I want records from table which stores the current date when a record is inserted with in current week only.
I have tried:
SELECT PId
,WorkDate
,Hours
,EmpId
FROM Acb
WHERE EmpId=#EmpId AND WorkDate BETWEEN DATEADD(DAY, -7, GETDATE()) AND GETDATE()
Do it like this:
SET DATEFIRST 1 -- Define beginning of week as Monday
SELECT [...]
AND WorkDate >= dateadd(day, 1-datepart(dw, getdate()), CONVERT(date,getdate()))
AND WorkDate < dateadd(day, 8-datepart(dw, getdate()), CONVERT(date,getdate()))
Explanation:
datepart(dw, getdate()) will return the number of the day in the current week, from 1 to 7, starting with whatever you specified using SET DATEFIRST.
dateadd(day, 1-datepart(dw, getdate()), getdate()) subtracts the necessary number of days to reach the beginning of the current week
CONVERT(date,getdate()) is used to remove the time portion of GETDATE(), because you want data beginning at midnight.
A better way would be
select datepart(ww, getdate()) as CurrentWeek
You can also use wk instead of ww.
Datepart Documentation
Its Working For Me.
Select * From Acb Where WorkDate BETWEEN DATEADD(DAY, -7, GETDATE()) AND DATEADD(DAY, 1, GETDATE())
You have to put this line After the AND Clause AND DATEADD(DAY, 1, GETDATE())
datepart(dw, getdate()) is the current day of the week, dateadd(day, 1-datepart(dw, getdate()), getdate()) should be the first day of the week, add 7 to it to get the last day of the week
You can use following query to extract current week:
select datepart(dw, getdate()) as CurrentWeek
SET DATEFIRST 1;
;With CTE
AS
(
SELECT
FORMAT(CreatedDate, 'MMMM-yyyy') as Months,
CASE
WHEN YEAR(DATEADD(DAY, 1-DATEPART(WEEKDAY, Min(CreatedDate)), Min(CreatedDate))) < YEAR(Min(CreatedDate))
THEN FORMAT(DATEADD(YEAR, DATEDIFF(YEAR, 0,DATEADD(YEAR, 0 ,GETDATE())), 0) ,'MMM dd') + ' - ' + FORMAT(DATEADD(dd, 7-(DATEPART(dw, Min(CreatedDate))), Min(CreatedDate)) ,'MMM dd')
ELSE
FORMAT(DATEADD(DAY, 1-DATEPART(WEEKDAY, Min(CreatedDate)), Min(CreatedDate)) ,'MMM dd') + ' - ' + FORMAT(DATEADD(dd, 7-(DATEPART(dw, Min(CreatedDate))), Min(CreatedDate)) ,'MMM dd')
END DateRange,
Sum(ISNULL(Total,0)) AS Total,
sum(cast(Duration as int)) as Duration
FROM TL_VriandOPI_Vendorbilling where VendorId=#userID and CompanyId=#CompanyID
Group By DATEPART(wk, CreatedDate) ,FORMAT(CreatedDate, 'MMMM-yyyy')
)
SELECT Months,DateRange,Total,Duration,
case when DateRange=(select FORMAT(DATEADD(DAY, 1-DATEPART(WEEKDAY, Min(getdate())), Min(getdate())) ,'MMM dd') + ' - ' +
FORMAT(DATEADD(dd, 7-(DATEPART(dw, Min(getdate()))), Min(getdate())) ,'MMM dd'))
then 1 else 0 end as Thisweek
FROM CTE order by Months desc
Using DATEDIFF works as well, however a bit hacky since it doesn't care about datefirst:
set datefirst 1; -- set monday as first day of week
declare #Now datetime = '2020-09-28 11:00';
select *
into #Temp
from
(select 1 as Nbr, '2020-09-22 10:00' as Created
union
select 2 as Nbr, '2020-09-25 10:00' as Created
union
select 2 as Nbr, '2020-09-28 10:00' as Created) t
select * from #Temp where DATEDIFF(ww, dateadd(dd, -##datefirst, Created), dateadd(dd, -##datefirst, #Now)) = 0 -- returns 1 result
select * from #Temp where DATEDIFF(ww, dateadd(dd, -##datefirst, Created), dateadd(dd, -##datefirst, #Now)) = 1 -- returns 2 results
drop table #Temp
Related
Suppose now we are in September, I want output of the last Saturday date in the previous month, August, where 28-08-2021 falls under last Saturday of previous month in SQL Server
..fiddle..
select *, datename(weekday, pmlsat), dateadd(week, 1, pmlsat)
from
(
select _date,
--last saturday of previous month
dateadd(day, -datepart(weekday, dateadd(day, ##datefirst, eomonth(_date, -1)))%7, eomonth(_date, -1)) as pmlsat
from
(
select top(100) dateadd(month, row_number() over(order by ##spid), '20141215') as _date
from sys.all_objects
) as d
) as p
order by _date;
DECLARE #date1 DATETIME
SET #date1='2021-8-31'
WHILE Day(#date1) >= 1
BEGIN
IF (SELECT Datename(weekday, #date1)) = 'Saturday'
BREAK
SET #date1=Dateadd(dd, -1, #date1)
CONTINUE
END
SELECT Datename(weekday, #date1) AS 'Datename',
(SELECT CONVERT(NVARCHAR(20), #date1, 23)) AS 'DATE'
First, let's talk about how to get the beginning of this month. There are a multiple ways, I find DATEFROMPARTS() the most intuitive (see Simplify Date Period Calculations in SQL Server):
DECLARE #FirstOfMonth date = DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 1);
SELECT #FirstOfMonth;
-- result:
-- 2021-09-01
Now, the last Saturday in the previous month must be between 1 and 7 days before the first of this month. So we can generate a sequence of 7 consecutive numbers, and subtract those days from the first of the month, like this:
DECLARE #FirstOfMonth date = DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 1);
SELECT #FirstOfMonth;
;WITH n(n) AS
(
SELECT 1 UNION ALL
SELECT n + 1 FROM n WHERE n < 7
)
SELECT d = DATEADD(DAY, -n, #FirstOfMonth) FROM n;
/* result:
2021-08-31
2021-08-30
2021-08-29
2021-08-28
2021-08-27
2021-08-26
2021-08-25 */
To determine what a Saturday is, you either need to rely on DATEPART(WEEKDAY, date) - which in turn is affected by SET DATEFIRST, or you need to rely on DATENAME(WEEKDAY, date) - which in turn is affected by SET LANGUAGE. I will err toward language being more stable (English), so:
DECLARE #FirstOfMonth date = DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 1);
SELECT #FirstOfMonth;
;WITH n(n) AS
(
SELECT 1 UNION ALL
SELECT n + 1 FROM n WHERE n < 7
),
d(d) AS
(
SELECT DATEADD(DAY, -n, #FirstOfMonth)
FROM n
)
SELECT LastMonthLastSaturday = d
FROM d
WHERE DATENAME(WEEKDAY, d) = 'Saturday';
-- result:
-- 2021-08-28
But that is a subjective call - if you can't rely on one of those, get a calendar table, then it's simply something like:
SELECT LastMonthLastSaturday = MAX(TheDate)
FROM dbo.Calendar
WHERE TheDayOfWeekName = 'Saturday'
AND TheDate < DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 1);
How can I get the date of specific day ? Like if I have Thursday or month number ?
If I give 12 for instance I want to get the date of 12th day of this month. Or if I give 'Sun' or 'Sat' is it possible to get the dates of these days ?
DATEFROMPARTS function can construct a date from day, month and year.
DATEPARTS does the opposite - gives you the day, month, year, hour, etc. of a date. Or you can use functions like YEAR, MONTH and DAY.
You can deconstruct the value returned by GETDATE function and construct whatever date you want. Here is for example how to get the date for 12th day of the current month:
select DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), 12)
Converting 'Sun' or 'Sat' to date is a bit more difficult. First, they aren't quite deterministic. If today is Friday, "Sunday this week" means "next Sunday" in some parts of the world and "last Sunday" in others. You should implement your own logic based on the value returned by DATEPART(dw, GETDATE()) (which will give you the day of the week).
To find the weekday of the current month
DECLARE #daynumber INT = 12
SELECT datename(weekday, dateadd(d, #daynumber - 1, getdate()))
To find the dates of the current month of a given weekday
DECLARE #dayname char(3) = 'sat'
;WITH CTE as
(
SELECt TOP
(datediff(D, eomonth(getdate(), -1),eomonth(getdate())))
dateadd(d,row_number()over(ORDER BY 1/0),
eomonth(getdate(),-1))date
FROM
(values(1),(2),(3),(4),(5),(6))x(x),
(values(1),(2),(3),(4),(5),(6))y(x)
)
SELECT day(date) monthday, date
FROM CTE
WHERE left(datename(weekday, date),3) = #dayname
select sysdatetime(); --2018-12-13 16:29:56.0560574
---If I give 12 for instance I want to get the date of 12th day of this month.
declare #numDate int = 12;
select dateadd(m, datediff(m,0,getdate()),#numDate - 1 ); --2018-12-12 00:00:00.000
--Or if I give 'Sun' or 'Sat' is it possible to get the dates of these days ?
declare #text nvarchar(20) = 'Sunday';
declare #dateStart date = dateadd(month, datediff(month, 0, sysdatetime()), 0),
#days int =( select (DAY(dateadd(dd,-1,DATEADD(m,1,cast(2018 as varchar(4)) + '-' + cast(12 as varchar(2)) +'-01')))));
declare #dateEnd date = DATEADD(day,#days-1,#dateStart);
;WITH CTE (Dates,EndDate) AS
(
SELECT #dateStart AS Dates,#dateEnd AS EndDate
UNION ALL
SELECT DATEADD(day,1,Dates),EndDate
FROM CTE
WHERE DATEADD(day,1,Dates) <= EndDate
)
SELECT CTE.Dates, DATENAME(DW, CTE.Dates)
FROM CTE
where DATENAME(DW, CTE.Dates) = #text;
Result:
Dates,Day
2018/12/2,Sunday
2018/12/9,Sunday
2018/12/16,Sunday
2018/12/23,Sunday
2018/12/30,Sunday
-- Here is how to get week day name to week day number
DECLARE #T TABLE (Dow INT, NameOfDay VARCHAR(15), ShortName CHAR(3));
WITH Days AS
(
SELECT TOP 7
ROW_NUMBER() OVER(PARTITION BY object_id ORDER BY object_id) AS RowNo
FROM
sys.all_columns
)
INSERT INTO #T
SELECT
RowNo,
DATENAME(WEEKDAY, RowNo - 1),
LEFT(DATENAME(WEEKDAY, RowNo - 1), 3)
FROM
Days
SELECT
*
FROM
#T;
-- Here is how to get start of period
SELECT
DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), 0) AS StartOfDay,
DATEADD(WEEK, DATEDIFF(WEEK, 0, GETDATE()), 0) AS StartOfWeek,
DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) AS StartOfMonth,
DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()), 0) AS StartOfYear;
-- An example
WITH
StartPeriods AS
(
SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, GETDATE()), 0) AS StartOfWeek
),
SelectedDay AS
(
SELECT
Dow - 1 AS Dow,
(SELECT StartOfWeek FROM StartPeriods) AS StartOfWeek
FROM
#T
WHERE
ShortName = 'Wed'
)
SELECT
DATEADD(DAY, Dow, StartOfWeek)
FROM
SelectedDay;
Can I find the date of a day that is on which dates the Saturdays and Sundays of a specific month fall? For e.g consider the month of JANUARY-2017. The following dates are weekend days:
7/1/2017 - Saturday
14/1/2017 - Saturday
21/1/2017 - Saturday
28/1/2017 - Saturday
1/1/2017 - Sunday
8/1/2017 - Sunday
15/1/2017 - Sunday
22/1/2017 - Sunday
29/1/2017 - Sunday
I want a SQL Server query for this such that when I pass in month and year as input, I should get back all the above dates (only dates of Saturday and Sunday) as output
I do not wish to use any user defined function and want to finish it in a single SELECT statement
Note: As already noted by another user in the comments, this query depends upon your server settings, namely DATEFIRST. If you need alterations to the query because of different settings, just tell me and I can change it around for you.
Using a CTE as dummy data...
/* Ignore this part...*/
WITH CTE AS
(
SELECT CAST('01/01/2017' AS DATE) AS [Date]
UNION ALL
SELECT DATEADD(DAY,1,[Date])
FROM CTE
WHERE DATE <= '12/31/2017'
)
/*Your actual SELECT statement would look like this, from your own table of course*/
SELECT
[Date]
,CASE DATEPART(dw,[Date])
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
FROM CTE
WHERE DATEPART(dw,[Date]) IN (1,7)
AND MONTH([Date]) = 12--<month>
AND YEAR([Date]) = 2017--<year>
OPTION (MAXRECURSION 0) -- You won't need this line if you're querying a real table
;
If running that works for you, then your real query would probably look something like this:
SELECT
[Date]
,CASE DATEPART(dw,[Date])
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
FROM < the table you want >
WHERE DATEPART(dw,[Date]) IN (1,7) -- Only Sundays and Saturdays
AND MONTH([Date]) = < the month you want >
AND YEAR([Date]) = < the year you want >
;
If you want to generate the data, then a CTE is the way to go. If you're passing parameters, it would look something like this:
DECLARE
#MONTH INT
,#YEAR INT
;
SET #MONTH = 1;
SET #YEAR = 2017;
WITH CTE AS
(
SELECT CAST(CAST(#MONTH AS VARCHAR(2)) + '/01/' + CAST(#YEAR AS VARCHAR(4)) AS [Date]) AS DATE
UNION ALL
SELECT DATEADD(DAY,1,[Date])
FROM CTE
WHERE DATE <= CAST(#MONTH AS VARCHAR(2)) +
CASE
WHEN #MONTH IN (9,4,6,11)
THEN '/30/'
WHEN #MONTH IN (1,3,5,7,8,10,12)
THEN '/31/'
WHEN #MONTH = 2 AND #YEAR/4.00 = #YEAR/4
THEN '/29/'
ELSE '/28/'
END
+ CAST(#YEAR AS VARCHAR(4))
)
SELECT
[Date]
,CASE DATEPART(dw,[Date])
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
FROM CTE
WHERE DATEPART(dw,[Date]) IN (1,7)
OPTION (MAXRECURSION 0)
;
Please try this one.
DECLARE #Year AS INT=2017,
#Month AS INT=3,
#FirstDateOfYear DATETIME,
#LastDateOfYear DATETIME
SELECT #FirstDateOfYear = DATEADD(yyyy, #Year - 1900, 0)
SELECT #LastDateOfYear = DATEADD(yyyy, #Year - 1900 + 1, 0)
-- Creating Query to Prepare Year Data
;WITH cte AS (
SELECT 1 AS DayID,
#FirstDateOfYear AS FromDate,
DATENAME(dw, #FirstDateOfYear) AS Dayname
UNION ALL
SELECT cte.DayID + 1 AS DayID,
DATEADD(d, 1 ,cte.FromDate),
DATENAME(dw, DATEADD(d, 1 ,cte.FromDate)) AS Dayname
FROM cte
WHERE DATEADD(d,1,cte.FromDate) < #LastDateOfYear
)
SELECT FromDate AS Date, Dayname
FROM CTE
WHERE DayName IN ('Saturday','Sunday') and month(FromDate) = #Month
OPTION (MaxRecursion 370)
This should do the trick:
DECLARE #month date = '2017-01-01'
SET #month = dateadd(month, datediff(month, 0, #month), 0)
;WITH CTE as
(
SELECT 0 x
FROM (values(1),(1),(1),(1),(1),(1)) x(n)
),
CTE2 as
(
SELECT
top(day(eomonth(#month)))
-- use this syntax for sqlserver 2008
-- top(datediff(d, #month,dateadd(month,1,#month)))
cast(dateadd(d, row_number()over(order by(select 1))-1,#month) as date) cDate
FROM CTE CROSS JOIN CTE C2
)
SELECT
cDate,
datename(weekday, cDate) Weekday
FROM CTE2
WHERE
datediff(d,0,cDate)%7 > 4
Fiddle
From https://www.sqlservercentral.com/articles/finding-the-correct-weekday-regardless-of-datefirst, you simply:
(DATEPART(dw, #your_date) + ##DATEFIRST) % 7 NOT BETWEEN 2 AND 6
As requested, single select, language neutral, dateFirst neutral, almost SQL version neutral:
declare #OneDate datetime = '28/01/2017'; -- Any date from the target month/year
select MyDate -- raw date or ...
-- convert(varchar, MyDate, 103) + ' - ' + dateName(dw, MyDate) -- as Sample
as WeekEndDate
from (
select dateAdd(dd, number, dateAdd(mm, dateDiff(mm, 0, #OneDate), 0)) as MyDate
from master..spt_values
where type = 'P' and number < 31
) j
where 1 + (datePart(dw, MyDate) + ##DATEFIRST + 5) % 7 in (6, 7)
and month(MyDate) = month(#OneDate)
-- order by 1 + (datePart(dw, MyDate) + ##DATEFIRST + 5) % 7, MyDate -- as Sample
;
Another way to solve this problem as follow -
DECLARE #MONTH INT,#YEAR INT
SET #MONTH = 1;
SET #YEAR = 2017;
Declare #StartDate date =CAST(CAST(#MONTH AS VARCHAR(2)) + '/01/' + CAST(#YEAR AS VARCHAR(4)) AS [Date]), #EndDate date
Set #EndDate = EOMONTH(#StartDate)
Declare #Temp table (DateOfDay date, DaysName varchar(50))
While(#StartDate <= #EndDate)
Begin
Insert into #Temp
SELECT #StartDate DateOfMonth,
case when DATENAME(DW, #StartDate) = 'Saturday' then DATENAME(DW, #StartDate)
when DATENAME(DW, #StartDate) = 'Sunday' then DATENAME(DW, #StartDate)
end DaysName
set #StartDate = DATEADD(d,1,#StartDate)
End
select * from #Temp where DaysName is not null order by DaysName, DateOfDay
Can't you do something like this?
SELECT DATENAME(dw,'10/11/2016') AS DATE
WHERE DATE CONTAINS('Saturday') OR DATE CONTAINS('SUNDAY')
and instead of '10/11/2016' you only have to figure out how to generate all the dates in a month/year?
What I want is the EmployeeName from the emp_mst table with some condition which is given below:-
All EmployeeName for last 7 months from the current date and also less 15 days.
from the below query I am getting the result for the last month, but I want this for the last 6 months
select DATEADD(month, -1, GETDATE()- 15)
I am using sql server 2008
UPDATED PROCEDURE
SELECT * FROM (SELECT CASE
WHEN (SELECT Isnull(Sum(total_day), 0)
FROM xxacl_erp_ab_pl_count_view
WHERE emp_card_no = em.emp_card_no) > 7 THEN
'DOC Exteded By 1 month. Reason:- Taken leave='
+ CONVERT(VARCHAR, (SELECT Sum(total_day) FROM
xxacl_erp_ab_pl_count_view
WHERE emp_card_no = em.emp_card_no))
+
' which is > 7. Actual DOC='
+ CONVERT(VARCHAR, Dateadd(mm, em.probation_period, em.date_of_joining), 103)
+ ''
ELSE 'N/A'
END Remark,
em.*
FROM emp_mst em
LEFT JOIN company_mst comp
ON em.comp_mkey = comp.mkey
AND comp.fa_year = 2008
AND company_name NOT LIKE '%HELIK%'
WHERE em.status IN ( 'A' ) --and em.emp_type='E'
AND em.emp_card_no != 9999
AND em.resig_date IS NULL
AND CONVERT(DATETIME, em.date_of_joining, 103) >=
CONVERT(DATETIME,
Dateadd(m, -6, Getdate()), 103)
AND em.emp_card_no NOT IN (SELECT emp_card_no
FROM p_emp_confirmation_hdr
WHERE delete_flag = 'N'
AND hr_flag = 'Y')) pp
WHERE remark = 'N/A'
Casting to date to avoid calculating with timestamps
WHERE
yourdate >= dateadd(m, -6, datediff(d, 15, getdate())) and
yourdate < dateadd(d, -15, datediff(d, 0, getdate()))
Changed answer to adjust for you using sqlserver 2005 or older
Added 15 days extra to the interval
SELECT [emp_name]
FROM [TABLE]
WHERE [DateColumn] BETWEEN DATEADD(MONTH, -6, CAST(GETDATE() AS DATE))
AND DATEADD(DAY, -15, CAST(GETDATE() AS DATE))
This will show you employees who were added between six months ago and 15 days ago, for example, running that today would give you employees from the range 2014-12-24 and 2015-06-09.
EDIT: For SQL Server 2005 and earlier:
SELECT [emp_name]
FROM [TABLE]
WHERE [DateColumn] BETWEEN DATEADD(MONTH, -6, cast(convert(char(11), getdate(), 113) as datetime))
AND DATEADD(DAY, -15, cast(convert(char(11), getdate(), 113) as datetime))
hi i want to find the total days of two month and split the days for month wise..for example...
26-02-2013 to 3-3-2013
here for the february month it shows 2days leave but march month i wont display the total leave..this is my query..can anyone correct my query..it shows only febraury days only,,march days is not shown here..
SELECT month(fdate) as Month_Number
, datename(month, fdate) as Month
, case when month(fdate) <> month(tdate) then
datediff(day, fdate, DATEADD(month, ((YEAR(fdate) - 1900) * 12) + MONTH(fdate), -1))
else
datediff(day, fdate, tdate)
end as Leaves
from test
where empid like '112'
Try this, it will display the number of days for each month:
SELECT *
, DATEADD(DAY, -1, DATEADD(MONTH, DATEDIFF(MONTH, 0, t.fdate) + 1, 0)) Last_In_Month_Of_Beginning
, DATEADD(MONTH, DATEDIFF(MONTH, 0, t.tdate), 0) First_In_Month_Of_End
INTO #temp1
FROM test t
WHERE empid LIKE '112'
SELECT number Month_Number
, CASE
WHEN MONTH(fdate) = MONTH(tdate) THEN DATEDIFF(DAY, fdate, tdate) - 1
WHEN MONTH(Last_In_Month_Of_Beginning) = number THEN DATEDIFF(DAY, fdate, Last_In_Month_Of_Beginning)
WHEN MONTH(First_In_Month_Of_End) = number THEN DATEDIFF(DAY, First_In_Month_Of_End, tdate)
END Leave
INTO #temp2
FROM #temp1 a
JOIN master..spt_values v ON
v.type = 'P'
AND v.number BETWEEN MONTH(a.Last_In_Month_Of_Beginning) AND MONTH(a.First_In_Month_Of_End)
SELECT Month_Number
, SUM(Leave) Leaves
FROM #temp2
GROUP BY Month_Number
Here is an SQL Fiddle