Multidimensional array: printing addition table in C - c

Question

int main(){
int row=0,col=0;
printf("Enter number of rows of the table\n");
scanf("%d",&row);
printf("Enter number of columns of the table\n");
scanf("%d",&col);
printTable(row,col);
}
void printTable(int row,int col){
int i =0,j=0,k=1,L=1,num=0;
printf("row: %d, col: %d\n",row,col);
int table[row][col];
for (i;i<row;i++){
for (j;j<col;j++){
table[i][j] = i+j;
printf("%d ", table[i][j]);
}
printf("\n");
}
}
Trying to print an addition table using multidimensional array, my output looks like this:
row: 4, col: 4
0 1 2 3
But I'm supposed to get
0 1 2 3
1 2 3 4
2 3 4 5
3 4 5 6
Please help me get right output. thanks

Answer 1

for (j;j<col;j++){
You aren't resetting j to zero before the second and subsequent passes. Change that to
for (j=0;j<col;j++){
You might want to change the other for-loop (on i) as well. Generally, unless you have a Very Good Reason for not doing so, you should always be initializing the loop variable before the first pass; that's why that first clause of the for syntax exists, after all.
By the way, if you didn't want to initialize the loop variable, you could have written this as for (;j<col;j++){ -- as you wrote it, the j is conceptually just retrieving that variable's value and throwing it away, and the for permits just leaving the initization, test, and/or update clauses empty if you don't need them. In fact, for(;;) { means the same thing as while(true) {, loop forever... and some people like to set up a macro,
#define EVER ;;
just so they can write the cutesy for(EVER) {

Answer 2

If you want output like
0 1 2 3
1 2 3 4
2 3 4 5
3 4 5 6
Then following code prints the same outpit
for (i=0;i<row;i++){
for (j=0;j<col;j++){
table[i][j] = i+j;
printf("%d ", table[i][j]);
}
printf("\n");
}