in controller
public function home($id=null){
$this->loadModel('Usermgmt.User');
if(isset($id)){
$groups=$this->User->findAllByuser_group_id($id);
$this->set('groups', $groups);
} else{
echo 'no id';
$users=$this->User->find('all');
$this->set('users', $users);
}
}
here i geeting value which matches the user_group_id and prints here i am geeting more then 10 users but i need to print only 5 on one page and need to give pagination how to give pagination here
view
<?php
if (!empty($groups)) {
// print_r($groups);
$sl=0;
foreach ($groups as $row1) {
//print_r($row1);
$sl++; ?>
<div style="width:100%;display:inline-block;">
<div style="float:left">
<?php
//echo $row1['id'];
echo $this->Html->link($this->Html->image('../files/user/photo/'.$row1 ['User']['photo_dir'].'/'.$row1 ['User']['photo'], array('width' => '180', 'height' => '180')),
array('controller'=>'Profiles','action'=>'index',$row1['User']['id']),
array('escape' => false));
?>
</div>
<div>
<?php echo h($row1['User']['first_name'])." ".h($row1['User']['last_name'])."</br>";
echo h($row1['User']['username'])."</br>";
echo h($row1['User']['email'])."</br>";
echo h($row1['User']['mobile'])."</br>";
echo h($row1['UserGroup']['name'])."</br>";
?></div>
<div style="clear:both;"></div>
</div>
<?php }
}?>
Call paginate
The equivalent paginate call to this:
$groups=$this->User->findAllByuser_group_id($id);
(incidentally - that should be findAllByUserGroupId) is this:
$groups = $this->paginate('User', array('user_group_id' => $id));
Changing default options
To achieve:
i need to print only 5 on one page
Modify the paginate property of your controller, e.g.:
class UsersController extends AppController {
public $paginate = array('limit' => 5);
function home($id = null) {
...
$conditions = array();
if ($id) {
$conditions['user_group_id'] = $id;
}
$groups = $this->paginate('User', $conditions);
...
}
}
View Modifications
In your view, the pagination helper, and the pagination information will automatically be available by calling paginate as shown above. To get pagination links use the pagination helper:
echo $this->Paginator->numbers();
See the documentation for more information and examples of using pagination.
As in cakephp pagination can be done using pagination helper of cakephp
In controller action use $this->paginate . From Model return all parameters like fields, conditions and so on in array format , so now in controller you will write
$data = $this->ModelName->functionname();
$currentPage = isset($_REQUEST['currentpage']) ? $_REQUEST['currentpage'] : '';
$this->paginate = array(
'fields' => $data['fields'],
'conditions' => $data['conditions'],
'order' => $data['order'],
'page' => $currentPage,
'limit' => 25
);
$currentPage is fetched from $_REQUEST['currentpage'];
and finally pass this data to Paginate Helper
$data = $this->paginate('ModelName');
Now in view you will use Pagination functions as shown below
<?php echo $this->Paginator->prev('revious'); ?>
<?php echo $this->Paginator->numbers(); ?>
<?php echo $this->Paginator->next('Next'); ?>
Related
home.ctp
<?php
echo $this->element('distromob/featured');
?>
WebsitesController.php
<?php
class WebsitesController extends AppController {
public $components = array('Paginator');
public function index(){
$images = $this->paginate('Website');
if (isset($this->params['requested'])) {
return $images;
} else {
$this->set('images', $images);
}
}
featured.ctp
<?php
$images = $this->requestAction('/Websites/index');
?>
<ul>
<?php
foreach($images as $image): ?>
<?php $domain = $image['Website']['domain'];?>
<li><?php echo $this->Html->image('websites/' . $image['Website']['image'],array('width'=>'234px','height' =>'208px','class' => 'random'));
?>
</li>
<?php endforeach;?>
</ul>
<?php echo $this->Paginator->prev('« Previous', null, null, array('class' => 'disabled')); ?>
<?php $this->Paginator->counter(); ?>
<?php echo $this->Paginator->next('Next »', null, null, array('class' => 'disabled')); ?>
AppController.php
class AppController extends Controller {
public function beforeFilter(){
$this->Paginator->settings=array(
'limit'=>4
);
}
}
Im new to cakephp I found some tutorial on the web but it seems not fit on my needs. My question was, why is it the previous and the next pagination data is not clickable, It seems that the pagination data is base on the limit i set on
public function beforeFilter(){
$this->Paginator->settings=array(
'limit'=>4
);
}
whenever i change the limit it will also display data but i cannot click the next and the previous
make the pagination data available in the element i.e $this->params['paging']
//index method
if ($this->params['requested'])
return array('images'=>$this->paginate('WebSite'), 'paging' => $this->params['paging']);
$this->set('images', $this->paginate('WebSite') );
then in your home.ctp do this
$images = $this->requestAction(array('controller'=>'websites','action'=>'index'));
// if the 'paging' variable is populated, merge it with the already present paging variable in $this->params. This will make sure the PaginatorHelper works
if(!isset($this->params['paging'])) $this->params['paging'] = array();
$this->params['paging'] = Hash::merge( $this->params['paging'] , $images['paging'] );
Try replacing ->counter() with ->numbers() to see if you have any page numbers
I am trying to add pagination in CakePHP 2.x with condition search in a form. However, in the View it doesn't give the next page with my condition. Here is my code:
Controller
public function result($palabraclave = null)
{
$this->layout = 'tempart';
$this->paginate = array(
'limit' => 5,
'order' => array(
'Articulo.created' => 'desc'),
'conditions'=>array("titulo like ?"=>"%".$this->data['Paginas']['palabraclave']."%")
)
$data = $this->paginate('Articulo');//Consulta a la base de datos
$this->set(compact('data'));
}
If I click "next" to see the next page result of the search, it doesn't pass on the pagination condition from page 1 to page 2. :(
View:
<div style="display: inline-block; width:70%;" id="test">
<?php foreach ($data as $da): ?>
<br />
<article>
<?php echo $this->Html->image('article_preview/mini_'.$da['Articulo']['imagen'], array('alt' => 'Hospital-Excel'))?>
<div style="text-align:left;">
<?php echo $this->Html->link("<h6 class='artnombre'>".$da['Articulo']['titulo']."<h6>", array('class'=>"artnombre",'action'=> 'articulo',$da['Articulo']['id']),array('escape' => false)); ?>
</div>
<br />
<p>
<?php echo $da['Articulo']['descripcion']; ?> <?php echo $this->Html->link('Read more ....', array('action'=> 'articulo',$da['Articulo']['id'])); ?>
<h5></h5>
</p>
<div class="puntoshorizontal" style="clear"></div>
</article>
<?php endforeach; ?>
<div style="text-align:center">
<?php
// Shows the page numbers
// Shows the next and previous links
echo $this->Paginator->prev('« Back', null, null, array('class' => 'disabled')) . " |";
echo $this->Paginator->numbers(). "| ";
echo $this->Paginator->next('Next »', null, null, array('class' => 'disabled'));
echo "<br />";
echo $this->Paginator->counter();
// prints X of Y, where X is current page and Y is number of pages
?>
</div>
</div>
a way to persist your search params on each page you should do the following:
After you post data, in your method you have $this->data['Paginas']['palabraClave'] then save it the the session. So in each subsequent call to /resultados/pag1,2,..n you get the value of palabra clave from the session.
Finally you would get something like:
public function resultados(){
$conditions = array();
if($this->Session->check('conditions')){
$conditions = $this->Session->read('conditions');
}
if(isset($this->data)){
$conditions = array("titulo LIKE" => "%".this->data['Paginas']'palabraclave']"%",));
//save to the session
$this->Session->write('conditions',$conditions);
}
$data = $this->painate('Articulo',$conditions);
$this->set('data');
}
This may need some adjust but the idea I think is clear.
Set your paginate conditions when calling the paginate method, like this:
$data = $this->paginate('Articulo', array(
"titulo LIKE" => "%" . $this->data['Paginas']['palabraclave'] . "%",
));
as opposed to in the paginate property.
this is example:
1: pass all URL arguments to paginator functions
$this->Paginator->options(array('url' => $this->passedArgs));
2: Common mistake: not keep condition search with paginate
if($this->data){
$this->passedArgs = array(
'name' => $this->data[‘User’]['name']
);
}else{
if(isset($this->passedArgs['name'])){
$this->data[‘User’]['name'] = $this->passedArgs['name'];
}else{
$this->data[‘User’]['name'] = ;
}
}
I try to create an Ajax search with CakePHP using the JsHelper. The Ajax request triggers but it never returns values:
Search form (find_entries.ctp):
<?php echo $this->Form->create('Entry');?>
<?php echo $this->Form->input('title', array('div' => false, 'empty', 'label' => false, 'placeholder' => 'Search'));?>
<?php echo $this->Js->submit('Upload', array(
'before'=>$this->Js->get('#checking')->effect('fadeIn'),
'success'=>$this->Js->get('#checking')->effect('fadeOut'),
'update'=>'#choose_options')
)
;?>
<?php echo $this->Form->end();?>
Controller:
public function find_entries(){
if(!empty($this->request->data)){
$entries = $this->Entry->find('all', array('conditions' => array('Entry.title' => $this->request->data['Entry']['title);
$this->set('entries', $entries);
if($this->RequestHandler->isAjax()){
$this->render('entries', 'ajax');
}
}
}
Partial to render (entries.ctp)
<div id="entries">
<?php foreach ($entries as $entry) :?>
<?php echo $entry['Entry']['title']; ?>
<?php endforeach ;?>
What goes wrong here? thanks!
have you created any div tag with id choose_options to render the ajax result? If not create a div tag like this in the view file.
<div id="choose_options"></div>
I am trying to finish this website in cake php that was previously in regular php, but as newbie in the cakephp world.. I have found some difficulties such as these.
1) .When I click on login, it transfers me to another page although i have specified no redirects in app controller except when there is a registration. The login is at the top and its viewable through out all the pages, but if i click login, it redirects me to the login page (which i do not want).
2.) After I login, it brings in the session with the user name saying welcome 'username' but then if I go to another page, it seems like it forgets the session and brings back the inputs for the login form at the top of the page.
Here is my code
app_controller
<?php
class AppController extends Controller {
var $helpers = array('Html', 'Form', 'Javascript', 'Session');
var $components = array('Auth', 'Session');
function beforeFilter() {
$this->Auth->allow('add','get_categories','get_home', 'get_others', 'pages');
$this->Auth->autoRedirect = false;
}
}
?>
UsersController
<?php
class UsersController extends AppController {
var $uses = array("User");
var $components = array('Auth', 'Session');
function index()
{
$this->set('users', $this->User->find('all'));
$this->layout = 'master_layout';
}
function add() {
if (!empty($this->data)) {
//pass is hashed already
//->data['User']['password'] = $this->Auth->password($this->data['User']['password']);
if ($this->User->save($this->data)) {
$this->Session->setFlash('Your were registered!.');
$this->redirect(array('action' => 'get_home'));
}
}
$this->layout = 'master_layout';
}
//IF THE DATABASE IS SET UP CORRECTLY CAKE AUTHENTICATES AUTOMATICALLY NO
//LOGIC IS NEEDED FOR LOGIN http://book.cakephp.org/view/1250/Authentication
function login() {
$this->layout = 'master_layout';
if ($this->data) {
if ($this->Auth->login($this->data)) {
// Retrieve user data
$results = $this->User->find(array('User.username' => $this->data['User']['username']), array('User.active'), null, false);
$this->redirect(array('controller' => 'users', 'action' => 'login'));
}
}
$this->data['User']['password'] = '';
}
function logout() {
$this->redirect($this->Auth->logout());
}
}
?>
elements/loginform.ctp
<?php
if ($this->Session->read('Auth.User.username')):?>
<?php
echo "Welcome".' ' ;
echo $this->Session->read('Auth.User.username');
echo " ";
echo $html->link('logout', array('action'=>'logout'));
?>
<?php else : ?>
<div class="types form">
<?php echo $form->create('User', array('controller' => 'Users','action' => 'login')); ?>
<?php echo $form->input('username', array('label' => 'username')); ?>
<?php echo $form->input('password',array('type'=>'password', 'label' => 'password')) ?>
<?php echo $form->submit('Submit'); ?>
</div>
<?php endif; ?>
UPDATE
I added the following to the app_controller
<?php
class AppController extends Controller {
var $helpers = array('Html', 'Form', 'Javascript', 'Session');
var $components = array('Auth', 'Session');
function beforeFilter() {
//new addition
$this->set('userData', $this->Session->read());
$this->Auth->allow('add','get_categories','get_home', 'get_others', 'pages', '*');
$this->Auth->autoRedirect = false;
}
}
?>
WHEN I LOGIN I GET THIS ARRAY
Array ( [Config] => Array
( [userAgent] => 8f12200c2d48fa7955465842befe1c9e
[time] => 1323562284 [timeout] => 10 )
[Auth] => Array (
[User] => Array (
[id] => 63
[user_role] => 2 [
[user_fname] => test
[user_lname] => test
[user_email] => test#test.com
[user_phone] => 677-988-7777
[user_cellphone] => 555-456-9999
[user_address1] => 1st Avenue
[user_address2] =>
[user_city] => Citiland FL
[user_zip] => 55555
[username] => admin2 ) ) )
BUT WHEN I NAVIGATE TO A NEW PAGE
Array ( [Config] => Array (
[userAgent] => 8f12200c2d48fa7955465842befe1c9e
[time] => 1323562591 [timeout] => 10 ) )
ADDED PRINT_R TO elements/loginform TO SEE THE VARIABLE CONTENTS ACROSS ALL PAGES
<?php
print_r($userData);
if ($this->Session->read('Auth.User.username')):?>
<?php
echo "Welcome".' ' ;
echo $this->Session->read('Auth.User.username');
echo " ";
echo $html->link('logout', array('action'=>'logout'));
?>
<?php else : ?>
<div class="types form">
<?php echo $form->create('User', array('controller' => 'Users','action' => 'login')); ?>
<?php echo $form->input('username', array('label' => 'username')); ?>
<?php echo $form->input('password',array('type'=>'password', 'label' => 'password')) ?>
<?php echo $form->submit('Submit'); ?>
</div>
<?php endif; ?>
1) This is because in your UsersController you have a redirect after the user is logged in.
Your login function should instead read:
function login() {
$this->layout = 'master_layout';
if ($this->data) {
if ($this->Auth->login($this->data)) {
// Retrieve user data
$results = $this->User->find(array('User.username' => $this->data['User']['username']), array('User.active'), null, false);
/*This is the offending line, I've commented it out, but you could have it redirect somewhere else (it might be a good idea to redirect to the index action, for example, or just delete it:*/
//$this->redirect(array('controller' => 'users', 'action' => 'login'));
}
}
$this->data['User']['password'] = '';
}
As for 2), I believe it may be because you are not setting the data afterwards, so that while it exists in a tmp directory on the server (using the Session component) it is not actually being passed along to the view. So basically I think it's because you can't call Session methods in the view. Even if I'm not entirely correct about that, what I'm suggesting to do should work: Instead of calling session methods in the view, call them in the controller, set them in a variable for the view to access using $this->set();, then test against that variable in the view.
If you need to do this for ton of views and actions, you could consider adding something like this to your controller or even your app controller:
function beforeFilter() {
// Get session data for appllication use
$this->appuserstuff = $this->Session->read();
}
function beforeRender() {
// Make app variables available to view
$this->set('userData', $this->appuserstuff);
}
Alternatively, if you just need this in a couple actions, you could just set the user data in those actions with a:
$this->set('userData', $this->Session->read());
Now I'd recommend that you do a <?php debug($userData); ?> in one of your views so you can see how the data is structured in the array when it is set, so that you can user or test conditionals against. Finally, you could replace the direct calls to Session in your view with instead checks against the array of data:
Please note that I'm not sure how your specific array is structured so do a debug as recommended above and plug in your own keys for it to work:
<?php
if (!empty($userData['User'])):?>
<?php
echo "Welcome".' ' ;
echo $userData['User']['username'];
echo " ";
echo $html->link('logout', array('action'=>'logout'));
?>
<?php else : ?>
<div class="types form">
<?php echo $form->create('User', array('controller' => 'Users','action' => 'login')); ?>
<?php echo $form->input('username', array('label' => 'username')); ?>
<?php echo $form->input('password',array('type'=>'password', 'label' => 'password')) ?>
<?php echo $form->submit('Submit'); ?>
</div>
<?php endif; ?>
My objective is to display records for a related child model (once removed) in the view. My problem is that I receive a 'Notice (8): Undefined index:' error message when I try to output the following query.
Tournaments have many tournamentDetails, and tournamentDetails have many updates. I'm trying to display all the updates for each tournamentDetail that is displayed on the tournaments view.
So my question is how to properly resolve the error message and display the updates for each tournamentDetail on the tournaments view page.
My find data in the 'tournaments' controller view action is:
$updates = $this->Tournament->TournamentDetail->Update->find('all', array( 'tournament_details.tournament_id'=> $this->data['Tournament']['id']));
In the view, I have this code.
<?php foreach ($tournament['Update'] as $update): ?>
<h3>Updates</h3>
<h1><?php echo $update ['title']; ?></h1>
<p><?php echo $update ['body']; ?></p>
<hr/>
<?php endforeach; ?>
This is the same 'foreach' code the I use for the other related child records without problem. I did use the debug() function to investigate but didn't see what I was missing.
The output of the $updates array from the debug function looks like this:
Array
(
[0] => Array
(
[Update] => Array
(
[id] => 1
[title] => first round matches start today
[date] => 2010-03-19
[body] => this tournament's first round matches start today.
[tournament_detail_id] => 4
[homeStatus] => no
)
Is there a special way to display records this deep?
As always, thanks in advance.
Paul
Update: Feb 23/11
After some testing the problem I seem to have is finding and passing the correct value to the $updates variable;
To summarize, I want the $updates variable to hold the current 'tournament_details_id'. This will then display the related update records in the 'tournaments' view.
I'm still a beginner and most likely overlooked the obvious.
Here is the model info:
class Tournament extends AppModel {
var $name = 'Tournament';
var $hasMany = array(
'TournamentDetail' => array(
'className' => 'TournamentDetail',
'foreignKey' => 'tournament_id',)
class TournamentDetail extends AppModel {
var $name = 'TournamentDetail';
var $belongsTo = array(
'Tournament' => array(
'className' => 'Tournament',
'foreignKey' => 'tournament_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
class Update extends AppModel {
var $name = 'Update';
var $belongsTo = array(
'TournamentDetails' => array(
'className' => 'TournamentDetails',
'foreignKey' => 'tournament_detail_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
Controller data:
class TournamentsController extends AppController
function view($slug = null) {
if (!$slug) {
$this->Session->setFlash(__('Invalid Tournament.', true));
$this->redirect(array('action'=>'index'));
}
$this->Tournament->recursive = 1;
$tournament = $this->Tournament->findBySlug($slug);
$updates = $this->Tournament->TournamentDetail->Update->find('all', array('conditions' => array( 'tournament_details_id' => $this->data['TournamentDetails']['id'] )));
$this->set(compact('tournament','updates', $updates ));
Tournament view. This is display the 'tournament details' and (ideally) related tournament detail 'updates'
<h2><?php echo $tournament['Tournament']['name']; ?></h2>
<?php foreach ($tournament['TournamentDetail'] as $tournamentDetail): ?>
<h1><?php echo $tournamentDetail ['title']; ?></h1>
<p><?php echo $tournamentDetail ['body']; ?></p>
<?php endforeach; ?>
<?php foreach ($updates['Update'] as $update): ?>
<h4>Update: <?php echo $update ['date']; ?></h4>
<p> <?php echo $update ['Update'] ['title']; ?></p>
<p><?php echo $update ['Update'] ['body']; ?></p>
<?php endforeach; ?>
I've tested this by adding in the tournament details 'id' as an integer and it pulls up the correct 'update' record. However I seem to have problems configuring the find operation to do the same.
As always I appreciate the help.
Thanks
Paul
Based on your debug output, it seems that your $tournaments variable consists of an array (instead of the associative array) so you might want to use the foreach to access each of those elements:
foreach ($tournaments as $update):
?>
<h3>Updates</h3>
<h1><?php echo $update ['Update']['title']; ?></h1>
<p><?php echo $update ['Update']['body']; ?></p>
<hr/>
<?php endforeach; ?>
It appears that you be using the wrong variable, you talk about the $updates variable but you're using the $tournament variable in your view.
<?php foreach ($updates['Update'] as $update): ?>
<h3>Updates</h3>
<h1><?php echo $update ['title']; ?></h1>
<p><?php echo $update ['body']; ?></p>
<hr/>
<?php endforeach; ?>
Additionally you haven't posted the whole controller method, which includes that find but you might not have sent the data to the view yet either
$this->set(compact('updates'));