Removing Characters of a String - c

Question

I'm trying to write a code that asks the user to enter a string and takes of all characters except the alphabetical.
Now i did it myself and it doesn't seem to work properly. I'm new to strings so i'm trying to understand and master strings. I tried to use gdb on mac but i don't have all the functions to understand this.
Could you please help?
What the code must do: User inputs (for example): h**#el(l)o&^w
and the output is hello.
here is my code:
#include <stdio.h>
#include <string.h>
int main()
{
char string[100];
int i;
int seen = 0;
printf("Enter String: ");
scanf("%s", string);
for (i=0; string[i]!='\0'; i++)
{
if (((string[i]<='a' || string[i]>'z')&&(string[i]<='A' || string[i]>'Z')) ||string[i]!='\0')
{
seen = 1;
}
else
seen = 0;
}
if (seen==0)
{
printf("%s", string);
}
}

Answer 1

well, your code has a couple of important problems:
you're not checking boundaries when iterating… what if I type in a 101 characters string? and a 4242 characters string?
next problem, is that scanf("%s", …) is considered dangerous, for the same reasons
so basically, what you'd want is to use fgets() instead of scanf().
But why not just get the input character by character, and build a string that has only the chars you want? It's simpler and flexible!
basically:
#include <ctype.h>
int main() {
char* string[100];
int i=0;
printf("Enter your string: ");
do {
// getting a character
char c = getchar();
// if the character is alpha
if (isalpha(c) != 0)
// we place the character to the current position and then increment the index
string[i++] = c;
// otherwise if c is a carriage return
else if (c == '\r') {
c = getchar(); // get rid of \n
// we end the string
string[i] = '\0'
}else if (c == '\n')
// we end the string
string[i] = '\0';
// while c is not a carriage return or i is not out of boundaries
} while (c != '\n' || i < 100);
// if we've got to the boundary, replace last character with end of string
if (i == 100)
string[i] = '\0';
// print out!
printf("Here's your stripped string: %s\n", string);
return 0;
}
I did not run it on my computer because it's getting late, so my apologies in case of mistakes.
Addendum:
wee the program skips my statement and shuts down
that's because your condition is inversed, and remove the \0 condition, as it will always happen with the scanf() that always append \0 to the string to end it. Try exchanging seen = 1 and seen = 0 or try using the following condition:
if ((string[i]>='a' && string[i]<='z')||(string[i]>='A' && string[i]<='Z')))
seen = 1;
else
seen = 0;
or simply, use ctypes's isalpha() function, like in our two examples!

Answer 2

No part(remove the extra characters) to change the string in your code.
#include <stdio.h>
#include <string.h>
#include <ctype.h>
char *filter(char *string, int (*test)(int)) {
char *from, *to;
for(to = from = string;*from;++from){
if(test(*from))
*to++ = *from;
}
*to = '\0';
return string;
}
int main(){
char string[100];
printf("Enter String: ");
scanf("%99s", string);
printf("%s\n", filter(string, isalpha));
return 0;
}