Expected declaration specifiers [closed] - c

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I am learning linked lists in C. I am new to using pass by references for manipulating the linked lists. Now I know I'm doing something really foolish in this program. This program creates a list and then basically returns the number of instances of a particular value(the data of node). I get an error like so, "Expected declaration specifier" before every statement of main!.
What's going on wrong?
#include<stdio.h>
#include<malloc.h>
struct list {
int number;
struct list *next;
};
typedef struct list node;
void create(node *);
int count(node **,int);
main()
int key,this_many;
node *head;
head = (node *)malloc(sizeof(node));
create(head);
printf("Which number?\n");
scanf("%d",&key);
this_many = count(&head,key);
printf("%d times\n",this_many);
return 0;
}
void create(node *list) {
printf("Enter a number -999 to stop\n");
scanf("%d",&list->number);
if(list->number == -999) {
list->next = NULL;
}
else {
list->next = (node *)malloc(sizeof(node));
create(list->next);
}
}
int count(node **addr_list,int key) {
int count = 0;
while(*addr_list != NULL) {
if((*addr_list)->number == key) {
count++;
}
*addr_list = (*addr_list)->next;
}
return(count);
}

Answer 1

Problems:
You are not specifying the return type of main.
You don't have the { to start the scope of main.
Change the lines starting with main to:
int main()
{
int key,this_many;
node *head;
head = (node *)malloc(sizeof(node));
create(head);
printf("Which number?\n");
scanf("%d",&key);
this_many = count(&head,key);
printf("%d times\n",this_many);
return 0;
}