I'm new to cakephp and I'm trying to add data to my coupon table with the following code.
In my UsersController I have:
public function addCoupon() {
if ($this->request->is('post')) {
if ($this->Coupon->save($this->request->data)) {
$this->Session->setFlash(__('The data has been saved'));
} else {
$this->Session->setFlash(__('The data could not be saved. Please, try again.'));
}
}
}
In my add_coupon.cpt I have:
<?php
echo $this->Form->create('Coupon',['url' => ['action' => 'addCoupon']]);
echo $this->Form->input('coupon_code');
echo $this->Form->input('expiration_date');
echo $this->Form->input('discount_amount');
echo $this->Form->input('usage_limit');
echo $this->Form->input('domain_limit');
echo $this->Form->input('description');
echo $this->Form->input('type');
echo $this->Form->button('Submit');
echo $this->Form->end();
?>
What is wrong with my code?
If your model is, in fact, named Coupon (singular) rather than Coupons (plural), try adding the following line of code anywhere before $this->Coupon->save(this->request->data):
$this->loadModel('Coupon');
But if it's actually named Coupons as convention would prescribe, change $this->Coupon->save(this->request->data) to $this->Coupons->save(this->request->data)
and add this line instead:
$this->loadModel('Coupons');
By default, the Users controller will only load the Users model. If you use any other models, you need to load them manually. Alternatively, you could move all of this to the Coupons controller, where it probably belongs anyways.
I have 2 db tables : Users & Projects.
Fields of Users table are :
id, name, username, password, email, address, phone.
Fields of Projects table are :
id, name, description, user_id, deadline, budget.
What I need is that, I'll have 1 form, where there will be all fields from these 2 tables. And, when I submit the form, these fields will be saved in these 2 tables.
For example, my form will be like this :
<?php
echo $this->Form->create('User');
echo $this->Form->input('name',array('type'=>'text','div'=>false));
echo $this->Form->input('username',array('type'=>'text','div'=>false));
echo $this->Form->input('password',array('type'=>'password','div'=>'false));
echo $this->Form->input('email',array('type'=>'email','div'=>false));
echo $this->Form->input('address',array('type'=>'textarea','div'=>false));
echo $this->Form->input('phone',array('type'=>'tel','div'=>false));
echo $this->Form->input('name',array('type'=>'text','div'=>false));
echo $this->Form->input('description',array('type'=>'text','div'=>false));
echo $this->Form->input('deadline',array('type'=>'date','div'=>false));
echo $this->Form->input('budget',array('type'=>'num','div'=>false));
echo $this->Form->submit('Save');
echo $this->Form->end();
?>
Now, I want that when I submit the form, the fields will be saved in the corresponding tables; Users table will receive & save its fields, and Projects table will receive & save its fields.
For this, I tried hasMany association between Users & Projects tables, means, each user from Users table will have many projects from Projects table.
In User.php, I tried this :
class User extends AppModel{
public $hasMany=array(
'Project'=>array(
'className'=>'Project')
);
}
I thought it'd work, but it didn't, only Users table get its values, no value goes to Project table. What is the problem here ? What should I do ?
Thanks.
try this in your view
echo $this->Form->create('User');
echo $this->Form->input('name',array('type'=>'text','div'=>false));
echo $this->Form->input('username',array('type'=>'text','div'=>false));
echo $this->Form->input('password',array('type'=>'password','div'=>false));
echo $this->Form->input('email',array('type'=>'email','div'=>false));
echo $this->Form->input('address',array('type'=>'textarea','div'=>false));
echo $this->Form->input('phone',array('type'=>'tel','div'=>false));
echo $this->Form->input('Project.0.name',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.0.description',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.0.deadline',array('type'=>'date','div'=>false));
echo $this->Form->input('Project.0.budget',array('type'=>'num','div'=>false));
echo $this->Form->submit('Save');
echo $this->Form->end();
And in your controller you have to use
$this->User->saveAssociated($data);
see the manual about how to save associated data
At first, add the model names User and Project as prefix to your form fields to separate them:
View:
<?php
echo $this->Form->create('User');
echo $this->Form->input('User.name',array('type'=>'text','div'=>false));
echo $this->Form->input('User.username',array('type'=>'text','div'=>false));
echo $this->Form->input('User.password',array('type'=>'password','div'=>false));
echo $this->Form->input('User.email',array('type'=>'email','div'=>false));
echo $this->Form->input('User.address',array('type'=>'textarea','div'=>false));
echo $this->Form->input('User.phone',array('type'=>'tel','div'=>false));
echo $this->Form->input('Project.name',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.description',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.deadline',array('type'=>'date','div'=>false));
echo $this->Form->input('Project.budget',array('type'=>'num','div'=>false));
echo $this->Form->submit('Save');
echo $this->Form->end();
At second, use the separation to save your data into different models. Do not forget to add an associated column user_id to your table projects.
Controller
class UserController extends AppController
{
function create()
{
$this->loadModel('Project');
if($this->request->is('post', 'put'))
{
$this->User->getDataSource()->begin($this); // Starts transaction
if($this->User->save($this->request->data['User']))
{
// Success, save project now
$this->request->data['Project']['user_id'] = $this->User->getLastInsertId();
if($this->Project->save($this->request->data['Project']))
{
$this->User->getDataSource()->commit($this); // Commit
// success
} else {
$this->User->getDataSource()->rollback($this); // Rollback
}
} else {
$this->User->getDataSource()->rollback($this); // Rollback
}
}
}
}
I tested this code → works.
Your question is not very clear to me but what I see is you need to save data using associations.
But an association is a connection between two Active Record models. Associations are created to maintain Primary Key-Foreign Key information between instances of the two models.
You will need to save your USERS table data first and get the primary ID of last saved and use it as user_id for PROJECTS table and save PROJECT table information creating a PROJECT instance.
view:
<?php
echo $this->Form->create('User');
echo $this->Form->input('name',array('type'=>'text','div'=>false));
echo $this->Form->input('username',array('type'=>'text','div'=>false));
echo $this->Form->input('password',array('type'=>'password','div'=>'false));
echo $this->Form->input('email',array('type'=>'email','div'=>false));
echo $this->Form->input('address',array('type'=>'textarea','div'=>false));
echo $this->Form->input('phone',array('type'=>'tel','div'=>false));
// adding associate model name to every field..
echo $this->Form->input('Project.name',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.description',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.deadline',array('type'=>'date','div'=>false));
echo $this->Form->input('Project.budget',array('type'=>'num','div'=>false));
echo $this->Form->submit('Save');
echo $this->Form->end();
Note: You can disable all 'div' on form creation.. Look documentation for details...
User model:
class User extends AppModel{
public $hasMany=array('Project');
}
UsersController:
public function add(){
if($this->request->is('post')){
$this->User->create();
if($this->User->save($this->request->data)){// if you association is correct, all associated data will save automatically.
$this->Session->setFlash('saved');
$this->redirect('where you wants to redirect');
}else{
$this->Session->setFlash('Something went wrong. Try again');
}
}
}
Easy way with saveAll
<!-- View -->
<?php
echo $this->Form->create('User');
echo $this->Form->input('name',array('type'=>'text','div'=>false));
echo $this->Form->input('username',array('type'=>'text','div'=>false));
echo $this->Form->input('password',array('type'=>'password','div'=>false));
echo $this->Form->input('email',array('type'=>'email','div'=>false));
echo $this->Form->input('address',array('type'=>'textarea','div'=>false));
echo $this->Form->input('phone',array('type'=>'tel','div'=>false));
echo $this->Form->input('Project.0.name',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.0.description',array('type'=>'text','div'=>false));
echo $this->Form->input('Project.0.deadline',array('type'=>'date','div'=>false));
echo $this->Form->input('Project.0.budget',array('type'=>'num','div'=>false));
echo $this->Form->submit('Save');
echo $this->Form->end();
?>
<!-- Controller -->
<?php
class UserController extends AppController
{
function create()
{
if($this->request->is('post', 'put'))
{
if($this->User->saveAll($this->request->data))
{
// Success - set your flashMessage
} else {
// Error - set your flashMessage
}
}
}
}
?>
I have a view file that looks like this:
<?php
echo $this->Form->create('ModelName');
echo $this->Form->input('ModelName.0.firstField');
echo $this->Form->input('ModelName.0.secondField');
echo $this->Form->input('ModelName.1.firstField');
echo $this->Form->input('ModelName.1.secondField');
echo $this->Form->end();
?>
My question is, how do I validate this data? I'm not saving, so it seems pointless to me to call the save or saveAll methods. I just want to validate the data before I process it and display the results to the user.
What happens currently using:
<?php
if ($this->request->is('post')) {
$this->ModelName->set($this->request->data);
if ($this->ModelName->validates()) {
echo $this->Session->setFlash('Success');
} else {
echo $this->Session->setFlash('Failure');
}
}
?>
Is it succeeds all the time even when I'm putting in data that should definitely fail.
I have also tried:
<?php
if ($this->request->is('post')) {
if ($this->ModelName->validateMany($this->request->data)) {
echo $this->Session->setFlash('Success');
} else {
echo $this->Session->setFlash('Failure');
}
}
?>
And that return success all the time as well, but that may be due to the fact that I don't know how to properly use validateMany.
Model::set is used for assigning a single set/record of data to the current instance of the Model. So it may be possible that you are only validating the first set of data in your POST data. You would have to iterate through each record in the POST data, Model::set it to the Model data, and then call Model::validates.
Instead of the above method or Model::validateMany, try using Model::saveAll without actually saving.
http://api20.cakephp.org/class/model#method-ModelsaveAll
validate: Set to false to disable validation, true to validate each record before saving, 'first' to validate all records before any are saved (default), or 'only' to only validate the records, but not save them.
<?php
if ($this->request->is('post')) {
if ($this->ModelName->saveAll($this->request->data, array('validate' => 'only'))) {
echo $this->Session->setFlash('Success');
} else {
echo $this->Session->setFlash('Failure');
}
}
?>
In my cake app I have a model called faqs, controller called faqs_controller & view called faqsindex.php.
I'm making a CMS so users can change the FAQs. The db table 'faqs' has 5 columns id, category, question, answer and number. "Number" is the order in which the FAQ's will appear.
The loop that lists all of the FAQs looks more or less like this:
<?php
foreach ($faqs as $faq):
<tr>
<td><?php echo $faq['Faq']['category']; ?></td>
<td><?php echo $faq['Faq']['number']; ?></td>
<td><?php echo $faq['Faq']['question']; ?></td>
<td><?php echo $faq['Faq']['answer']; ?></td>
</tr>
<?php endforeach; ?>
I want to make it so that the user can change the "number" cell from this screen, instead of going into a separate edit screen for each row and changing the number there.
You know, like how netflix's queue works, where the user can reorder it from the list, you don't have to click on the movie you want to see to change its order in your queue.
EDIT I set up edit in faqs_controller.php like this:
function edit() {
if(!empty($this->data)) {
$this->Faq->saveAll($this->data['Faq']);
}
else {
$this->data['Faq'] = Set::combine($this->Faq->find('all'), '{n}.Faq.id', '{n}.Faq');
}
}
and in the index view I made a foreach that looks like this:
echo $form->create('Faq', array('action'=>'edit'));
foreach($this->viewVars['faqs'] as $key => $value) {
echo 'id:'.$value['Faq']['id'];
echo '<br/>question:'.$value['Faq']['question'];
echo $form->input('Faq.'.$key.'.number');
}
In this case the foreach goes round 8 times because there are 8 rows. If I submit them, I create 8 new rows & can't update existing rows.
-EDIT-
I changed the form echo here:
echo $form->input('Faq.'.$key.'.question',array('value'=>$value['Faq']['question']));
to prepopulate the form. What I can't figure out is how to update the proper row. If I submit the form I get 8 mysql queries like this:
INSERT INTO faqs (question) VALUES ('THE NEW QUESTION I JUST ADDED?') when I don't want an insert but an update.
Put each faq id inside your form?
echo $form->create('Faq', array('action'=>'edit'));
foreach($this->viewVars['faqs'] as $key => $value) {
echo 'id:'.$value['Faq']['id'];
echo '<br/>question:'.$value['Faq']['question'];
echo $form->hidden('Faq.'.$key.'.id', array('value' => $value['Faq']['id']));
echo $form->input('Faq.'.$key.'.number');
}
if you are using jquery: http://jqueryui.com/demos/sortable/ All the ordering is done on client side, you put the order value into hidden input and use javascript to change them according to user interaction. There's nothing to change on the server side script.
Edit:
echo $form->create('Faq', array('action'=>'edit'));
foreach($this->data['Faq'] as $key => $value) {
echo 'id:'.$value['Faq']['id'];
echo '<br/>question:'.$value['Faq']['question'];
echo $form->input('Faq.'.$key.'.number');
echo $form->input('Faq.'.$key.'.id');
}
echo $form->end('Save');
and the controller:
function edit() {
if(!empty($this->data)) {
$this->Faq->saveAll($this->data['Faq']);
}
$this->data['Faq'] = Set::combine($this->Faq->find('all'), '{n}.Faq.id', '{n}.Faq');
}
unless you redirect them somewhere else after saving.
If you're wanting to update a specific row with Cake it is as simple as setting the appropriate row ID in your saveAll() query.
function edit() {
if (!empty($this->data)) {
$this->Faq->saveAll($this->data['Faq'], array('conditions' => array('Faq.id' => $yourId)));
}
...
}
This is telling Cake's ORM to save the information into the row only where Faq.id is equal to $yourId. If $yourId matches an existing ID in your table then that row should be updated.
Edit
You can put the id field into a hidden form element using CakePHP's FormHelper.
$this->Form->hidden('id', array('value' => $value['Faq']['id']));
I have a addstudent.ctp file to add students
echo $this->Form->create('Student');
echo $this->Form->input('FirstName');
echo $this->Form->input('LastName');
echo $this->Form->end('Register');
echo $this->Form->create('Address',array('controller'=>'addresses','action'=>'addaddress'));
echo$this->Form->end('NextAdressDetails',array('controller'=>'addresses','action'=>'addaddress'));
after clicking on it is going to add method of StudentsController.it has to add student object to session and should redirect to same page.like this i can able to add as many students as possible ,so my problem is to how to add the multiple students into session whenever clicks on register button.
$students = $this->Session->read('Students');
if (!$students) {
$students = array();
}
$students[] = /* data */;
$this->Session->write('Students', $students);