My program stops looping and i cannot figure out why - c

Question

if the user inputs the "value" as 1223445 the output should read as follows:
After change #1: 12235
After change #2: 135
the code is meant to take out two consecutive numbers with the same value. the first loop works but then it stops and I cannot figure why. here is the code:
{
int count;
int y;
int z;
int b;
int c;
int d;
int a;
int ct;
y = 0;
z = 1;
d = 0;
count = 0;
if (value > 0)
while ((z * 10 + z) != (y % 100))
{
y = value % 10 + y * 10;
z = y % 10;
value /= 10;
count = count + 1;
}
value = value * pow(10, count - 2);
y = y / 100;
count = count - 3;
while(y > 0)
{
b = y % 10;
c = pow(10, count);
d = d + c * b;
y = y / 10;
count = count - 1;
}
value = value + d;
ct = 1;
printf("After change #%d: %d\n", ct, value);
a = value;
while (a > 1)
{
if((a % 100) - (a % 10) - (10 * (a % 10)) == 0)
Change(value);
else
a = a / 10;
}
return;
}

Answer 1

Here's a simple solution: (not sure how you want to handle odd numbered repeats e.g. '111', '11111')
public static long strip(long value, long sum) {
if(value==0) return sum;
long tens = value % 100;
long ones = value % 10;
if(ones*10 == tens-ones) {
return strip(value /100, sum);
}
if(sum==0) sum +=(value%10);
else {
long x = (long)Math.ceil((Math.log10(sum)));
sum =(long) (Math.pow(10,x) * ones + sum);
}
return strip(value /10, sum);
}