convert decimal to time 6.80 =7.20 hrs in SQL [duplicate] - sql-server

Question

This question already has answers here:
Convert decimal time to hours and minutes
(4 answers)
Closed 9 years ago.
Please help me to do this
decimal 6.80 should equal to 7.20 hours
DECLARE #R1 decimal(4,2);
DECLARE #R2 decimal(4,2);
declare #Type1 decimal(4,2);
declare #Type2 decimal(4,2);
DECLARE #R1Time decimal(4,2);
DECLARE #R2Time decimal(4,2);
SET #R1=2.5
SET #R2=3.5
SET #Type1=17;
SET #Type2=7;
SET #R1Time=(FORMAT((ISNULL(60.0/NULLIF(#R1,0),0)),'N2'))
SET #R2Time=(FORMAT((ISNULL(60.0/NULLIF(#R2,0),0)),'N2'))
SELECT #R1Time as R1Min
SELECT #R2Time as R2Min
SELECT FORMAT(((#Type1*#R1Time)/60.0),'N2') R1Hrs -- 6.80 hours this = 24*17=408/60
SELECT FORMAT(((#Type2*#R2Time)/60.0),'N2') R2Hrs
SELECT CONVERT(CHAR(5), DATEADD(MINUTE, 60*(convert(decimal(4,2),FORMAT(((#Type1*#R1Time)/60.0),'N2'))), 0), 108);--6.48 hours
6.80 hours this = 24*17=408/60 this should be 7.20 hours not 6.48 is it?. Did I am wrong please help me thanks
#R1 is how many in an hour 60/2.5 =24min per Type1 and 17 Type1 is 17*24 =408 min then convert to time –

Answer 1

So what you are saying is that the number before the decimal seperator is correct (in hours) and the number after the decimal seperator is in the absolute amount of minutes?
Then in pseudocode you can do something like this:
INPUT = 6.80
HOURS = FLOOR(INPUT)
DECIMALS = (INPUT - HOURS) * 100
if ( DECIMALS > 60 )
{
HOURS = HOURS + 1
MINUTES = DECIMALS - 60
}
// Now hours and minutes are in the way you intended
Now all you have to do is convert this pseudocode into SQL code.
In function form, this would look something like this (I wrote this by heart so beware for typo's/ errors):
CREATE FUNCTION ChangeTime
-- Input current time decimal
(#CurrentTime decimal(2,1) )
RETURNS decimal(2,1) -- New time
AS
BEGIN
DECLARE #Hours int, #Minutes int;
SET #Hours = FLOOR(#CurrentTime);
SET #Minutes = (#CurrentTime - #Hours)*100;
IF #Minutes >= 60
BEGIN
SET #Hours = #Hours + 1; -- New hours
SET #Minutes = #Minutes - 60; -- New minutes
END
RETURN ( #Hours + (#Minutes/100) ) -- New (corrected) time
END
On the other hand, if you mean: I need to convert the decimals such that 6.50 becomes 6 hours and 30 minutes and 6.80 becomes 6 hours and 48 minutes, then we can change the function to the following:
CREATE FUNCTION ChangeTime
-- Input current time decimal
(#CurrentTime decimal(2,1) )
RETURNS decimal(2,1) -- New time
AS
BEGIN
DECLARE #Hours int, #Minutes int;
SET #Hours = FLOOR(#CurrentTime);
SET #Minutes = (#CurrentTime - #Hours)*100;
SET #Minutes = (#Minutes / 100) * 60; -- New minutes
RETURN ( #Hours + (#Minutes/100) ) -- New (corrected) time
END
If both of these functions do not get the desired result, then please update your question with an explanation of what you exactly want to achieve.
Good luck!

Answer 2

declare #hour decimal(6,2) = 6.8
select floor(#hour) + floor(#hour%1/.6) + #hour%1%.6
Result:
7.20
If you want it as a function:
CREATE FUNCTION f_convert(#hour decimal(6,2))
RETURNS decimal(6,2)
AS
BEGIN
RETURN floor(#hour) + floor(#hour%1/.6) + #hour%1%.6
END
Test(sqlserver 2008+):
SELECT dbo.f_convert(hour)
FROM (values (6.8),(3.9),(.59)) x(hour)
Result:
7.20
4.30
0.59