This is a problem I don't understand - I am using fgets() in main and it works. I use it (I think) in exactly the same way in a function and I get an error [Segmentation fault core dumped -- exit code 139).
This code is based on a sample program in book Ivor Horton's "Beginning C" (it's a old tile but I'm just wanting to learn the basics from it).
My program is as follows. I am working on *nix using Geany (basically, compiling with GCC). You can see that fgets works in main (output is the string you enter). But it doesn't work in the function str_in(). It gets as far as the second printf() statement to enter a string, no further. Note that in the book, Horton uses gets(). I am trying to implement a safer string input function here, but no joy.
By the way the program is supposed to sort strings stored in an array of string pointers.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define TRUE 1
#define FALSE 0
#define MAX_NUM_STRINGS 50
int str_in(char **); /*Pointer to a string pointer*/
void str_sort(char *[], int n); /*Array of pointers to strings, number of strings in array*/
void str_out (char *[], int n); /*Array of pointers to strings, number of strings in array*/
int main(){
char *pS[MAX_NUM_STRINGS] = { NULL }; /*Array of pointers to strings stored in str_space*/
int numStrings = 0; /*Count of strings*/
char buffer[BUFSIZ];
printf("Enter a string\n");
fgets(buffer, BUFSIZ, stdin);
printf("%s", buffer);
printf("fgets works here\n\n");
/* get string input from user - a pointer to each string is saved in pS */
while ( str_in(&pS[numStrings]) && numStrings < MAX_NUM_STRINGS)
numStrings++;
if ( numStrings > 0 ){
str_sort(pS, numStrings);
str_out(pS, numStrings);
}
return 0;
}
int str_in(char** pString){
char buffer[BUFSIZ];
char *p;
printf ("Enter string:\n");
fgets(buffer, 60, stdin);
printf("fgets doesn't work here!!\n");
if( buffer != NULL ){
printf("here");
if ((p = strchr(buffer, '\n')) != NULL)
*p = '\0'; /*replace newline with null character*/
else
return FALSE;
if ( strlen(buffer) > 0 ){
strcpy(*pString, buffer);
return TRUE;
}
else
return FALSE; /*blank line - end of input*/
}
else
return FALSE;
}
void str_sort(char* pStrings[], int n){
/*sort strings by manipulating array of string pointers*/
char *temp;
int sorted = FALSE;
int i = 0;
while (!sorted){
sorted = TRUE;
for(i = 0; i < n - 1; i++){
temp = pStrings[i];
if ( strcmp(temp, pStrings[i+1]) > 1 ){
pStrings[i] = pStrings[i+1];
pStrings[i+1] = temp;
sorted = FALSE;
break;
}
}
}
}
void str_out(char* pStrings[], int n){
/*print strings to standard output. Free memory as each string is printed */
int i = 0;
printf("Sorted strings:\n");
for(i = 0; i < n; i++){
printf("%s", pStrings[i]);
free(pStrings[i]);
}
}
The segmentation fault is not caused by fgets(), but by strcpy():
strcpy(*pString, buffer);
You try to write to *pString, but you never allocate memory for it. pS in main() is just an array of null pointers.
Another thing is with the test with if( buffer != NULL ), that would never be true since buffer is an array, not a pointer.
You must check for the return value of fgets to see if you have successfully received something, if not then you should never use your buffer as a string as you are not NUL terminating the buffer.
/* Checking for buffer != NULL is of no use */
/* as buffer will always be not NULL since */
/* since you have allocated it as char buffer[BUFSIZ] */
if (fgets(buffer, BUFSIZ, stdin) == NULL) {
/* buffer may not be a valid string */
}
So what you can do it to initialize the buffer to a NUL string, as soon as you enter the function (after your declarations are done
buffer[0] = 0; /* initialize to NUL string */
now you can use buffer as a string anywhere.
Also note than if BUFSIZ is too big greater than a couple of KB, then your might get seg fault due to stack overflow. If they are too big you could make buffer as "static char" instead of "char".
Related
I'm writing a c code to read strings from stdin with scanf() and while loop (into a two-dimensional char array). My strategy is to use an input array to temporarily store each string and then assign it to a preword array (fixed sized). However, my strategy failed and all strings stored in my arrays are the same (the last string input). How to fix it?
I used a fgets() and it works find. However, I cannot use it to deal with a new line of strings (from stdin). My fgets() reads only the first line and that's why I turn to scanf and while loop.
#include<stdio.h>
#include<stdlib.h>
#define MAX 1000
#define size 50
int main ()
{
int count = 0;
char input[size];
char * preword[MAX];
while (scanf("%s",input)!= EOF){
preword[count] = input;
printf("preword[%d] is %s\n",count,preword[count]);
count++;
}
printf("the count is %d\n",count);
for (int i = 0; i < count; i++){
printf("preword[%d] is %s\n",i,preword[i]);
}
return 0;
}
I expect my input arrays from stdin will be stored in a two-dimensional char array. Below is the output in terminal after compilation. My input is a txt file, in which I have
hello world
I am a hero
It turns out that all strings stored in the two-d array are the last word.
preword[0] is hello
preword[1] is world
preword[2] is I
preword[3] is am
preword[4] is a
preword[5] is hero
the count is 6
preword[0] is hero
preword[1] is hero
preword[2] is hero
preword[3] is hero
preword[4] is hero
preword[5] is hero
Firstly here
char * preword[MAX];
preword is array of character pointer i.e each element is a char pointer & when you are doing like
preword[count] = input;
as #paddy pointed its copies input in every element of preword and it's the same pointer since you haven't allocated memory for preword[count], correct way is to allocate memory for each pointer and then copy.
Also use fgets() instead of scanf() here. For e.g
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define MAX 1000
#define size 50
int main (void)
{
int count = 0;
char input[size] = {0};
char * preword[MAX] = {0};
size_t retStrCspn = 0;
while (fgets(input, size, stdin) != NULL){
/* remove trailing new line if its stored at end of buffer by fgets() */
input[retStrCspn = strcspn(input, "\n")] = 0; /* remove the trailing & use the return value for allocating memory purpose \n */
preword[count] = malloc(retStrCspn + 1); /* Allocate memory for each pointer elements */
if(preword[count] != NULL) {
memcpy (preword[count], input, retStrCspn + 1); /* copy input buffer into each different memory location */
printf("preword[%d] is %s\n",count,preword[count]);
count++;
}
else {
/* #TODO malloc erro handling */
}
}
printf("the count is %d\n",count);
for (int i = 0; i < count && preword[i] != NULL; i++){
printf("preword[%d] is %s\n",i,preword[i]);
free(preword[count]); /* free dynamically allocated memory here*/
}
return 0;
}
So I started to learn how to code a few weeks ago, and this site helped me so much, thank you for that. But this time I got stuck and canĀ“t really figure out why...Hope you can help me.
Basically I have a function prototype I have to use in my program and I have my troubles with it. The function should receive a string and then only copy every second char of that string and return the result...
This is what I've got so far:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define max_size 1000
char * everySecondChar(char * dest, char * input);
int main() {
char inputstr[max_size] = {0};
char *input[max_size] = {0};
char *dest[max_size] = {0};
char temp[max_size] = {0};
int i = 0;
while (fgets(inputstr, max_size, stdin) != NULL)
{
input[i] = strndup(inputstr, max_size);
strcat(temp,inputstr);
i++;
}
input[0] = strndup(temp, max_size);
printf("Inputted text:\n%s", *input);
printf("\n");
printf("\n");
printf("Resulting string:\n");
everySecondChar(*dest, *input);
printf("%s", *dest);
return 0;
}
char * everySecondChar(char * dest, char * input)
{
int i = 0;
for(i = 0; i < max_size; i+=2) {
strcat(dest,input);
}
return dest;
}
I know this is probably a 1-min challenge for the most of you, but I am having my troubles whenever I see those nasty * in a function prototype :(
Congrats on getting started with programming!
To your question: there's quite a few things that could be addressed, but since there seems to be some more basic confusion and misunderstanding, I'll address what makes sense given the context of your issue.
First, you're using strcat which concatenates strings (e.g. adds to the string), when you just need simple character assignment.
Next, you have a lot of pointers to arrays and there seems to be some confusion regarding pointers; in your main function, you don't need all of the temporary variables to do what you're wanting.
You could have simply:
char inputstr[MAX_SIZE] = {0};
char dest[MAX_SIZE] = {0};
You could have less (realistically) but we'll stick with the basics for now.
Next, you're looping to get user input:
while (fgets(inputstr, max_size, stdin) != NULL)
{
input[i] = strndup(inputstr, max_size);
strcat(temp,inputstr);
i++;
}
Here, you don't check if i exceeds max_size which your input variable has been allocated for; if i exceeds max_size when you go to assign input[i] to the memory location returned by strndup (which calls malloc), you are writing beyond your memory bounds, which is also known as a buffer overflow. This is potentially where your segmentation fault is happening. You could also have some issues when you do strcat(temp,inputstr); since strcat:
Appends a copy of the source string to the destination string. The terminating null character in destination is overwritten by the first character of source, and a null-character is included at the end of the new string formed by the concatenation of both in destination.
If you're simply just trying to get what the user entered, and print every 2nd character with your function, you don't need to loop:
if (fgets(inputstr, MAX_SIZE, stdin) != NULL) {
everySecondChar(dest, inputstr);
printf("Inputted text:\n%s\n\nResulting string:\n%s\n", inputstr, dest);
}
Lastly, in your everySecondChar function, you're using strcat again when all you need to do is simple assignment (which does a 'copy'):
char * everySecondChar(char * dest, char * input)
{
int i, j;
for(i = 0, j = 0; i < MAX_SIZE; ++i, ++j) {
if (input[i] == 0) break; // end if string?
dest[j] = input[i++];
}
return dest;
}
Putting all of it together, you get:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_SIZE 1000
char * everySecondChar(char * dest, char * input);
int main(void)
{
char inputstr[MAX_SIZE] = {0};
char dest[MAX_SIZE] = {0};
printf("Enter some text: ");
if (fgets(inputstr, MAX_SIZE, stdin) != NULL) {
everySecondChar(dest, inputstr);
printf("Inputted text:\n%s\n\nResulting string:\n%s\n", inputstr, dest);
}
return 0;
}
char * everySecondChar(char * dest, char * input)
{
int i, j;
for(i = 0, j = 0; i < MAX_SIZE; ++i, ++j) {
if (input[i] == 0) break; // end if string?
dest[j] = input[i++];
}
return dest;
}
That aside, I'll address some other things; typically if you have a constant value, like your max_size variable, it's considered "best practice" to capitalize the entire thing:
`#define MAX_SIZE 1000`
I am having my troubles whenever I see those nasty * in a function prototype :(
Those nasty *'s in your function prototype (and variable declarations) are known as a pointer qualifier; it indicates that the type of the variable is a pointer to the type specified. A pointer isn't something to be scared of, you're learning C, it's highly important you understand what a pointer is and it's utility.
I won't dive into all of the specificities of pointers, aliases, etc. etc. since that is beyond the scope of this Q&A, but WikiBooks has a great intro and explanation covering a lot of those concepts.
Hope that can help!
I tried to get the inputs(strings) from user and store them in an array.But after I ran this code, the program instantly crashed.
#include <stdio.h>
int main() {
int i;
char *word[3];
for(i=0;i<3;i++)
{
printf(" Enter a word: ");
scanf("%s", &word[i]);
}
printf("%s ", word[0]);
return 0;
}
In this line:
scanf("%s", &word[i]);
You need to make sure word[i] is pointing somewhere, and has enough space to occupy the string entered. Since word[i] is a char * pointer, you need to at some time allocate memory for this. Otherwise, it is just a dangling pointer not pointing anywhere.
If you want to stick with scanf(), then you can allocate some space beforehand with malloc.
malloc() allocates requested memory on the heap, then returns a void* pointer at the end.
You can apply malloc() in your code like this:
size_t malloc_size = 100;
for (i = 0; i < 3; i++) {
word[i] = malloc(malloc_size * sizeof(char)); /* allocates 100 bytes */
printf("Enter word: ");
scanf("%99s", word[i]); /* Use %99s to avoid overflow */
/* No need to include & address, since word[i] is already a char* pointer */
}
Note: Must check return value of malloc(), because it can return NULL when unsuccessful.
Additionally, whenever you allocate memory with the use of malloc(), you must use free to deallocate requested memory at the end:
free(word[i]);
word[i] = NULL; /* safe to make sure pointer is no longer pointing anywhere */
Another approach without scanf
A more proper way to read strings should be with fgets.
char *fgets(char *str, int n, FILE *stream) reads a line from an input stream, and copies the bytes over to char *str, which must be given a size of n bytes as a threshold of space it can occupy.
Things to note about fgets:
Appends \n character at the end of buffer. Can be removed easily.
On error, returns NULL. If no characters are read, still returns NULL at the end.
Buffer must be statically declared with a given size n.
Reads specified stream. Either from stdin or FILE *.
Here is an example of how it can be used to read a line of input from stdin:
char buffer[100]; /* statically declared buffer */
printf("Enter a string: ");
fgets(buffer, 100, stdin); /* read line of input into buffer. Needs error checking */
Example code with comments:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define NUMSTR 3
#define BUFFSIZE 100
int main(void) {
char *words[NUMSTR];
char buffer[BUFFSIZE];
size_t i, count = 0, slen; /* can replace size_t with int if you prefer */
/* loops only for three input strings */
for (i = 0; i < NUMSTR; i++) {
/* read input of one string, with error checking */
printf("Enter a word: ");
if (fgets(buffer, BUFFSIZE, stdin) == NULL) {
fprintf(stderr, "Error reading string into buffer.\n");
exit(EXIT_FAILURE);
}
/* removing newline from buffer, along with checking for overflow from buffer */
slen = strlen(buffer);
if (slen > 0) {
if (buffer[slen-1] == '\n') {
buffer[slen-1] = '\0';
} else {
printf("Exceeded buffer length of %d.\n", BUFFSIZE);
exit(EXIT_FAILURE);
}
}
/* checking if nothing was entered */
if (!*buffer) {
printf("No string entered.\n");
exit(EXIT_FAILURE);
}
/* allocate space for `words[i]` and null terminator */
words[count] = malloc(strlen(buffer)+1);
/* checking return of malloc, very good to do this */
if (!words[count]) {
printf("Cannot allocate memory for string.\n");
exit(EXIT_FAILURE);
}
/* if everything is fine, copy over into your array of pointers */
strcpy(words[count], buffer);
/* increment count, ready for next space in array */
count++;
}
/* reading input is finished, now time to print and free the strings */
printf("\nYour strings:\n");
for (i = 0; i < count; i++) {
printf("words[%zu] = %s\n", i, words[i]);
free(words[i]);
words[i] = NULL;
}
return 0;
}
Example input:
Enter a word: Hello
Enter a word: World
Enter a word: Woohoo
Output:
Your strings:
words[0] = Hello
words[1] = World
words[2] = Woohoo
There seems to be a bit of confusion in this area. Your primary problem is you are attempting to write each word to the address of each of pointers you declare with char *word[3];. (not to mention you have no storage allocated at the location pointed to by each pointer -- but you never get there as you attempt to write to the address of each pointer with &word[i] rather than to the pointer itself)
While you can use scanf you will quickly run into one of the many pitfalls with taking user input with scanf that plague all new C programmers (e.g. failing to handle the '\n' left in the input buffer, failing to handle whitespace in strings, failing to limit the number of characters read/written, failing to validate the read or handle EOF, etc...)
A better approach is to simply use fgets and then trim the '\n' that fgets read and includes in the buffer to which it stores the string. A simple example would be:
#include <stdio.h>
#include <string.h>
#define NWDS 3 /* declare a constant for the maximum number of words */
int main (void) {
int i, n = 0;
char word[NWDS][50] = { "" }; /* provide storage or allocate */
for (i = 0; i < NWDS; i++) { /* for a max of NWDS */
printf ("Enter word : "); /* prompt */
if (!fgets (word[i], sizeof word[i], stdin)) /* read/validate */
break; /* protect against EOF */
size_t len = strlen (word[i]); /* get length */
if (word[i][len-1] == '\n') /* check for trailing '\n' */
word[i][--len] = 0; /* overwrite with nulbyte */
}
n = i; /* store number of words read */
putchar ('\n'); /* make it pretty */
for (i = 0; i < n; i++) /* output each word read */
printf (" word[%d] : %s\n", i, word[i]);
#if (defined _WIN32 || defined _WIN64)
getchar(); /* keep terminal open until keypress if on windows */
#endif
return 0;
}
Go ahead and cancel input at any time by generating an EOF during input (ctrl + d on Linux or ctrl + z on windoze), you are covered.
Example Use/Output
$ ./bin/wordsread
Enter word : first word
Enter word : next word
Enter word : last word
word[0] : first word
word[1] : next word
word[2] : last word
Looks things over, consider the other answers, and let me know if you have further questions.
char *word[3]; // <-- this is an array of 3 dangling pointers, of type char*
// they still point nowhere, we later need to set them to some allocated location.
...
for(i=0;i<3;i++) {
word[i] = malloc(some_max_size * sizeof(char)); // <-- allocate space for your word
printf(" Enter a word: ");
scanf("%s", word[i]); // <-- not &word[i]; word[i] is already a char* pointer
}
You are declaring word as array of pointer (char *word[3];). You have to allocate memory to store data. Allocate memory with malloc or similar functions before assigning values.
Yes the code crashes because declaring an array of character
pointers is not enough, you need to set the pointers to point
to memory where the strings can be stored.
E.g.
const int maxLen = 32;
char* word[3] = {NULL,NULL,NULL};
word[i] = malloc(maxLen);
then read the string from keyboard, to ensure that the string is not too
long use fgets and maxLen:
printf("Enter a word:");
fgets(word[i],maxLen,stdin);
#include <stdio.h>
int main(){
int n;
int i=0;
scanf("%d",&n);
char arr[n];
while(n>i){
scanf("%s",&arr[i]);
i+=1;
}
while(n-i<n){
printf(" %c ",arr[n-i]);
i-=1;
}
}
The code char *word[3] made a 3-element array of pointers!
See, you have basically created a character array of pointers, so you cannot put a "string" into each one of them, because the type of a pointer variable is long hexadecimal.
I'm trying to write a program that takes in a plaintext file as it's argument and parses through it, adding all the numbers together and then print out the sum. The following is my code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
static int sumNumbers(char filename[])
{
int sum = 0;
FILE *file = fopen(filename, "r");
char *str;
while (fgets(str, sizeof BUFSIZ, file))
{
while (*str != '\0')
{
if (isdigit(*str))
{
sum += atoi(str);
str++;
while (isdigit(*str))
str++;
continue;
}
str++;
}
}
fclose(file);
return sum;
}
int main(int argc, char *argv[])
{
if (argc != 2)
{
fprintf(stderr, "Please enter the filename as the argument.\n");
exit(EXIT_FAILURE);
}
else
{
printf("The sum of all the numbers in the file is : %d\n", sumNumbers(argv[1]));
exit(EXIT_SUCCESS);
}
return 0;
}
And the text file I'm using is:
This a rather boring text file with
some random numbers scattered
throughout it.
Here is one: 87 and here is another: 3
and finally two last numbers: 12
19381. Done. Phew.
When I compile and try to run it, I get a segmentation fault.
You've not allocated space for the buffer.The pointer str is just a dangling pointer. So your program effectively dumps the data read from the file into memory location which you don't own, leading to the segmentation fault.
You need:
char *str;
str = malloc(BUFSIZ); // this is missing..also free() the mem once done using it.
or just:
char str[BUFSIZ]; // but then you can't do str++, you'll have to use another
// pointer say char *ptr = str; and use it in place of str.
EDIT:
There is another bug in:
while (fgets(str, sizeof BUFSIZ, file))
The 2nd argument should be BUFSIZ not sizeof BUFSIZ.
Why?
Because the 2nd argument is the maximum number of characters to be read into the buffer including the null-character. Since sizeof BUFSIZ is 4 you can read max upto 3 char into the buffer. That is reason why 19381 was being read as 193 and then 81<space>.
You haven't allocated any memory to populate str. fgets takes as its first argument a buffer, not an unassigned pointer.
Instead of char *str; you need to define a reasonably sized buffer, say, char str[BUFSIZ];
Because you've not allocated space for your buffer.
A number of people have already addressed the problem you asked about, but I've got a question in return. What exactly do you think this accomplishes:
if (isdigit(*str))
{
if (isdigit(*str))
{
sum += atoi(str);
str++;
while (isdigit(*str))
str++;
continue;
}
}
What's supposed to be the point of two successive if statements with the exact same condition? (Note for the record: neither one has an else clause).
You have declared char* str, but you have not set aside memory for it just yet. You will need to malloc memory for it.
Many memory related errors such as this one can be easily found with valgrind. I'd highly recommend using it as a debugging tool.
char *str;
str has no memory allocated for it. Either use malloc() to allocate some memory for it, or declared it with a predefined size.
char str[MAX_SIZE];
Your program has several bugs:
It does not handle long lines correctly. When you read a buffer of some size it may happen that some number starts at the end of the buffer and continues at the beginning of the next buffer. For example, if you have a buffer of size 4, there might be the input The |numb|er 1|2345| is |larg|e., where the vertical lines indicate the buffer's contents. You would then count the 1 and the 2345 separately.
It calls isdigit with a char as argument. As soon as you read any "large" character (greater than SCHAR_MAX) the behavior is undefined. Your program might crash or produce incorrect results or do whatever it wants to do. To fix this, you must first cast the value to an unsigned char, for example isdigit((unsigned char) *str). Or, as in my code, you can feed it the value from the fgetc function, which is guaranteed to be a valid argument for isdigit.
You use a function that requires a buffer (fgets) but you fail to allocate the buffer. As others noted, the easiest way to get a buffer is to declare a local variable char buffer[BUFSIZ].
You use the str variable for two purposes: To hold the address of the buffer (which should remain constant over the whole execution time) and the pointer for analyzing the text (which changes during the execution). Make these two variables. I would call them buffer and p (short for pointer).
Here is my code:
#include <ctype.h>
#include <stdio.h>
static int sumNumbers(const char *filename)
{
int sum, num, c;
FILE *f;
if ((f = fopen(filename, "r")) == NULL) {
/* TODO: insert error handling here. */
}
sum = 0;
num = 0;
while ((c = fgetc(f)) != EOF) {
if (isdigit(c)) {
num = 10 * num + (c - '0');
} else if (num != 0) {
sum += num;
num = 0;
}
}
if (fclose(f) != 0) {
/* TODO: insert error handling here. */
}
return sum;
}
int main(int argc, char **argv) {
int i;
for (i = 1; i < argc; i++)
printf("%d\t%s\n", sumNumbers(argv[i]), argv[i]);
return 0;
}
Here is a function, that does your job:
static int sumNumbers(char* filename) {
int sum = 0;
FILE *file = fopen(filename, "r");
char buf[BUFSIZ], *str;
while (fgets(buf, BUFSIZ, file))
{
str=buf;
while (*str)
{
if (isdigit(*str))
{
sum += strtol(str, &str, 10);
}
str++;
}
}
fclose(file);
return sum;
}
This doesn't includes error handling, but works quite well. For your file, output will be
The sum of all the numbers in the file is : 19483
What is the simplest way to read a full line in a C console program
The text entered might have a variable length and we can't make any assumption about its content.
You need dynamic memory management, and use the fgets function to read your line. However, there seems to be no way to see how many characters it read. So you use fgetc:
char * getline(void) {
char * line = malloc(100), * linep = line;
size_t lenmax = 100, len = lenmax;
int c;
if(line == NULL)
return NULL;
for(;;) {
c = fgetc(stdin);
if(c == EOF)
break;
if(--len == 0) {
len = lenmax;
char * linen = realloc(linep, lenmax *= 2);
if(linen == NULL) {
free(linep);
return NULL;
}
line = linen + (line - linep);
linep = linen;
}
if((*line++ = c) == '\n')
break;
}
*line = '\0';
return linep;
}
Note: Never use gets ! It does not do bounds checking and can overflow your buffer
If you are using the GNU C library or another POSIX-compliant library, you can use getline() and pass stdin to it for the file stream.
A very simple but unsafe implementation to read line for static allocation:
char line[1024];
scanf("%[^\n]", line);
A safer implementation, without the possibility of buffer overflow, but with the possibility of not reading the whole line, is:
char line[1024];
scanf("%1023[^\n]", line);
Not the 'difference by one' between the length specified declaring the variable and the length specified in the format string. It is a historical artefact.
So, if you were looking for command arguments, take a look at Tim's answer.
If you just want to read a line from console:
#include <stdio.h>
int main()
{
char string [256];
printf ("Insert your full address: ");
gets (string);
printf ("Your address is: %s\n",string);
return 0;
}
Yes, it is not secure, you can do buffer overrun, it does not check for end of file, it does not support encodings and a lot of other stuff.
Actually I didn't even think whether it did ANY of this stuff.
I agree I kinda screwed up :)
But...when I see a question like "How to read a line from the console in C?", I assume a person needs something simple, like gets() and not 100 lines of code like above.
Actually, I think, if you try to write those 100 lines of code in reality, you would do many more mistakes, than you would have done had you chosen gets ;)
getline runnable example
getline was mentioned on this answer but here is an example.
It is POSIX 7, allocates memory for us, and reuses the allocated buffer on a loop nicely.
Pointer newbs, read this: Why is the first argument of getline a pointer to pointer "char**" instead of "char*"?
main.c
#define _XOPEN_SOURCE 700
#include <stdio.h>
#include <stdlib.h>
int main(void) {
char *line = NULL;
size_t len = 0;
ssize_t read = 0;
while (1) {
puts("enter a line");
read = getline(&line, &len, stdin);
if (read == -1)
break;
printf("line = %s", line);
printf("line length = %zu\n", read);
puts("");
}
free(line);
return 0;
}
Compile and run:
gcc -ggdb3 -O0 -std=c99 -Wall -Wextra -pedantic -o main.out main.c
./main.out
Outcome: this shows on therminal:
enter a line
Then if you type:
asdf
and press enter, this shows up:
line = asdf
line length = 5
followed by another:
enter a line
Or from a pipe to stdin:
printf 'asdf\nqwer\n' | ./main.out
gives:
enter a line
line = asdf
line length = 5
enter a line
line = qwer
line length = 5
enter a line
Tested on Ubuntu 20.04.
glibc implementation
No POSIX? Maybe you want to look at the glibc 2.23 implementation.
It resolves to getdelim, which is a simple POSIX superset of getline with an arbitrary line terminator.
It doubles the allocated memory whenever increase is needed, and looks thread-safe.
It requires some macro expansion, but you're unlikely to do much better.
You might need to use a character by character (getc()) loop to ensure you have no buffer overflows and don't truncate the input.
As suggested, you can use getchar() to read from the console until an end-of-line or an EOF is returned, building your own buffer. Growing buffer dynamically can occur if you are unable to set a reasonable maximum line size.
You can use also use fgets as a safe way to obtain a line as a C null-terminated string:
#include <stdio.h>
char line[1024]; /* Generously large value for most situations */
char *eof;
line[0] = '\0'; /* Ensure empty line if no input delivered */
line[sizeof(line)-1] = ~'\0'; /* Ensure no false-null at end of buffer */
eof = fgets(line, sizeof(line), stdin);
If you have exhausted the console input or if the operation failed for some reason, eof == NULL is returned and the line buffer might be unchanged (which is why setting the first char to '\0' is handy).
fgets will not overfill line[] and it will ensure that there is a null after the last-accepted character on a successful return.
If end-of-line was reached, the character preceding the terminating '\0' will be a '\n'.
If there is no terminating '\n' before the ending '\0' it may be that there is more data or that the next request will report end-of-file. You'll have to do another fgets to determine which is which. (In this regard, looping with getchar() is easier.)
In the (updated) example code above, if line[sizeof(line)-1] == '\0' after successful fgets, you know that the buffer was filled completely. If that position is proceeded by a '\n' you know you were lucky. Otherwise, there is either more data or an end-of-file up ahead in stdin. (When the buffer is not filled completely, you could still be at an end-of-file and there also might not be a '\n' at the end of the current line. Since you have to scan the string to find and/or eliminate any '\n' before the end of the string (the first '\0' in the buffer), I am inclined to prefer using getchar() in the first place.)
Do what you need to do to deal with there still being more line than the amount you read as the first chunk. The examples of dynamically-growing a buffer can be made to work with either getchar or fgets. There are some tricky edge cases to watch out for (like remembering to have the next input start storing at the position of the '\0' that ended the previous input before the buffer was extended).
How to read a line from the console in C?
Building your own function, is one of the ways that would help you to achieve reading a line from console
I'm using dynamic memory allocation to allocate the required amount of memory required
When we are about to exhaust the allocated memory, we try to double the size of memory
And here I'm using a loop to scan each character of the string one by one using the getchar() function until the user enters '\n' or EOF character
finally we remove any additionally allocated memory before returning the line
//the function to read lines of variable length
char* scan_line(char *line)
{
int ch; // as getchar() returns `int`
long capacity = 0; // capacity of the buffer
long length = 0; // maintains the length of the string
char *temp = NULL; // use additional pointer to perform allocations in order to avoid memory leaks
while ( ((ch = getchar()) != '\n') && (ch != EOF) )
{
if((length + 1) >= capacity)
{
// resetting capacity
if (capacity == 0)
capacity = 2; // some initial fixed length
else
capacity *= 2; // double the size
// try reallocating the memory
if( (temp = realloc(line, capacity * sizeof(char))) == NULL ) //allocating memory
{
printf("ERROR: unsuccessful allocation");
// return line; or you can exit
exit(1);
}
line = temp;
}
line[length] = (char) ch; //type casting `int` to `char`
length++;
}
line[length + 1] = '\0'; //inserting null character at the end
// remove additionally allocated memory
if( (temp = realloc(line, (length + 1) * sizeof(char))) == NULL )
{
printf("ERROR: unsuccessful allocation");
// return line; or you can exit
exit(1);
}
line = temp;
return line;
}
Now you could read a full line this way :
char *line = NULL;
line = scan_line(line);
Here's an example program using the scan_line() function :
#include <stdio.h>
#include <stdlib.h> //for dynamic allocation functions
char* scan_line(char *line)
{
..........
}
int main(void)
{
char *a = NULL;
a = scan_line(a); //function call to scan the line
printf("%s\n",a); //printing the scanned line
free(a); //don't forget to free the malloc'd pointer
}
sample input :
Twinkle Twinkle little star.... in the sky!
sample output :
Twinkle Twinkle little star.... in the sky!
I came across the same problem some time ago, this was my solutuion, hope it helps.
/*
* Initial size of the read buffer
*/
#define DEFAULT_BUFFER 1024
/*
* Standard boolean type definition
*/
typedef enum{ false = 0, true = 1 }bool;
/*
* Flags errors in pointer returning functions
*/
bool has_err = false;
/*
* Reads the next line of text from file and returns it.
* The line must be free()d afterwards.
*
* This function will segfault on binary data.
*/
char *readLine(FILE *file){
char *buffer = NULL;
char *tmp_buf = NULL;
bool line_read = false;
int iteration = 0;
int offset = 0;
if(file == NULL){
fprintf(stderr, "readLine: NULL file pointer passed!\n");
has_err = true;
return NULL;
}
while(!line_read){
if((tmp_buf = malloc(DEFAULT_BUFFER)) == NULL){
fprintf(stderr, "readLine: Unable to allocate temporary buffer!\n");
if(buffer != NULL)
free(buffer);
has_err = true;
return NULL;
}
if(fgets(tmp_buf, DEFAULT_BUFFER, file) == NULL){
free(tmp_buf);
break;
}
if(tmp_buf[strlen(tmp_buf) - 1] == '\n') /* we have an end of line */
line_read = true;
offset = DEFAULT_BUFFER * (iteration + 1);
if((buffer = realloc(buffer, offset)) == NULL){
fprintf(stderr, "readLine: Unable to reallocate buffer!\n");
free(tmp_buf);
has_err = true;
return NULL;
}
offset = DEFAULT_BUFFER * iteration - iteration;
if(memcpy(buffer + offset, tmp_buf, DEFAULT_BUFFER) == NULL){
fprintf(stderr, "readLine: Cannot copy to buffer\n");
free(tmp_buf);
if(buffer != NULL)
free(buffer);
has_err = true;
return NULL;
}
free(tmp_buf);
iteration++;
}
return buffer;
}
There is a simple regex like syntax that can be used inside scanf to take whole line as input
scanf("%[^\n]%*c", str);
^\n tells to take input until newline doesn't get encountered. Then, with %*c, it reads newline character and here used * indicates that this newline character is discarded.
Sample code
#include <stdio.h>
int main()
{
char S[101];
scanf("%[^\n]%*c", S);
printf("%s", S);
return 0;
}
On BSD systems and Android you can also use fgetln:
#include <stdio.h>
char *
fgetln(FILE *stream, size_t *len);
Like so:
size_t line_len;
const char *line = fgetln(stdin, &line_len);
The line is not null terminated and contains \n (or whatever your platform is using) in the end. It becomes invalid after the next I/O operation on stream.
Something like this:
unsigned int getConsoleInput(char **pStrBfr) //pass in pointer to char pointer, returns size of buffer
{
char * strbfr;
int c;
unsigned int i;
i = 0;
strbfr = (char*)malloc(sizeof(char));
if(strbfr==NULL) goto error;
while( (c = getchar()) != '\n' && c != EOF )
{
strbfr[i] = (char)c;
i++;
strbfr = (void*)realloc((void*)strbfr,sizeof(char)*(i+1));
//on realloc error, NULL is returned but original buffer is unchanged
//NOTE: the buffer WILL NOT be NULL terminated since last
//chracter came from console
if(strbfr==NULL) goto error;
}
strbfr[i] = '\0';
*pStrBfr = strbfr; //successfully returns pointer to NULL terminated buffer
return i + 1;
error:
*pStrBfr = strbfr;
return i + 1;
}
The best and simplest way to read a line from a console is using the getchar() function, whereby you will store one character at a time in an array.
{
char message[N]; /* character array for the message, you can always change the character length */
int i = 0; /* loop counter */
printf( "Enter a message: " );
message[i] = getchar(); /* get the first character */
while( message[i] != '\n' ){
message[++i] = getchar(); /* gets the next character */
}
printf( "Entered message is:" );
for( i = 0; i < N; i++ )
printf( "%c", message[i] );
return ( 0 );
}
Here is a minimal implementation to do it, the nice thing is that it will not keep the '\n', however you have to give it a size to read for security:
#include <stdio.h>
#include <errno.h>
int sc_gets(char *buf, int n)
{
int count = 0;
char c;
if (__glibc_unlikely(n <= 0))
return -1;
while (--n && (c = fgetc(stdin)) != '\n')
buf[count++] = c;
buf[count] = '\0';
return (count != 0 || errno != EAGAIN) ? count : -1;
}
Test with:
#define BUFF_SIZE 10
int main (void) {
char buff[BUFF_SIZE];
sc_gets(buff, sizeof(buff));
printf ("%s\n", buff);
return 0;
}
NB: You are limited to INT_MAX to find your line return, which is more than enough.