VALUES (justInsertedValue1, justInsertedValue2, justInsertedValue3);
END
GO
Tbl_Expenses has about 9 columns in which two have default values and two have auto-increment set. How can I get the just inserted record just below my INSERT statement?
I know that I can use SCOPE_IDENTITY() and then a SELECT, but a query would probably make it inefficient (am I right?).
(By getting the just inserted record, I mean values of all fields of the just inserted record)
Edit: I haven't specified values for all the fields in my INSERT statement. I want to get those values inserted automatically by SQL Server due to DEFAULT/AUTO INCREMENT constraints also.
You can use the OUTPUT clause. You can even combine both inserts into one composite:
create table T1 (ID int IDENTITY(1,1) not null,ColA varchar(10) not null)
create table T2 (ID int IDENTITY(1,1) not null,T1ID int not null,ColB varchar(10) not null)
--Look ma! no local variables at all
insert into T2 (T1ID,ColB)
select t1.ID,'def'
from (
insert into T1(ColA)
output inserted.ID
values ('abc')
) t1
select * from T1
select * from T2
Results:
ID ColA
----------- ----------
1 abc
ID T1ID ColB
----------- ----------- ----------
1 1 def
I have two tables with foreign key constraint on TableB on TablesAs KeyA column. I was doing manual inserts till now as they were only few rows to be added. Now i need to do a bulk insert, so my question if i insert multiple rows in TableA how can i get all those identity values and insert them into TableB along with other column values. Please see the script below.
INSERT INTO Tablea
([KeyA]
,[Value] )
SELECT 4 ,'StateA'
UNION ALL
SELECT 5 ,'StateB'
UNION ALL
SELECT 6 ,'StateC'
INSERT INTO Tableb
([KeyB]
,[fKeyA] //Get value from the inserted row from TableA
,[Desc])
SELECT 1 ,4,'Value1'
UNION ALL
SELECT 2 ,5,'Value2'
UNION ALL
SELECT 3 ,6, 'Value3'
You can use the OUTPUT clause of INSERT to do this. Here is an example:
CREATE TABLE #temp (id [int] IDENTITY (1, 1) PRIMARY KEY CLUSTERED, Val int)
CREATE TABLE #new (id [int], val int)
INSERT INTO #temp (val) OUTPUT inserted.id, inserted.val INTO #new VALUES (5), (6), (7)
SELECT id, val FROM #new
DROP TABLE #new
DROP TABLE #temp
The result set returned includes the inserted IDENTITY values.
Scope identity sometimes returns incorrect value. See the use of OUTPUT in the workarounds section.