Creating a new directory without mkdir() - c

In C I'm using 'open()' to create and open files:
fd = open(fileName, O_CREAT | O_RDWR, 0644);
if 'fileName' includes a directory the file is created only if the directory exists and the application has permission to write to this directory.
If the directory does not exists 'open()' returns an error and I would like to create the directory.
With makedir (see below) I am able to create the directory.
int mkdir(const char *path, mode_t mode);
I was wondering, are there other ways to create a directory? I believe we can also use ioctl()? Are there more alternatives?
I'm asking this because in our code we are not allowed to use mkdir.

I was wondering, are there other ways to create a directory? I believe we can also use ioctl()?
At least on Linux and HP-UX, mkdir is a system call on its own.
So, No, there is no other way to create a directory, at least not on Linux - other systems might implement directory creation differently. But on any reasonable system, I would expect directory creation to be a privileged operation, so you need to go through the kernel.
The only slightly different approach would be to execute the system call directly, by bypassing the C runtime library. In assembly nasm syntax on an i386 architecture, this would look something like
mkdir:
mov eax, 39 ; System-call "sys_mkdir"
mov ebx, dirName ; directory name to create
mov ecx, 0x755 ; creation mode
int 80H ; call sys_mkdir
However, this is not something you would normally do since it is completely system dependant. Switching to a different CPU would require different register setup and/or different instructions - that is what the C runtime library encapsulates.
See also
http://docs.cs.up.ac.za/programming/asm/derick_tut/syscalls.html
http://asm.sourceforge.net/syscall.html
http://en.wikipedia.org/wiki/System_call

A kernel driver can create a folder using
struct file *fp = (struct file *) NULL;
fp = filp_open("/home/testdir", O_DIRECTORY|O_CREAT, S_IRUSR);
I can imagine some situations when a "make_dir" driver which creates large number of folders will be faster than calling mkdir for every folder.

Related

O_PATH equivalent in MacOS?

Linux has the O_PATH flag to open() which allows one to get a fd to be used in fstat, fcntl and others without actually opening the file for reading (or having permissions to do so). However the O_PATH flag is Linux specific.
Is there an equivalent to the O_PATH flag to open() in MacOS? For example, how can I use fstat() on a file I don't have read permissions for?
macOS doesn't have an equivalent to O_PATH, so it's impossible to have a reference to a file without opening it. Regarding the one bit of functionality that you mentioned, you can call stat with a given file path as long as you have "execution" rights to its parent directory, regardless of whether you have any rights to that file.

stat alternative for long file paths

I'm writing a program that iterates through a directory tree depth first (similar to the GNU find program) by recursively constructing paths to each file in the tree and stores the relative paths of encountered files. It also collects some statistics about these files. For this purpose I'm using the stat function.
I've notices that this fails for very deep directory hierarchies, i.e. long file paths, in accordance with stat's documentation.
Now my question is: what alternative approach could I use here that is guaranteed to work for paths of any length? (I don't need working code, just a rough outline would be sufficient).
As you are traversing, open each directory you traverse.
You can then get information about a file in that directory using fstatat. The fstatat function takes an additional parameter, dirfd. If you pass a handle to an open directory in that parameter, the path is interpreted as relative to that directory.
int fstatat(int dirfd, const char *pathname, struct stat *buf,
int flags);
The basic usage is:
int dirfd = open("directory path", O_RDONLY);
struct stat st;
int r = fstatat(dirfd, "relative file path", &st, 0);
You can, of course, also use openat instead of open, as you recurse. And the special value AT_FDCWD can be passed as dirfd to refer to the current working directory.
Caveats
It is easy to get into symlink loops and recurse forever. It is not uncommon to find symlink loops in practice. On my system, /usr/bin/X11 is a symlink to /usr/bin.
Alternatives
There are easier ways to traverse file hierarchies. Use ftw or fts instead, if you can.

Ext2 - how is a file created

How does the process of creating a file in ext2 file system look like?
I am trying to make a simple syscall which takes a path and creates given file - like touch.
For example, the code:
int main(void)
{
syscall(MY_SYSCALL_NUMBER, "/tmp/file");
}
Should create a file called "file" in /tmp.
Now how should the syscall itself work?
My work so far (I ommited error checking for readibility here):
asmlinkage long sys_ccp(const char __user *arg)
{
struct path path;
struct inode *new_inode;
struct qstring qname;
//ommited copy from user for simplicity
qname.name = arg;
qname.len = length(arg);
kern_path(src, LOOKUP_FOLLOW, &path);
new_inode = ext2_new_inode(path.dentry->d_parent->d_inode, S_IFREG, &qname);
}
This seems to work (I can see in logs that an inode is allocated), however, when I call ls on the directory I can't see the file there.
My idea was to add the new inode to struct dentry of directory, so I added this code:
struct dentry *new_dentry;
new_dentry = d_alloc(path.dentry->d_parent, &qname);
d_instantiate(new_dentry, new_inode);
However, this still doesn't seem to work (I can't see the file using ls).
How to implement this syscall correctly, what am I missing?
EDIT:
Regarding R.. answer - purpuse of this syscall is to play around with ext2 and learn about its design, so we can assumie that path is always valid, the filesystem is indeed ext2 and so on.
You're completely mixing up the abstraction layers involved. If something like your code could even work at all (not sure if it can), it would blow up badly and crash the kernel or lead to runaway wrong code execution if someone happened to make this syscall on a path that didn't actually correspond to an ext2 filesystem.
In the kernel's fs abstraction, the fact that the underlying filesystem is ext2 (or whatever it is) is irrelevant to the task of making a file on it. Rather all of this has to go through fs-type-agnostic layers which in turn end up using the fs-type-specific backends for the fs mounted at the path.

Create Directory Permissions

I would like to know something about directory creation in C.
I know in unix based systems, you can create a directory with this function:
mkdir (const char* directory_name,mode_t mode);
but, in windows, mkdir function, only accept one argument, the name of the directory.
you cannot specify mode bits for access permissions.
in windows the function for creating the directory is:
_mkdir (const char* directory_name);
so, a portable way to creating a directory is like:
#ifdef WIN32
_mkdir (directory_name);
#else
mkdir (directory_name,mode);
#endif
my question is, is there a way to specify permissions like mkdir in unix, but in windows?
You can use CreateDirectory and supply the appropriate SECURITY_ATTRIBUTES (the linked example uses the security descriptor and attributes for a registry key, but fundamentally this is no different than for a file).
You can set permissions with CreateDirectory, from the API Windows.
On windows there also is the chmod() analogon _chmod(): http://msdn.microsoft.com/en-us/library/1z319a54%28v=vs.100%29.aspx

Duplicate file descriptor with its own file offset

How can one create a new file descriptor from an existing file descriptor such that the new descriptor does not share the same internal file structure/entry in the file table? Specifically attributes such as file offset (and preferably permissions, sharing and modes) should not be shared between the new and old file descriptors.
Under both Windows and Linux, dup() will duplicate the file descriptor, but both descriptors still point to the same file structure in the process' file table. Any seeking on either descriptor will adjust the position for the other descriptors as well.
Note
I've since received answers for both Windows and Linux and adjusted the question a little too often, which has made it difficult for people to answer. I'll adjust my votes and accept the cleanest answer which covers both Windows and Linux. Apologies to all, I'm still new to the SO paradigm. Thanks for the great answers!
So basically, what you really want is to be given a file descriptor, and basically open the same file over again, to get a separate position, sharing, mode, etc. And you want to do this on Windows (where the "file descriptor" is basically a foreign object, not something used directly by the OS or the run-time library at all.
Amazingly enough, there is a way to do that, at least with MS VC++. All but two steps of it use only the Win32 API so porting to other compilers/libraries should be fairly reasonable (I think most supply versions of those two functions). Those are for converting a Unix-style file descriptor to a native Win32 file handle, and converting a native Win32 file handle back to a Unix-style file descriptor.
Convert file-descriptor to native file handle with _get_osfhandle()
Get a name for the file with GetFileInformationByHandleEx(FILE_NAME_INFO)1
Use CreateFile to open a new handle to that file
Create a file descriptor for that handle with _open_osfhandle()
Et voilĂ , we have a new file descriptor referring to the same file, but with its own permissions, position, etc.
Toward the end of your question, you make it sound like you also want the "permissions", but that doesn't seem to make any real sense -- the permissions attach to the file itself, not to how the file is opened, so opening or reopening the file has no effect on the file's permissions. If you really want to know the, you can get it with GetFileInformationByHandle, but be aware that file permissions in Windows are quite a bit different from the (traditional) file permissions in Unix. Unix has owner/group/world permissions on all files, and most systems also have ACLs (though there's more variation in how they work). Windows either has no permissions at all (e.g., files on FAT or FAT32) or else uses ACLs (e.g., files on NTFS), but nothing that's really equivalent to the traditional owner/group/world permissions most people are accustomed to on Unix.
Perhaps you're using "permissions" to refer to whether the file was open for reading, writing, or both. Getting that is considerably uglier than any of the preceding. The problem is that most of it is in the library, not Win32, so there's probably no way to do it that will be even close to portable between compilers. With MS VC++ 9.0 SP1 (not guaranteed for any other compiler) you can do this:
#include <stdio.h>
int get_perms(int fd) {
int i;
FILE * base = __iob_func();
for (i=0; i<_IOB_ENTRIES; i++)
if (base[i]._file == fd)
return base[i]._flag; // we've found our file
return 0; // file wasn't found.
}
Since this involved some spelunking, I wrote a quick test to verify that it might actually work:
#ifdef TEST
#include <io.h>
void show_perms(int perms, char const *caption) {
printf("File opened for %s\n", caption);
printf("Read permission = %d\n", (perms & _IOREAD)!=0);
printf("Write permission = %d\n", (perms & _IOWRT)!=0);
}
int main(int argc, char **argv) {
FILE *file1, *file2;
int perms1, perms2;
file1=fopen(argv[1], "w");
perms1 = get_perms(_fileno(file1));
fclose(file1);
file2=fopen(argv[1], "r");
perms2 = get_perms(_fileno(file2));
fclose(file2);
show_perms(perms1, "writing");
show_perms(perms2, "reading");
return 0;
}
#endif
And the results seem to indicate success:
File opened for writing
Read permission = 0
Write permission = 1
File opened for reading
Read permission = 1
Write permission = 0
You can then test that returned flag against _IOREAD, _IOWRT, and _IORW, which are defined in stdio.h. Despite my previous warnings, I should probably point out that I suspect (though I certainly can't guarantee) that this part of the library is fairly stable, so the real chances of major changes are probably fairly minimal.
In the other direction, however, there's basically no chance at all that it'll work with any other library. It could (but certainly isn't guaranteed to) work with the other compilers that use the MS library, such as Intel, MinGW or Comeau using MS VC++ as its back-end. Of those, I'd say the most likely to work would be Comeau, and the least likely MinGW (but that's only a guess; there's a good chance it won't work with any of them).
Requires the redistributable Win32 FileID API Library
So, I recommend reading up on this a little more. The dup() and related functions serve to create a duplicate value in the file descriptor table pointing to the same entry in the open file table. This is intended to have the same offset. If you call open(), you will create a new entry the open file table.
It doesn't make any sense to create a duplicate of a file descriptor and that new file descriptor have a different offset in the open file table (this seems to contradict what the word "duplicate" means).
I'm not sure what your question is actually. I mean, it isn't the same thing as a duplicate. You could read:
/proc/self/fd/[descriptor]
and get the string that was used to open that file descriptor; bear in mind this may provide some pitfalls, some of which you actually noted in your observation of calling open() again.
Maybe you can explain a little more and I can try to update to help.
Why don't you just open the file a second time with open() or CreateFile() on windows? This gives you all freedom of different access rights and separate offset.
This of course has the drawback that you you can not open the file exclusively, but it solves your problem very simply.

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