I have two CSV files that I want to compare with Perl.
I have the code to get the files into Perl using Text::CSV::Slurp and it gives me a nice array of hash references for the files.
Using Data::Dumper::Concise shows all my data imports correctly.
use strict;
use warnings;
use Text::CSV::Slurp;
use Data::Dumper::Concise;
my $file1_src = "IPB-CSV.csv";
my $file2_src = "SRM-CSV.csv";
my $IPB = Text::CSV::Slurp->load(file => $file1_src);
my $SRM = Text::CSV::Slurp->load(file => $file2_src);
print Dumper($IPB);
print Dumper($SRM);
The results of the dump look something like this
$IPB
[
{
Drawing => "1001"
},
{
Drawing => "1002"
},
{
Drawing => "1003"
}
]
$SRM
[
{
Drawing => "1001",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "1002",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "2001",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "2002",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
}
]
I want to compare the two arrays based on each hash's Drawing key, and create two CSV files as follows
One containing the items that are in $IPB but not $SRM, containing only the data in the `Drawing column.
Another where the item is in the $SRM but not the $IPB, containing all the fields that are related to the Drawing column.
I have found lots of information to compare files to see if they match, or to compare hashes or arrays for single pieces of data, but I can't find something specific to what I need.
This short program uses your example values for $ipb and $srm and creates the output that I think you want. (Please don't use capital letters for anything but global identifiers like package names.)
There are a couple of problems
Using Text::CSV::Slurp leaves you with two arrays of hashes that are no use for this task without further indexing. You would be much better off creating appropriate data structures from scratch by processing the file line-by-line
You say that your second file must contain all of the information related to each Drawing key, but, because Perl hashes are inherently unordered, Text::CSV::Slurp has lost the order of the field names. The best that can be done is to print the data in whatever order it is found, but preceding it by a header line showing the field names. This is another reason for avoiding Text::CSV::Slurp
use strict;
use warnings;
use autodie;
# The original data
my $ipb = [{ Drawing => 1001 }, { Drawing => 1002 }, { Drawing => 1003 }];
my $srm = [
{
Drawing => "1001",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "1002",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "2001",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
},
{
Drawing => "2002",
Figure => "Figure 2-8",
Index => 2,
Nomenclature => "Some Part"
}
];
# Index the data
my %srm;
for my $item (#$srm) {
my $drawing = $item->{Drawing};
$srm{$drawing} = $item;
}
my %ipb;
for my $item (#$ipb) {
my $drawing = $item->{Drawing};
$ipb{$drawing} = 1;
}
# Create the output files
open my $csv1, '>', 'file1.csv';
for my $id (sort keys %ipb) {
next if $srm{$id};
print $csv1 $id, "\n";
}
close $csv1;
open my $csv2, '>', 'file2.csv';
my #keys = keys %{ $srm->[0] };
print $csv2 join(',', #keys), "\n";
for my $id (sort keys %srm) {
next if $ipb{$id};
print $csv2 join(',', #{$srm{$id}}{#keys}), "\n";
}
close $csv2;
output
file1.csv
1003
file2.csv
Drawing,Nomenclature,Index,Figure
2001,Some Part,2,Figure 2-8
2002,Some Part,2,Figure 2-8
Since drawing is a criterion of sorts, why not "index" the data into something a little more convenient where the drawing index is the key and the corresponding data is a corresponding value?
my %ipb;
for my $record ( #$IPB ) {
my $index = $record->{Drawing};
push #{ $ipb{$index} }, $record;
}
my %srm;
for my $record ( #$SRM ) {
my $index = $record->{Drawing};
push #{ $srm{$index} }, $record;
}
Now it should be a breeze to figure out the indexes unique to $IPB and $SRM:
use List::MoreUtils 'uniq';
my #unique_ipb = uniq( grep { $ipb{$_} and not $srm{$_} } keys( %ipb ), keys( %srm ) );
my #unique_srm = uniq( grep { $srm{$_} and not $ipb{$_} } keys( %ipb ), keys( %srm ) );
What's common to both?
my #intersect = uniq( grep { $srm{$_} and $ipb{$_} } keys( %ipb ), keys( %srm ) );
What are all the figure number(s) for Drawing index 1002?
print $_->{Figure}, "\n" for #{ $ipb{1002} // [] }, #{ $srm{1002} // [] };
This is a bit complicated, because your data structures are less than ideal for comparing. You have references to arrays of hash references, and you care about the data in one of the keys of the hashref. My first step would be to flatten IPB to an array (since there is no data under this), and convert SRM to a single hashref.
my #ipbarray = map { ${$_}{Drawing} } $IPB; # Creates an array from IPB.
my $srmhash = {};
for my $hash ($SRM) {
${$srmhash}{${$hash}{Drawing}} = $hash unless defined ${$srmhash}{${$hash}{Drawing}}; # Don't overwrite if it exists
}
Now we have 2 more workable data structures.
Next step is to contrast these values:
my #ipbonly = ();
my #srmonly = ();
for my $ipbitem (#ipbarray) {
push #ipbonly, ( Drawing => $ipbitem } unless defined ${$srmhash}{$ipbtem};
}
for my $srmitem (keys $srmhash) {
push #srmonly, ${$srmhash}{$srmitem} unless grep { $_ == $srmitem } #ipbarray;
}
At this point, #ipbonly and #srmonly will contain the data you want.
Related
My task is convert array, containing hash with x keys to x-1 dimensional hash.
Example:
use Data::Dumper;
my $arr = [
{
'source' => 'source1',
'group' => 'group1',
'param' => 'prm1',
'value' => 1,
},
{
'source' => 'source1',
'group' => 'group1',
'param' => 'prm2',
'value' => 2,
},
];
my $res;
for my $i (#$arr) {
$res->{ $i->{source} } = {};
$res->{ $i->{source} }{ $i->{group} } = {};
$res->{ $i->{source} }{ $i->{group} }{ $i->{param} } = $i->{value};
}
warn Dumper $res;
my $res_expected = {
'source1' => {
'group1' => {
'prm1' => 1, # wasn't added, why ?
'prm2' => 2
}
}
};
However it doesn't work as expected, 'prm1' => 1 wasn't added. What is wrong and how to solve this task ?
The problem is that you are assigning to the source even if something was there, and you lose it. Just do a ||= instead of = and you'll be fine.
Or even easier, just use the fact that Perl autovivifies and leave that out.
my $res;
for my $i (#$arr) {
$res->{ $i->{source} }{ $i->{group} }{ $i->{param} } = $i->{value};
}
warn Dumper $res;
The first 2 lines in the for loop are what is causing your problem. They assign a new hash reference each iteration of the loop (and erase what was entered in the previous iteration). In perl, there is no need to set a reference as you did. Just eliminate the first 2 lines and your data structure will be as you wish.
The method you chose only shows 'prmt' => 2 because that was the last item entered.
If I wanted to add a new hash to all the arrays in the mother_hash using a loop, what would be the syntax?
My hash:
my %mother_hash = (
'daughter_hash1' => [
{
'e' => '-4.3',
'seq' => 'AGGCACC',
'end' => '97',
'start' => '81'
}
],
'daughter_hash2' => [
{
'e' => '-4.4',
'seq' => 'CAGT',
'end' => '17',
'start' => '6'
},
{
'e' => '-4.1',
'seq' => 'GTT',
'end' => '51',
'start' => '26'
},
{
'e' => '-4.1',
'seq' => 'TTG',
'end' => '53',
'start' => '28'
}
],
#...
);
If you have a hash of arrays of hashes and want to add a new hash to
the end of each of the arrays, you can do:
push #{ $_ }, \%new_hash for (values %mother_hash);
This loop iterates over the values of %mother_hash (which are array refs in this case) and setting $_ for each iteration. Then in each iteration, we push the reference to the new hash %new_hash to the end of that array.
First I would point out the daughter hashes aren't hashes but arrays of anonymous hashes. To add another daughter hash:
$mother_hash{daughter_hash3} = [ { %daughter_hash3 } ];
This creates an anonymous array that contains an anonymous hash with the contents of %daughter_hash3.
For a loop:
$mother_hash{$daughter_hash_key} = [ { %daughter_hash } ];
where $daughter_hash_key is a string contain the key for the %mother_hash and %daughter_hash is the hash to add.
To add another hash to a daughter array with key $daughter_hash_key:
push #{ $mother_hash{$daughter_hash_key} }, { %daughter_hash };
I know ti's complicated but I suggest you use Data::Dumper to dump the contents of %mother_hash each time thru the loop to see if it grows correctly.
use Data::Dumper;
print Dumper \%mother_hash;
See perldoc Data::Dumper for details..
Data::Dumper is a standard module that comes with Perl. For a list of standard modules, see perldoc perlmodlib.
mother_hash is a hash of arrays of hashes.
To add another top-level array of hashes.
%mother_hash{$key} = [ { stuff }, { stuff } ];
To add another entry to an existing array
push #{%mother_hash{'key'}} { stuff };
To add another entry to the hash in the embedded array
%{#{%mother_hash{'top_key'}}[3]}{'new_inner_key'} = value;
When confused and attempting to match up the "types" of hash / array / scalar containing a hash reference / array reference, you can use the following technique
use Data::Dumper;
$Data::Dumper::Terse = 1;
printf("mother_hash reference = %s\n", Dumper(\%mother_hash));
printf("mother_hash of key 'top_key' = %s\n", Dumper(%mother_hash{top_key}));
and so on to find your way through a large data structure and validate that you are narrowing down to the region you want to access or alter.
I have this big array that I need to break down and only display specific elements within it that match a criteria.
My array looks like this.
[
{
:id => 9789,
:name => "amazing location",
:priority => 1,
:address_id => 12697,
:disabled => false
},
{
:id => 9790,
:name => "better location",
:priority => 1,
:address_id => 12698,
:disabled => false
},
{
:id => 9791,
:name => "ok location",
:priority => 1,
:address_id => 12699,
:disabled => true
}
]
What I need is to only display the elements within this array that have disabled set to true.
However when I try this, I get the error stating no implicit conversion of Symbol into Integer
array.map do |settings, value|
p hash[:disabled][:true]
end
I'm wondering if there is another way, or if there is a way to do this. If anyone could take a look, I would greatly appreciate it.
By providing two arguments to #map on an array, you're actually getting the first hash and then nil. When in reality you just want to loop for each and select those where disabled is true. You can do that instead with Array#select which will filter all elements of the array where the block returns a truthy value:
print array.select { |hash| hash[:disabled] }
=> [{:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}]
You can try this with a short each or select.
a.each { |k,_v| puts k if k[:disabled] == true }
=> {:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}
This iterates over each element (hash) inside the array you have and checks if the value of the key disabled on each value is true, and puts the key, just for example, you can set it as you want to do.
Or shorter:
puts a.select { |k,_v| k[:disabled] }
=> {:id=>9791, :name=>"ok location", :priority=>1, :address_id=>12699, :disabled=>true}
Your error shows up when you are treating an array or string as a Hash.
In PHP, array keys can be either numbers or strings, whereas in Ruby associative arrays are a separate data type, called a hash.
Here’s a cheatsheet for various foreach variants, translated into idiomatic Ruby:
Looping over a numeric array (PHP) :
<?php
$items = array( 'orange', 'pear', 'banana' );
# without indexes
foreach ( $items as $item ) {
echo $item;
}
# with indexes
foreach ( $items as $i => $item ) {
echo $i, $item;
}
Looping over an array (Ruby) :
items = ['orange', 'pear', 'banana']
# without indexes
items.each do |item|
puts item
end
# with indexes
items.each_with_index do |item, i|
puts i, item
end
Looping over an associative array (PHP) :
<?php
$continents = array(
'africa' => 'Africa',
'europe' => 'Europe',
'north-america' => 'North America'
);
# without keys
foreach ( $continents as $continent ) {
echo $continent;
}
# with keys
foreach ( $continents as $slug => $title ) {
echo $slug, $title;
}
Looping over a hash (Ruby):
continents = {
'africa' => 'Africa',
'europe' => 'Europe',
'north-america' => 'North America'
}
# without keys
continents.each_value do |continent|
puts continent
end
# with keys
continents.each do |slug, title|
puts slug, title
end
In Ruby 1.9 hashes were improved so that they preserved their internal order. In Ruby 1.8, the order in which you inserted items into a hash would have no correlation to the order in which they were stored, and when you iterated over a hash, the results could appear totally random. Now hashes preserve the order of insertion, which is clearly useful when you are using them for keyword arguments in method definitions. (thanks steenslag for correcting me on this)
I have a problem with referencing a hash in an array to another array.
I have an array #result which looks like this:
#result = (
{ "type" => "variable",
"s" => "NGDP",
"variable" => "NGDP" },
{"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP" },
{ "type" => "colon",
"s" => ",",
"colon" => "," },
{ "type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP" },
{ "type" => "operator",
"s" => "+",
"operator => "+" },
{"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP" },
);
I want to divide this array into colons and push elements of the #result array to another array, so i wrote the script:
for ($i = 0; $i <= $#result; $i++) {
if (defined $result[$i]{subject} or $result[$i]{operator} and not defined $result[$i]{colon}) {
push #part_col, \%{$result[$i]};
}
elsif ($i == $#result) {
push #part_col_all, \#part_col;
}
elsif (defined $result[$i]{colon}) {
push #part_col_all, \#part_col;
my #part_col;
}
}
So what I need is that if I print out $part_col_all[0][0]{subject} the result will be "USA",
and for $part_col_all[1][0]{subject} will be "JPN",
and for $part_col_all[1][1]{operator} will be "+" etc.
My result for $part_col_all[0][0]{subject} is "USA"
and for $part_col_all[0][1]{subject} is "JPN" which should be in $part_col_all[1][0]{subject}.
The result for $part_col_all[0][3]{subject} is "CHN", while it should be in $part_col_all[1][2]{subject}.
I'm making an application which is creating graphs from economical data based on a certain economical input. The #result array is my preprocessed input where I know to which country which variable belongs. If I get an input like GDP USA CAN, JPN+CHN I need to split this input to GDP USA CAN and JPN+CHN. That's why I made a condition, if colon is found, push everything in #part_col to the first element of #part_col_all, and then if it's on the end of the input, push JPN+CHN to the second element of #push_col_all.
So #part_col_all should looks like this:
#part_col_all = (
(
{"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP" },
{"type" => "subject",
"s" => "CAN",
"subject" => "CAN",
"variable" => "NGDP" },
),
(
{ "type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP" },
{ "type" => "operator",
"s" => "+",
"operator" => "+" },
{"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP" },
)
);
I dont know what I'm doing wrong. Sorry if there are any basic mistakes, im a beginner. Thanks a lot.
First, you're missing a quote:
{ "type" => "operator",
"s" => "+",
"operator" => "+" },
^ missing
As for printing, you can do the following:
foreach my $part (#part_col){
print $part->{operator}."\n";
}
Or do whatever you want in the print cycle with the values
You should read the Perl Reference Tutorial to help you.
There's no sin in dereferencing to simplify your code:
my #part_col;
my #part_col_all;
for $i ( 0..$#array ) {
my %hash = ${ $result[$i] }; # Make it easy on yourself. Dereference
if ( defined $hash{subject} or defined $hash{operator} and not defined $hash{colon} ) {
push #part_col, \%hash; # or push, #par_col, $result[$i]
}
}
Notice I changed the for from the three part setup you had to a cleaner and easier to understand way of stating it.
Looking closer at your data structure, I notice that $hash{type} will tell you whether or not $hash{operator}, $hash{subject}, or $hash{colon} is defined. Let's just use $hash{type} and simplify that if:
my #part_col;
my #part_col_all;
for my $i ( 0..$#array ) {
my %hash = ${ $result[$i] }; # Make it easy on yourself. Dereference
if ( $hash{type} eq "subject" or $hash{type} eq "operator" ) {
push #part_col, \%hash; # or push, #par_col, $result[$i]
}
}
In fact, since #array is just an array, I'll treat it like one. I'll use a simple for structure to go through each element of my array. Each element is a hash_reference, so:
for my $hash_ref ( #array ) {
my %hash = %{ %hash_ref };
if ( $hash{type} eq "subject" or $hash{type} eq "operator" ) {
push #part_col, \%hash;
}
}
And further simplification, I can dereference and talk about a particular element of my hash all at once by using the -> syntax:
for my $hash_ref ( #array ) {
if ( $hash_ref->{type} eq "subject" or $hash_ref->{type} eq "operator" ) {
push #part_col, $hash_ref;
}
}
I'm trying to understand the rest of your code:
elsif ($i == $#result) {
push #part_col_all, \#part_col;
}
elsif (defined $hash_ref->{colon}) {
push #part_col_all, \#part_col;
my #part_col;
}
}
These pushes of #part_col onto #part_col_all confuse me. Exactly what are you trying to store in #part_col_all? Remember that \#part_col is the location in memory where you're storing #part_col. You're pushing that same memory location over and over onto that hash, so you're storing the same reference over and over again. Is that really what you want? I doubt it.
You need to do is to decide exactly what your data structure really represents. A data structure should have a solid definition. What does the data structure #part_col_all represent? What does the data structure $part_col_all[$i] represent? What does the data structure $part_col_all[$i]->[$j] represent? Without knowing this, it's very hard to answer the rest of your question.
Are you storing elements where the type is colon in one array and everything else in another array? Or are you storing everything in one array, and in another array, storing everything that's not a type colon?
Once I understand this, I can answer the rest of your question.
Addendum
Thank you for your reply, I will try that way and write my results. It is realy helpful. I updated my question with more information about data structure of #part_col_all. I hope that you understand what I'm trying to explain, if not I'll try it again.
If I understand what you're doing, someone enters in NGDP USA , JPN+CNA and that means you're comparing the NGDP between the United States vs. Japan and China combined.
It seems to me that you would want three separate variables:
$parameter - What you are measuring. (GDP, etc.)
#countries_set_1 - The first set of countries
#countries_set_2 - The second set of countries which you're comparing against the first set.
And, what you call the colon (which we would call a comma in the U.S.) as a separator between the first set of countries vs. the second set. Then, you'd simply go through a loop. It could be that the two arrays are merely two elements of the same array, and the sets of countries are array references. I imagine something like this:
#input = qw(GDP USA, JPN CHN); # Compare the GDP of the USA with Japan and China together
my $parameter = shift #input; # Remove what you're measuring
my #country_sets; # An array of arrays
my $set = 0 # Which set you're on
for my $value ( #input ) {
if ( $value eq "," ) {
$set += 1; # Next Set
next;
}
push #{ $country_sets[$set] }, $input;
}
This would create a data structure like this:
#country_sets = (
(
USA,
),
(
JPN,
CHN,
),
)
No need for the complex #results since you're only going to have a single operation (GDP, etc.) for all involved.
However, I think I see what you want. We'll go with an array of arrays. Here's what I had before:
for my $hash_ref ( #array ) {
if ( $hash_ref->{type} eq "subject" or $hash_ref->{type} eq "operator" ) {
push #part_col, $hash_ref;
}
}
We'll combine that and the code I offered right above which splits the countries into two sets:
my #country_sets; # An array of arrays
my $set = 0 # Which set you're on
for my $country_ref ( #array ) {
next if $country_ref->{type} eq "variable"; # We don't want variables
if ( $country_ref{type} eq "colon" ) { # Switch to the other country set
set += 1;
next;
}
push #{ $country_sets[$set] }, $country_ref;
}
The first few entries will go into $country_sets[0] which will be an array reference. After the colon (which won't be input into the set), the second set of countries will go into $country_sets[1] which will be an other array_ref to a reference of hashes:
#country_sets - Contains the input information into two sets
#country_sets[$x] - A particular set of countries (and possibly operator)
#country_sets[$x]->[$y] - A Particular country or operator
#country_sets[$x]->[$y]->{$key} - A particular value from a particular country
Where $x goes from 0 to 1. This will give you something like this:
$country_sets[0] = (
{
"type" => "subject",
"s" => "USA",
"subject" => "USA",
"variable" => "NGDP",
},
)
$country_sets[1] = (
{
"type" => "subject",
"s" => "JPN",
"subject" => "JPN",
"variable" => "NGDP",
},
{
"type" => "operator",
"s" => "+",
"operator => "+",
},
{
"type" => "subject",
"s" => "CHN",
"subject" => "CHN",
"variable" => "NGDP",
},
);
This is the code snippet I am working with:
my %photo_details = (
'black_cat' => (
('size' => '1600x1200', 'position' => -25),
('size' => '1280x1024', 'position' => 25),
('size' => '800x600', 'position' => 0),
),
'race_car' => (
('size' => '1600x1200', 'position' => 10),
('size' => '800x600', 'position' => 5),
),
);
my $photo = 'black_cat';
foreach my $photo_detail ($photo_details{$photo})
{
my $size = $photo_detail{'size'};
my $position = $photo_detail{'position'};
print ("size = $size, position = $position\n");
}
What I am expecting to get is:
size = 1600x1200, position = -25
size = 1280x1024, position = 25
size = 800x600, position = 0
What I do get is:
Use of uninitialized value $size in concatenation (.) or string at C:\Test.pl line 23.
Use of uninitialized value $position in concatenation (.) or string at C:\Test.pl line 23.
size = , position =
The foreach statement is clearly wrong as not only are there no values for $size and $position, it has only gone through the loop once instead of three times. I have tried all sorts of variants of variable prefixes and found none that work.
What am I doing wrong?
Here is some updated code, with an explanation below:
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
my %photo_details = (
'black_cat' => [
{'size' => '1600x1200', 'position' => -25},
{'size' => '1280x1024', 'position' => 25},
{'size' => '800x600', 'position' => 0},
],
'race_car' => [
{'size' => '1600x1200', 'position' => 10},
{'size' => '800x600', 'position' => 5},
],
);
print Dumper( %photo_details );
foreach my $name ( keys %photo_details ) {
foreach my $photo_detail ( #{ $photo_details{$name} } ) {
my $size = $photo_detail->{'size'};
my $position = $photo_detail->{'position'};
print Dumper( $photo_details{$photo} );
print ("size = $size, position = $position\n");
}
}
I've replaced some of your parentheses with square and curly brackets. In Perl, square brackets give you a reference to an anonymous array, and curly brackets denote a reference to an anonymous hash. These are called anonymous because there's no explicit variable name for the anonymous array or hash.
As Perl data structures make you store a reference to a hash rather than the actual hash, you need these to construct the references. You can do this in two steps like this:
my #array = ( 1, 2, 3 );
my $array_ref = \#array;
my %hash = ( 'one' => 1, 'two' => 2, 'three' => 3 );
my $hash_ref = \%hash_ref;
To get data out of $array_ref and $hash_ref, you need the -> operator:
print $array_ref->[0], "\n";
print $hash_ref->{one}, "\n";
You don't need the quotes inside of the {} when referencing a hash key, although some people consider quotes on a hash key to be good practice.
I added an example of iteration over the entire data structure as an example rather than just looking at one reference. Here's the first line:
foreach my $name ( keys %photo_details ) {
The keys method returns all of the keys in a hash, so that you can get them in order. The next line iterates over all of the photo_detail hashrefs in %photo_details:
foreach my $photo_detail ( #{ $photo_details{$photo} } ) {
The #{ $photo_details{$photo} } de-references the reference $photo_details{$photo} into an array, which you can iterate over it with foreach.
The last thing that I added is a call to Data::Dumper, a very useful module distributed with Perl that prints out data structures for you. This is very handy when building up data structures like this, as is its closely related cousin Data::Dumper::Simple. This module is unfortunately not distributed with Perl, but I prefer its output as it includes variable names.
For some further reading about how to build up complex data structures using references, check out perlreftut.
First of all, always start every script or module with:
use strict;
use warnings;
You will get more warning messages and sooner, which greatly helps debugging.
I cannot duplicate your error: when I put that code into a file and run it with no additional flags, I get: size = , position =. There is no $size variable in the code you printed, so the error message does not match.
Nevertheless, you are declaring your data structures incorrectly. Hashes and arrays can
only contain scalar values, not lists: so if you want to nest an array or
a hash, you need to make it a reference. See perldoc perldata, perldoc perldsc
and perldoc perlreftut for more about data structures and references.
my %photo_details = (
black_cat => [
{ size => '1600x1200', position => -25 },
{ size => '1280x1024', position => 25 },
{ size => '800x600', position => 0 },
],
race_car => [
{ size => '1600x1200', position => 10 },
{ size => '800x600', position => 5 },
],
);
foreach my $photo_detail (#{$photo_details{black_cat}})
{
my $size = $photo_detail->{size};
my $position = $photo_detail->{position};
print ("size = $size, position = $position\n");
}
There's really only one thing you have to worry about, and that's the top level of the data structure. After that, you just use the right indexing syntax for each level:
If you have a regular hash, you access the key that you want then line up the additional indices for each level after it:
%regular_hash = ...;
$regular_hash{$key}[$index]{$key2};
If you have a reference, you do almost the same thing, but you have to start off with the initial dereference with an arrow, ->, after the top-level reference. After that it's the same indexing sequence:
$hash_ref = ...;
$hash_ref->{$key}[$index]{$key2};
For all of the details, see Intermediate Perl where we explain reference syntax.