AngularJs validate whole model - angularjs

Question

I have a view with some inputs in a table row. Is there a way to check if the whole model is valid without using form (can't have form in tr ) ?
<tr ng-controller="SomeCtrl">
<td>
<input type="text" ng-model="someModel.name" required="required" ng-minlength="3">
</td>
<td>
<input type="text" ng-model="someModel.x" required="required" ng-minlength="3">
</td>
<td>
<input type="text" ng-model="someModel.y" required="required" ng-minlength="3">
</td>
<td>
<button ng-click="save(someModel)">Save</button>
</td>
</tr>
In controller i want to have something like this
function ($rootScope, $scope, serive) {
$scope.save = function (someModel) {
if (someModel.$valid) {}
};
}

Answer 1

If you use a form and it has a name, it automatically can give you exactly what you required.
<form name="someForm">
<tr ng-controller="SomeCtrl">
<td>
<input type="text" ng-model="someModel.name" data-ng-required="true" ng-minlength="3">
</td>
<td>
<input type="text" ng-model="someModel.x" data-ng-required="true" ng-minlength="3">
</td>
<td>
<input type="text" ng-model="someModel.y" data-ng-required="true" ng-minlength="3">
</td>
<td>
<button data-ng-disabled="!someForm.$valid" ng-click="someForm.$valid && Namesave(someModel)">Save</button>
</td>
</tr>
</form>
Otherwise, there is no automagical way to do that. I guess you can write a directive which gives you all your inputs and their validators, parse them, and have a validation on the whole model, but no such thing readily exists, I believe.

Answer 2

Better way to do it:
ng-form name="myForm" can be used to avoid using tag and it should work - plunker.
but using ng-include will make the form unavailable to controller - plunker , explanation. A work around for this issue is to pass the form as parameter to the controller method - plunker