scanf check in while loop to restrict integer input - c

Question

I am writing a code asking the user to input 10 integers, which are then fed to him backwards. I would like to create a "scanf check" to restrict character input. The while loop works insofar that it doesn't accept char, but it skips a integer input.
int main()
{
int i = 0, number[10] = {0};
char buf[128] = {0};
for (i = 0; i < 10; i++)
{
printf("Please input number %d : ", i+1);
while(scanf("%d", &number[i]) != 1)
{
scanf("%s", &buf);
printf("Sorry, [%s] is not a number. Please input number %d : ", &buf, i);
}
}
for (i = 0; i < 10; i++)
{
printf("\n Number %d is %d", (10-i), number[9-i]);
}
return EXIT_SUCCESS;
}

Answer 1

As pointed out by H2CO3, don't use scanf, an alternative is fgets and strtol:
int i, number[10] = {0};
char buf[128], *p;
for (i = 0; i < 10; i++) {
printf("Please input number %d : ", i+1);
while (1) {
fgets(buf, sizeof(buf), stdin);
if ((p = strchr(buf, '\n')) != NULL) {
*p = '\0';
}
number[i] = (int)strtol(buf, &p, 10);
if (p == buf || *p != '\0') {
printf("Sorry, [%s] is not a number. Please input number %d : ", buf, i + 1);
} else {
break;
}
}
}
for (i = 0; i < 10; i++) {
printf("\n Number %d is %d", (10-i), number[9-i]);
}
return EXIT_SUCCESS;

Answer 2

The code works fine for integer also. The only mistake I found is while printing the sorry message, you are printing just i, it should be i+1.
int i = 0, number[10] = {0};
char buf[128] = {0};
for (i = 0; i < 10; i++)
{
printf("Please input number %d : ", i+1);
while(scanf("%d", &number[i]) != 1)
{
scanf("%s", &buf);
printf("Sorry, [%s] is not a number. Please input number %d : ", &buf, i+1);
}
}
for (i = 0; i < 10; i++)
{
printf("\n Number %d is %d", (10-i), number[9-i]);
}