How to kill a process synchronously on Linux? - c

When I call kill() on a process, it returns immediately, because it just send a signal. I have a code where I am checking some (foreign, not written nor modifiable by me) processes in a loop infinitely and if they exceed some limits (too much ram eaten etc) it kills them (and write to a syslog etc).
Problem is that when processes are heavily swapped, it takes many seconds to kill them, and because of that, my process executes the same check against same processes multiple times and attempts to send the signal many times to same process, and write this to syslog as well. (this is not done on purpose, it's just a side effect which I am trying to fix)
I don't care how many times it send a signal to process, but I do care how many times it writes to syslog. I could keep a list of PID's that were already sent the kill signal, but in theory, even if there is low probability, there could be another process spawned with same pid as previously killed one had, which might also be supposed to be killed and in this case, the log would be missing.
I don't know if there is unique identifier for any process, but I doubt so. How could I kill a process either synchronously, or keep track of processes that got signal and don't need to be logged again?

Even if you could do a "synchronous kill", you still have the race condition where you could kill the wrong process. It can happen whenever the process you want to kill exits by its own volition, or by third-party action, after you see it but before you kill it. During this interval, the PID could be assigned to a new process. There is basically no solution to this problem. PIDs are inherently a local resource that belongs to the parent of the identified process; use of the PID by any other process is a race condition.
If you have more control over the system (for example, controlling the parent of the processes you want to kill) then there may be special-case solutions. There might also be (Linux-specific) solutions based on using some mechanisms in /proc to avoid the race, though I'm not aware of any.
One other workaround may be to use ptrace on the target process as if you're going to debug it. This allows you to partially "steal" the parent role, avoiding invalidation of the PID while you're still using it and allowing you to get notification when the process terminates. You'd do something like:
Check the process info (e.g. from /proc) to determine that you want to kill it.
ptrace it, temporarily stopping it.
Re-check the process info to make sure you got the process you wanted to kill.
Resume the traced process.
kill it.
Wait (via waitpid) for notification that the process exited.

This will make the script wait for process termination.
kill $PID
while [ kill -0 $PID 2>/dev/null ]
do
sleep 1
done
kill -0 [pid] tests the existence of a process

The following solution works for most processes that aren't debuggers or processes being debugged in a debugger.
Use ptrace with argument PTRACE_ATTACH to attach to the process. This stops the process you want to kill. At this point, you should probably verify that you've attached to the right process.
Kill the target with SIGKILL. It's now gone.
I can't remember whether the process is now a zombie that you need to reap or whether you need to PTRACE_CONT it first. In either case, you'll eventually have to call waitpid to reap it, at which point you know it's dead.

If you are writing this in C you are sending the signal with the kill system call. Rather than repeatedly sending the terminating signal just send it once and then loop (or somehow periodically check) with kill(pid, 0); The zero value of signal will just tell you if the process is still alive and you can act appropriately. When it dies kill will return ESRCH.

when you spawn these processes, the classical waitpid(2) family can be used
when not used anywhere else, you can move the processes going to be killed into an own cgroup; there can be notifiers on these cgroups which get triggered when process is exiting.
to find out, whether process has been killed, you can chdir(2) into /proc/<pid> or open(2) this directory. After process termination, the status files there can not be accessed anymore. This method is racy (between your check and the action, the process can terminate and a new one with the same pid be spawned).

Related

A C program process is waited by some OS routine?

Well, I'm learning about processes using the C language, and I have seen that when you call the exit function a process is terminated and without waiting for it, it will become a zombie process. My question is, if the first process created when executing the program is a process itself, is there a 0S routine that wait for it after an exit() call, avoiding that it becomes a zombie process? I'm curious about it.
For Unix systems at least (and I expect Windows is similar), when the system boots, it creates one special first process. Every process after that is created by some existing process.
When you log into a windowed desktop interface, there is some desktop manager process (that has been created by the first process or one of its descendants) managing windows. When you start a program by clicking on it, that desktop manager or one of its children (maybe some file manager software) creates a process to run the program. When you start a program by executing a command in a terminal window, there is a command line shell process that is interpreting the things you type, and it creates a process to run the program.
So, in all cases, your user program has a parent process, either a command-line shell or some desktop software.
If a child process creates another child (even as the first instruction) then the parent also has to wait for it or it becomes a zombie.
Basically processes always become zombie until they are removed from the process table, the OS (via the process init) will handle and wait() for orphans (zombies without parents), it does that periodically so normally you won't have orphans running for very long.
On Linux, the top most (parent) process is init. This is the only process, which has no parent. Any other process (without any exception) do have a parent and hence is a child of another process.
See:
init
Section NOTES on wait
A child that terminates, but has not been waited for becomes a
"zombie". The kernel maintains a minimal set of information
about the zombie process (PID, termination status, resource usage
information) in order to allow the parent to later perform a wait
to obtain information about the child. As long as a zombie is
not removed from the system via a wait, it will consume a slot in
the kernel process table, and if this table fills, it will not be
possible to create further processes. If a parent process
terminates, then its "zombie" children (if any) are adopted by
init(1), ... init(1) automatically performs a wait to remove the
zombies.

How to asynchronously wait for process termination and find out the exit code?

The waiting works fine with pidfd_open and poll.
The problem I’m facing, after the process quits, apparently the poll() API removes the information about the now dead process, so the waitid with P_PIDFD argument fails at once saying code 22 “Invalid argument”
I don’t think I can afford launching a thread for every child process to sleep on the blocking waitpid, I have multiple processes, and another handles which aren’t processes I need to poll efficiently.
Any workarounds?
If it matters, I only need to support Linux 5.13.12 and newer running on ARM64 and ARMv7 CPUs.
The approximate sequence of kernel calls is following:
fork
In the child: setresuid, setresgid, execvpe
In the new child: printf, sleep, _exit
Meanwhile in the parent: pidfd_open, poll, once completed waitid with P_PIDFD first argument.
Expected result: waitid should give me the exit code of the child.
Actual result: it does nothing and sets errno to EINVAL
There is one crucial bit. From man waitid:
Applications shall specify at least one of the flags WEXITED, WSTOPPED, or WCONTINUED to be OR'ed in with the options argument.
I was passing was WNOHANG
And you want to pass WNOHAND | WEXITED ;)
You can use a single reaper thread, looping on waitpid(-1, &status, 0). Whenever it reaps a child process, it looks it up in the set of current child processes, handles possible notifications (semaphore or callback), and stores the exit status.
There is one notable situation that needs special consideration: the child process may exit before fork() returns in the parent process. This means it is possible for the reaper to see a child process exiting before the code that did the fork() manages to register the child process ID in any data structure. Thus, both the reaper and the fork() registering functions must be ready to look up or create the record in the data store keeping track of child processes; including calling the callback or posting the semaphore. It is not complicated at all, but unless you are used to thinking in asynchronous terms, it is easy to miss these corner cases.
Because wait(...)/waitpid(-1,...) returns immediately when there are no child processes to wait for (with -1 and errno set to ECHILD), the reaper thread should probably wait on a condition variable when there are no child processes to wait for, with the code that registers the child process ID signaling on that condition variable to minimize resource use in the no-child-processes case. (Also, do remember to minimize the reaper thread stack size, as it is unreasonably large (order of 8 MiB) by default, and wastes resources. I often use 2*PTHREAD_STACK_MIN, myself.)

Calling exec() or spawn(P_OVERLAY) unblocks the console; any way to keep the console blocked?

Ina console application, passing _P_OVERLAY to a spawn function (which has the same effect as calling exec), destroys the current process.
This would be the desired behavior if it were not for the fact that doing so causes the calling process (which is often cmd.exe) to assume its callee has returned, whereas in reality the spawned sub-process of that callee is still running and therefore the caller should wait for that callee to terminate before continuing to use the console.
So, if the caller is cmd.exe (the command prompt), what happens is that as soon as the callee spawns the sub-process, the user is immediately prompted with the C:\Users\User> prompt, and becomes free to type in more commands, even though the sub-process is still running.
The best solution I have is to avoid terminating the current process until the child has terminated, but I'm wondering: is there any way to have the calling process wait on the spawned sub-processes before continuing when the callee has terminated?
No, there is no way to do this - if you want cmd.exe to wait for your child to exit, then you need to wait for your child to exit.
The reason is that when cmd.exe launches your process it receives a process handle; it then waits for that process handle to become signaled. Most other parents (for example, the C runtime library) will behave the same way. Process handles are signaled when the process they refer to exits, and there is no way to change that behaviour.
Workaround: presumably you are using _P_OVERLAY because you're porting from UNIX code. If there is too much code to conveniently change all of the instances to wait for the child before exiting, you could start a child process as soon as your process starts, and run all of the UNIX-based code in the child. In this model, the only thing the top-level process does is to wait for the rest of the process tree to exit. (You can use a job object to keep track of the process tree.)

Why are all processes killed when a terminal session ends?

Not long ago, I wondered about the question: why are all processes killed when you close a terminal on Linux, and not passed to the "init" process (with pid 1)?
Because, all child processes are adopted by "init" process after termination of the parent.
Please, help me understand difference and the errors in my reasoning.
And also:
If it's possible, then can we use a system call to stop this happening? I think, that for this the programs need use setsid(), but in practice it's not correct.
As explained by cnicutar, it's due to the SIGHUP sent to all processes in the process group associated with the controlling terminal. You may either install a handler for this signal or ignore it completely. For arbitrary programs, you can start them with the nohup utility designed for this purpose.
You can also place the process in a new process group without a controlling terminal.
why on close terminal on linux all his processes will terminated, but
not passed to "init" process (with pid 1)
The processes are losing their controlling terminal so the kernel sends them a SIGHUP. The default action of SIGHUP is to terminate the process.
i think this will help you to understand
http://www.digipedia.pl/usenet/thread/18802/10189/

Passing the shell to a child before aborting

Current scenario, I launch a process that forks, and after a while it aborts().
The thing is that both the fork and the original process print to the shell, but after the original one dies, the shell "returns" to the prompt.
I'd like to avoid the shell returning to the prompt and keep as if the process didn't die, having the child handle the situation there.
I'm trying to figure out how to do it but nothing yet, my first guess goes somewhere around tty handling, but not sure how that works.
I forgot to mention, the shell takeover for the child could be done on fork-time, if that makes it easier, via fd replication or some redirection.
I think you'll probably have to go with a third process that handles user interaction, communicating with the "parent" and "child" through pipes.
You can even make it a fairly lightweight wrapper, just passing data back and forth to the parent and terminal until the parent dies, and then switching to passing to/from the child.
To add a little further, as well, I think the fundamental problem you're going to run into is that the execution of a command by the shell just doesn't work that way. The shell is doing the equivalent of calling system() -- it's going to wait for the process it just spawned to die, and once it does, it's going to present the user with a prompt again. It's not really a tty issue, it's how the shell works.
bash (and I believe other shells) have the wait command:
wait: wait [n]
Wait for the specified process and report its termination status. If
N is not given, all currently active child processes are waited for,
and the return code is zero. N may be a process ID or a job
specification; if a job spec is given, all processes in the job's
pipeline are waited for.
Have you considered inverting the parent child relationship?
If the order in which the new processes will die is predictable, run the code that will abort in the "child" and the code that will continue in the parent.

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