I have a table
CREATE TABLE #tblA (mem_id int, type varchar(20), address1 varchar(20),group_id int)
insert into #tblA (mem_id, type, address1,group_id)
values (1,'self','abc St',1),
(2,'Child','abc St',1),
(3,'Child','xyz st',1),
(4,'spouse','pqr st',1),
(5,'Child','abc St',1),
(6,'Child','xyz st',1),
(7,'self','mno st',2),
(8,'Child','def St',2),
(9,'Child','def st',2),
(10,'self','loi st',3),
(11,'Child','loi St',3),
(12,'Child','ewr st',3)
(13,'self','ooo st',NULL),
So, I want to select:
For every group, select "self".
Select self if it has no group.
If other people live at different address than self, select those
members.
if multiple members live at different address, pick 1 member living
at a different address
So expected result:
(1,'self','abc St',1),
(3,'Child','xyz st',1),
(4,'spouse','pqr st',1),
(7,'self','mno st',2),
(8,'Child','def St',2),
(10,'self','loi st',3),
(12,'Child','ewr st',3)
(13,'self','ooo st',NULL),
Thanks
My code: not working:
select
mem_id
from
(select
a.*,
RANK() over (partition by group_id order by AddressCnt DESC) as AddressRank
from
(select
a.*,
(case when max(address1) over (partition by group_id) = min(address1) over (partition by group_id)
then 1 else 0
end) as AddressSame,
count(*) over (partition by group_id, address1) as AddressCnt
from #tblA a) a
) a
where
(AddressSame = 1 or type in ('Self') or
(AddressRank > 1 OR type in ('Self') or group_id is null
Here's a solution.
Create a CTE identifying the "self" records.
Create another cte identifying the "others" with a join from self to tableA
Use row_number to find just one record for the other
union the two cte's
WITH self
AS (SELECT *
FROM tbla
WHERE type = 'self'),
others
AS (SELECT a.mem_id,
a.type,
a.address1,
a.group_id,
Row_number()
OVER (
partition BY a.group_id, a.address1
ORDER BY a.mem_id) rn
FROM self s
INNER JOIN tbla a
ON s.group_id = a.group_id
AND s.mem_id <> a.mem_id --Exclude self records
AND s.address1 <> a.address1 --Exclude the same address as self)
SELECT mem_id,
type,
address1,
group_id
FROM self
UNION
SELECT mem_id,
type,
address1,
group_id
FROM others
WHERE rn = 1
ORDER BY mem_id
DEMO
This MySQL query gives the desired output:
select * from tblA having type='self' UNION select * from tblA group by address1 having address1 not in (select address1 from tblA where type='self') ORDER by mem_id;
Related
I am stuck with this. I have a simple set-up with two tables. One table is holding emailaddresses one table is holding vouchercodes. I want to join them in a third table, so that each emailaddress has one random vouchercode.
Unfortunatly I am stuck with this as there are no identic Ids to match both values. What I have so far brings no result:
Select
A.Email
B.CouponCode
FROM Emailaddresses as A
JOIN CouponCodes as B
on A.Email = B.CouponCode
A hint would be great as search did not bring me any further yet.
Edit -
Table A (Addresses)
-------------------
Column A | Column B
-------------------------
email1#gmail.com True
email2#gmail.com
email3#gmail.com True
email4#gmail.com
Table B (Voucher)
-------------------
ABCD1234
ABCD5678
ABCD9876
ABCD5432
Table C
-------------------------
column A | column B
-------------------------
email1#gmail.com ABCD1234
email2#gmail.com ABCD5678
email3#gmail.com ABCD9876
email4#gmail.com ABCD5432
Sample Data:
While joining without proper keys is not a good solution, for your case you can try this. (note: not tested, just a quick suggestion)
;with cte_email as (
select row_number() over (order by Email) as rownum, Email
from Emailaddresses
)
;with cte_coupon as (
select row_number() over (order by CouponCode) as rownum, CouponCode
from CouponCodes
)
select a.Email,b.CouponCode
from cte_email a
join cte_coupon b
on a.rownum = b.rownum
You want to randomly join records, one email with one coupon each. So create random row numbers and join on these:
select
e.email,
c.couponcode
from (select t.*, row_number() over (order by newid()) as rn from emailaddresses t) e
join (select t.*, row_number() over (order by newid()) as rn from CouponCodes t) c
on c.rn = e.rn;
Give a row number for both the tables and join it with row number.
Query
;with cte as(
select [rn] = row_number() over(
order by [Column_A]
), *
from [Table_A]
),
cte2 as(
select [rn] = row_number() over(
order by [Column_A]
), *
from [Table_B]
)
select t1.[Column_A] as [Email_Id], t2.[Column_A] as [Coupon]
from cte t1
join cte2 t2
on t1.rn = t2.rn;
Find a demo here
I have 36 Sales tables each referred to one store:
st1.dbo.Sales
st2.dbo.Sales
...
st35.dbo.Sales
st36.dbo.Sales
Each record has the following key columns:
UserName, PostalCode, Location, Country, InvoiceAmount, ItemsCount, StoreID
Here is SQLFiddle
I need to copy into Customers table all Username (and their details) that are not already present into Customers
in case of duplicated it is required to use the fields of record where InvoiceAmount is MAX
I tried to build a query but looks too complicated and it is also wrong because in CROSS APPLY should consider the full list of Sales Tables
INSERT INTO Customers (.....)
SELECT distinct
d.UserName,
w.postalCode,
w.location,
W.country,
max(w.invoiceamount) invoiceamount,
max(w.itemscount) itemscount,
w.storeID
FROM
(SELECT * FROM st1.dbo.Sales
UNION
SELECT * FROM st2.dbo.Sales
UNION
...
SELECT * FROM st36.dbo.Sales) d
LEFT JOIN
G.dbo.Customers s ON d.Username = s.UserName
CROSS APPLY
(SELECT TOP (1) *
FROM s.dbo.[Sales]
WHERE d.Username=w.Username
ORDER BY InvoiceAmount DESC) w
WHERE
s.UserName IS NULL
AND d.username IS NOT NULL
GROUP BY
d.UserName, w.postalCode, w.location,
w.country, w.storeID
Can somebody please give some hints?
As a basic SQL query, I'd create a row_number in the inner subquery and then join to customers and then isolated the max invoice number for each customer not in the customer table.
INSERT INTO Customers (.....)
SELECT w.UserName,
w.postalCode,
w.location,
w.country,
w.invoiceamount,
w.itemscount,
w.storeID
FROM (select d.*,
row_number() over(partition by d.Username order by d.invoiceamount desc) rownumber
from (SELECT *
FROM st1.dbo.Sales
UNION
SELECT *
FROM st2.dbo.Sales
UNION
...
SELECT *
FROM st36.dbo.Sales
) d
LEFT JOIN G.dbo.Customers s
ON d.Username = s.UserName
WHERE s.UserName IS NULL
AND d.username IS NOT NULL
) w
where w.rownumber = 1
Using your fiddle this will select distinct usernames rows with max invoiceamount
with d as(
SELECT * FROM Sales
UNION
SELECT * FROM Sales2
)
select *
from ( select *,
rn = row_number() over(partition by Username order by invoiceamount desc)
from d) dd
where rn=1;
step 1 - use cte .
select username , invoiceamount ,itemscount from Sales
UNION all
select user name , invoiceamount ,itemscount from Sales
.....
...
step 2
next cte use group by and get max invoiceamount ,itemscount for user of last result set.
,cte2 as (
select user name , max (invoiceamount) as invoiceamount ,max(itemscount) as itemscount from cte)
step3
use left join with user table and find missing record and itemscount invoiceamount
I have a two tables like below
A
Id Name
1 a
2 b
B
Id Name
1 t
6 s
My requirement is to find the maximum id from table and display the name and id for that maximum without using case and if.
i findout the maximum by using below query
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
I findout the maximum 6 using the above query.but i can't able to find the name.I tried the below query but it's not working
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
How to find the name?
Any help will be greatly appreciated!!!
First combine the tables, since you need to search both. Next, determine the id you need. JOIN the id back with the temporarily created table to retreive the name that belongs to that id:
WITH tmpTable AS (
SELECT id,name FROM A
UNION
SELECT id,name FROM B
)
, max AS (
SELECT MAX(id) id
FROM tmpTable
)
SELECT t.id, t.name
FROM max m
JOIN tmpTable t ON m.id = t.id
You could use ROW_NUMBER(). You have to UNION ALL TableA and TableB first.
WITH TableA(Id, Name) AS(
SELECT 1, 'a' UNION ALL
SELECT 2, 'b'
)
,TableB(Id, Name) AS(
SELECT 1, 't' UNION ALL
SELECT 6, 's'
)
,Combined(Id, Name) AS(
SELECT * FROM TableA UNION ALL
SELECT * FROM TableB
)
,CTE AS(
SELECT *, RN = ROW_NUMBER() OVER(ORDER BY ID DESC) FROM Combined
)
SELECT Id, Name
FROM CTE
WHERE RN = 1
Just order by over the union and take first row:
SELECT TOP 1 * FROM (SELECT * FROM A UNION SELECT * FROM B) x
ORDER BY ID DESC
This won't show ties though.
For you stated that you used SQL Server 2008. Therefore,I used FULL JOIN and NESTED SELECT to get what your looking for. See below:
SELECT
(SELECT
1,
ISNULL(A.Id,B.Id)Id
FROM A FULL JOIN B ON A.Id=B.Id) AS Id,
(SELECT
1,
ISNULL(A.Name,B.Name)Name
FROM A FULL JOIN B ON A.Id=B.Id) AS Name
It's possible to use ROW_NUMBER() or DENSE_RANK() functions to get new numiration by Id, and then select value with newly created orderId equal to 1
Use:
ROW_NUMBER() to get only one value (even if there are some repetitions of max id)
DENSE_RANK() to get all equal max id values
Here is an example:
DECLARE #tb1 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
DECLARE #tb2 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
INSERT INTO #tb1 VALUES (1, 'A');
INSERT INTO #tb1 VALUES (7, 'B');
INSERT INTO #tb2 VALUES (4, 'C');
INSERT INTO #tb1 VALUES (7, 'D');
SELECT * FROM
(SELECT Id, Name, ROW_NUMBER() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
SELECT * FROM
(SELECT Id, Name, DENSE_RANK() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
Results are:
i have a table similar this
id-value-RowInid
1-xy-1
1-xx-2
1-xz-3
2-xx-1
2-xr-2
3-xq-1
4-xa-1
4-xc-2
...
i need a function for this table with similar output to get maximum of RowInid in separated id group
1-xz-3
2-xr-2
3-xq-1
4-xc-2
...
You just need to use MAX(RowInid) with GROUP BY Id, value
SELECT ID, VALUE, MAX(RowInid) FROM myTable GROUP BY ID, VALUE
EDIT:
As you updated your question, you can get value field using sub-query like this:
SELECT ID, VALUE, RowInid
FROM myTable t1 WHERE RowInid =
(
SELECT MAX(RowInid) FROM myTable WHERE id = t1.id GROUP BY id
)
ORDER BY id ASC;
You can also achieve this using INNER JOIN like this:
SELECT t2.ID, VALUE, t2.RowInid FROM myTable t1
INNER JOIN
(
SELECT ID, MAX(RowInid) AS RowIniD FROM myTable GROUP BY ID
) AS t2
ON t1.ID = t2.ID AND t1.RowInid = t2.RowInid
ORDER BY t1.ID ASC;
See this SQLFiddle
See more about GROUP BY and MAX in SQL Server.
no need for group by or max at all
select id, value, rowinid from
( select *, row_number() over (partition by id, order by rowinid desc) rn from yourtable ) v
where rn = 1
Try with,
Use Sub Query to get Id, Value and Max RowInid,
SELECT m1.[Id],m1.Value, m1.RowInid
FROM [Practice].[dbo].[myTable] m1 WHERE RowInid = (SELECT MAX(m2.RowInid) FROM [Practice].[dbo].[myTable] m2 WHERE M1.Id = m2.Id GROUP BY Id)
above query return result like:
4-xx-2
3-xx-1
2-xx-2
1-xx-3
To Ascending this use,
SELECT m1.[id],m1.Value, m1.RowInid
FROM [Practice].[dbo].[myTable] m1 WHERE m1.RowInid = (SELECT MAX(m2.RowInid) FROM [Practice].[dbo].[myTable] m2 WHERE M2.id = m1.id GROUP BY id) ORDER BY m1.id ASC
I have two columns:
namecode name
050125 chris
050125 tof
050125 tof
050130 chris
050131 tof
I want to group by namecode, and return only the name with the most number of occurrences. In this instance, the result would be
050125 tof
050130 chris
050131 tof
This is with SQL Server 2000
I usually use ROW_NUMBER() to achieve this. Not sure how it performs against various data sets, but we haven't had any performance issues as a result of using ROW_NUMBER.
The PARTITION BY clause specifies which value to "group" the row numbers by, and the ORDER BY clause specifies how the records within each "group" should be sorted. So partition the data set by NameCode, and get all records with a Row Number of 1 (that is, the first record in each partition, ordered by the ORDER BY clause).
SELECT
i.NameCode,
i.Name
FROM
(
SELECT
RowNumber = ROW_NUMBER() OVER (PARTITION BY t.NameCode ORDER BY t.Name),
t.NameCode,
t.Name
FROM
MyTable t
) i
WHERE
i.RowNumber = 1;
select distinct namecode
, (
select top 1 name from
(
select namecode, name, count(*)
from myTable i
where i.namecode = o.namecode
group by namecode, name
order by count(*) desc
) x
) as name
from myTable o
SELECT max_table.namecode, count_table2.name
FROM
(SELECT namecode, MAX(count_name) AS max_count
FROM
(SELECT namecode, name, COUNT(name) AS count_name
FROM mytable
GROUP BY namecode, name) AS count_table1
GROUP BY namecode) AS max_table
INNER JOIN
(SELECT namecode, COUNT(name) AS count_name, name
FROM mytable
GROUP BY namecode, name) count_table2
ON max_table.namecode = count_table2.namecode AND
count_table2.count_name = max_table.max_count
I did not try but this should work,
select top 1 t2.* from (
select namecode, count(*) count from temp
group by namecode) t1 join temp t2 on t1.namecode = t2.namecode
order by t1.count desc
Here are to examples that you could use but the temp table use is more efficient than the view, but was done on a small data sample. You would want to check your own statistics.
--Creating A View
GO
CREATE VIEW StateStoreSales AS
SELECT t.state,t.stor_id,t.stor_name,SUM(s.qty) 'TotalSales'
,ROW_NUMBER() OVER (PARTITION BY t.state ORDER BY SUM(s.qty) DESC) AS 'Rank'
FROM [dbo].[sales] s
JOIN [dbo].[stores] t ON (s.stor_id = t.stor_id)
GROUP BY t.state,t.stor_id,t.stor_name
GO
SELECT * FROM StateStoreSales
WHERE Rank <= 1
ORDER BY TotalSales Desc
DROP VIEW StateStoreSales
---Using a Temp Table
SELECT t.state,t.stor_id,t.stor_name,SUM(s.qty) 'TotalSales'
,ROW_NUMBER() OVER (PARTITION BY t.state ORDER BY SUM(s.qty) DESC) AS 'Rank' INTO #TEMP
FROM [dbo].[sales] s
JOIN [dbo].[stores] t ON (s.stor_id = t.stor_id)
GROUP BY t.state,t.stor_id,t.stor_name
SELECT * FROM #TEMP
WHERE Rank <= 1
ORDER BY TotalSales Desc
DROP TABLE #TEMP