C - use libcurl to list imap sent mails - c

Question

I use libcurl library to get all email in sent mail box from url : imaps://imap.gmail.com:993/[Gmail]/Sent Mail .But it not run and show error :
curl_easy_perform() failed: URL using bad/illegal format or missing URL
Please help me to check it . Thanks in advance. Toan Nguyen
struct string {
char *ptr;
size_t len;
};
void init_string(struct string *s) {
s->len = 0;
s->ptr = malloc(s->len+1);
if (s->ptr == NULL) {
fprintf(stderr, "malloc() failed\n");
exit(EXIT_FAILURE);
}
s->ptr[0] = '\0';
}
size_t writefunc(void *ptr, size_t size, size_t nmemb, struct string *s)
{
size_t new_len = s->len + size*nmemb;
s->ptr = realloc(s->ptr, new_len+1);
if (s->ptr == NULL) {
fprintf(stderr, "realloc() failed\n");
exit(EXIT_FAILURE);
}
memcpy(s->ptr+s->len, ptr, size*nmemb);
s->ptr[new_len] = '\0';
s->len = new_len;
return size*nmemb;
}
int main(int argc,char *argv[])
{
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
struct string s;
init_string(&s);
curl_easy_setopt(curl,CURLOPT_USERNAME,argv[1]);
curl_easy_setopt(curl,CURLOPT_PASSWORD,argv[2]);
curl_easy_setopt(curl, CURLOPT_URL, "imaps://imap.gmail.com:993/%5BGmail%5D%2FSent%20Mail;UID=*");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writefunc);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, &s);
res = curl_easy_perform(curl);
printf("%s\n", s.ptr);
free(s.ptr);
/* Check for errors */
if(res != CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
/* always cleanup */
curl_easy_cleanup(curl);
}
return 0;
}

Answer 1

The problem is in your IMAPS URI. According to RFC3501, mailbox names with spaces must be enclosed between double quotes " when used with SELECT or any other IMAP command.
The following should work:
curl_easy_setopt(curl, CURLOPT_URL, "imaps://imap.gmail.com:993/\"[Gmail]/All Mail\"");