I have created sql query which is working fine.
But i want to convert this sql query in cakephp format.
I try to convert this query in cakephp but
i am not understanding how to apply where conditions with group by clause.
And i only need to select this column u_data.lane_id AS LaneId, origin_city.pcode AS origin_pcode, dest_city.pcode AS dest_pcode....
not all columns from table.
plz help me to do this.
$options['conditions'] = array(
'CustomerRoute.portfolio_id' => '".$_SESSION["portfolioid"]."'
);
$content = $this->Customer->find('all', $options);
You simply need to define "group" and "fields" within $options-
Instead of $_SESSION, you should stick to the convention and use $this->Session->read instead.
//Eg: $_SESSION["portfolioid"] can be replaced with $this->Session->read("portfolioid")
$options['conditions'] = array(
"CustomerRoute.portfolio_id" => $this->Session->read("portfolioid"),
"u_data.supplier_id" => $this->Session->read("supplierid")
);
$options['fields'] = array(
"u_data.lane_id AS LaneId",
"origin_city.pcode AS origin_pcode",
"dest_city.pcode AS dest_pcode"
); // Add this
$options['group'] = array('CustomerRoute.id'); // Add this
$content = $this->Customer->find('all', $options);
This should give you what you're looking for.
Peace! xD
Can't make sort links work. (concrete or virtual fields).
Vitual fields for my sum() field on this action:
$this->Qca->virtualFields['comps'] = 'Sum(CASE WHEN Qca.qca_tipcode = 1 THEN 1 END)';
$this->Qca->virtualFields['production'] = 'Sum(qca_end - qca_start)';
$this->Qca->virtualFields['idle'] = 'Sum(Qca.qca_durend)';
My find(), works fine:
$hoursvalues = $this->Qca->find('all', array('conditions' => $conditions,
'fields' => array('Qca.dir_id', 'Qca.name', 'Sum(CASE WHEN Qca.qca_tipcode = 1 THEN 1 END) AS Qca__comps', 'Sum(qca_end - qca_start) as Qca__production', 'Sum(Qca.qca_durend) as Qca__idle'),
'group' => array('Qca.dir_id')
)
);
and then:
$this->paginate('Qca' );
$this->set('hoursvalues', $hoursvalues);
What extra settings does $this->paginate('Qca' ); needs? Please note I have all data I need via find().
What is it I'm missing that sorting does not work for either concrete or virtual fields?
Thansk a lot!
Carlos
Part of your problem is the following:
$this->paginate('Qca');
$this->set('hoursvalues', $hoursvalues);
$this->paginate() returns an array with sorted values. What you need to do is specify your extra settings in $this->paginate array and then
$this->set('hoursvalues', $this->paginate('Qca'));
For your other fields, making them virtualFields will make them easier to work with.
I am using the query function in cake PHP ($this->query(select...)), and I know it returns an array of the values. If the query will only return one value, what is the position of that value in the array?
Would $element = $arrayName(0) be correct?
I'm trying to use it as such:
$flowsheet_name = $this->query("select FLOWSHEET_NAME from FLOWSHEET_TEMPLATE where FLOWSHEET_ID = ".$value.";");
$flowsheet_question = $flowsheet_name(0);
array_push($this->$filedMethodMappings, $flowsheet_question => array(
CaBase::KEY_MAPPING_LOGIC_COMPLEXITY => CaBase::LEVEL3_COMPLEXITY,
CaBase::KEY_FIELD_LOGIC_NAME => 'wsUnifiedKey',
CaBase::KEY_FIELD_QUESTION_ID => ''.$value,
)
);
But I can't tell if it's working. I'm getting a double arrow error here:
$flowsheet_question => array(
In CakePHP, easy way to see what is going on in your array is:
debug($flowsheet_name);
I have this $data array: (built on a shell, not a form)
(debugged here)
array(
(int) 0 => array(
(int) 0 => 's511013t',
(int) 1 => 'id3422',
(int) 2 => '1'
),
(int) 1 => array(
(int) 0 => 's511013t',
(int) 1 => 'id3637',
(int) 2 => '1'
)
)
And using saveMany :
$this->Dir->saveMany($data, array( 'validate' => 'false', 'fieldList' => array('name','dir_dataname', 'project_id')));
Saving fails with no error.
I'm not sure if my $data array is well formatted, (I'm confused whether it should have another level) I built it from sql selects, etc. However it does contain all info I need saved, single model.
I'm running all this from a Shell and it does work to save a single record provided the field names everytime:
// this works
$this->Dir->save(array('name' => $data[0][0], 'project_id' => $data[0][2], 'dir_dataname' => $data[0][1]));
Already read Saving your data, and I'd really like to use saveMany and a fieldList due to my custom $data format. (I wouldn't like to have to insert field names on my $data).
(no sql_dump to show since is pretty cumbersome to get it from a shell task)
I've spent all evening trying to figure it out, can you point me in the right direction, Please?
IMHO, the keys in each arrays are not valid fields in your database table. They should represent the same name as your table field.
When you build the array from sql, the output should look like these - an associative array:
array(
(int) 0 => array(
(string) name => 's511013t',
(string) dir_dataname => 'id3422',
(string) project_id => '1'
),
(int) 1 => array(
(string) name => 's511013t',
(string) dir_dataname => 'id3637',
(string) project_id => '1'
)
)
Cake2.0 Docs
$this->Dir->saveMany($data);
You can get the log via
debug($this->Dir->getDataSource()->getLog());
It looks as if you are using fieldList incorrectly. fieldList is a list of fields that are to be whitelisted for saving to the database, not a "mapping" like you are using.
You need to specify field => value pairs in the array for each record, not numerical indexes. I may be wrong, but I've never seen that and it doesn't look to be that way according to docs.
I am writing a CakePHP 1.2 app. I have a list of people that I want the user to be able to filter on different fields. For each filterable field, I have a drop down list. Choose the filter combination, click filter, and the page shows only the records that match.
In people_controller, I have this bit of code:
$first_names = $this->Person->find('list', array(
'fields'=>'first_name',
'order'=>'Person.first_name ASC',
'conditions'=> array('Person.status'=>'1')
));
$this->set('first_names', $first_names);
(Status = 1 because I am using a soft delete.)
That creates an ordered list of all first_names. But duplicates are in there.
Digging around in the Cookbook, I found an example using the DISTINCT keyword and modified my code to use it.
$first_names = $this->Person->find('list', array(
'fields'=>'DISTINCT first_name',
'order'=>'Person.first_name ASC',
'conditions'=> array('Person.status'=>'1')
));
This gives me an SQL error like this:
Query: SELECT `Person`.`id`, DISTINCT `Person`.` first_name` FROM `people` AS `Person` WHERE `Person`.`status` = 1 ORDER BY `Person`.`first_name` ASC
The problem is obvious. The framework is adding Person.id to the query. I suspect this comes from using 'list'.
I will use the selected filter to create an SQL statement when the filter button is clicked. I don't need the is field, but can't get rid of it.
Thank you,
Frank Luke
Try to use 'group by', it works perfectry:
$first_names = $this->Person->find('list', array(
'fields'=>'first_name',
'order'=>'Person.first_name ASC',
'conditions'=> array('Person.status'=>'1'),
'group' => 'first_name'));
You're right, it seems that you cannot use DISTINCT with list. Since you don't need id but only the names, you can use find all like above and then $first_names = Set::extract($first_names, '/Person/first_name');. That will give you a array with distinct first names.
Here's how I did it in CakePHP 3.x:
$query = $this->MyTables->find('all');
$result = $query->distinct()->toArray();
You can try this.
Here this takes Person id as key, so there is no chance for duplicate entries.
$first_names = $this->Person->find('list', array(
'fields' => array('id','first_name'),
'conditions' => array('Person.status' => '1'),
));
$this->set('first_names', $first_names);
Using SQL grouping will also produce a distinct list. Not sure of the negative consequences if any, but it seems to work fine for me.
$first_names = $this->Person->find('list', array(
'fields' => 'first_name',
'order' => 'first_name',
'group' => 'first_name',
'conditions' => array('Person.status' => '1'),
));
$this->set('first_names', $first_names);
I know it is a question for CakePHP 1.2, but I was searching for that too with CakePHP version 3. And in this version there is a method to form the Query into a distinct one:
$first_names = $this->Persons->find(
'list',
[
'fields'=> ['name']
]
)
->distinct();
;
This will generate a sql query like this:
SELECT DISTINCT Persons.name AS `Persons__name` FROM persons Persons
But the distinct method is a bit mightier than just inserting DISTINCT in the query.
If you want to just distinct the result on one field, so just throwing away a row with a duplicated name, you can also use the distinct method with an array of the fields as parameter:
$first_names = $this->Persons->find(
'list',
[
'fields'=> ['id', 'name'] //it also works if the field isn't in the selection
]
)
->distinct(['name']); //when you use more tables in the query, use: 'Persons.name'
;
This will general a sql query like this (for sure it is a group query):
SELECT DISTINCT
Persons.id AS `Persons__id`, Persons.name AS `Persons__name`
FROM persons Persons
GROUP BY name #respectively Persons.name
Hope I will help some for CakePHP 3. :)
Yes the problem is that you are using a listing which designed for a id / value output. You probably will have to do a find('all') and then build the list yourself.
Yes I also tried to fetch unique results with 'list' but its not working. Then I fixed the problem by using 'all'.
In the example now on the book for version 2 it states the following:
public function some_function() {
// ...
$justusernames = $this->Article->User->find('list', array(
'fields' => array('User.username')
));
$usernameMap = $this->Article->User->find('list', array(
'fields' => array('User.username', 'User.first_name')
));
$usernameGroups = $this->Article->User->find('list', array(
'fields' => array('User.username', 'User.first_name', 'User.group')
));
// ...
}
With the above code example, the resultant vars would look something like this:
$justusernames = Array
(
//[id] => 'username',
[213] => 'AD7six',
[25] => '_psychic_',
[1] => 'PHPNut',
[2] => 'gwoo',
[400] => 'jperras',
)
$usernameMap = Array
(
//[username] => 'firstname',
['AD7six'] => 'Andy',
['_psychic_'] => 'John',
['PHPNut'] => 'Larry',
['gwoo'] => 'Gwoo',
['jperras'] => 'Joël',
)
$usernameGroups = Array
(
['User'] => Array
(
['PHPNut'] => 'Larry',
['gwoo'] => 'Gwoo',
)
['Admin'] => Array
(
['_psychic_'] => 'John',
['AD7six'] => 'Andy',
['jperras'] => 'Joël',
)
)
You have to plan your query in a slightly different way and plan your database to accommodate a list find.
In some cases, you wish to group by using some key, but you want unique element within the results.
For example, you have a calendar application with two types of events. One event on day 1rst and the other one on the 2nd day of month 1. And you want to show or rather count all the events, grouped by day and by type.
If you use only DISTINCT, it is quite difficult. The simplest solution is to group twice:
$this->Events->virtualFields['count'] = 'COUNT(*)';
$acts = $this->Activity->find('all',array(
'group' => array('DAY(Event.start)','EventType.id'),
));
Just group by the fields that you want to get distinct.. or use Set::extract() and then array_unique()
In 2.7-RC version, this is working
$this->Model1->find('list', array(
'fields' => array('Model1.field1', Model1.field1')
));