Change letters alphabetically in a for loop to print all tokens - batch-file

I have a file (MyFile.txt) with a string like this, for example:
var1,var2,asds,123,var6
This file is generated automatically, and I don't know how many words it will have.
I make a for to print all words, one in each line. And process them one by one
for /f "tokens=1-30 delims=," %%a in (MyFile.txt) do call Process.bat %%a
In Process.bat I have ping %1 for example.
This only processes the first token. My problem is, I need to process all tokens, but I need to do it automatically, is there a way to loop over all existing tokens?
In my example: var1,var2,asds,123,var6 it would be: do call Process.bat %%a, then %%b, then %%c, then %%d and %%e.
Thank you.

This will work even if you have various line in Myfile.txt
#echo off&cls
for /f "delims=" %%a in (MyFile.txt) do for %%b in (%%a) do call Process.bat %%b

What about this:
set /p var=<MyFile.txt
set var="%var%"
for %%a in ("%var:,=" "%) do call Process.bat %%a
That Should work.
Mona

you can combine for to read all your lines and call to parse the vars in the line
try this to get you started
#echo off
setlocal enabledelayedexpansion
for /f %%a in (file.txt) do (
set line=%%a
set line=!line:,= !
call :parms !line!
)
goto :eof
:parms
if "%1"=="" goto :eof
echo ping %1
shift
goto :parms
goto :eof

Related

Separate first and last names with for loop

I'm working on a batch that creates a .txt-file from a record. The file will be processed later by another program.
The record looks like this at the moment:
11111;Lastname Firstname SecondFirstname;1234567;SomeText
22222;Lastname Firstname;1254557;SomeText
33333;Lastname Firstname;1234567;SomeText
I would like to have a semicolon between the last name and the first name. The problem is the sentences with two first names. Here should be no semicolon between the names.
In the end it should look like this:
11111;Lastname;Firstname SecondFirstname;1234567;SomeText
22222;Lastname;Firstname;1254557;SomeText
33333;Lastname;Firstname;1234567;SomeText
Does anyone have an idea here?
I have tried the following but that does not solve the problem with the two first names:
type nul>tmp.txt
for /f "delims=: tokens=1*" %%i in ('findstr /n "^" "test_output.txt"') do set "Zeile=%%j" &call :sub
move /y "tmp.txt" "test_output.txt"
goto :eof
:sub
if not defined Zeile (
>>tmp.txt echo.
goto :eof
)
>>tmp.txt echo %Zeile: =;%
goto :eof
Parsing the first time by the ; delimiter and parsing the second token (the third, if you take the line numbers into account) a second time by a <SPACE> delimiter (with tokens=1,*) solves your problem:
#echo off
(for /f "tokens=1-3,* delims=;:" %%A in ('findstr /n "^" "test_output.txt"') do (
if "%%B"=="" echo/
for /f "tokens=1,*" %%M in ("%%C") do (
echo/%%B;%%M;%%N;%%D
)
))>tmp.txt
goto :eof
(redirecting the whole output at once is a lot faster than redirecting single lines - especially with big files)
You need two nested for /F the first to split at the semicolon, the 2nd to split at the space limited to 2 splits.
Using uppercase %A and lowercase %a for the meta variables, in cmd line:
for /F "tokens=1-3* delims=;" %A in (test_output.txt) do #for /F "tokens=1*" %a in ("%B") do #Echo %A;%a;%b;%C;%D
In a batch file saving to new_output.txt:
:: Q:\Test\2019\06\04\SO_56443069.cmd
#Echo off&SetLocal EnableDelayedExpansion
(for /F "tokens=1-3* delims=;" %%A in (test_output.txt
) do for /F "tokens=1*" %%a in ("%%B"
) do Echo %%A;%%a;%%b;%%C;%%D
) >new_output.txt
Sample output:
> type new_output.txt
11111;Lastname;Firstname SecondFirstname;1234567;SomeText
22222;Lastname;Firstname;1254557;SomeText
33333;Lastname;Firstname;1234567;SomeText

Read command from .txt file and run it in batch

I would like to make batch file read from a .txt and have the output be entered as a command. I have written this code, but it won't work when the command has a spaces in it.
#echo off
:READ
for /f "delims= tokens=*" %%c in (C:\file.txt) do (set command=%%c)
%command%
goto READ
What do I do to make it work?
I suppose this is what you want to do:
#echo off
for /f "tokens=*" %%c in (C:\file.txt) do %%c
I would suggest using this if you need to have the command variable to do other stuff (beside executing) with it. If this is not the case #Henrik's answer would suffice:
#echo off
setlocal EnableDelayedExpansion
:READ
for /f "tokens=* usebackq delims=" %%c in ("C:\file.txt") do (
set "command=%%c"
!command!
)
pause

Batchfile: read last lines from logfiles and copy them to a new file

This is my first posting so if the format is not as it supposed to be please excuse me for this. (Suggestions for
improvement are welcome.)
I am trying to create a batchfile that will read last lines from logfiles and copy them to a new file.
Until now I have found here a way to read the last line.
Code would be something like:
for /f %%i in ('find /v /c "" ^< someFile.txt') do set /a lines=%%i
set /a startLine=%lines% - 1
more /e +%startLine% someFile.txt > lastLines.txt
The above code works for one file at a time. What I need is to read the last line from all files in a known list and add this line to a new .csv file.
I have been using the following code for getting the 4th entry in the logfiles but it returns every line of every logfile:
for /f %%x in (%list%) do for /f "delims=.txt, tokens=4" %%i in (%%x.txt) do echo %%x, %%i >> output.csv
What I would need is a sort of combination of both but I don't know how to combine them and make the complete last line be copied to the .csv file.
===
#Magoo:
Thanx for your reaction.
In every logfile can be 1 to >100 lines with comma separated information. Something like:
"LOGON,6-1-2015,12:43:39,USERNAME,HOSTNAME,,,,192.168.209.242,00:21:5A:2E:64:5E"
The last code with the 4th entry was used to get a list of all accounts that had logged in to the computers. This code gave me a very large list of all logon/logoff events on all computerlogs I checked in %list%.
In %list$ I had all the names of logfiles I wanted to be checked. This returned all lines.
For a new batchfile I need only the last logon/logoff entry and I want the whole last line.
So I have a .txt file with the hostnames of all computers I need to examine.
This .txt file will be read line by line via the variable %list%.
From every logfile I need only the last line copied to an output file.
===
I just tried the solution offered by JosefZ. Unfortunately this does not work for me yet. No lastlines are copied to the resultfile. In the code I removed the extra entry for possible lastlines for there are no empty lines in the logs, I also added an entry for the hostname I want to be available in the result. JosefZ had the filename there:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "host=%%~x"
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=.\logs\%filename:&=^&%.txt"
echo %host%,%lastline%>>output.csv
goto :eof
The resultfile shows only the hostnames. I'll puzzle some more with this but all tips are welcome!
===
Got it!!!
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set filename= :: *empty previous filename*
set lastline= :: *empty previous lastline*
set "host=%%~x"
set "filename=.\logs\%host%.txt" :: *creating the filename from path+hostname+extention*
for /F "tokens=*" %%G in ('type "%filename%"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
echo %host%,%lastline%>>output.csv
goto :eof
Your approach with line numbering could fail if a file has more trailing empty lines. Fortunately for /F loop ignores (does not iterate) empty lines; let's put to use this feature: in the script used next practices:
disabledelayedexpansion to allow ! in file names
set "list=_listing.txt" where the _listing.txt contains list of file names (full path and extension .txt including), one file name on one line: got by dir /b /s *.txt>_listing.txt
type nul>files\output.csv to empty the output file (optional)
set "lastline=!!!file empty!!!" to initialize variable %lastline%; could be set "lastline=" as well
call :lline to process variables %filename% and %lastline%
set "filename=%filename:&=^&%" to allow & in file names
The script is as follows:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>files\output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "filename=%%~x"
set "lastline=!!!file empty!!!"
rem the whole line
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
rem the fourth token only
rem for /F "tokens=4" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=%filename:&=^&%"
echo %filename% %lastline%
rem >>files\output.csv
goto :eof
Sample _listing.txt file:
d:\bat\files\1exclam!ation.txt
d:\bat\files\2exc!lam!ation.txt
d:\bat\files\11per%cent.txt
d:\bat\files\12per%cent%.txt
d:\bat\files\17per%Gcent.txt
d:\bat\files\18per%%Gcent.txt
d:\bat\files\21ampers&nd.txt
d:\bat\files\22ampers&&nd.txt
Output:
d:\bat>lastlines
d:\bat\files\1exclam!ation.txt 0 15.01.2015 1:52:28.48 -15072 20465
d:\bat\files\2exc!lam!ation.txt 6 15.01.2015 1:52:28.50 3250 16741
d:\bat\files\11per%cent.txt -8 15.01.2015 1:52:28.50 -3692 27910
d:\bat\files\12per%cent%.txt !!!file empty!!!
d:\bat\files\17per%Gcent.txt 0 15.01.2015 1:52:28.56 14508 12374
d:\bat\files\18per%%Gcent.txt 1 15.01.2015 1:52:28.56 30540 26959
d:\bat\files\21ampers&nd.txt 15.01.2015 1:22:50.18
d:\bat\files\22ampers&&nd.txt 15.01.2015 1:22:50.18
Honestly, all that ballast is for (possibly) trailing empty lines in files and for (possibly) ! and & in file names only; all could be done with
for /f %%x in (%list%) do for /f "skip=%startLine% tokens=4" %%i in (%%x) do echo %%x, %%i >> output.csv
You should use a simple FOR to iterate a list of values, not FOR /F.
Something like the following should work:
#echo off
setlocal enableDelayedExpansion
>>output.csv (
for %%F in (
"file1.log"
"file2.log"
"file3.log"
etc.
) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
The quotes around the file names are there in case you get a name with spaces.
You could use your LIST variable if it looks something like
set LIST="file1.log" "file2.log" "file3.log" etc.
#echo off
setlocal enableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
If any of your file names contain the ! character, then you must toggle delayed expansion ON and OFF within your loop. Otherwise the delayed expansion will corrupt the names when %%F is expanded.
#echo off
setlocal disableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
setlocal enableDelayedExpansion
more +!skip! %%F
endlocal
)
)

Can't get last 2 characters in token, and for loop returns first token in a vaiable

Ok, here's the set up:
I have a ton of text files with the following format:
filename## time Description of file with spaces
I'm trying to rename the actual file on disk with the description of the file, using a for loop:
FOR /F "tokens=1,2,*" %%a IN (%1) DO call :rename %%a %%b "%%c"
goto :eof
:rename
set origfilename=%1
set last2=%1:~-2%
set time=%2
set "multiword=%~3"
ren %origfilename%.ext "%last2%_%time%_%multiword%.ext"
set origfilename=
set last2=
set time=
set multiword=
Here's what's happening:
last2 is never picking up the last 2 characters of the original file name, and if I echo %3 after the DO instead of the call to :rename, it has the full token with spaces. When I try to use %3 in the loop, it only contains the first token of %3.
I tried using setlocal EnableDelayedExpansion before the for, but it didn't work as I expected.
Am I trying to do too many things at once? Thanks for the help!
Try this. I think this will do what you want.
#echo off
for /f "Tokens=1,2,3*" %%a in ('dir /b filename*') do (
call :rename "%%a %%b %%c %%d" %%a %%b "%%c %%d")
goto :eof
:rename full orig time new
echo %2
set last2=%2
set last2=%last2:~-2%
echo ren "%~1.ext" "%last2%_%3_%~4.ext"
Remove the Echo if everything looks good

batch script - read line by line

I have a log file which I need to read in, line by line and pipe the line to a next loop.
Firstly I grep the logfile for the "main" word (like "error") in a separate file - to keep it small. Now I need to take the seperate file and read it in line by line - each line needs to go to another loop (in these loop I grep the logs and divide it in blocks) but I stuck here.
The log looks like
xx.xx.xx.xx - - "http://www.blub.com/something/id=?searchword-yes-no" 200 - "something_else"
with a for /f loop I just get the IP instead of the complete line.
How can I pipe/write/buffer the whole line? (doesn't matter what is written per line)
Try this:
#echo off
for /f "tokens=*" %%a in (input.txt) do (
echo line=%%a
)
pause
because of the tokens=* everything is captured into %a
edit:
to reply to your comment, you would have to do that this way:
#echo off
for /f "tokens=*" %%a in (input.txt) do call :processline %%a
pause
goto :eof
:processline
echo line=%*
goto :eof
:eof
Because of the spaces, you can't use %1, because that would only contain the part until the first space. And because the line contains quotes, you can also not use :processline "%%a" in combination with %~1. So you need to use %* which gets %1 %2 %3 ..., so the whole line.
The "call" solution has some problems.
It fails with many different contents, as the parameters of a CALL are parsed twice by the parser.
These lines will produce more or less strange problems
one
two%222
three & 333
four=444
five"555"555"
six"&666
seven!777^!
the next line is empty
the end
Therefore you shouldn't use the value of %%a with a call, better move it to a variable and then call a function with only the name of the variable.
#echo off
SETLOCAL DisableDelayedExpansion
FOR /F "usebackq delims=" %%a in (`"findstr /n ^^ t.txt"`) do (
set "myVar=%%a"
call :processLine myVar
)
goto :eof
:processLine
SETLOCAL EnableDelayedExpansion
set "line=!%1!"
set "line=!line:*:=!"
echo(!line!
ENDLOCAL
goto :eof
This has worked for me in the past and it will even expand environment variables in the file if it can.
for /F "delims=" %%a in (LogName.txt) do (
echo %%a>>MyDestination.txt
)
For those with spaces in the path, you are going to want something like this:
n.b. It expands out to an absolute path, rather than relative, so if your running directory path has spaces in, these count too.
set SOURCE=path\with spaces\to\my.log
FOR /F "usebackq delims=" %%A IN ("%SOURCE%") DO (
ECHO %%A
)
To explain:
(path\with spaces\to\my.log)
Will not parse, because spaces.
If it becomes:
("path\with spaces\to\my.log")
It will be handled as a string rather than a file path.
"usebackq delims="
See docs will allow the path to be used as a path (thanks to Stephan).

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