I've just discovered variadic functions in C and have defined one as a general notification typedef, that as well as a pointer to a text string can optionally have whatever arguments sent along with it- useful as a generic debug function for instance where I want all the output string manipulation in one place.
Since I want my C files to be as generic as possible I have static variables that contain pointers to possible callbacks in higher code, populated in an init call. Since the pointers may be null if higher code isn't interested, I'd normally have a local wrapper that only calls through the pointer if it's not null. But I'm having trouble figuring out how to forward this fuzzy thing represented by '...' and simply calling the function with '...' in the argument list gives a syntax error.
Is there any way to do this, or am I stuck with having a dummy local handler and having init set null callbacks to a pointer to that?
You can't pass on the variadic arguments. You have to fetch them into a va_list and pass this to the inner function.
Take a look at this Question at the C FAQ. It defines a variadic error function that wants to forward to printf. This is just your use case.
In the same FAQs, it is generally recommended to have a version taking va_list for every (or most) variadic functions
Related
Let's say I have a function:
int foo (int A, char B){...}
One of the features I want to implement is the capability for the user to call any function on the application through the Linux terminal. So as an input for the software, in the terminal they type something like:
foo 2 'a'
Then my application parses that, and using the symbol tables it is able to find the address for foo(), as well as the type for all its parameters.
However, I'm not sure how I would pass the parameters to the function when calling it, since I can have hundreds of different parameters types combination depending on the function called.
Any hint how that could be achieved without having hundreds of nested if statements to cast the parameters to the correct types before calling the functions?
That functionality is similar to what GDB has, where you can do call foo(2,'a') and GDB calls that function to you.
There are two approaches to this. If what you described is all you want to do, then you can use the dyncall library so that you dont have to worry about platform/compiler-specific calling semantics yourself:
The dyncall library encapsulates architecture-, OS- and compiler-specific function call semantics in a virtual bind argument parameters from left to right and then call interface allowing programmers to call C functions in a completely dynamic manner. In other words, instead of calling a function directly, the dyncall library provides a mechanism to push the function parameters manually and to issue the call afterwards.
The other approach is, if you might want to do more: e.g. what if an argument cannot be created by a literal? What if the argument is the output of another function? Can you write f(123, g("a")) in your console? Can you write x=g("a"); f(x)? And if(cond) x="a" else x="b"; f(x) In this case you need to embed a scripting language like e.g. LUA.
If you compile your binary with debug information, you can extract it using libdwarf (https://www.prevanders.net/dwarf.html), so for every function you can get a list a parameters with types and you would know how to interpret user's input.
I am trying to implement low-level code that passes variadic arguments to a function pointer (with the function defined in NASM). This pointer can change at any time, so I need to declare a function pointer with the following signature:
typedef int (__fastcall* callback)(...);
However, unless I declare it with a non-variadic parameter (which wont work), the compiler outputs the error "error : expected a type specifier". Is there any way to fix this just using C? Is there a different implementation that would work short of adjusting all of the other parameters based on calling convention in assembly? Any ideas or solutions would be appreciated.
Edit: I'm aware that this is a very hacky implementation, but I am working with a legacy codebase. So as much as I'd like to, I can't completely change how everything works as I need a solution which will work in the current codebase.
So I never realized this until I accidentally did it. The following is a method header i have:
void processI_TypeInstruction(char *I_TypeInstruction, char* currentLine,
FILE *outputFilePointer, VariableVector *labelVector);
one of my calls to this method looks like this:
processI_TypeInstruction("lw", line1, outputFile);
and all my tests pass and everything works. I was wondering what C does to make this functionality work??? Thanks.
You must not have the header file with the prototype for processI_TypeInstruction in the file with that call.
Function prototypes are not required in C. If a function does not have a prototype, the compiler makes no assumption about the number of parameters so it will allow you to pass any number of parameters in a function call. The is the behavior of the original language. Function prototypes were not added until the 1989 C standard.
The call works because the C calling convention has the caller clean up the stack. Since the caller knows how many parameters were passed, it can clean up all the parameters that it passed. Of course if the function tries to access a parameter then it will read into un-initialized stack space and who knows what will happen.
That should definitely be a compilation error in C, however, C++ does support function overloading (same function name, different number of arguments, different function signature)...
I am currently changing the function signatures of a class of functions in an application. These functions are being stored in a function table, so I was expecting to change this function table as well. I have just realised that in certain instances, we already use the new function signature. But because everything is casted to the correct function type as it is put into the function table, no warnings are being raised.
When the function is called, it will be passed extra parameters that are not really part of the function declaration, but they are on the end of the parameter list.
I can't determine if this is guaranteed by the way function parameters are passed in C. I guess to do variadic functions like sprintf, it has to be the case that earlier arguments can be resolved correctly whatever is on the end of the parameter list?
It evidently works just fine across multiple platforms but out of curiosity I'd like to know how and why it works.
But because everything is casted to the correct function type as it is put into the function table, no warnings are being raised.
So the compiler gets to be no help to speak of. C programmers cast too much. >_<
I can't determine if this is guaranteed by the way function parameters are passed in C. I guess to do variadic functions like sprintf, it has to be the case that earlier arguments can be resolved correctly whatever is on the end of the parameter list?
Technically, you've got undefined behavior. But it's defined for your platform to use the standard C calling conventions (see Scott's answer), or something that maps directly to them (usually by mapping the first N parameters to a certain set of processor registers).
This comes up a lot with variable argument lists, too. For example, printf is declared something like:
int printf(const char* format, ...);
And its definition usually uses the stdarg system to handle the extra arguments, which looks like:
#include <stdarg.h>
int printf(const char* format, ...)
{
va_list ap;
int result;
va_start(ap, format);
result = vprintf(format, ap);
va_end(ap);
return result;
}
If you're on a platform with standard C calling conventions, that va_end(ap) macro usually turns into a do-nothing. In this case, you can get away with passing extra arguments to a function. But on some platforms, the va_end() call is required to restore the stack to a predictable state (i.e. where it was before the call to va_start); in those cases, your functions will not leave the stack the way it found it (it won't pop enough arguments back off the stack) so your calling function could, for example, crash on exit when it fetches a bogus value for a return address.
Your functions must certainly be using the cdecl calling convention (http://en.wikipedia.org/wiki/X86_calling_conventions#cdecl). This pushes arguments on the stack in reverse order, from right to left, ensuring that the last argument can be easily located (top of the stack) and used to interpret the remainder, such as a printf format string. It is also the responsibility of the caller to clean up the stack, which is a bit less compact than the function itself doing so (as in pascal/stdcall convention), but ensures that variable argument lists can be used, and implies that trailing arguments can be ignored.
I'm trying to plug a hole in my knowledge. Why variadic functions require at least two arguments? Mostly from C's main function having argc as argument count and then argv as array of arrays of chars? Also Objective-C's Cocoa has NSString methods that require format as first argument and afterwards an array of arguments ([NSString stringWithFormat:#"%#", foo]). Why is it impossible to create a variadic function accepting only a list of arguments?
argc/argv stuff is not really variadic.
Variadic functions (such as printf()) use arguments put on the stack, and don't require at least 2 arguments, but 1.
You have void foo(char const * fmt, ...) and usually fmt gives a clue about the number of arguments.
That's minimum 1 argument (fmt).
C has very limited reflection abilities so you must have some way to indicate what it is that the variable arguments contain - either specifying the number of arguments or the type of them (or both), and that is the logic behind having one more parameter. It is required by the ISO C standard so you can't omit it. If feel you don't need any extra parameters because the number and type of the arguments is always constant then there is no need for variable arguments in the first place.
You could of course design other ways to encode the number / type information inside the variable arguments such as a sentinel value. If you want to do this, you can just supply a dummy value for the first argument and not use it in the method body.
And just to be pedantic about your title, variadic functions only require one argument (not two). It's perfectly valid to make a call to a variadic function without providing any optional arguments:
printf("Hello world");
I think, that the reason is the following:
in the macro va_start(list, param); you specify the last fixed argument - it is needed to determine the address of the beginning of the variable arguments list on the stack.
How would you then know if the user provided any arguments?
There has to be some information to indicate this, and C in general wasn't designed to do behind-your-back data manipulation. So anything you need, it makes you pass explicitly.
I'm sure if you really wanted to you could try to enforce some scheme whereby the variadic function takes only a certain type of parameter (a list of ints for example) - and then you fill some global variable indicating how many ints you had passed.
Your two examples are not variadic functions. They are functions with two arguments, but they also highlight a similar issue. How can you know the size of a C array without additional information? You can either pass the size of the array, or you describe a scheme with some sentinel value demarcating the end of the array (i.e. '\0' for a C string).
In both the variadic case and the array case you have the same problem, how can you know how much data you have legitimate access to? If you don't know this with the array case, you will go out of bounds. If you don't know this with the variadic case you will call va_arg too many times, or with the wrong type.
To turn the question around, how would you be able to implement a function taking a variable number of arguments without passing the extra information?