I am looking for an LDAP query that would return all groups that are members of a certain LDAP/AD group, including all children.
Imagine this tree: A, A.1, A.2, A.1.1
I want to query A and get: 3 results: A.1, A.2, A.1.1
From my initial research it seems that is related to LDAP_MATCHING_RULE_IN_CHAIN from http://msdn.microsoft.com/en-us/library/aa746475%28VS.85%29.aspx but I wasn't able to figure out the proper syntax for performing the query.
Note: this is a Microsoft Active Directory so the solution doesn't have to be generic.
Not sure from your explanation what you are trying to accomplish, but One of these should work:
Resolves all members (including nested) security groups (requires at least Windows 2003 SP2)#
(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
Or to retrieve only users:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=YOURDOMAIN,DC=NET)
-jim
Related
For authentication in Jitsi Meet, we would like to read out a Windows AD group with an ldap query. Unfortunately our ldap query does not work.
LDAP_URL=ldaps://server.domain.local:636/
LDAP_BASE=DC=domain,DC=local
LDAP_BINDDN=CN=bind_user,OU=Administrative Accounts,OU=Benutzer,DC=domain,DC=local
LDAP_BINDPW=*
LDAP_FILTER= (&(|objectclass=user))(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)
(primaryGroupID=4989))
The error must be due to the filter, it works with the filter LDAP_FILTER = (sAMAccountName =% u).
Can you tell me what is wrong with our query.
A few things stand out to me:
The | in front of objectClass should not be there.
You have two closing parentheses after the objectClass condition, but the second one should be moved to the end of the whole query.
Oddly, objectClass=user will actually end up including other objects than just user accounts (like computer accounts). If you want to filter to only user objects, you have to use both (objectClass=user)(objectCategory=person). But that would only matter if you have other types of objects as members of that group.
Maybe this is just an error with pasting into the question, but there is a line break before (primaryGroupID=
I've never used Jitsi, but it may or may not like the space after LDAP_FILTER=. The other examples I see online don't show a space there.
It should look like this:
LDAP_FILTER=(&(objectclass=user)(objectCategory=person)(|(memberof=CN=group,OU=Jitsi,OU=Sicherheit,OU=Gruppen,DC=domain,DC=local)(primaryGroupID=4989)))
That means: find all user objects that are either members of that group, or have a primary group ID of 4989.
I have groups as such:
GroupA
GroupB
Users
GroupG
Users
So the goal is to get all users that are members of parent group GroupA.
I have the following filter:
(&(objectCategory=Person)(objectClass=User)(mail=*MyEmailDomain.com)(memberOf=CN=GroupB,OU=MyOU3,OU=MyOU2,OU=MyOU1,DC=MyDomain,DC=LOCAL))
Which works for the lowest level groups.
From research, it seems that this should work, but doesn't:
(&(objectCategory=Person)(objectClass=User)(mail=*MyEmailDomain.com)(memberof:1.2.840.113556.1.4.1941:=(CN=GroupA,OU=MyOU3,OU=MyOU2,OU=MyOU1,DC=MyDomain,DC=LOCAL)))
If it matters, I'm using Active Directory Explorer to get the Distinguished Names, and the LDAP Input step in Pentaho's Data Integration tool (Kettle/PDI) to retrieve the data.
I love the fact that I always find the answer to my questions as soon as I post them somewhere. I need to learn to post much earlier and maybe I will spend less time searching :)
Found a random stackoverflow post that indicated there's an error in the msdn article for this and it has too many parenthesis.
This won't work:
(&(objectCategory=Person)(objectClass=User)(mail=*MyEmailDomain.com)(memberof:1.2.840.113556.1.4.1941:=(CN=GroupA,OU=MyOU3,OU=MyOU2,OU=MyOU1,DC=MyDomain,DC=LOCAL)))
But this DOES work:
(&(objectCategory=Person)(objectClass=User)(mail=*MyEmailDomain.com)(memberof:1.2.840.113556.1.4.1941:=CN=GroupA,OU=MyOU3,OU=MyOU2,OU=MyOU1,DC=MyDomain,DC=LOCAL))
(no parenthesis around the Distinguished Name)
Hi This does not fetch the users recursively. This is just giving the list of users of parent group only.
(&(objectCategory=Person)(objectClass=User)(mail=*MyEmailDomain.com)(memberof:1.2.840.113556.1.4.1941:=CN=GroupA,OU=MyOU3,OU=MyOU2,OU=MyOU1,DC=MyDomain,DC=LOCAL))
I would like to write a search filter which would help me retrieve all groups which a user is part of.
For instance:
Say I am retrieving entries for user A (which is part of group A). And group A may be part of group B and group D which in turn may be part of group E.
Now, my search filter should return me MemberOf attribute as all possible groups which user A is part of (in this specific case it is Group A, B, D, E).
Any pointers on how the search filter can look like?
This should do what you are asking about. It will return the FDN of each group the user is a memberOf, however, this queries the group, not the user.
As an example, to find all the groups that "CN=John Smith,DC=MyDomain,DC=NET" is a member of, set the base to the groups container DN; for example (OU=groupsOU,DC=MyDomain,DC=NET) and the scope to subtree, and use the following filter.
(member:1.2.840.113556.1.4.1941:=(CN=John Smith,DC=MyDomain,DC=NET))
-jim
There is an attribute called tokenGroups in user object. It's a constructed attributes calculated by Active Directory on the runtime. It includes all the groups the user object belong to.
Make sure your domain has a Global Catalog and make sure the account that you are using Pre-Windows 2000 Compatible Access group. Then, make sure tokenGroups is specified as one of the returned property. Do a base scope search on the user object.
You can use adfind.exe (joeware) to sort out this issue and to utilize standard ldap filters that are described here. For example:
http://social.technet.microsoft.com/wiki/contents/articles/5392.active-directory-ldap-syntax-filters.aspx
Group nesting is specified to be like this:
(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)
and if you use adfind, then it would look like this:
adfind -f "(member:1.2.840.113556.1.4.1941:=cn=Jim Smith,ou=West,dc=Domain,dc=com)" samaccountname -list
If you want to have output other than samaccountname, for example displayname, or mail attribute, just add to the list. Also if you want to search multiple users, then you might want to have inputfile containing all users and some script to extract each lines to adfind for example.
How can I use a a search filter to display users of a specific group?
I've tried the following:
(&
(objectCategory=user)
(memberOf=MyCustomGroup)
)
and this:
(&
(objectCategory=user)
(memberOf=cn=SingleSignOn,ou=Groups,dc=tis,dc=eg,dc=ddd,DC=com)
)
but neither display users of a specific group.
memberOf (in AD) is stored as a list of distinguishedNames. Your filter needs to be something like:
(&(objectCategory=user)(memberOf=cn=MyCustomGroup,ou=ouOfGroup,dc=subdomain,dc=domain,dc=com))
If you don't yet have the distinguished name, you can search for it with:
(&(objectCategory=group)(cn=myCustomGroup))
and return the attribute distinguishedName. Case may matter.
For Active Directory users, an alternative way to do this would be -- assuming all your groups are stored in OU=Groups,DC=CorpDir,DC=QA,DC=CorpName -- to use the query (&(objectCategory=group)(CN=GroupCN)). This will work well for all groups with less than 1500 members. If you want to list all members of a large AD group, the same query will work, but you'll have to use ranged retrieval to fetch all the members, 1500 records at a time.
The key to performing ranged retrievals is to specify the range in the attributes using this syntax: attribute;range=low-high. So to fetch all members of an AD Group with 3000 members, first run the above query asking for the member;range=0-1499 attribute to be returned, then for the member;range=1500-2999 attribute.
If the DC is Win2k3 SP2 or above, you can use something like:
(&(objectCategory=user)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com))
to get the nested group membership.
Source: https://ldapwiki.com/wiki/Active%20Directory%20Group%20Related%20Searches
And the more complex query if you need to search in a several groups:
(&(objectCategory=user)(|(memberOf=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf=CN=GroupTwo,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf=CN=GroupThree,OU=Security Groups,OU=Groups,DC=example,DC=com)))
The same example with recursion:
(&(objectCategory=user)(|(memberOf:1.2.840.113556.1.4.1941:=CN=GroupOne,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupTwo,OU=Security Groups,OU=Groups,DC=example,DC=com)(memberOf:1.2.840.113556.1.4.1941:=CN=GroupThree,OU=Security Groups,OU=Groups,DC=example,DC=com)))
I have a scheme that looks like this:
Users exist like UserA, UserB, UserC.
Groups exist like OverGroup, SubGroup.
OverGroup automatically adds new users like UserA, UserB, etc. to its membership.
SubGroup I created myself. I have set OverGroup to be a member of SubGroup.
I want to be able to one-line query SubGroup and retrieve not OverGroup, i.e.:
Values:
CN=OverGroup,OU=Groups,DC=example,DC=com
but the full enumeration of the actual Users (User A, B, C) within OverGroup, i.e.:
Values:
CN=UserA,OU=OtherOU,DC=example,DC=com
CN=UserB,OU=OtherOU,DC=example,DC=com
CN=UserC,OU=OtherOU,DC=example,DC=com
Is there a one-liner LDAP filter that could retrieve this? (It will be put into the ExternalAuth configuration 'ldap' section in a Request Tracker instance. Pretty sure I can only do this with one query the ExternalAuth module can understand.)
Everything I try does not work, and from my reading, it does not seem possible to enumerate a list of users within a group that is a member of another group with any one-line query. Thoughts?
Active Directory has a special search filter option that allows it to filter through chained objects, like nested groups. The capability is described here.
Here is an example of how to retrieve all users in a group, including nested groups:
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:={0}))
where {0} is the DN of the parent group.
(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:=CN=MPV_BedPlacement,OU=Security Groups,OU=Groups,OU=CCHCS,DC=CCHCS,DC=LDAP))
You have to add the full DN for the group and no curly braces.