filling a Char array with scanf in C - c

How can I fill an empty Char Array with keyboard?
something like
char a_string[];
while("if not Q")
{
printf("Enter a number: ");
scanf("%c", a_string);
}
I know this is wrong
I just want to know how to give values to my a_string[], without limiting the size.
so the size will vary depend on how many keys i'm gonna enter from keyboard.
Thanks!

If you will know at the start of runtime how many keys you'll enter, you can have it ask first for the number of keys and then for the individual characters, as in the untested snippet below.
Otherwise, you have to set some real-world maximum (e.g. 10000) that will never be reached, or, if that's not possible, set a per-array maximum and make provisions for rollover into a new array. That last option really is the same (eventually bounded by memory) but gives you a larger maximum.
char *mychars;
int numchars;
printf("Please enter the total number of characters:\n");
if (scanf("%d", &numchars) == NULL) {
printf("couldn't read the input; exiting\n");
exit(EXIT_FAILURE);
}
if (numchars <= 0) {
printf("this input must be positive; exiting\n");
exit(EXIT_FAILURE);
}
mychars = (char *) malloc (numchars * sizeof(char));
int current_pos = 0;
printf("Enter a digit and hit return:\n");
while (scanf("%c", &mychars[current_pos]) != NULL && current_pos < numchars) {
current_pos++;
printf("Enter a digit and hit return:\n");
}

Try this:
#include <stdlib.h>
#include <stdio.h>
int main() {
char *string = NULL;
char *newstring = NULL;
char c = '\0';
unsigned int count = 0;
while(c != 'Q'){
c = getc(stdin);
if(string == NULL){
string = (char *) malloc(sizeof(char)); // remember to include stdlib.h
string[0] = c;
}
else{
newstring = (char *) realloc(string, sizeof(char)*count);
string = newstring;
string[count] = c;
}
count++;
}
string[count-1] = '\0'; // remove the Q character
fprintf(stderr,"here you are: %s",string);
free(string); // remember this!
return 0;
}

Repetitive calls to realloc() will meet the need.
Double realloc() size as needed to avoid O(n) calls.
char *GetQLessString(void) {
size_t size_alloc = 1;
size_t size_used = size_alloc;
char *a_string = malloc(size_alloc);
if (a_string == NULL) {
return NULL; // Out of memory
}
char ch;
while(scanf("%c", &ch) == 1 && (ch != 'Q')) {
size_used++;
if (size_used > size_alloc) {
if (size_alloc > SIZE_MAX/2) {
free(a_string);
return NULL; // Too big - been typing a long time
}
size_alloc *= 2;
char *new_str = realloc(a_string, size_alloc);
if (new_str == NULL) {
free(a_string);
return NULL; // Out of memory
}
a_string = new_str;
}
a_string[size_used - 2] = ch;
}
a_string[size_used - 1] = '\0';
return a_string;
}
Code could do a final realloc(a_string, size_used) to trim excess memory allocation.
Calling routine needs to call free() when done with the buffer.
The following would be cleaner.
int ch;
while((ch = fgetc(stdin)) != EOF && (ch != 'Q')) {

Related

Reading in a line from file or stdin dynamically

I am posed with a situation where my function does exactly what I want except handle higher amounts of input.
I initially thought to process each character one by one but was running into problems doing this. So fscanf not only does what I want it to do but it is essential in reading in only one line. I noticed, I cannot reallocate space for bigger array this way though. I have tried using format specifiers i.e. %*s to include a specific amount of buffer space before hand but this still does not work.
I have noticed also, I would have no way of knowing the size of the string I am reading in.
Here is my attempt and thoughts:
#define LINE_MAX 1000
char* getline(FILE* inputStream)
{
int capacity = LINE_MAX;
char* line = malloc(capacity * sizeof(char));
int ch;
/* if (sizeof(capacity) == sizeof(line)) { // Not a valid comparison? Too late?
capacity *= 2;
line = realloc(line, capacity * sizeof(line));
} */
if (fscanf(stream, "%[^\n]s", line) == 1) {
ch = fgetc(inputStream);
if (ch != '\n' && ch != EOF) {
fscanf(inputStream, "%*[^\n]");
fscanf(inputStream, "%*c");
}
free(line);
return line;
}
free(line);
return NULL;
}
I am new to memory allocation in general but I feel as though I had a good idea of what to do here. Turns out I was wrong.
Here is an example to read a line and store it in a Character array.
#include <stdio.h>
#include <stdlib.h>
int main(void) {
signed char *str;
int c;
int i;
int size = 10;
str = malloc(size*sizeof(char));
for(i=0;(c=getchar()) !='\n' && c != EOF;++i){
if( i == size){
size = 2*size;
str = realloc(str, size*sizeof(char));
if(str == NULL){
printf("Error Unable to Grow String! :(");
exit(-1);
}
}
str[i] = c;
}
if(i == size){
str = realloc(str, (size+1)*sizeof(char));
if(str == NULL){
printf("Error Unable to Grow String! :(");
exit(-1);
}
}
str[i] = '\0';
printf("My String : %s", str);
return 0;
}
The array is resized to twice it's original size if current array can't hold the characters read from input.

Input a char string with any size [duplicate]

If I don't know how long the word is, I cannot write char m[6];,
The length of the word is maybe ten or twenty long.
How can I use scanf to get input from the keyboard?
#include <stdio.h>
int main(void)
{
char m[6];
printf("please input a string with length=5\n");
scanf("%s",&m);
printf("this is the string: %s\n", m);
return 0;
}
please input a string with length=5
input: hello
this is the string: hello
Enter while securing an area dynamically
E.G.
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE* fp, size_t size){
//The size is extended by the input with the value of the provisional
char *str;
int ch;
size_t len = 0;
str = realloc(NULL, sizeof(*str)*size);//size is start size
if(!str)return str;
while(EOF!=(ch=fgetc(fp)) && ch != '\n'){
str[len++]=ch;
if(len==size){
str = realloc(str, sizeof(*str)*(size+=16));
if(!str)return str;
}
}
str[len++]='\0';
return realloc(str, sizeof(*str)*len);
}
int main(void){
char *m;
printf("input string : ");
m = inputString(stdin, 10);
printf("%s\n", m);
free(m);
return 0;
}
With the computers of today, you can get away with allocating very large strings (hundreds of thousands of characters) while hardly making a dent in the computer's RAM usage. So I wouldn't worry too much.
However, in the old days, when memory was at a premium, the common practice was to read strings in chunks. fgets reads up to a maximum number of chars from the input, but leaves the rest of the input buffer intact, so you can read the rest from it however you like.
in this example, I read in chunks of 200 chars, but you can use whatever chunk size you want of course.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readinput()
{
#define CHUNK 200
char* input = NULL;
char tempbuf[CHUNK];
size_t inputlen = 0, templen = 0;
do {
fgets(tempbuf, CHUNK, stdin);
templen = strlen(tempbuf);
input = realloc(input, inputlen+templen+1);
strcpy(input+inputlen, tempbuf);
inputlen += templen;
} while (templen==CHUNK-1 && tempbuf[CHUNK-2]!='\n');
return input;
}
int main()
{
char* result = readinput();
printf("And the result is [%s]\n", result);
free(result);
return 0;
}
Note that this is a simplified example with no error checking; in real life you will have to make sure the input is OK by verifying the return value of fgets.
Also note that at the end if the readinput routine, no bytes are wasted; the string has the exact memory size it needs to have.
I've seen only one simple way of reading an arbitrarily long string, but I've never used it. I think it goes like this:
char *m = NULL;
printf("please input a string\n");
scanf("%ms",&m);
if (m == NULL)
fprintf(stderr, "That string was too long!\n");
else
{
printf("this is the string %s\n",m);
/* ... any other use of m */
free(m);
}
The m between % and s tells scanf() to measure the string and allocate memory for it and copy the string into that, and to store the address of that allocated memory in the corresponding argument. Once you're done with it you have to free() it.
This isn't supported on every implementation of scanf(), though.
As others have pointed out, the easiest solution is to set a limit on the length of the input. If you still want to use scanf() then you can do so this way:
char m[100];
scanf("%99s",&m);
Note that the size of m[] must be at least one byte larger than the number between % and s.
If the string entered is longer than 99, then the remaining characters will wait to be read by another call or by the rest of the format string passed to scanf().
Generally scanf() is not recommended for handling user input. It's best applied to basic structured text files that were created by another application. Even then, you must be aware that the input might not be formatted as you expect, as somebody might have interfered with it to try to break your program.
There is a new function in C standard for getting a line without specifying its size. getline function allocates string with required size automatically so there is no need to guess about string's size. The following code demonstrate usage:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
char *line = NULL;
size_t len = 0;
ssize_t read;
while ((read = getline(&line, &len, stdin)) != -1) {
printf("Retrieved line of length %zu :\n", read);
printf("%s", line);
}
if (ferror(stdin)) {
/* handle error */
}
free(line);
return 0;
}
If I may suggest a safer approach:
Declare a buffer big enough to hold the string:
char user_input[255];
Get the user input in a safe way:
fgets(user_input, 255, stdin);
A safe way to get the input, the first argument being a pointer to a buffer where the input will be stored, the second the maximum input the function should read and the third is a pointer to the standard input - i.e. where the user input comes from.
Safety in particular comes from the second argument limiting how much will be read which prevents buffer overruns. Also, fgets takes care of null-terminating the processed string.
More info on that function here.
EDIT: If you need to do any formatting (e.g. convert a string to a number), you can use atoi once you have the input.
Safer and faster (doubling capacity) version:
char *readline(char *prompt) {
size_t size = 80;
char *str = malloc(sizeof(char) * size);
int c;
size_t len = 0;
printf("%s", prompt);
while (EOF != (c = getchar()) && c != '\r' && c != '\n') {
str[len++] = c;
if(len == size) str = realloc(str, sizeof(char) * (size *= 2));
}
str[len++]='\0';
return realloc(str, sizeof(char) * len);
}
Read directly into allocated space with fgets().
Special care is need to distinguish a successful read, end-of-file, input error and out-of memory. Proper memory management needed on EOF.
This method retains a line's '\n'.
#include <stdio.h>
#include <stdlib.h>
#define FGETS_ALLOC_N 128
char* fgets_alloc(FILE *istream) {
char* buf = NULL;
size_t size = 0;
size_t used = 0;
do {
size += FGETS_ALLOC_N;
char *buf_new = realloc(buf, size);
if (buf_new == NULL) {
// Out-of-memory
free(buf);
return NULL;
}
buf = buf_new;
if (fgets(&buf[used], (int) (size - used), istream) == NULL) {
// feof or ferror
if (used == 0 || ferror(istream)) {
free(buf);
buf = NULL;
}
return buf;
}
size_t length = strlen(&buf[used]);
if (length + 1 != size - used) break;
used += length;
} while (buf[used - 1] != '\n');
return buf;
}
Sample usage
int main(void) {
FILE *istream = stdin;
char *s;
while ((s = fgets_alloc(istream)) != NULL) {
printf("'%s'", s);
free(s);
fflush(stdout);
}
if (ferror(istream)) {
puts("Input error");
} else if (feof(istream)) {
puts("End of file");
} else {
puts("Out of memory");
}
return 0;
}
I know that I have arrived after 4 years and am too late but I think I have another way that someone can use. I had used getchar() Function like this:-
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//I had putten the main Function Bellow this function.
//d for asking string,f is pointer to the string pointer
void GetStr(char *d,char **f)
{
printf("%s",d);
for(int i =0;1;i++)
{
if(i)//I.e if i!=0
*f = (char*)realloc((*f),i+1);
else
*f = (char*)malloc(i+1);
(*f)[i]=getchar();
if((*f)[i] == '\n')
{
(*f)[i]= '\0';
break;
}
}
}
int main()
{
char *s =NULL;
GetStr("Enter the String:- ",&s);
printf("Your String:- %s \nAnd It's length:- %lu\n",s,(strlen(s)));
free(s);
}
here is the sample run for this program:-
Enter the String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
Your String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
And It's length:- 67
Take a character pointer to store required string.If you have some idea about possible size of string then use function
char *fgets (char *str, int size, FILE* file);
else you can allocate memory on runtime too using malloc() function which dynamically provides requested memory.
i also have a solution with standard inputs and outputs
#include<stdio.h>
#include<malloc.h>
int main()
{
char *str,ch;
int size=10,len=0;
str=realloc(NULL,sizeof(char)*size);
if(!str)return str;
while(EOF!=scanf("%c",&ch) && ch!="\n")
{
str[len++]=ch;
if(len==size)
{
str = realloc(str,sizeof(char)*(size+=10));
if(!str)return str;
}
}
str[len++]='\0';
printf("%s\n",str);
free(str);
}
I have a solution using standard libraries of C and also creating a string type (alias of char*) like in C++
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef char* string;
typedef struct __strstr {
char ch;
struct __strstr *next;
}Strstr;
void get_str(char **str) {
char ch, *buffer, a;
Strstr *new = NULL;
Strstr *head = NULL, *tmp = NULL;
int c = 0, k = 0;
while ((ch = getchar()) != '\n') {
new = malloc(sizeof(Strstr));
if(new == NULL) {
printf("\nError!\n");
exit(1);
}
new->ch = ch;
new->next = NULL;
new->next = head;
head = new;
}
tmp = head;
while (tmp != NULL) {
c++;
tmp = tmp->next;
}
if(c == 0) {
*str = "";
} else {
buffer = malloc(sizeof(char) * (c + 1));
*str = malloc(sizeof(char) * (c + 1));
if(buffer == NULL || *str == NULL) {
printf("\nError!\n");
exit(1);
}
tmp = head;
while (tmp != NULL) {
buffer[k] = tmp->ch;
k++;
tmp = tmp->next;
}
buffer[k] = '\0';
for (int i = 0, j = strlen(buffer)-1; i < j; i++, j--) {
a = buffer[i];
buffer[i] = buffer[j];
buffer[j] = a;
}
strcpy(*str, buffer);
// Dealloc
free(buffer);
while (head != NULL) {
tmp = head;
head = head->next;
free(tmp);
}
}
}
int main() {
string str;
printf("Enter text: ");
get_str(&str);
printf("%s\n", str);
return 0;
}

Dynamic array of pointers from user input

I need some help regarding dynamic allocation of arrays of pointers in C. I am trying to create a program that reads a sentence of words from user input, and stores the words in character array strings. I then want to save the pointers char *word to these words in an array of pointers char **wordArray.
Creating a working method for dynamic allocation for the words was easy enough, and it reads character by character from user input. However, trying to adapt this method for the array of pointers was trickier.
The current function char **varArray is obviously flawed, but my thinking was "while the user has input, get words pointers for the array of pointers". It now effectively loops the first word for every char c.
My question is, how do I implement a second layer (char **varArray()) of dynamic memory allocation of my array of pointers? How can the function detect when to call char *word()?
Feedback for the code, style, or other errors are of course appreciated. My level is intermediate beginner.
/*CREATES AND ALLOCATES DYNAMIC VARIABLE ARRAY*/
#include <stdio.h>
#include <stdlib.h>
char **varArray();
char *word();
char **varArray()
{
char **tmp=NULL;
char **wordArray=NULL;
size_t size=0;
char c = EOF;
int words=0;
while(c) {
c=getc(stdin);
if (c == EOF || c == '\n')
c=0;
if (size <= words) {
size+=sizeof(char *);
tmp = realloc(wordArray,size);
if(tmp == NULL) {
free(wordArray);
wordArray=NULL;
printf("Memory allocation failed. Aborted.\n");
break;
}
wordArray=tmp;
}
words++;
wordArray[words]= word();
return wordArray;
}
The method for retrieving ONE word:
/*GETS ONE WORD FROM USER INPUT*/
char *word()
{
char *word=NULL, *tmp=NULL;
size_t size=0;
char c = EOF;
int letters=0;
while(c) { //reads character by character
c=getc(stdin);
if (c == EOF || c == '\n' || c==' ') //remove ' ' to read all input
c =0;
if (size <= letters) { //increase and reallocate memory
size = size + sizeof(char);
tmp = realloc(word,size);
if (tmp==NULL) { //check if allocation failed
free(word);
word=NULL;
printf("Memory allocation failed. Aborted.\n");
break;
}
word= tmp;
}
letters=letters+1;
word[letters]=c;
}
/*ADD SENTINEL CHARACTER*/
letters++;
size += sizeof(char);
word = realloc(word,size);
word[letters]='\n';
return word;
}
Here's the skeleton of the program you want to write.
...
char* currentWord;
char **wordArray=NULL;
while ((currentWord = word()) != NULL) {
.... add current word to word array with realloc...
}
....
char* word() {
int ch;
char* outputWord = NULL;
while ((ch = getch()) != EOF) {
if ( ... ch is a word character ... )
... add ch to output word with realloc ...
else {
char* ret = outputWord;
outputWord = NULL;
return ret;
}
}
return NULL;
}
Note how the two while loops are doing exactly the same thing.
while ((element = getNextElement()) != sentinelValue) {
.... process newly obtained element ....
}
I have now successfully implemented a version of the shell provided by #n.m. However, another problem arose - since word() relies on the sentinel newline character \n to quit, it also fails to read the final word, and does not enter the loop the last, vital time.
I have tried to implement some if-cases, but these of course fail due to the while-condition. Another idea would be to implement some switch case, but I am not sure that would avoid the nastiness of the while loop?
Do note that the code has little error checking to minimise the clutter.
char **wordArray() {
char *currentWord;
char **wordArray=NULL;
size_t size=0;
int i=0;
while((currentWord = word()) != NULL) {
size+=sizeof(char *);
wordArray=(char **) realloc(wordArray,size);
wordArray[i]=currentWord;
printf("Test - Current word: %s\n",currentWord);
i++;
}
return wordArray;
}
The relevant word() function:
char *word() {
char ch;
int i=0;
size_t size=0;
char *returnWord = NULL;
char *outputWord = NULL;
char *tmp = NULL;
while((ch = getc(stdin)) != EOF && ch !='\n') { //&& ch !='\n'
if (ch != ' ' ) { //&& ch !='\n'
size += sizeof(char);
tmp = (char *) realloc(outputWord,size);
outputWord= tmp;
outputWord[i]=ch;
printf("Test1: %c\n",*(outputWord+i));
i++;
} else {
printf("Test2: %s\n",outputWord);
returnWord=outputWord;
outputWord=NULL;
printf("Test3: %s\n",returnWord);
return returnWord;
}
}
return NULL;
}

can anyone explain me how does this function work?

I don't understand what this function do. Can anyone explain me in detail please?
char *my_getline(FILE *stream) {
char *line = NULL;
size_t pos = 0;
int c;
while ((c = getc(stream)) != EOF) {
char *newp = realloc(line, pos + 2);
if (newp == NULL) {
free(line);
return NULL;
}
line = newp;
if (c == '\n')
break;
line[pos++] = (char)c;
}
if (line) {
line[pos] = '\0';
}
return line;
}
If you can add a comment on my code, I think that will help me. I want to search a substring in a string and I found this function code.
This is the main function:
int main(void) {
char *str, *sub;
size_t len1, len2, i, count = 0;
printf("Insert string :\n");
str = my_getline(stdin);
printf("insert substring :\n");
sub = my_getline(stdin);
if (str && sub) {
len1 = strlen(str);
len2 = strlen(sub);
for (i = 0; i + len2 <= len1; i++) {
if (!memcmp(str + i, sub, len2)) {
count++;
printf("Substring found at index : %d\n", i);
}
}
printf("in the number of: %d\n", count);
if (count == 0) {
printf("Substring not found\n");
}
}
free(str);
free(sub);
return 0;
}
I understand the main function but unable to understand the logic in function my_getline.
Please help me in understanding the logic. Thanks!
char *my_getline(FILE *stream) {
// pointer to the line to be read:
char *line = NULL;
// position of the next character:
size_t pos = 0;
// single character:
int c;
while ((c = getc(stream)) != EOF) { // read 1 character at a time until EOF
// allocate a new buffer with room for the char just read + a 0 terminator
// when `line` is NULL, this is the same as `malloc()`, otherwise it
// will change the size of the allocation:
char *newp = realloc(line, pos + 2);
// check for errors:
if (newp == NULL) {
free(line);
return NULL;
}
// no errors, assign new buffer to `line`:
line = newp;
// end of line found: we're done:
if (c == '\n')
break;
// otherwise add new character to the line:
line[pos++] = (char)c;
}
// if there was *anything* to read, add 0 terminator (marks end of string):
if (line) {
line[pos] = '\0';
}
return line;
}
That's about it. Note it's horribly inefficient for two reasons: It reads only one character at a time and it calls realloc() for each and every character.
A better solution would use e.g. fgets() and increase the buffer size in reasonable chunks, for example like this:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define GETLINE_CHUNK 1024
static void xrealloc(void *bufPtr, size_t size)
{
void **buf = bufPtr;
void *tmp = realloc(*buf, size);
if (!tmp)
{
free(*buf);
*buf = 0;
}
*buf = tmp;
}
char *my_getline(FILE *stream)
{
// allocate first chunk:
char *buf = malloc(GETLINE_CHUNK);
if (!buf) return 0;
*buf = 0;
size_t pos = 0;
// read up to GETLINE_CHUNK bytes, until newline:
while (fgets(buf + pos, GETLINE_CHUNK, stream))
{
// look for newline:
char *nlPos = strchr(buf, '\n');
if (nlPos)
{
// found, then our line is complete
*nlPos = 0;
// shrink buffer to needed size
xrealloc(&buf, nlPos-buf+1);
return buf;
}
// set next offset to read
pos = strlen(buf);
// increase buffer size to have room for a whole other GETLINE_CHUNK:
xrealloc(&buf, pos + GETLINE_CHUNK);
if (!buf) return 0;
}
// if nothing was read, free buffer and return NULL:
if (*buf == 0)
{
free(buf);
buf = 0;
}
return buf;
}
int main(void)
{
char *line = my_getline(stdin);
if (line)
{
puts(line);
free(line);
}
else puts("no input!");
return 0;
}
Well this function gives you line, Lets go Step by Step:
char *my_getline(FILE *stream) {
char *line = NULL; //this is just pointer initialization
size_t pos = 0; //position variable definition and init
int c; //a variable to store temporary character
while ((c = getc(stream)) != EOF) //read every character till end of file
{
// To dynamically allocate memory, with reference to the
// number of character and plus '2' is just to compensate null
// character and the character(Since pos is 0)
char *newp = realloc(line, pos + 2);
if (newp == NULL) { // this is to check whether memory was alloacted properly or not.
free(line); //if not free line
return NULL;// break the program and return NULL
}
line = newp;// if memory is allocated properly store allocated memory in line pointer
if (c == '\n') //if new line is detected
break;// break the while loop
line[pos++] = (char)c; // store the character in dynamically allocated memory and new character in new location.
}
if (line) { //if line contains something then add a null character at last, to complete that string
line[pos] = '\0';
}
return line; //returns the content of line.
}
Hope this helps :)

How can I read an input string of unknown length?

If I don't know how long the word is, I cannot write char m[6];,
The length of the word is maybe ten or twenty long.
How can I use scanf to get input from the keyboard?
#include <stdio.h>
int main(void)
{
char m[6];
printf("please input a string with length=5\n");
scanf("%s",&m);
printf("this is the string: %s\n", m);
return 0;
}
please input a string with length=5
input: hello
this is the string: hello
Enter while securing an area dynamically
E.G.
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE* fp, size_t size){
//The size is extended by the input with the value of the provisional
char *str;
int ch;
size_t len = 0;
str = realloc(NULL, sizeof(*str)*size);//size is start size
if(!str)return str;
while(EOF!=(ch=fgetc(fp)) && ch != '\n'){
str[len++]=ch;
if(len==size){
str = realloc(str, sizeof(*str)*(size+=16));
if(!str)return str;
}
}
str[len++]='\0';
return realloc(str, sizeof(*str)*len);
}
int main(void){
char *m;
printf("input string : ");
m = inputString(stdin, 10);
printf("%s\n", m);
free(m);
return 0;
}
With the computers of today, you can get away with allocating very large strings (hundreds of thousands of characters) while hardly making a dent in the computer's RAM usage. So I wouldn't worry too much.
However, in the old days, when memory was at a premium, the common practice was to read strings in chunks. fgets reads up to a maximum number of chars from the input, but leaves the rest of the input buffer intact, so you can read the rest from it however you like.
in this example, I read in chunks of 200 chars, but you can use whatever chunk size you want of course.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readinput()
{
#define CHUNK 200
char* input = NULL;
char tempbuf[CHUNK];
size_t inputlen = 0, templen = 0;
do {
fgets(tempbuf, CHUNK, stdin);
templen = strlen(tempbuf);
input = realloc(input, inputlen+templen+1);
strcpy(input+inputlen, tempbuf);
inputlen += templen;
} while (templen==CHUNK-1 && tempbuf[CHUNK-2]!='\n');
return input;
}
int main()
{
char* result = readinput();
printf("And the result is [%s]\n", result);
free(result);
return 0;
}
Note that this is a simplified example with no error checking; in real life you will have to make sure the input is OK by verifying the return value of fgets.
Also note that at the end if the readinput routine, no bytes are wasted; the string has the exact memory size it needs to have.
I've seen only one simple way of reading an arbitrarily long string, but I've never used it. I think it goes like this:
char *m = NULL;
printf("please input a string\n");
scanf("%ms",&m);
if (m == NULL)
fprintf(stderr, "That string was too long!\n");
else
{
printf("this is the string %s\n",m);
/* ... any other use of m */
free(m);
}
The m between % and s tells scanf() to measure the string and allocate memory for it and copy the string into that, and to store the address of that allocated memory in the corresponding argument. Once you're done with it you have to free() it.
This isn't supported on every implementation of scanf(), though.
As others have pointed out, the easiest solution is to set a limit on the length of the input. If you still want to use scanf() then you can do so this way:
char m[100];
scanf("%99s",&m);
Note that the size of m[] must be at least one byte larger than the number between % and s.
If the string entered is longer than 99, then the remaining characters will wait to be read by another call or by the rest of the format string passed to scanf().
Generally scanf() is not recommended for handling user input. It's best applied to basic structured text files that were created by another application. Even then, you must be aware that the input might not be formatted as you expect, as somebody might have interfered with it to try to break your program.
There is a new function in C standard for getting a line without specifying its size. getline function allocates string with required size automatically so there is no need to guess about string's size. The following code demonstrate usage:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
char *line = NULL;
size_t len = 0;
ssize_t read;
while ((read = getline(&line, &len, stdin)) != -1) {
printf("Retrieved line of length %zu :\n", read);
printf("%s", line);
}
if (ferror(stdin)) {
/* handle error */
}
free(line);
return 0;
}
If I may suggest a safer approach:
Declare a buffer big enough to hold the string:
char user_input[255];
Get the user input in a safe way:
fgets(user_input, 255, stdin);
A safe way to get the input, the first argument being a pointer to a buffer where the input will be stored, the second the maximum input the function should read and the third is a pointer to the standard input - i.e. where the user input comes from.
Safety in particular comes from the second argument limiting how much will be read which prevents buffer overruns. Also, fgets takes care of null-terminating the processed string.
More info on that function here.
EDIT: If you need to do any formatting (e.g. convert a string to a number), you can use atoi once you have the input.
Safer and faster (doubling capacity) version:
char *readline(char *prompt) {
size_t size = 80;
char *str = malloc(sizeof(char) * size);
int c;
size_t len = 0;
printf("%s", prompt);
while (EOF != (c = getchar()) && c != '\r' && c != '\n') {
str[len++] = c;
if(len == size) str = realloc(str, sizeof(char) * (size *= 2));
}
str[len++]='\0';
return realloc(str, sizeof(char) * len);
}
Read directly into allocated space with fgets().
Special care is need to distinguish a successful read, end-of-file, input error and out-of memory. Proper memory management needed on EOF.
This method retains a line's '\n'.
#include <stdio.h>
#include <stdlib.h>
#define FGETS_ALLOC_N 128
char* fgets_alloc(FILE *istream) {
char* buf = NULL;
size_t size = 0;
size_t used = 0;
do {
size += FGETS_ALLOC_N;
char *buf_new = realloc(buf, size);
if (buf_new == NULL) {
// Out-of-memory
free(buf);
return NULL;
}
buf = buf_new;
if (fgets(&buf[used], (int) (size - used), istream) == NULL) {
// feof or ferror
if (used == 0 || ferror(istream)) {
free(buf);
buf = NULL;
}
return buf;
}
size_t length = strlen(&buf[used]);
if (length + 1 != size - used) break;
used += length;
} while (buf[used - 1] != '\n');
return buf;
}
Sample usage
int main(void) {
FILE *istream = stdin;
char *s;
while ((s = fgets_alloc(istream)) != NULL) {
printf("'%s'", s);
free(s);
fflush(stdout);
}
if (ferror(istream)) {
puts("Input error");
} else if (feof(istream)) {
puts("End of file");
} else {
puts("Out of memory");
}
return 0;
}
I know that I have arrived after 4 years and am too late but I think I have another way that someone can use. I had used getchar() Function like this:-
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//I had putten the main Function Bellow this function.
//d for asking string,f is pointer to the string pointer
void GetStr(char *d,char **f)
{
printf("%s",d);
for(int i =0;1;i++)
{
if(i)//I.e if i!=0
*f = (char*)realloc((*f),i+1);
else
*f = (char*)malloc(i+1);
(*f)[i]=getchar();
if((*f)[i] == '\n')
{
(*f)[i]= '\0';
break;
}
}
}
int main()
{
char *s =NULL;
GetStr("Enter the String:- ",&s);
printf("Your String:- %s \nAnd It's length:- %lu\n",s,(strlen(s)));
free(s);
}
here is the sample run for this program:-
Enter the String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
Your String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
And It's length:- 67
Take a character pointer to store required string.If you have some idea about possible size of string then use function
char *fgets (char *str, int size, FILE* file);
else you can allocate memory on runtime too using malloc() function which dynamically provides requested memory.
i also have a solution with standard inputs and outputs
#include<stdio.h>
#include<malloc.h>
int main()
{
char *str,ch;
int size=10,len=0;
str=realloc(NULL,sizeof(char)*size);
if(!str)return str;
while(EOF!=scanf("%c",&ch) && ch!="\n")
{
str[len++]=ch;
if(len==size)
{
str = realloc(str,sizeof(char)*(size+=10));
if(!str)return str;
}
}
str[len++]='\0';
printf("%s\n",str);
free(str);
}
I have a solution using standard libraries of C and also creating a string type (alias of char*) like in C++
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef char* string;
typedef struct __strstr {
char ch;
struct __strstr *next;
}Strstr;
void get_str(char **str) {
char ch, *buffer, a;
Strstr *new = NULL;
Strstr *head = NULL, *tmp = NULL;
int c = 0, k = 0;
while ((ch = getchar()) != '\n') {
new = malloc(sizeof(Strstr));
if(new == NULL) {
printf("\nError!\n");
exit(1);
}
new->ch = ch;
new->next = NULL;
new->next = head;
head = new;
}
tmp = head;
while (tmp != NULL) {
c++;
tmp = tmp->next;
}
if(c == 0) {
*str = "";
} else {
buffer = malloc(sizeof(char) * (c + 1));
*str = malloc(sizeof(char) * (c + 1));
if(buffer == NULL || *str == NULL) {
printf("\nError!\n");
exit(1);
}
tmp = head;
while (tmp != NULL) {
buffer[k] = tmp->ch;
k++;
tmp = tmp->next;
}
buffer[k] = '\0';
for (int i = 0, j = strlen(buffer)-1; i < j; i++, j--) {
a = buffer[i];
buffer[i] = buffer[j];
buffer[j] = a;
}
strcpy(*str, buffer);
// Dealloc
free(buffer);
while (head != NULL) {
tmp = head;
head = head->next;
free(tmp);
}
}
}
int main() {
string str;
printf("Enter text: ");
get_str(&str);
printf("%s\n", str);
return 0;
}

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