Simple way to copy a file - file

Question

Is there any simple/fast way to copy a file in Go?
I couldn't find a fast way in the Doc's and searching the internet doesn't help as well.

Answer 1

Warning: This answer is mainly about adding a hard link to a file, not about copying the contents.
A robust and efficient copy is conceptually simple, but not simple to implement due to the need to handle a number of edge cases and system limitations that are imposed by the target operating system and it's configuration.
If you simply want to make a duplicate of the existing file you can use os.Link(srcName, dstName). This avoids having to move bytes around in the application and saves disk space. For large files, this is a significant time and space saving.
But various operating systems have different restrictions on how hard links work. Depending on your application and your target system configuration, Link() calls may not work in all cases.
If you want a single generic, robust and efficient copy function, update Copy() to:
Perform checks to ensure that at least some form of copy will succeed (access permissions, directories exist, etc.)
Check to see if both files already exist and are the same using
os.SameFile, return success if they are the same
Attempt a Link, return if success
Copy the bytes (all efficient means failed), return result
An optimization would be to copy the bytes in a go routine so the caller doesn't block on the byte copy. Doing so imposes additional complexity on the caller to handle the success/error case properly.
If I wanted both, I would have two different copy functions: CopyFile(src, dst string) (error) for a blocking copy and CopyFileAsync(src, dst string) (chan c, error) which passes a signaling channel back to the caller for the asynchronous case.
package main
import (
"fmt"
"io"
"os"
)
// CopyFile copies a file from src to dst. If src and dst files exist, and are
// the same, then return success. Otherise, attempt to create a hard link
// between the two files. If that fail, copy the file contents from src to dst.
func CopyFile(src, dst string) (err error) {
sfi, err := os.Stat(src)
if err != nil {
return
}
if !sfi.Mode().IsRegular() {
// cannot copy non-regular files (e.g., directories,
// symlinks, devices, etc.)
return fmt.Errorf("CopyFile: non-regular source file %s (%q)", sfi.Name(), sfi.Mode().String())
}
dfi, err := os.Stat(dst)
if err != nil {
if !os.IsNotExist(err) {
return
}
} else {
if !(dfi.Mode().IsRegular()) {
return fmt.Errorf("CopyFile: non-regular destination file %s (%q)", dfi.Name(), dfi.Mode().String())
}
if os.SameFile(sfi, dfi) {
return
}
}
if err = os.Link(src, dst); err == nil {
return
}
err = copyFileContents(src, dst)
return
}
// copyFileContents copies the contents of the file named src to the file named
// by dst. The file will be created if it does not already exist. If the
// destination file exists, all it's contents will be replaced by the contents
// of the source file.
func copyFileContents(src, dst string) (err error) {
in, err := os.Open(src)
if err != nil {
return
}
defer in.Close()
out, err := os.Create(dst)
if err != nil {
return
}
defer func() {
cerr := out.Close()
if err == nil {
err = cerr
}
}()
if _, err = io.Copy(out, in); err != nil {
return
}
err = out.Sync()
return
}
func main() {
fmt.Printf("Copying %s to %s\n", os.Args[1], os.Args[2])
err := CopyFile(os.Args[1], os.Args[2])
if err != nil {
fmt.Printf("CopyFile failed %q\n", err)
} else {
fmt.Printf("CopyFile succeeded\n")
}
}

Answer 2

import (
"io/ioutil"
"log"
)
func checkErr(err error) {
if err != nil {
log.Fatal(err)
}
}
func copy(src string, dst string) {
// Read all content of src to data, may cause OOM for a large file.
data, err := ioutil.ReadFile(src)
checkErr(err)
// Write data to dst
err = ioutil.WriteFile(dst, data, 0644)
checkErr(err)
}

Answer 3

If you are running the code in linux/mac, you could just execute the system's cp command.
srcFolder := "copy/from/path"
destFolder := "copy/to/path"
cpCmd := exec.Command("cp", "-rf", srcFolder, destFolder)
err := cpCmd.Run()
It's treating go a bit like a script, but it gets the job done. Also, you need to import "os/exec"

Answer 4

Starting with Go 1.15 (Aug 2020), you can use File.ReadFrom:
package main
import "os"
func main() {
r, err := os.Open("in.txt")
if err != nil {
panic(err)
}
defer r.Close()
w, err := os.Create("out.txt")
if err != nil {
panic(err)
}
defer w.Close()
w.ReadFrom(r)
}

Answer 5

Perform the copy in a stream, using io.Copy.
Close all opened file descriptors.
All errors that should be checked are checked, including the errors in deferred (*os.File).Close calls.
Gracefully handle multiple non-nil errors, e.g. non-nil errors from both io.Copy and (*os.File).Close.
No unnecessary complications that were present in other answers, such as calling Close twice on the same file but ignoring the error on one of the calls.
No unnecessary stat checks for existence or for file type. These checks aren't necessary: the future open and read operations will return an error anyway if it's not a valid operation for the type of file. Secondly, such checks are prone to races (e.g. the file might be removed in the time between stat and open).
Accurate doc comment. See: "file", "regular file", and behavior when dstpath exists. The doc comment also matches the style of other functions in package os.
// Copy copies the contents of the file at srcpath to a regular file at dstpath.
// If dstpath already exists and is not a directory, the function truncates it.
// The function does not copy file modes or file attributes.
func Copy(srcpath, dstpath string) (err error) {
r, err := os.Open(srcpath)
if err != nil {
return err
}
defer r.Close() // ok to ignore error: file was opened read-only.
w, err := os.Create(dstpath)
if err != nil {
return err
}
defer func() {
e := w.Close()
// Report the error from Close, if any.
// But do so only if there isn't already
// an outgoing error.
if e != nil && err == nil {
err = e
}
}()
_, err = io.Copy(w, r)
return err
}

Answer 6

In this case there are a couple of conditions to verify, I prefer non-nested code
func Copy(src, dst string) (int64, error) {
src_file, err := os.Open(src)
if err != nil {
return 0, err
}
defer src_file.Close()
src_file_stat, err := src_file.Stat()
if err != nil {
return 0, err
}
if !src_file_stat.Mode().IsRegular() {
return 0, fmt.Errorf("%s is not a regular file", src)
}
dst_file, err := os.Create(dst)
if err != nil {
return 0, err
}
defer dst_file.Close()
return io.Copy(dst_file, src_file)
}

Answer 7

If you are on windows, you can wrap CopyFileW like this:
package utils
import (
"syscall"
"unsafe"
)
var (
modkernel32 = syscall.NewLazyDLL("kernel32.dll")
procCopyFileW = modkernel32.NewProc("CopyFileW")
)
// CopyFile wraps windows function CopyFileW
func CopyFile(src, dst string, failIfExists bool) error {
lpExistingFileName, err := syscall.UTF16PtrFromString(src)
if err != nil {
return err
}
lpNewFileName, err := syscall.UTF16PtrFromString(dst)
if err != nil {
return err
}
var bFailIfExists uint32
if failIfExists {
bFailIfExists = 1
} else {
bFailIfExists = 0
}
r1, _, err := syscall.Syscall(
procCopyFileW.Addr(),
3,
uintptr(unsafe.Pointer(lpExistingFileName)),
uintptr(unsafe.Pointer(lpNewFileName)),
uintptr(bFailIfExists))
if r1 == 0 {
return err
}
return nil
}
Code is inspired by wrappers in C:\Go\src\syscall\zsyscall_windows.go

Answer 8

Here is an obvious way to copy a file:
package main
import (
"os"
"log"
"io"
)
func main() {
sFile, err := os.Open("test.txt")
if err != nil {
log.Fatal(err)
}
defer sFile.Close()
eFile, err := os.Create("test_copy.txt")
if err != nil {
log.Fatal(err)
}
defer eFile.Close()
_, err = io.Copy(eFile, sFile) // first var shows number of bytes
if err != nil {
log.Fatal(err)
}
err = eFile.Sync()
if err != nil {
log.Fatal(err)
}
}

Answer 9

You can use "exec".
exec.Command("cmd","/c","copy","fileToBeCopied destinationDirectory") for windows
I have used this and its working fine. You can refer manual for more details on exec.